Shell script to verify data packages - macos

I need to make shell script to check my algorithms with loads of data(tests packages saved in .in files, every package contains folder with .in file and the other one with .out file where supposed to be correct result)
Sometimes It's about 1000 files in one packages so there's no point of doing it manually. I need some kind of loop which opens this .in file then redirect input of my c++ program and also redirect output of this program(save result to .out files) But the point is I can't get this language as quick as I need.
And I would like this script to compare results of my algorithm to .out files from packages
for f in ExternalIn/*.in; do//part of code which opens process with my algorithm and compare its .out file to .out file from package

Skipping checks for missing files, whitespace-safety, etc., you probably need something like:
for f in ExternalIn/*.in; do
# diff the result of my_cpp_app eating file.in with file.out
# and store the comparison result in file.diff
diff ${f/.in/.out} <(my_cpp_app <$f 2>/dev/null) > ${f/.in/.diff}
done
Although I would probably do it with find / xargs pipeline which is not only safer but also allows parallel execution.
Or even write a Makefile for this and use make, which after all is a tool for exactly this kind of work.

Related

Combine CSV files with condition

I need to combine all the csv files in some directory (.csv), provided that there are other files with the same name in this directory, but with different expansion (.csv.done).
If a csv file doesn't have .done in this extension then I don't need it for combine process.
What is the best way to do it using Bash ?
This approach is a solution to your problem. I see you've commented that it "didn't work", but whatever the reason is for it not working, it's likely simple to fix e.g. if you forgot to include key details, or failed to adapt it appropriately to suit your specific situation. If you need further help troubleshooting, add more info to your question.
The approach:
for f in *.csv.done
do
cat "${f%.*}" >> combined_file.csv
done
How it works:
In your example, you have 3 files named 1.csv 2.csv 3.csv and two 'done' files named 1.csv.done 2.csv.done.
This script begins by making a list of all files that end in .csv.done (two files: 1.csv.done 2.csv.done).
It then uses a parameter expansion, specifically ${parameter%word}, to 'shorten' the name of the two files in the list to .csv (instead of .csv.done).
Then it 'prints' the content of the two 'shortened' filenames (1.csv and 2.csv) into a 'combined' file.
It doesn't 'print' the content of 1.csv.done or 2.csv.done, or 3.csv, because these files weren't in the original 'list'.
If you run this script multiple times, it will keep adding the contents of files 1.csv and 2.csv to the 'combined' file (only run it once, or delete the 'combined' file before running it again)

Shell, copy files with similar names

I would like to copy a series of similar files from the current directory to the target directory, the files under the current directory are:
prod07_sim0500-W31-0.2_velocity-models-2D_t80_f0001_ux.hst
prod07_sim0500-W31-0.2_velocity-models-2D_t80_f0001_uz.hst
prod07_sim0500-W31-0.2_velocity-models-2D_t80_f0002_ux.hst
prod07_sim0500-W31-0.2_velocity-models-2D_t80_f0002_uz.hst
prod07_sim0500-W31-0.2_velocity-models-2D_t80_f0003_ux.hst
prod07_sim0500-W31-0.2_velocity-models-2D_t80_f0003_uz.hst
Where sim is from sim0001 to sim0500 and f is from f0001 to f0009. I only need f0002, f0005 and f0008. I write the following code:
target_dir="projects/data"
for i in {0001..0500}; do
for s in f000{2,5,8}; do
files="[*]$i[*]$s[*]"
cp $files target_dir
done
done
I am very new to Shell, and wondering how to write the $files="[*]$i[*]$s[*]"$, so that it could match only the f0002, f0005 and f0008. The reason why I also use for i in {0001..0500}; do is that the files are too large and I would like to make sure I could access some completed ones (for example, including all sim0001) in the beginning.
Edit: changed for s in f0002 f0005 f0008; do to f000{2,5,8}.
What you need is globbing and a bit different quoting:
cp *"$i"*"$s"* "$target_dir"
Not storing this in a variable is intentional - it's faster and it's safe. If you end up with such a large list of files that you start running into system limits you'll have to look into xargs.

Bash get all specific files in specific directory

I have a script that takes as an argument a path to a file upon which it performs certain operations. These files are stored in directories with path storage///_id/files (so in 2016 July 22 it would be storage/2016/Jul/22_1/files for the first set of files, .../Jul/22_2/files for second one etc.). The problem is each directory stores files with two extensions (say file.doc, file.txt) and I want to perform operations only on .txt files. I've tested earlier something like
for file in "/home/gonczor/temp/"*/*".txt"; do
echo "$file"
done
And it worked perfectly given that names in directories don't change. When I move one step further and add this 22_1, 22_2, 23_1 directories something strange happens.
This is my script (simplified):
for file in "$FILE_PATH/""$YEAR/""$MONTH/""$DAY"*/*".txt"; do
my_program ${report}
done
And instead of finding .../2016/Jul/22_1/file.txt it finds /2016/Jul/22*/*.txt
How can I make it work? The solution I've tried to make up is from here

Writing to popen and reading back several files in Ruby

I need to run some shell commands on a number of files and sometimes I get back more than one file in response. The question is: How can I read back several files from IO.popen in Ruby?
For instance, imagine the following case:
file = grid.get(record['_id']) # fetch a file from database
IO.popen('tar -Oxmz', 'ab') {|pipe| pipe.write(file.read)} # pass to tar and extract
This necessitates that I reread all the extracted files from the filesystem. I figured out this is the speed bottleneck of my script and I wonder if I can accomplish the same task in-memroy. I tried the following:
file = grid.get(record['_id'])
IO.popen('tar -Oxmz', 'w+b') do |pipe|
pipe.write(file.read)
pipe.close_write
output = pipe.read
end
It works, but I get the whole response, here including several extracted files, in one piece (in variable output). I need the files separate from each other and possibly with their names. Is there any way to do this?
By the way, the resulting files are most of the time text, but sometimes binary. Running a pipe for each output file is not a solution, because the actual overhead of running the commands for each file outweights the benefits of doing the transformation in-memory.
P.S. The actual use case does not rely on tar only. I use software that do not have Ruby wrappers.

Finding and Removing Unused Files Through Command Line

My websites file structure has gotten very messy over the years from uploading random files to test different things out. I have a list of all my files such as this:
file1.html
another.html
otherstuff.php
cool.jpg
whatsthisdo.js
hmmmm.js
Is there any way I can input my list of files via command line and search the contents of all the other files on my website and output a list of the files that aren't mentioned anywhere on my other files?
For example, if cool.jpg and hmmmm.js weren't mentioned in any of my other files then it could output them in a list like this:
cool.jpg
hmmmm.js
And then any of those other files mentioned above aren't listed because they are mentioned somewhere in another file. Note: I don't want it to just automatically delete the unused files, I'll do that manually.
Also, of course I have multiple folders so it will need to search recursively from my current location and output all the unused (unreferenced) files.
I'm thinking command line would be the fastest/easiest way, unless someone knows of another. Thanks in advance for any help that you guys can be!
Yep! This is pretty easy to do with grep. In this case, you would run a command like:
$ for orphan in `cat orphans.txt`; do \
echo "Checking for presence of ${orphan} in present directory..." ;
grep -rl $orphan . ; done
And orphans.txt would look like your list of files above, one file per line. You can add -i to the grep above if you want to grep case-insensitively. And you would want to run that command in /var/www or wherever your distribution keeps its webroots. If, after you see the above "Checking for..." and no matches below, you haven't got any files matching that name.

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