Achieve desired value after a 3D die roll without face texture swapping - three.js

I'm making a 3d dice game and came to one issue I can't wrap my head around so I'm turning to you for help.
In the scene/world (using threejs with cannonjs) I have a plane and one die, which I'm throwing on the plane (screenshots here pre-roll http://prntscr.com/l9rat5, result http://prntscr.com/l9rdeb). All works fine, until I want to throw some specific value on a die like 1 for example.
Since I'm using loaded models instead of texture images for faces of the cube, I cannot handle this just by changing faces of the cube in threejs (since model has 100s of them). Therefore I was hoping I can achieve this by somehow changing the initial quaternion of the body (kind of pre-rotate it) so the die falls on a specific side. The die mesh is just following the body position and quaternion.
I have these questions:
Is this even possible to do? Maybe when I change quaternion pre throw it will result always in different final quaternion, which I can not determine? If it is not possible to do with quaternions, any tips?
If it is possible, how do I figure out by which quaternion do I need to multiply my initial one to get desired result value 1? I have available the final quaternion and I know which values are on each face from emulated throw so I was trying to play with quaternion inverse but no luck.
If I just rotate the initial body so that face 1 rotates to the result face (eg. 6) it works in some cases (i throw 1 when emulated result was 6), but when the throw gets more complicated (more rotations) it is not working of course since I'm not counting on all possible rotations.
If it is not clear what I mean let me know pls.
Thanks a lot
m

First of all, make sure that you use fixed step simulation. You do this by passing 3 arguments to world.step() instead of one. This will make sure that your simulation will behave the same every time, regardless of frame rate.
Also make sure that your initial position, velocity and force of the die is the same every throw.
If you construct the quaternion using the built in cannon functions, like .setFromAxisAngle(), all should be good... Use .setFromAxisAngle() with even 90-degree angles around different axis. Why bother using quaternion inverse?
If you want an alternative way of rotating the die, put the mesh below an empty parent mesh in your scene. During simulation, copy the cannon.js output to the parent mesh. Then rotate the child die mesh to get the desired initial (and end) rotation.

For the note, I solved it by rotating just the geometry (not mesh) in threejs and not touching the quaternion of the body at all.

Related

Babylon.js - Solid Particle System - Move In Facing Direction

I want to emit a bunch of particles inside of a sphere, then connect them all up with lines and make everything move around.
I am at the point where I want to animate the particles of the Solid Particle System.
They are currently facing different directions, because of this line inside of the SPS.initParticles function:
particle.rotation = new BABYLON.Vector3(getRandomArbitrary(0,360), getRandomArbitrary(0,360), getRandomArbitrary(0,360));
Now i want to move them in the direction they are facing.
My theoretical thinking would be to get the vector the particle is facing, multiply it by some factor to modulate the speed and then add that to the old position in the update function.
However
SPS.particles[0].rotation
returns Euler angles, if I am not mistaken and I have not found a .toVector method.
Is there either a cleverer way to do this or have I missed something obvious?
I made a playgound, if it helps: https://www.babylonjs-playground.com/#CIN41K

How to determine camera location from view matrix?

for a personal project, I've created a simple 3D engine in python using as little libraries as possible. I did what I wanted - I am able to render simple polygons, and have a movable camera. However, there is a problem:
I implemented a simple flat shader, but in order for it to work, I need to know the camera location (the camera is my light source). However, the problem is that I have no way of knowing the camera's location in the world space. At any point, I am able to display my view matrix, but I am unsure about how to extract the camera's location from it, especially after I rotate the camera. Here is a screenshot of my engine with the view matrix. The camera has not been rotated yet and it is very simple to extract its location (0, 1, 4).
However, upon moving the camera to a point between the X and Z axes and pointing it upwards (and staying at the same height), the view matrix changes to this:
It is obvious now that the last column cannot be taken directly to determine the camera location (it should be something like (4,1,4) on the last picture).
I have tried a lot of math, but I can't figure out the way to determine the camera x,y,z location from the view matrix. I will appreciate any and all help in solving this, as it seems to be a simple problem, yet whose solution eludes me. Thank you.
EDIT:
I was advised to transform a vertex (0,0,0,1) by my view matrix. This, however, does not work. See the example (the vertex obviously is not located at the printed coordinates):
Just take the transform of the vector (0,0,0,1) with the modelview matrix: Which is simply the rightmost column of the modelview matrix.
EDIT: #ampersander: I wonder why you're trying to work with the camera location in the first place, if you assume the source of illumination to be located at the camera's position. In that case, just be aware, that in OpenGL there is no such thing as a camera, and in fact, what the "view" transform does, is move everything in the world around so that where you assume your camera to be ends up at the coordinate origin (0,0,0).
Or in other words: After the modelview transform, the transformed vertex position is in fact the vector from the camera to the vertex, in view space. Which means that for your assumed illumination calculation the direction toward the light source, is the negative vertex position. Take that, normalize it to unit length and stick it into the illumination term.

Can points or meshes be drawn at infinite distance?

I'm interested in drawing a stardome in THREE.js using either mesh points or a particle system.
I don't want the camera to be able to move any closer to any part of the stardome, since the stars are effectively at infinite distance.
I can think of a couple of ways to do this:
A very large mesh (or very large point/particle distances)
Camera and stardome have their movement exactly linked.
Is there any way to specify a mesh, point, or particle system is automaticaly rendered at infinite distance so it is always drawn behind any foreground objects?
I haven't used three.js, but my guess is no. OpenGL camera's need a "near clipping plane" and "far clipping plane", which effectively denote the minimum and maximum distance that it'll render things in. If you've played video games where you move too close to a wall and start to see through it, or see things in the distance suddenly vanish as you move away, those were probably the clipping planes at work.
The workaround is usually one of 2 ways:
1) Set the far clipping plane distance as high as it'll let you go. I don't know what data type three.js would use for this, but my guess is a 32-bit float.
2) Render it in "layers". Render all the stars first before anything else in the scene.
Option 2 is the one I usually use.
Even if you used option 1, you would still synchronize the position of the camera and skybox.
If you do not depth cull, draw the skybox first and match its position, but not rotation, to the camera.
Also disable lighting on the skybox. Instead, bake an ambience directly into its texture.
You're don't want things infinitely away, you just want them not to move with respect to the viewer and to not appear in front of things. The best way to do that is to prevent the viewer from getting closer to them which produces the illusion of the object being far away. The second thing is to modify your depth culling function so that the skybox is always considered further away than whatever you are currently drawing.
If you create a very large mesh object, you'll have to set your camera's far plane large enough to include the mesh which means you'll end up drawing things that you really do want to cull.

three.js - Overlapping layers flickering

When several objects overlap on the same plane, they start to flicker. How do I tell the renderer to put one of the objects in front?
I tried to use .renderDepth, but it only works partly -
see example here: http://liveweave.com/ahTdFQ
Both boxes have the same size and it works as intended. I can change which of the boxes is visible by setting .renderDepth. But if one of the boxes is a bit smaller (say 40,50,50) the contacting layers are flickering and the render depth doesn't work anymore.
How to fix that issue?
When .renderDepth() doesn't work, you have to set the depths yourself.
Moving whole meshes around is indeed not really efficient.
What you are looking for are offsets bound to materials:
material.polygonOffset = true;
material.polygonOffsetFactor = -0.1;
should solve your issue. See update here: http://liveweave.com/syC0L4
Use negative factors to display and positive factors to hide.
Try for starters to reduce the far range on your camera. Try with 1000. Generally speaking, you shouldn't be having overlapping faces in your 3d scene, unless they are treated in a VERY specific way (look up the term 'decal textures'/'decals'). So basically, you have to create depth offsets, and perhaps even pre sort the objects when doing this, which all requires pretty low-level tinkering.
If the far range reduction helps, then you're experiencing a lack of precision (depending on the device). Also look up 'z fighting'
UPDATE
Don't overlap planes.
How do I tell the renderer to put one of the objects in front?
You put one object in front of the other :)
For example if you have a camera at 0,0,0 looking at an object at 0,0,10, if you want another object to be behind the first object put it at 0,0,11 it should work.
UPDATE2
What is z-buffering:
http://en.wikipedia.org/wiki/Z-buffering
http://msdn.microsoft.com/en-us/library/bb976071.aspx
Take note of "floating point in range of 0.0 - 1.0".
What is z-fighting:
http://en.wikipedia.org/wiki/Z-fighting
...have similar values in the z-buffer. It is particularly prevalent with
coplanar polygons, where two faces occupy essentially the same space,
with neither in front. Affected pixels are rendered with fragments
from one polygon or the other arbitrarily, in a manner determined by
the precision of the z-buffer.
"The renderer cannot reposition anything."
I think that this is completely untrue. The renderer can reposition everything, and probably does if it's not shadertoy, or some video filter or something. Every time you move your camera the renderer repositions everything (the camera is actually the only thing that DOES NOT MOVE).
It seems that you are missing some crucial concepts here, i'd start with this:
http://www.opengl-tutorial.org/beginners-tutorials/tutorial-3-matrices/
About the depth offset mentioned:
How this would work, say you want to draw a decal on a surface. You can 'draw' another mesh on this surface - by say, projecting a quad onto it. You want to draw a bullet hole over a concrete wall and end up with two coplanar surfaces - the wall, the bullet hole. You can figure out the depth buffer precision, find the smallest value, and then move the bullet hole mesh by that value towards the camera. The object does not get scaled (you're doing this in NDC which you can visualize as a cube and moving planes back and forth in the smallest possible increment), but does translate in depth direction, ending up in front of the other.
I don't see any flicker. The cube movement in 3D seems to be super-smooth. Can you try in a different computer (may be faster one)? I used Chrome on Macbook Pro.

Orthographic 3D Backface Culling using Surface Normals

I'm creating an HTML5 canvas 3D renderer, and I'd say I've gotten pretty far without the help of SO, but I've run into a showstopper of sorts. I'm trying to implement backface culling on a cube with the help of some normals calculations. Also, I've tagged this as WebGL, as this is a general enough question that it could apply to both my use case and a 3D-accelerated one.
At any rate, as I'm rotating the cube, I've found that the wrong faces are being hidden. Example:
I'm using the following vertices:
https://developer.mozilla.org/en/WebGL/Creating_3D_objects_using_WebGL#Define_the_positions_of_the_cube%27s_vertices
The general procedure I'm using is:
Create a transformation matrix by which to transform the cube's vertices
For each face, and for each point on each face, I convert these to vec3s, andn multiply them by the matrix made in step 1.
I then get the surface normal of the face using Newell's method, then get a dot-product from that normal and some made-up vec3, e.g., [-1, 1, 1], since I couldn't think of a good value to put in here. I've seen some folks use the position of the camera for this, but...
Skipping the usual step of using a camera matrix, I pull the x and y values from the resulting vectors to send to my line and face renderers, but only if they have a dot-product above 0. I realize it's rather arbitrary which ones I pull, really.
I'm wondering two things; if my procedure in step 3 is correct (it most likely isn't), and if the order of the points I'm drawing on the faces is incorrect (very likely). If the latter is true, I'm not quite sure how to visualize the problem. I've seen people say that normals aren't pertinent, that it's the direction the line is being drawn, but... It's hard for me to wrap my head around that, or if that's the source of my problem.
It probably doesn't matter, but the matrix library I'm using is gl-matrix:
https://github.com/toji/gl-matrix
Also, the particular file in my open source codebase I'm using is here:
http://code.google.com/p/nanoblok/source/browse/nb11/app/render.js
Thanks in advance!
I haven't reviewed your entire system, but the “made-up vec3” should not be arbitrary; it should be the “out of the screen” vector, which (since your projection is ⟨x, y, z⟩ → ⟨x, y⟩) is either ⟨0, 0, -1⟩ or ⟨0, 0, 1⟩ depending on your coordinate system's handedness and screen axes. You don't have an explicit "camera matrix" (that is usually called a view matrix), but your camera (view and projection) is implicitly defined by your step 4 projection!
However, note that this approach will only work for orthographic projections, not perspective ones (consider a face on the left side of the screen, facing rightward and parallel to the view direction; the dot product would be 0 but it should be visible). The usual approach, used in actual 3D hardware, is to first do all of the transformation (including projection), then check whether the resulting 2D triangle is counterclockwise or clockwise wound, and keep or discard based on that condition.

Resources