Open file, delete zeros, sort it - NASM - sorting

Question

I am currently working on some problems and this is the one I am having trouble with. To make it all clear, I am a beginner, so any help is more than welcome.
Problem:
Sort the content of a binary file in descending order. The name of the file is passed as a command line argument. File content is interpreted as four-byte positive integers, where value 0, when found, is not written into the file. The result must be written in the same file that has been read.
The way I understand is that I have to have a binary file. Open it. Get its content. Find all characters while keeping in mind those are positive, four-byte integers, find zeros, get rid of zeros, sort the rest of the numbers.
We are allowed to use glibc, so this was my attempt:
section .data
warning db 'File does not exist!', 10, 0
argument db 'Enter your argument.', 10, 0
mode dd 'r+'
opened db 'File is open. Time to read.', 10, 0
section .bss
content resd 10
counter resb 1
section .text
extern printf, fopen, fgets, fputc
global main
main:
push rbp
mov rbp, rsp
push rsi
push rdi
push rbx
;location of argument's address
push rsi
cmp rdi, 2
je .openfile
mov rdi, argument
mov rax, 0
call printf
jmp .end
.openfile:
pop rbx
;First real argument of command line
mov rdi, [rbx + 8]
mov rsi, mode
mov rax, 0
call fopen
cmp al, 0
je .end
push rax
mov rdi, opened
mov rax, 0
call printf
.readfromfile:
mov rdi, content
mov rsi, 12 ;I wrote 10 numbers in my file
pop rdx
mov rax, 0
call fgets
cmp al, 0
je .end
push rax
mov rsi, tekst
pop rdi
.loop:
lodsd
inc byte[counter]
cmp eax, '0'
jne .loop
;this is the part where I am not sure what to do.
;I am trying to delete the zero with backspace, then use space and
;backspace again - I saw it here somewhere as a solution
mov esi, 0x08
call fputc
mov esi, 0x20
call fputc
mov esi, 0x08
call fputc
cmp eax, 0
je .end
jmp .loop
.end:
pop rdi
pop rsi
pop rbx
mov rsp, rbp
pop rbp
ret
So, my idea was to open the file, find zero, delete it by using backspace and space, then backspace again; Continue until I get to the end of the file, then sort it. As it can be seen I did not attempt to sort the content because I cannot get program to do the first part for me. I have been trying this for couple of days now and everything is getting foggy.
If someone can help me out, I would be very grateful. If there is something similar to this problem, feel free to link it to me. Anything that could help, I am ready to read and learn.
I am also unsure about how much information do I have to give. If something is unclear, please point it out to me.
Thank you

Answer 1

For my own selfish fun, an example of memory area being "collapsed" when dword zero value is detected:
to build in linux with NASM for target ELF64 executable:
nasm -f elf64 so_64b_collapseZeroDword.asm -l so_64b_collapseZeroDword.lst -w+all
ld -b elf64-x86-64 -o so_64b_collapseZeroDword so_64b_collapseZeroDword.o
And for debugger I'm using edb (built from sources) (the executable doesn't do anything observable by user, when it works correctly, it's supposed to be run in debugger single-stepping over instructions and having memory view over the .data segment to see how the values are moved around in memory).
source file so_64b_collapseZeroDword.asm
segment .text
collapseZeroDwords:
; input (custom calling convention, suitable only for calls from assembly):
; rsi - address of first element
; rdx - address beyond last element ("vector::end()" pointer)
; return: rdi - new "beyond last element" address
; modifies: rax, rsi, rdi
; the memory after new end() is not cleared (the zeroes are just thrown away)!
; search for first zero (up till that point the memory content will remain same)
cmp rsi, rdx
jae .noZeroFound ; if the (rsi >= end()), no zero was in the memory
lodsd ; eax = [rsi], rsi += 4
test eax, eax ; check for zero
jne collapseZeroDwords
; first zero found, from here on, the non-zero values will be copied to earlier area
lea rdi, [rsi-4] ; address where the non-zero values should be written
.moveNonZeroValues:
cmp rsi, rdx
jae .wholeArrayCollapsed ; if (rsi >= end()), whole array is collapsed
lodsd ; eax = [rsi], rsi += 4
test eax, eax ; check for zero
jz .moveNonZeroValues ; zero detected, skip the "store" value part
stosd ; [rdi] = eax, rdi += 4 (pointing beyond last element)
jmp .moveNonZeroValues
.noZeroFound:
mov rdi, rdx ; just return the original "end()" pointer
.wholeArrayCollapsed: ; or just return when rdi is already set as new end()
ret
global _start
_start: ; run some hardcoded simple tests, verify in debugger
lea rsi, [test1]
lea rdx, [test1+4*4]
call collapseZeroDwords
cmp rdi, test1+4*4 ; no zero collapsed
lea rsi, [test2]
lea rdx, [test2+4*4]
call collapseZeroDwords
cmp rdi, test2+3*4 ; one zero
lea rsi, [test3]
lea rdx, [test3+4*4]
call collapseZeroDwords
cmp rdi, test3+3*4 ; one zero
lea rsi, [test4]
lea rdx, [test4+4*4]
call collapseZeroDwords
cmp rdi, test4+2*4 ; two zeros
lea rsi, [test5]
lea rdx, [test5+4*4]
call collapseZeroDwords
cmp rdi, test5+2*4 ; two zeros
lea rsi, [test6]
lea rdx, [test6+4*4]
call collapseZeroDwords
cmp rdi, test6+0*4 ; four zeros
; exit back to linux
mov eax, 60
xor edi, edi
syscall
segment .data
; all test arrays are 4 elements long for simplicity
dd 0xCCCCCCCC ; debug canary value to detect any over-read or over-write
test1 dd 71, 72, 73, 74, 0xCCCCCCCC
test2 dd 71, 72, 73, 0, 0xCCCCCCCC
test3 dd 0, 71, 72, 73, 0xCCCCCCCC
test4 dd 0, 71, 0, 72, 0xCCCCCCCC
test5 dd 71, 0, 72, 0, 0xCCCCCCCC
test6 dd 0, 0, 0, 0, 0xCCCCCCCC
I tried to comment it extensively to show what/why/how it is doing, but feel free to ask about any particular part. The code was written with simplicity on mind, so it doesn't use any aggressive performance optimizations (like vectorized search for first zero value, etc).