Im having a hard time figuring out how to integrate this ajax request into my view. I'm still learning how to integrate django with ajax requests.
My first question would be: Does the ajax request need to have its own dedicated URL?
In my case I am trying to call it on a button to preform a filter(Preforms a query dependent on what is selected in the template). I have implemented this using just django but it needs to make new request everytime the user preforms a filter which I know is not efficient.
I wrote the most basic function using JQuery to make sure the communication is there. Whenever the user changed the option in the select box it would print the value to the console. As you will see below in the view, I would to call the ajax request inside this view function, if this is possible or the correct way of doing it.
JQuery - Updated
$("#temp").change( function(event) {
var filtered = $(this).val();
console.log($(this).val());
$.ajax({
url : "http://127.0.0.1:8000/req/ajax/",
type : "GET",
data : {
'filtered': filtered
},
dataType: 'json',
success: function(data){
console.log(data)
},
error: function(xhr, errmsg, err){
console.log("error")
console.log(error_data)
}
});
Views.py
def pending_action(request):
requisition_status = ['All', 'Created', 'For Assistance', 'Assistance Complete', 'Assistance Rejected']
FA_status = RequisitionStatus.objects.get(status='For Assistance')
current_status = 'All'
status_list = []
all_status = RequisitionStatus.objects.all()
status_list = [status.status for status in all_status]
# This is where I am handling the filtering currently
if request.GET.get('Filter') in status_list:
user_req_lines_incomplete = RequisitionLine.objects.filter(Q(parent_req__username=request.user) & Q(status__status=request.GET.get('Filter')))
current_status = request.GET.get('Filter')
else:
user_req_lines_incomplete = RequisitionLine.objects.filter(parent_req__username=request.user).exclude(status__status='Completed')
user_reqs = Requisition.objects.filter(par_req_line__in=user_req_lines_incomplete).annotate(aggregated_price=Sum('par_req_line__total_price'),
header_status=Max('par_req_line__status__rating'))
return render(request, 'req/pending_action.html', { 'user_reqs':user_reqs,
'user_req_lines_incomplete':user_req_lines_incomplete,
'requisition_status':requisition_status,
'current_status':current_status,
'FA_status':FA_status})
def filter_status(request):
status = request.GET.get('Filter')
data = {
'filtered': RequisitionLine.objects.filter(Q(parent_req__username=request.user) & Q(status__status=status)),
'current_status': status
}
return JsonResponse(data)
Urls.py
path('pending/', views.pending_action, name='pending_action')
First: you have to divide your template to unchangeable part and the part that you want to modify with your filter.
Second: for your goal you can use render_to_string. See the followning link https://docs.djangoproject.com/en/2.1/topics/templates/#usage
code example (views.py):
cont = {
'request': request, #important key-value
'your_models_instances': your_models_instances
}
html = render_to_string('your_filter_template.html', cont)
return_dict = {'html': html}
return JsonResponse(return_dict)
In your js file you need to determine relative url "{% url 'name in yours url file'%}"
And in success you need to add next line:
success: function(data){
$(".filter-block").html(data.html);
}
i hope it will help you! Good luck!
Related
I'm processing a table of banking/statement entries that have been exported from another system via a CSV file. They are imported into a view and checked for duplicates before being presented to the user in a HTML table for final review.
Once checked they are sent via AJAX to the server so they can be added into a Django model. Everything is working OK including CSRF but I cannot access the POSTed variable although I can see it!
Unfortunately making a hidden form isn't viable as there are 80+ rows to process.
My Javascript looks like:
$.ajax({
type: 'POST',
url: '......./ajax/handleImports/',
data: entriesObj,
success: function (data) {
if (data.response && data.response) {
console.log("Update was successful");
console.log(data.entries)
} else { ... }
},
error: function() { ... }
where entriesObj is
var entriesObj = JSON.stringify({ "newentries": newEntries });
console.log(entriesObj)
and when dumped to console.log looks like:
{"newentries":[{"Include":"","Upload ID":"0","Date":"2019-01-09", ... }
Now in view.py when I return the whole request.POST object as data.entries using
context['entries'] = request.POST
return JsonResponse(context)
I get
{"{"newentries":[{"Include":"","Upload ID":"0","Date":"2019-01-09", ... }
but if I try and retrieve newentries with:
entries = request.POST.get('newentries', None)
context['entries'] = entries
return JsonResponse(context)
the console.log(data.entries) will output null?
How am I supposed to access the POSTed entriesObj?
The data is JSON, you need to get the value from request.body and parse it.
data = json.loads(request.body)
entries = data.get('newentries')
Django 1.7.2/ python 3.4
this code is about 'like'.
if user click the 'like' button, ajax calls 'pushLike'.
if the user has liked the article before(saved inside Mysql), delete the row on table(DB).
or if the user is not liking the article, create a row and insert it on the table(DB).
after that, count how many like has beed clicked on that article.
I would like to pass the likeCnt(count) to ajax, and write it on the button.
The likeCnt has the right value(I checked it on the server mysql table).
The button color does change(white to blue, and vise versa), but the text does not change.
It seems like json does not pass to ajax. I tried passing data by 'text' type and it did worked, but i want it by json.
I've tried simplejson, json, mimetype, content_type on HttpResponse.
please help me.
view
#login_required
def pushLike(request):
pk = request.GET['writing_id']
try:
la = LikeArticles.objects.get(user = User.objects.get(username=request.user.username), article_id=pk)
if(la.is_like()):
la.delete()
likeCnt = LikeArticles.objects.filter(article_id=pk).count()
FreeBoards.objects.filter(id=pk).update(like = likeCnt)
else: #Never happens
la.like = True
la.save()
likeCnt = LikeArticles.objects.filter(article_id=pk).count()
FreeBoards.objects.filter(id=pk).update(like = likeCnt)
except ObjectDoesNotExist:
la = LikeArticles(user = User.objects.get(username=request.user.username),
article = FreeBoards.objects.get(id=pk),
like = True,
)
la.save()
likeCnt = LikeArticles.objects.filter(article_id=pk).count()
FreeBoards.objects.filter(id=pk).update(like = likeCnt)
data = {'likeCnt': likeCnt}
# return render(request, url, context)
return HttpResponse(simplejson.dumps(data), mimetype='application/javascript')
javascript
<script type="text/javascript">
$(document).ready(function(){
$('#btn-like').click(function(){
var e = $('#btn-like').css('background-color');
$.ajax({
url : '/sle/freeboards/pushLike/',
data : {'writing_id':{{writing_id}},
},
dataType : "json",
success:function(data){
alert(data.likeCnt);
if(e == 'rgb(59, 89, 152)') {
$('#btn-like').css('background-color', '#ffffff').css('color', '#000000');
$('#btn-like').text(data.likeCnt);
} else {
$('#btn-like').css('background-color', '#3b5998').css('color', '#ffffff');
$('#btn-like').text(data.likeCnt);
}
},
failure: function(data){
alert('fail!!')
}
});
});
});
</script>
you'll want to be sure to set the proper mimetype in your HttpResponse
#login_required
def pushLike(request):
...
# return json -- !!not javascript!!
return HttpResponse(simplejson.dumps(...), mimetype="application/json")
--or--
#login_required
def pushLike(request):
...
# return json -- !!not javascript!!
return JsonResponse({"your": "context dictionary"})
If that doesn't work, have you tried parsing the json with your Jquery code?
ie:
$.ajax({
...
success: function(data){
var response = $.parseJSON(data);
...
}
});
javascript might actually receiving bytes back from whatever you are serving your django app with... so instead of getting JSON back, you're actually getting string that looks like JSON. http://api.jquery.com/jquery.parsejson/
I am trying to check if the user name is available for use using ajax and codeigniter. I have problem to get the response from the codeingniter controller in my js. file but without success.
Here is the controller function, relevant to the question:
if ($username == 0) {
$this->output->set_output(json_encode(array("r" => true)));
} else {
$this->output->set_output(json_encode(array("r" => false, "error" => "Username already exits")));
}
Rest assured that I do get 1 if username already exists in thedatabase and 0 if it does not exist.
I have the following js.file
// list all variables used here...
var
regform = $('#reg-form'),
memberusername = $('#memberusername'),
memberpassword = $('#memberpassword'),
memberemail = $('#memberemail'),
memberconfirmpassword = $('#memberconfirmpassword');
regform.submit(function(e) {
e.preventDefault();
console.log("I am on the beggining here"); // this is displayed in console
var memberusername = $(this).find("#memberusername").val();
var memberemail = $(this).find("#memberemail").val();
var memberpassword = $(this).find("#memberpassword").val();
var url = $(this).attr("action");
$.ajax({
type: "POST",
url: $(this).attr("action"),
dataType: "json",
data: {memberusername: memberusername, memberemail: memberemail, memberpassword: memberpassword},
cache: false,
success: function(output) {
console.log('I am inside...'); // this is never displayed in console...
console.log(r); // is never shonw in console
console.log(output); is also never displayed in console
$.each(output, function(index, value) {
//process your data by index, in example
});
}
});
return false;
})
Can anyone help me to get the username value of r in the ajax, so I can take appropriate action?
Cheers
Basically, you're saying that the success handler is never called - meaning that the request had an error in some way. You should add an error handler and maybe even a complete handler. This will at least show you what's going on with the request. (someone else mentioned about using Chrome Dev Tools -- YES, do that!)
As far as the parse error. Your request is expecting json data, but your data must not be returned as json (it's formatted as json, but without a content type header, the browser just treats it as text). Try changing your php code to this:
if ($username == 0) {
$this->output->set_content_type('application/json')->set_output(json_encode(array("r" => true)));
} else {
$this->output->set_content_type('application/json')->set_output(json_encode(array("r" => false, "error" => "Username already exits")));
}
This question already has an answer here:
Closed 10 years ago.
Possible Duplicate:
django file upload from json
Hi am using the following ajax upload from the template but i do not get a response from django view.What is wrong here..i do not see any alert
function ajax_upload(formid)
{
var form = $(formid);
form.ajaxSubmit({
dataType: 'json',
success: function (data) {
alert("Hereeeeeeee");
if(data.status == '1')
{
alert("Uploaded Successfull");
}
else
{
alert("Uploaded UnSuccessfull :(");
}
}
} ) ;
}
EDIT
Django:
def someview(request):
response_dict={'status':1}
logging.debug("seen") //This is seen in the logs
return HttpResponse(simplejson.dumps(response_dict), mimetype='application/javascript')
EDIT1
Please also for complete source code look at django file upload from json
From your code:
form.ajaxSubmit({
dataType: 'json',
success: function (data) {
alert("Hereeeeeeee");
Your callback executes on 'success', so we can narrow down the failure to the django view side. Assuming everything is syntactically correct, my best guess is that since you're returning json data, your response mimetype should be:
mimetype='application/json'.
If that doesn't work, I would suggest using Firebug on Firefox or Developer Tools on Chrome to look at the server response. You should be able to see a django stacktrace there.
Check that someview added to urls.py.
Check that {% csrf_token %} added to form
It's rather impossible you will see that log, hence this is a python syntax error:
response_dict{'status':1}
and should be:
response_dict = dict(status=1)
or:
response_dict = {'status':1}
or:
response_dict = dict()
response_dict['status'] = 1
or:
response_dict = dict()
response_dict.update({'status':1})
I'm trying to run some tests on some Ajax code we have written, now obviously when tested locally it runs very fast and is great. I need to enforce a delay of 3 seconds so that I can see that the loader is being displayed and the user experiance is good enough.
I have tried the following but recieve the error "Useless settimeout" any other suggestions to achieve this? Any browser plugins?
$('#formAddPost').submit(function() {
//Load the values and check them
var title = $(this).find('#Title');
var description = $(this).find('#Description');
var catId = $(this).find('#Categories');
if (ValidateField(title) == false || ValidateField(description) == false) {
$('.error-message').show();
return false;
}
$('.error-message').hide();
//Show the loading icon
$('.add-post').hide();
$('.add-post-loader').show();
//Temp for testing - allows the showing to the loader icon
setTimeout(MakeAJAXCall(title.val(), catId.val(), description.val()), 1500);
return false;
});
function MakeAJAXCall(title, catId, description) {
$.ajax({
url: "/Message/CreatePost/",
cache: false,
type: "POST",
data: ("title=" + title + "&description=" + description + "&categories=" + catId + "&ajax=1?"),
dataType: "html",
success: function(msg) {
$('#TableMessageList').replaceWith(msg);
$('.add-post-loader').hide();
$('.add-post').show();
}
});
}
As you're testing your page for a delay in the server response, can you put a delay in the server side code instead of client side?
You might be able to do that using fiddler.
The examples scripts include some samples that pause the response.
Would this tool from jsFiddle.net be helpful?
Echo Javascript file and XHR requests
http://doc.jsfiddle.net/use/echo.html