I need to make view accessible without authentication, based on a variable passed in urls.py.
My idea is something like this:
urls.py
url(r'^oidc-api/', include('api.urls'), {'logged': True})
views.py
class ExampleViewSet(ModelViewSet):
if logged: # How can I get this variable, passed in urls.py?
permission_classes = () # This will exclude current view from authentication
queryset = Widget.objects.filter(visible=True)
serializer_class = ExampleSerializer
filter_backends = (DjangoFilterBackend,)
filter_fields = ('example_id',)
However, I can not access logged variable that is passed from urls.py.
John
You can't do that.
What you could do is, remove those permission classes from the views manually or set those to an empty set as,
class ExampleViewSet(ModelViewSet):
permission_classes = ()
Related
How to handle complex required permissions in any API using django-rest-framework?
For example, you have three tier support operators who have access to APIs, but they should only have access to respective endpoint and as the last tier, superadmin should have everything in hands.
How to solve this simple problem by django group and permissions?
There are lots of answers being related to AND or OR the perms in permission_classes like
def get_permissions(self):
return (
IsAuthenticated & (IsCommitteeHead|IsCommitteeMember|IsAdminUser)
)()
or
permission_classes = [IsAuthenticated &(IsCommitteeHead|IsCommitteeMember|IsAdminUser)]
but I think hard coding always makes the code a complete mess!
Create new permission model permission from django base model permission like this:
from rest_framework.permissions import DjangoModelPermissions
class FullDjangoModelPermissions(DjangoModelPermissions):
perms_map = {
'GET': ['%(app_label)s.view_%(model_name)s'],
'OPTIONS': ['%(app_label)s.view_%(model_name)s'],
'HEAD': ['%(app_label)s.view_%(model_name)s'],
'POST': ['%(app_label)s.add_%(model_name)s'],
'PUT': ['%(app_label)s.change_%(model_name)s'],
'PATCH': ['%(app_label)s.change_%(model_name)s'],
'DELETE': ['%(app_label)s.delete_%(model_name)s'],
}
And in view class like this:
class SomeAwuful(GenericAPIView):
...
permission_classes = [FullDjangoModelPermissions]
...
Then you can go in Django admin dashboard and set who has access to what, or creating group to access features, like this:
I'm using Django Rest Framework for created a API. In this project i want to capture parameters in the URL. For example i want to capture the username and password of a user and my idea is like this:
http://localhost:8000/accounts/login/?unsername=username&password=password
But i cant, I' usin routers and django-filter, but i cant get the parameters url. My project files are there:
view.py:
class AccountsData(viewsets.ModelViewSet):
queryset = models.UserData.objects.all()
serializer_class = serializers.AccountsDataSerializer
permission_classes = (IsAuthenticated,)
filter_backends = (filters.DjangoFilterBackend,)
filterset_fields = ['username', 'password']
lookup_url_kwarg = 'username'
#action(methods=['get'], detail=True, url_name='login', url_path='login')
def login(self, request, pk=None):
return Response({"Login successfully"}, 200)
urls.py:
from api import views
router = routers.SimpleRouter()
router.register(r'accounts', views.AccountsData)
Request query parameters have nothing to do with routing, they are passed with the request independently of how you configure the route. You have access to them in request.query_params, for example, request.query_params.get('username') would get the value of the username parameter.
Being said that, your idea has a terrible mistake: password or any kind of confidential data should NEVER go in query parameters, you should use an http verb that carries the data in its body (POST, for example).
I am trying to create a post request from Angular 5 to DRF. The field is a form that a user submits. I created the serializer and i can post something from DRF interface
models.py
class UserForm(models.Model):
id_user_form = models.AutoField(primary_key=True)
user = models.ForeignKey(User, on_delete=models.CASCADE, db_column='idUser', unique=False)
name = models.CharField(max_length=50)
type = models.CharField(max_length=25)
location = models.CharField(max_length=200)
serilizers.py
`class UserFormSerializer(serializers.ModelSerializer):
class Meta:
model = UserForm
fields = ('user', 'name', 'type', 'location')
def create(self, validated_data):
user_data = validated_data.pop('user')
user_form = UserForm.objects.create(user_id=user_data, **validated_data)
return user_form
views.py
class FormSubmit(generics.ListCreateAPIView):
queryset = UserForm.objects.all()
serializer_class = UserFormSerializer
When i try to post it via Angular I get this error:
Forbidden (CSRF token missing or incorrect.): /api/form/
Am I doing something wrong?
Had the exact same problem when I wanted to upload a profile picture to my Django REST backend.
You have 2 options, basically.
The first one is disabling the CSRF checks, which are by default enforced by DRF. Have a read here. You may do this for testing purposes.
The second option would be to pass the CSRF Token inside your request header. To do that, have a look at the $cookies API.
With that, you can get the token out of the cookie and paste it into your header like so: 'X-CSRFToken': your-csrf-token-here.
You can verify this by opening your dev tools inside the browser and navigating to your site's cookies. You should see one called csrftoken there.
I hope this sent you on the right track.
i have this view handling only /GET/ request to display all authors only if the logged user is superuser
class AuthorView(generics.ListAPIView):
serializer_class = AuthorSerializer
queryset = Author.objects.all()
permission_class = (IsSuperUser,)
And the permission for superuser:
class IsSuperUser(permissions.BasePermission):
def has_permission(self, request, view):
user = request.user
return user.is_authenticated() and user.is_superuser
The permission does not seems to be working, placed the pdb in has_permission the control does not seems to coming there.
What am i missing ?
It should be:
permission_classes = (IsSuperUser,)
and not
permission_class = (IsSuperUser,)
I set basic authentication in my setting.py as follows. Now I need a view that doesn't use basic authentication. How can I do it.
REST_FRAMEWORK = {
'DEFAULT_AUTHENTICATION_CLASSES': (
'rest_framework.authentication.BasicAuthentication',),
}
To exclude a view from authentication, set authentication_classes and permission_classes to [].
class SignupView(APIView):
authentication_classes = []
permission_classes = []
def post(self, request):
# view code
You simply need to set the authentication_classes on your view. Have a look at http://www.django-rest-framework.org/api-guide/authentication/#setting-the-authentication-scheme for an example.
Edit:
To remove authentication, set the authentication_classes to an empty list. Don't forget to remove permissions as well since they usually rely on authentication.