I want to get the value from the inner hash. In this case RU - alway the first value.
PAYMENT_TYPE_TO_CURRENCY_AND_COUNTRY_MAPPING = {
zimpler: { 'EUR' => ['FI'], 'SEK' => ['SE'] },
qiwi: { 'EUR' => ['RU', 'KZ'], 'RUB' => ['RU'], 'KZT' => ['KZ'], 'USD' => ['UA'] },
payu: { 'CZK' => ['CZ'], 'PLN' => ['PL']},
entercash: { 'EUR' => ['AT', 'DE', 'FI'], 'SEK' => ['SE'] },
carulla: { 'USD' => ['CO'] }
}
I tried this:
PAYMENT_TYPE_TO_CURRENCY_AND_COUNTRY_MAPPING.each do |payment_method_key, array|
p payment_method_key.to_s /// prints "qiwi" - OK
p array.keys.first /// prints "EUR" - OK
p array[array.keys.first] //// prints ["RU", "KZ"] - not OK - need only RU
end
How I can implement this functionality?
It isn't clear to me if you only want to get the first element each time (which the previous answer accomplishes), or if you only want a 'specific' element each time. Another way to do this that allows you to select specific countries no matter where they are in the array would be:
PAYMENT_TYPE_TO_CURRENCY_AND_COUNTRY_MAPPING.each_pair do |method, currencies|
currencies.each_pair do |currency, countries|
countries.each do |country|
p country if country == "RU"
end
end
end
output:
=> "RU"
"RU"
return value would be the original hash:
=> {:zimpler=>{"EUR"=>["FI"], "SEK"=>["SE"]},
:qiwi=>{"EUR"=>["RU", "KZ"], "RUB"=>["RU"], "KZT"=>["KZ"], "USD"=>["UA"]},
:payu=>{"CZK"=>["CZ"], "PLN"=>["PL"]},
:entercash=>{"EUR"=>["AT", "DE", "FI"], "SEK"=>["SE"]},
:carulla=>{"USD"=>["CO"]}}
Related
I have the array of objects "orders". I want to obtain a first most frequent value in the my array, who often takes a book:
orders = [
{'book' => '1', 'reader' => 'Denis' },
{'book' => '2', 'reader' => 'Mike' },
{'book' => '3', 'reader' => 'Denis' },
{'book' => '3', 'reader' => 'Mike' },
{'book' => '5', 'reader' => '2' }
]
I tried this method, but it's good only for arrays of strings: ['string', 'string'...]:
def most_common_value(a)
a.group_by(&:itself).values.max_by(&:size).first
end
Expected result:
=> "Denis"
I'd do it like this:
orders = [
{'book' => '1', 'reader' => 'Denis' },
{'book' => '2', 'reader' => 'Mike' },
{'book' => '3', 'reader' => 'Denis' },
{'book' => '3', 'reader' => 'Mike' },
{'book' => '5', 'reader' => '2' }
]
orders.each_with_object(Hash.new(0)) { |order, hash| hash[order['reader']] += 1 }.max_by { |k, v| v }
# => ["Denis", 2]
The problem with this is, if there are multiple "max" then the result will be returned based on the order the data is found. For instance, if the order is different:
orders.push(orders.shift)
# => [{"book"=>"2", "reader"=>"Mike"},
# {"book"=>"3", "reader"=>"Denis"},
# {"book"=>"3", "reader"=>"Mike"},
# {"book"=>"5", "reader"=>"2"},
# {"book"=>"1", "reader"=>"Denis"}]
the result changes:
orders.each_with_object(Hash.new(0)) { |order, hash| hash[order['reader']] += 1 }.max_by { |k, v| v }
# => ["Mike", 2]
key = 'reader'
x = orders.inject({}) do |a,i|
a[i[key]] = 0 unless a.has_key? i[key]
a[i[key]] +=1
a
end.max_by{|k,v| v}
Which returns:
=> ["Denis", 2]
I saw this a few days ago and thought this would be easy if Array or Enumerable had a mode_by! Well I finally got around to whipping one up.
Implementing mode_by
A true mode_by would probably return a subarray of the items matching a block:
orders.mode_by{|order| order['reader']}
#=> [{'book'=>'1', 'reader'=>'Denis'}, {'book'=>'3', 'reader'=>'Denis'}]
and to get your desired result:
orders.mode_by{|order| order['reader']}.first['reader']
#=> "Denis"
So let's implement a mode_by:
class Array
def mode_by(&block)
self.group_by(&block).values.max_by(&:size)
end
end
et voila!
A custom alternative
In your case, you don't need to return array elements. Let's simplify further by implementing something that returns exactly what you want, the first result of the block that appears the most. We'll call it mode_of:
class Array
def mode_of(&block)
self.group_by(&block).max_by{|k,v| v.size}.first
end
end
Now you can simply do this:
orders.mode_of{|order| order['reader']}
#=> "Denis"
using group_by and max_by :
orders.group_by { |h| h['reader']}.to_a.max_by {|x| x[1].length}.first
Output :
=> "Denis"
According to example below: Value is stored only in A1, other cells return nil.
How is possible to get the A1'a value from the others merged cells, or simply check range of the A1 cell?
here is my take, if all merged fields are same as prev - then non-merged fields should become array
xlsx = Roo::Excelx.new(__dir__ + "/output.xlsx", { expand_merged_ranges: true })
parsed = xlsx.sheet(0).parse(headers: true).drop(1)
parsed_merged = []
.tap do |parsed_merged|
parsed.each do |x|
if parsed_merged.empty?
parsed_merged << {
"field_non_merged1" => x["field_non_merged1"],
"field_merged1" => [x["field_merged1"]],
"field_merged2" => [x["field_merged2"]],
"field_merged3" => [x["field_merged3"]],
"field_merged4" => [x["field_merged4"]],
"field_non_merged2" => x["field_non_merged2"],
"field_non_merged3" => x["field_non_merged3"],
}
else
field_merged1_is_same_as_prev = x["field_non_merged1"] == parsed_merged.last["field_non_merged1"]
field_merged2_is_same_as_prev = x["field_non_merged2"] == parsed_merged.last["field_non_merged2"]
field_merged3_is_same_as_prev = x["field_non_merged3"] == parsed_merged.last["field_non_merged3"]
merged_rows_are_all_same_as_prev = field_non_merged1_is_same_as_prev && field_merged2_is_same_as_prev && field_merged3_is_same_as_prev
if merged_rows_are_all_same_as_prev
parsed_merged.last["field_merged1"].push x["field_merged1"]
parsed_merged.last["field_merged2"].push x["field_merged2"]
parsed_merged.last["field_merged3"].push x["field_merged3"]
parsed_merged.last["field_merged4"].push x["field_merged4"]
else
parsed_merged << {
"field_non_merged1" => x["field_non_merged1"],
"field_merged1" => [x["field_merged1"]],
"field_merged2" => [x["field_merged2"]],
"field_merged3" => [x["field_merged3"]],
"field_merged4" => [x["field_merged4"]],
"field_non_merged2" => x["field_non_merged2"],
"field_non_merged3" => x["field_non_merged3"],
}
end
end
end
end
.map do |x|
{
"field_non_merged1" => x["field_non_merged1"],
"field_merged1" => x["field_merged1"].compact.uniq,
"field_merged2" => x["field_merged2"].compact.uniq,
"field_merged3" => x["field_merged3"].compact.uniq,
"field_merged4" => x["field_merged4"].compact.uniq,
"field_non_merged2" => x["field_non_merged2"],
"field_non_merged3" => x["field_non_merged3"],
}
end
This is not possible without first assigning the value to all the cells of the range, even in Excel VBA this is the case.
See this sample
require 'axlsx'
p = Axlsx::Package.new
wb = p.workbook
wb.add_worksheet(:name => "Basic Worksheet") do |sheet|
sheet.add_row ["Val", nil]
sheet.add_row [nil, nil]
merged = sheet.merge_cells('A1:B2')
p sheet.rows[0].cells[0].value # "Val"
p sheet.rows[0].cells[1].value # nil
sheet[*merged].each{|cell|cell.value = sheet[*merged].first.value}
p sheet.rows[0].cells[0].value # "Val"
p sheet.rows[0].cells[1].value # "Val"
end
p.serialize('./simple.xlsx')
Please add a sample yourself next time so that we see which gem you used, which code, error etc.
I want to compare two XML files where one is input and the other is output. I am converting both into a hash.
My idea is to get all the keys from the input XML converted to hash, and search each key in both the input and output hashes for their respective key/value pairs.
I have a hash:
{
"requisition_header" => {
"requested_by" => {"login" => "coupasupport"},
"department" => {"name" => "Marketing"},
"ship_to_address" => {"name" => "Address_1431693296"},
"justification" => nil,
"attachments" => [],
"requisition_lines" => [
{
"description" => "Cleaning Services for Building A",
"line_num" => 1,
"need_by_date" => 2010-09-23 07:00:00 UTC,
"source_part_num" => nil,
"supp_aux_part_num" => nil,
"unit_price" => #<BigDecimal:a60520c,'0.3E4',9(18)>,
"supplier" => {"name" => "amazon.com"},
"account" => {
"code" => "SF-Marketing-Indirect",
"account_type" => {"name" => "Ace Corporate"}
},
"currency" => {"code" => "USD"},
"payment_term" => {"code" => "Net 30"},
"shipping_term" => {"code" => "Standard"},
"commodity" => {"name" => "Marketing-Services"}
}
]
}
}
It is nested and all the values are not directly accessible.
I want a way to generate direct access to each value in the hash.
For example:
requisition_header.requested_by.login
will access "coupasupport".
requisition_header.department.name
will access "Marketing".
requisition_header.requisition_lines[0].description
will access "Cleaning Services for Building A".
requisition_header.requisition_lines[0].line_num
will access "1".
requisition_header.requisition_lines[0].need_by_date
will access "2010-09-23 07:00:00 UTC".
Each key built can be used to search for the value directly inside the hash.
That could be done with the following method, that translates the nested hash into nested OpenStructs:
require 'ostruct'
def deep_structify(hash)
result = {}
hash.each do |key, value|
result[key] = value.is_a?(Hash) ? deep_structify(value) : value
end if hash
OpenStruct.new(result)
end
hash = {"requisition_header"=>{"requested_by"=>{"login"=>"coupasupport"}, "department"=>{"name"=>"Marketing"}, "ship_to_address"=>{"name"=>"Address_1431693296"}, "justification"=>nil, "attachments"=>[], "requisition_lines"=>[{"description"=>"Cleaning Services for Building A", "line_num"=>1, "need_by_date"=>2010-09-23 07:00:00 UTC, "source_part_num"=>nil, "supp_aux_part_num"=>nil, "unit_price"=>#<BigDecimal:a60520c,'0.3E4',9(18)>, "supplier"=>{"name"=>"amazon.com"}, "account"=>{"code"=>"SF-Marketing-Indirect", "account_type"=>{"name"=>"Ace Corporate"}}, "currency"=>{"code"=>"USD"}, "payment_term"=>{"code"=>"Net 30"}, "shipping_term"=>{"code"=>"Standard"}, "commodity"=>{"name"=>"Marketing-Services"}}]}}
struct = deep_structify(hash)
struct.requisition_header.department.name
#=> "Marketing"
You can do it by overriding OpenStruct#new as well,
require 'ostruct'
class DeepStruct < OpenStruct
def initialize(hash=nil)
#table = {}
#hash_table = {}
if hash
hash.each do |k,v|
#table[k.to_sym] = (v.is_a?(Hash) ? self.class.new(v) : v)
#hash_table[k.to_sym] = v
new_ostruct_member(k)
end
end
end
def to_h
#hash_table
end
end
Now you can do:
require 'deep_struct'
hash = {"requisition_header"=>{"requested_by"=>{"login"=>"coupasupport"}, "department"=>{"name"=>"Marketing"}, "ship_to_address"=>{"name"=>"Address_1431693296"}, "justification"=>nil, "attachments"=>[], "requisition_lines"=>[{"description"=>"Cleaning Services for Building A", "line_num"=>1, "need_by_date"=>2010-09-23 07:00:00 UTC, "source_part_num"=>nil, "supp_aux_part_num"=>nil, "unit_price"=>#<BigDecimal:a60520c,'0.3E4',9(18)>, "supplier"=>{"name"=>"amazon.com"}, "account"=>{"code"=>"SF-Marketing-Indirect", "account_type"=>{"name"=>"Ace Corporate"}}, "currency"=>{"code"=>"USD"}, "payment_term"=>{"code"=>"Net 30"}, "shipping_term"=>{"code"=>"Standard"}, "commodity"=>{"name"=>"Marketing-Services"}}]}}
mystruct = DeepStruct.new hash
mystruct.requisition_header.requested_by.login # => coupasupport
mystruct.requisition_header.to_h # => {"requested_by"=>{"login"=>"coupasupport"}
You could use BasicObject#method_missing:
Code
class Hash
def method_missing(key,*args)
(args.empty? && key?(key)) ? self[key] : super
end
end
Example
hash = { animals: {
pets: { dog: "Diva", cat: "Boots", python: "Stretch" },
farm: { pig: "Porky", chicken: "Little", sheep: "Baa" }
},
finishes: {
tinted: { stain: "Millers", paint: "Oxford" },
clear: { lacquer: "Target", varnish: "Topcoat" }
}
}
hash.finishes.tinted.stain
#=> "Millers
hash.animals.pets.cat
#=> "Boots"
hash.animals.pets
#=> {:dog=>"Diva", :cat=>"Boots", :python=>"Stretch"}
hash.animals
#=> {:pets=>{:dog=>"Diva", :cat=>"Boots", :python=>"Stretch"},
# :farm=>{:pig=>"Porky", :chicken=>"Little", :sheep=>"Baa"}}
Reader challenge
There is a potential "gotcha" with this approach. I leave it to the reader to identify it. My example contains a clue. (Mind you, there may be other problems I haven't thought of.)
I'm writing an API parser at the moment, and I'm working on formatting the data nicely.
So far, I have the following code:
data.each {|season| episodes[season["no"].to_i] = season["episode"].group_by{|i| i["seasonnum"].to_i}}
However, the only issue with this is that the output comes out like this:
8 => {
1 => [
[0] {
"epnum" => "150",
"seasonnum" => "01",
"prodnum" => "3X7802",
"airdate" => "2012-10-03",
"link" => "http://www.tvrage.com/Supernatural/episodes/1065195189",
"title" => "We Need to Talk About Kevin"
}
],
2 => [
[0] {
"epnum" => "151",
"seasonnum" => "02",
"prodnum" => "3X7803",
"airdate" => "2012-10-10",
"link" => "http://www.tvrage.com/Supernatural/episodes/1065217045",
"title" => "What's Up, Tiger Mommy?"
}
]
}
So there's a redundant array in each value of the secondary hash. How would I remove this array and just have the inside hash? So, for example I want:
8 => {
1 => {
"epnum" => "150",
"seasonnum" => "01",
"prodnum" => "3X7802",
"airdate" => "2012-10-03",
"link" => "http://www.tvrage.com/Supernatural/episodes/1065195189",
"title" => "We Need to Talk About Kevin"
}
,
etc.
EDIT: Here's the full file:
require 'httparty'
require 'awesome_print'
require 'debugger'
require 'active_support'
episodes = Hash.new{ [] }
response = HTTParty.get('http://services.tvrage.com/feeds/episode_list.php?sid=5410')
data = response.parsed_response['Show']['Episodelist']["Season"]
data.each { |season|
episodes[season["no"].to_i] = season["episode"].group_by{ |i|
i["seasonnum"].to_i
}
}
ap episodes
Input data: http://services.tvrage.com/feeds/episode_list.php?sid=5410
Wild guess:
data.each { |season|
episodes[season["no"].to_i] = season["episode"].group_by{ |i|
i["seasonnum"].to_i
}.first
}
It looks like you're using group_by (array of entries with same key) when you really want index_by (one entry per key).
data.each {|season| episodes[season["no"].to_i] = season["episode"].index_by {|i| i["seasonnum"].to_i}}
NOTE: If you can have MORE than one episode with the same seasonnum, you SHOULD use group by and have an array of values here. If you're just building a hash of episodes with a convenient lookup (one to one mapping), then index_by is what you want.
I have a test like so:
it "should not indicate backwards jumps if the checker position is not a king" do
board = Board.new
game_board = board.create_test_board
board.add_checker(game_board, :red, 3, 3)
x_coord = 3
y_coord = 3
jump_locations = {}
jump_locations["upper_left"] = true
jump_locations["upper_right"] = false
jump_locations["lower_left"] = false
jump_locations["lower_right"] = true
adjusted_jump_locations = #bs.adjust_jump_locations_if_not_king(game_board, x_coord, y_coord, jump_locations)
adjusted_jump_locations["upper_left"].should == true
adjusted_jump_locations["upper_right"].should == false
adjusted_jump_locations["lower_left"].should == false
adjusted_jump_locations["lower_right"].should == false
end
which, I know, is verbose. Is there a more concise way to state my expectations? I've looked at the docs but I can't see where to compress my expectations. Thanks.
It works for hashes too:
expect(jump_locations).to include(
"upper_left" => true,
"upper_right" => false,
"lower_left" => false,
"lower_right" => true
)
Source:
include matcher # relishapp.com
Just wanna add to #David's answer. You could nest and use matchers in your include hash. For example:
# Pass
expect({
"num" => 5,
"a" => {
"b" => [3, 4, 5]
}
}).to include({
"num" => a_value_between(3, 10),
"a" => {
"b" => be_an(Array)
}
})
A caveat: a nested include hash must test all keys or the test will fail, e.g.:
# Fail
expect({
"a" => {
"b" => 1,
"c" => 2
}
}).to include({
"a" => {
"b" => 1
}
})
Syntax has changed for RSpec 3, but include matcher is still the one:
expect(jump_locations).to include(
"upper_left" => true,
"upper_right" => false,
"lower_left" => false,
"lower_right" => true
)
See built-in-matchers#include-matcher.
Another easy way to test if the whole content is a Hash is to checkout if the content is the Hash Object itself:
it 'is to be a Hash Object' do
workbook = {name: 'A', address: 'La'}
expect(workbook.is_a?(Hash)).to be_truthy
end
For the question above we can check as follow:
expect(adjusted_jump_locations).to match(hash_including('upper_left' => true))