I have the following function that lists the Leads and the pages, I am asked to sort it by the activities but I have the problem that this is from another table if I do it in SQL mode I get the result, but with the actual writing of the code I don't get it.
This is my query, it has join with contacts and a left join with activities, the problem is that I only need to be able to sort it by activities.
SELECT l.id,l.status_id,l.user_id,l.created_at,l.ticket_id,l.last_lead, c.full_name, COUNT(a.lead_id) as total FROM `leads` l join contacts c on l.contact_id = c.id left join activities a on a.lead_id =l.id where active=1 and status_id=7 and project_id in (8,9,10,11) GROUP by l.id order by total desc;
And this is my eloquent query:
Order by comments.
if ($sortField == 'last_comment') {
$user = User::withRole(['salesman'])->pluck('id');
$sortField = Comment::select('created_at')
->whereColumn('comments.lead_id','leads.id')
->where('comments.user_id',implode(',',$user->toArray()))
->latest()
->take(1);
}
$leads_ = $this->leads
->openedStage() // where status_id = 7
->ticketActive() // where active = 1
->searchTickets($projects)
->orderBy($sortField,'desc')
->paginate((int)$per_page);
Where the following methods mean:
**openedStage()**: where status_id = 7
**ticketActive()**: where active = 1
**searchTickets($projects):
whereHas('contacts', function ($q) use ($projects){
$q->whereIn('project_id',$projects->toArray());
});
I have students and subjects table in many-to-many relation (pivot table is student_subject).
Student Model
public function subjects()
{
return $this->belongsToMany(Subject::class, 'student_subject');
}
Subject Model
public function students()
{
return $this->belongsToMany(Student::class, 'student_subject');
}
Here I want the particular student subjects counts. I tried the below methods it's working fine but I want the best efficient way for this purpose.
1.
$student = Student::find($id);
$subject_count = $student->subjects()->count();
I checked the SQL query through laravel debuger it shows as below
select * from `students` where `students`.`id` = '10' limit 1
select count(*) as aggregate from `subjects` inner join `student_subject` on `subjects`.`id` = `student_subject`.`subject_id` where `student_subject`.`student_id` = 10 and `subjects`.`deleted_at` is null
$student = Student::withCount('subjects')->find($id);
$subject_count = $student->subjects_count;
I checked the SQL query through laravel debuger it shows as below
select `students`.*, (select count(*) from `subjects` inner join `student_subject` on `subjects`.`id` = `student_subject`.`subject_id` where `students`.`id` = `student_subject`.`student_id` and `subjects`.`deleted_at` is null) as `subjects_count` from `students` where `students`.`id` = '10' limit 1
$student = Student::find($id);
$subject_count = $student->loadCount('subjects')->subjects_count;
I checked the SQL query through laravel debuger it shows as below
select * from `students` where `students`.`id` = '10' limit 1
select `id`, (select count(*) from `subjects` inner join `student_subject` on `subjects`.`id` = `student_subject`.`subject_id` where `students`.`id` = `student_subject`.`student_id` and `subjects`.`deleted_at` is null) as `subjects_count` from `students` where `students`.`id` in (10)
$student = Student::find($id);
$subject_count = DB::table('student_subject')->where('student_id', $student->id)->count();
I checked the SQL query through laravel debuger it shows as below
select * from `students` where `students`.`id` = '10' limit 1
select count(*) as aggregate from `student_subject` where `student_id` = 10
According to the above ways which one is best and why? or if any different best way also there?
Doing relation()->count() is probably faster.
But if all you need is the count, withCount() should be better in terms of memory consumption.
I want to get most view by query:
$this->db->select("a.pid, a.title, a.pic, a.date_created, d.view as post_view");
$this->db->from("posts as a");
$this->db->join('views as d', 'd.post_id=a.pid');
$this->db->join('cats as b', 'b.catid=a.catid'); //ensure Cat existed
$this->db->where("a.block", 0);
$this->db->order_by("d.view", "desc");
$this->db->limit(5);
$query = $this->db->get();
return $query->result();
but always automatically add order_by pid asc. and never order desc for d.view field. i try to print query string and here:
SELECT `a`.`pid`, `a`.`title`, `a`.`pic`, `a`.`date_created`, `d`.`view` as `post_view` FROM `posts` as `a` JOIN `views` as `d` ON `d`.`post_id`=`a`.`pid` JOIN `cats` as `b` ON `b`.`catid`=`a`.`catid` WHERE `a`.`block` =0 ORDER BY `pid` asc, `d`.`view` DESC LIMIT 5
Any suggestion to fix? (CI version 3.*)
My Sql query is like this
$view = mysql_query ("SELECT domain,count(distinct session_id) as
views FROM `statistik` left join statistik_strippeddomains on
statistik_strippeddomains.id = statistik.strippeddomain WHERE
`angebote_id` = '".(int)$_GET['id']."' and strippeddomain!=1
group by domain having count (distinct session_id) >
".(int)($film_daten['angebote_views']/100)." order
count(distinct session_id$vladd) desc limit 25");
How can I write its Codeigniter Model I appreciate any Help
try this
$this->db->select('statistik.domain,statistik.count(DISTINCT(session_id)) as views');
$this->db->from('statistik');
$this->db->join('statistik_strippeddomains', 'statistik_strippeddomains.id = statistik.strippeddomain', 'left');
$this->db->where('angebote_id',$_GET['id']);
$this->db->where('strippeddomain !=',1);
$this->db->group_by('domain');
$this->db->having('count > '.$film_daten['angebote_views']/100, NULL, FALSE);
$this->db->order_by('count','desc');
$this->db->limit('25');
$query = $this->db->get();
Comment me If you have any query.
i have 4 tables jobs, company, employment_type & job_category the primary key for each are job_id, com_id, type_id, job_cat_id, but (com_id, type_id, job_cat_id) are foreign key to jobs table.
my query without active record work perfectly and it is as follow
select company.com_id, company.company_name, jobs.job_id, jobs.title, jobs.opening_date, jobs.closing_date, jobs.number_of_pos, employment_type.type_id, employment_type.type, job_category.job_cat_id, job_category. category from company inner join jobs on company.com_id=jobs.com_id inner join employment_type on employment_type.type_id=jobs.type_id inner join job_category on job_category.job_cat_id=jobs.job_cat_id
but if i try to use codeiginiter active record such as
$this->db->select('company.com_id, company.company_name, jobs.job_id, jobs.title, jobs.opening_date, jobs.closing_date, jobs.number_of_pos, employment_type.type_id, employment_type.type, job_category.job_cat_id, job_category. category');
$this->db->from('company');
$this->db->join('jobs','company.com_id=jobs.com_id','inner');
$this->db->join('employment_type', 'employment_type.type_id=jobs.type_id','inner');
$this->db->join('job_category', 'job_category.job_cat_id=jobs.job_cat_id','inner');
$this->db->order_by('job_id','DESC');
$this->db->limit($limit, $offset);
$query = $this->db->get();
return $query->result_array();
i end up with the following error
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '`) INNER JOIN `jobs` ON `company`.`com_id`=`jobs`.`com_id` INNER JOIN `employmen' at line 1
SELECT `company`.`com_id`, `company`.`company_name`, `jobs`.`job_id`, `jobs`.`title`, `jobs`.`opening_date`, `jobs`.`closing_date`, `jobs`.`number_of_pos`, `employment_type`.`type_id`, `employment_type`.`type`, `job_category`.`job_cat_id`, `job_category`.` category FROM (`company`) INNER JOIN `jobs` ON `company`.`com_id`=`jobs`.`com_id` INNER JOIN `employment_type` ON `employment_type`.`type_id`=`jobs`.`type_id` INNER JOIN `job_category` ON `job_category`.`job_cat_id`=`jobs`.`job_cat_id` ORDER BY `job_id` DESC LIMIT 10
Any help would be appreciated
you have a space in job_category. category remove that and you should be golden
Format your query like this
$data = array(
'company.com_id',
'company.company_name',
'jobs.job_id',
'jobs.title',
'jobs.opening_date',
'jobs.closing_date',
'jobs.number_of_pos',
'employment_type.type_id',
'employment_type.type',
'job_category.job_cat_id',
'job_category.category'
);
$this->db->select($data);
$this->db->from('company');
$this->db->join('jobs','company.com_id=jobs.com_id','inner');
$this->db->join('employment_type', 'employment_type.type_id=jobs.type_id','inner');
$this->db->join('job_category', 'job_category.job_cat_id=jobs.job_cat_id','inner');
$this->db->order_by('job_id','DESC');
$this->db->limit($limit, $offset);
$query = $this->db->get();
return $query->result_array();