I am trying to get a collection which has index as column values.
First level will have product_id as index and second level will have stock_date.
$data = Model::select('column1', 'product_id', 'stock_date')
->where('some condition')
->get();
$data = collect($data)->groupBy('product_id');
With the code above, I get the collection with product_id as the indexes.
I need the data of each product indexed by stock_date
If, for example, for product_id - 1, I have multiple records, I tried
$product_details = collect($data[1])->groupBy('stock_date');
But it does not index the records with stock_date further.
Need help to index them with stock_date.
possible solution.
// first index grouped by product_id
$original = Model::select('column1', 'product_id', 'stock_date')
->where('some condition')
->get()
->groupBy->product_id;
$final = collect();
// iterate through each group and
// group inner collection with 'stock_date'
// and put them back in an collecion
foreach($original as $key => $value) {
$final->put($key, $value->groupBy->stock_date);
}
Do you means these records are nested by stock_date,
and then stock_dates are nested by product_id
If it is, please try this below, the collect() method make all nested records becomes collection, you don't need to use collect() again.
$data = Model::select('column1', 'product_id', 'stock_date')
->where('some condition')
->get();
$data = collect($data)->groupBy('product_id');
$nested_products = [];
foreach($data as $product_id => $items) {
$nested_products []= $items->groupBy('stock_date');
}
Or you can try this line, it's more elegant:
collect($data)->groupBy('product_id')->transform(function($item, $k) { return $item->groupBy('stock_date');})
Related
I have a query that return a collection of stdclass objects with 'data' and 'day properties. Returns a collection, with all the days that return data, but not those with no lines
$reservations = DB::table('reservation')->selectRaw("
count(id) AS data,
DAY(created_at) AS day
")
->where( DB::raw('YEAR(created_at)'), '=', '2023')
->where( DB::raw('MONTH(created_at)'), '=', '12')
->groupBy('day')
->get();
I need to create an array with values for each day of the month containing only the data field. If the day does not exist in the collection, assign it a 0.
$array = [10, 23, 12, 0, 10...];
I thought about making a loop for each day with CarbonPeriod, but inside I have to make another loop with the result to check if there is a match, add the value, and if not add the 0. Is there a collection method or other way to facilitate this?
foreach (CarbonPeriod::create($initmonth,'1 day',$lastDayMonth) as $key => $day) {
foreach ($reservations as $key => $value) {
//here I'm trying to find the match
if($day->day == $value->day) $array[] = $value->data // else ???
}
}
I am using laravel eager loading to load data on the jquery datatables. My code looks like:
$columns = array(
0 => 'company_name',
1 => 'property_name',
2 => 'amenity_review',
3 => 'pricing_review',
4 => 'sqft_offset_review',
5 => 'created_at',
6 => 'last_uploaded_at'
);
$totalData = Property::count();
$limit = $request->input('length');
$start = $request->input('start');
$order = $columns[$request->input('order.0.column')];
$dir = $request->input('order.0.dir');
$query = Property::with(['company','notices']);
$company_search = $request->columns[0]['search']['value'];
if(!empty($company_search)){
$query->whereHas('company', function ($query) use($company_search) {
$query->where('name','like',$company_search.'%');
});
}
$property_search = $request->columns[1]['search']['value'];
if(!empty($property_search)){
$query->where('properties.property_name','like',$property_search.'%');
}
if(!Auth::user()->hasRole('superAdmin')) {
$query->where('company_id',Auth::user()->company_id);
}
$query->orderBy($order,$dir);
if($limit != '-1'){
$records = $query->offset($start)->limit($limit);
}
$records = $query->get();
With this method I received error: Column not found: 1054 Unknown column 'company_name' in 'order clause' .
Next, I tried with following order condition:
if($order == 'company_name'){
$query->orderBy('company.name',$dir);
}else{
$query->orderBy($order,$dir);
}
However, it also returns similar error: Column not found: 1054 Unknown column 'company.name' in 'order clause'
Next, I tried with whereHas condition:
if($order == 'company_name'){
$order = 'name';
$query->whereHas('company', function ($query) use($order,$dir) {
$query->orderBy($order,$dir);
});
}else{
$query->orderBy($order,$dir);
}
But, in this case also, same issue.
For other table, I have handled this type of situation using DB query, however, in this particular case I need the notices as the nested results because I have looped it on the frontend. So, I need to go through eloquent.
Also, I have seen other's answer where people have suggested to order directly in model like:
public function company()
{
return $this->belongsTo('App\Models\Company')->orderBy('name');
}
But, I don't want to order direclty on model because I don't want it to be ordered by name everytime. I want to leave it to default.
Also, on some other scenario, I saw people using join combining with, but I am not really impressed with using both join and with to load the same model.
What is the best way to solve my problem?
I have table like: companies: id, name, properties: id, property_name, company_id, notices: title, slug, body, property_id
The issue here is that the Property::with(['company','notices']); will not join the companies or notices tables, but only fetch the data and attach it to the resulting Collection. Therefore, neither of the tables are part of the SQL query issued and so you cannot order it by any field in those tables.
What Property::with(['company', 'notices'])->get() does is basically issue three queries (depending on your relation setup and scopes, it might be different queries):
SELECT * FROM properties ...
SELECT * FROM companies WHERE properties.id in (...)
SELECT * FROM notices WHERE properties.id in (...)
What you tried in the sample code above is to add an ORDER BY company_name or later an ORDER BY companies.name to the first query. The query scope knows no company_name column within the properties table of course and no companies table to look for the name column. company.name will not work either because there is no company table, and even if there was one, it would not have been joined in the first query either.
The best solution for you from my point of view would be to sort the result Collection instead of ordering via SQL by replacing $records = $query->get(); with $records = $query->get()->sortBy($order, $dir);, which is the most flexible way for your task.
For that to work, you would have to replace 'company_name' with 'company.name' in your $columns array.
The only other option I see is to ->join('companies', 'companies.id', 'properties.company_id'), which will join the companies table to the first query.
Putting it all together
So, given that the rest of your code works as it should, this should do it:
$columns = [
'company.name',
'property_name',
'amenity_review',
'pricing_review',
'sqft_offset_review',
'created_at',
'last_uploaded_at',
];
$totalData = Property::count();
$limit = $request->input('length');
$start = $request->input('start');
$order = $columns[$request->input('order.0.column')];
$dir = $request->input('order.0.dir');
$query = Property::with(['company', 'notices']);
$company_search = $request->columns[0]['search']['value'];
$property_search = $request->columns[1]['search']['value'];
if (!empty($company_search)) {
$query->whereHas(
'company', function ($query) use ($company_search) {
$query->where('name', 'like', $company_search . '%');
});
}
if (!empty($property_search)) {
$query->where('properties.property_name', 'like', $property_search . '%');
}
if (!Auth::user()->hasRole('superAdmin')) {
$query->where('company_id', Auth::user()->company_id);
}
if ($limit != '-1') {
$records = $query->offset($start)->limit($limit);
}
$records = $query->get()->sortBy($order, $dir);
I am trying to get all rows and distinct column from single query. but paginate method is only giving result but not pagination option like total prev next etc..
$offers = Offer::whereHas('users', function ($q) use ($authUser) {
$q->where('user_id', $authUser->parent_id);
$q->where('publisher_id', '=', $authUser->id);
});
and distinct column
$websites = $offers->distinct()->get(['website']);
with pivot columns (just wanted to show my full query)
$offers->orderBy($sortBy, $orderBy)->paginate($perPage)->map(function ($offer) {
if (!empty($offer->users)) {
$manager = $publisher = '';
foreach ($offer->users as $user) {
$manager = $user->pivot->user_id;
$publisher = $user->pivot->publisher_id;
}
$offer->manager = $manager;
$offer->publisher = $publisher;
}
return $offer;
});
Return
return response()->json([
'offers' => $offers,
'websites' => $websites
], 200);
hope my question will make sense.
Thanks.
You should run getCollection() before mapping to get the paginator's underlying collection.
(https://laravel.com/api/7.x/Illuminate/Pagination/LengthAwarePaginator.html#method_getCollection)
$offers->orderBy($sortBy, $orderBy)->paginate($perPage)
->getCollection()
->map(function ($offer) {
// ...
return $offer;
});
I'm answering based on it being $offers:
Your usage of map() is copying the modified results of your paginate() call to a new collection and that collection does not include the pagination information. That's why you no longer have pagination information.
Since there result of paginate() is already a usable collection, you can use each() instead of map() which will alter the objects in-place.
I am learning larvel 5.6 so I am trying to retrieve number of messages that have id larger than last_seen_id in pivot table
I have user table which have the default columns generated by:
php artisan make:auth
and messages tables which have the following columns:
id, from, message_content, group_id
and the group table have the columns:
id,type
now there is many to many relation between the users and groups table through the custom pivot table which have the columns:
group_id,user_id,last_id_seen
now if I want to retrieve the messages which belong to same group and have larger id than last_id_seen in the pivot table how to do it?
I think you are looking for something like this:
$groupId = 1; // set to whatever you want
$lastSeenId = \Auth::user()->groups()
->where('group_id', $groupId)
->first()->pivot->last_id_seen;
$messages = Message::where('id', '>', $lastSeenId)->get();
A more robust version, which does not fail when your user does not have an entry for the group yet, would be:
$groupId = 1; // set to whatever you want
$group = \Auth::user()->groups()->where('group_id', $groupId)->first();
$lastSeenId = $group ? $group->pivot->last_id_seen : null;
$messages = Message::when($lastSeenId, function($query, $id) {
$query->where('id', '>', $id);
})->get();
Note: normally you'd use optional() in the second snippet, but Laravel 5.2 does not come with this helper...
If you want both the count() of the results and the results themselves, you can store the query in a variable and perform two queries with it. You then don't have to rewrite the same query twice:
$groupId = 1; // set to whatever you want
$group = \Auth::user()->groups()->where('group_id', $groupId)->first();
$lastSeenId = $group ? $group->pivot->last_id_seen : null;
$query = Message::when($lastSeenId, function($query, $id) {
$query->where('id', '>', $id);
});
$count = $query->count();
$messages = $query->get();
I'd like to know the position of a user based on its creation date. How do I do that using Eloquent?
I'd like to be able to do something like this:
User::getRowNumber($user_obj);
I suppose you want MySQL solution, so you can do this:
DB::statement(DB::raw('set #row:=0'));
User::selectRaw('*, #row:=#row+1 as row')->get();
// returns all users with ordinal 'row'
So you could implement something like this:
public function scopeWithRowNumber($query, $column = 'created_at', $order = 'asc')
{
DB::statement(DB::raw('set #row=0'));
$sub = static::selectRaw('*, #row:=#row+1 as row')
->orderBy($column, $order)->toSql();
$query->remember(1)->from(DB::raw("({$sub}) as sub"));
}
public function getRowNumber($column = 'created_at', $order = 'asc')
{
$order = ($order == 'asc') ? 'asc' : 'desc';
$key = "userRow.{$this->id}.{$column}.{$order}";
if (Cache::get($key)) return Cache::get($key);
$row = $this->withRowNumber($column, $order)
->where($column, '<=',$this->$column)
->whereId($this->id)->pluck('row');
Cache::put($key, $row);
return $row;
}
This needs to select all the rows from the table till the one you are looking for is found, then selects only that particular row number.
It will let you do this:
$user = User::find(15);
$user->getRowNumber(); // as default ordered by created_at ascending
$user->getRowNumber('username'); // check order for another column
$user->getRowNumber('updated_at', 'desc'); // different combination of column and order
// and utilizing the scope:
User::withRowNumber()->take(20)->get(); // returns collection with additional property 'row' for each user
As this scope requires raw statement setting #row to 0 everytime, we use caching for 1 minute to avoid unnecessary queries.
$query = \DB::table(\DB::raw('Products, (SELECT #row := 0) r'));
$query = $query->select(
\DB::raw('#row := #row + 1 AS SrNo'),
'ProductID',
'ProductName',
'Description',
\DB::raw('IFNULL(ProductImage,"") AS ProductImage')
);
// where clauses
if(...){
$query = $query->where('ProductID', ...));
}
// orderby clauses
// ...
// $query = $query->orderBy('..','DESC');
// count clause
$TotalRecordCount = $query->count();
$results = $query
->take(...)
->skip(...)
->get();
I believe you could use Raw Expresssions to achieve this:
$users = DB::table('users')
->select(DB::raw('ROW_NUMBER() OVER(ORDER BY ID DESC) AS Row, status'))
->where('status', '<>', 1)
->groupBy('status')
->get();
However, looking trough the source code looks like you could achieve the same when using SQLServer and offset. The sources indicates that if you something like the following:
$users = DB::table('users')->skip(10)->take(5)->get();
The generated SQL query will include the row_number over statement.
[For Postgres]
In your model
public function scopeWithRowNumber($query, $column = 'id', $order = 'asc'){
$sub = static::selectRaw('*, row_number() OVER () as row_number')
->orderBy($column, $order)
->toSql();
$query->from(DB::raw("({$sub}) as sub"));
}
In your controller
$user = User::withRowNumber()->get();