Cant i have two names with one route?
Something like below:
Route::get('/', 'Admin\HomeController#index')->name(['admin.home', 'planner.home.index']);
Thanks!
This works only if you need the name, not the URL, although it's tricky and sloppy.
Route::get('/', 'Admin\HomeController#index')->name('admin.home');
Route::get('/2', function() {
return redirect()->route('admin.home')
})->name('planner.home.index');
So if you use route('admin.home') or route('planner.home.index') it will redirects you to the method index in your HomeController.
You can make this, if you seek to have 2 version(route name) in the same app.
<?php
$routes = ['v1' => 'app.name1.', 'v2' => 'app.name2.'];
foreach ($routes as $routeVersion => $routeName) {
// Yours router app (i.e app/v1/pages or app/v2/pages)
// Your router name (i.e app.name1 or app.name2)
Route::prefix('app' . $routeVersion)
->middleware('auth')
->name($routeName)
->group(function(){
# Your custom routes
...
}
}
}
?>
This is an example of the response in the route list
I hope it serves you!
foreach($pages as $key => $page){
Route::any("/".$page, "Controller#index")->name($page);
}
Related
I am new in laravel framework now I'm working fully developed website using Laravel. I have changed blog url form {id} to {id}/{name} like www.example.com/news/203 to www.example.com/news/203/title. It's working fine. but i need to redirect if old url enter into current url opened from cache or something else.
Route::get('{id}/{name}', 'EventController#show')
->name('events-detail')
->where([
"id" => "[0-9]+"
]);
You can define another route in which you will find the model by id and use its title to redirect the user to the new route:
Route::get('{id}', function ($id) {
$model = Model::findOrFail($id);
return redirect()->route('events-detail', ['id' => $id, 'name' => $model->name]);
});
Note that you have to change Model with the class you use for this route.
Create 2 routes and add below code.
Route::get('{id}/{name}', function () {
//new URL as you want
return redirect()->route({id}/{name});
});
Route::get('{id}', function () {
//as you want for simple URL
});
I'm assuming the name portion is not really used at all, except for SEO/friendlier urls. If this is the case, just make the name parameter optional, and there will be no need for a redirect:
Route::get('{id}/{name?}', 'EventController#show')
->name('events-detail')
->where([
"id" => "[0-9]+"
]);
This route will match /203 and /203/news-title.
Let's say I have a function in my controller which retrieves users looking something like this:
public function index($category) {
// retrieve users depending on category or all
}
Now is there a way to make named routes to include the function parameter like so:
Route::get('passengers', 'Controller#index(1)')->name('passengers');
Route::get('attendees', 'Controller#index(2)')->name('attendees');
This way they can all use the same function
No you can not pass a parameter the action name, and there is a problem in you routing logic :
Route::get('/{categoryName}', 'Controller#index')->name('index');
And in the controller you will for example get the category by name like this :
public function index($categoryName) {
$category = Category::where('name', $categoryName)->first();
// use $ category as you please ;)
}
In the blade :
route('index', ['categoryName' => $category->name])
If the named route defines parameters, you may pass the parameters as the second argument to the route function. The given parameters will automatically be inserted into the URL in their correct positions
https://laravel.com/docs/5.5/routing#named-routes
So, use route() helper like this:
route('passengers', ['category' => 1])
Then you need to add {category} to the route. Also, it's really better to use show() instead of index() here. So, your route will look like this:
Route::get('passengers/{category}', ['as' => 'passengers', 'uses' => 'Controller#show']);
Yes, you can define the param in the url like so:
Route::get('passengers/{yourParam}', 'Controller#index')->name('passengers');
View in docs
Route::get( '{category}', [ 'as' => 'users', 'uses' => 'Controller#index' ]);
Remember to add this route at the end of your routes file in order to not to collide with any other route.
Now in your controller
use Illuminate\Http\Request;
public function index(Request $request)
{
$category = $request->query('category');
// $category will be passengers, attendees, etc
}
Your routes will be
/passengers can be accessed as route('users', ['category' => 'passengers'])
/attendees can be accessed as `route('users', ['category' => 'attendees'])
In session i set default language code for example de. And now i want that in link i have something like this: www.something.com/de/something.
Problem is that i cant access session in routes. Any suggestion how can i do this?
$langs = Languages::getLangCode();
if (in_array($lang, $langs)) {
Session::put('locale', $lang);
return redirect::back();
}
return;
Route::get('blog/articles', 'StandardUser\UserBlogController#AllArticles');
So i need to pass to route as prefix this locale session.
If you want to generate a link to your routes with the code of the current language, then you need to create routes group with a dynamic prefix like this:
Example in Laravel 5.7:
Route::prefix(app()->getLocale())->group(function () {
Route::get('/', function () {
return route('index');
})->name('index');
Route::get('/post/{id}', function ($id) {
return route('post', ['id' => $id]);
})->name('post');
});
When you use named routes, URLs to route with current language code will be automatically generated.
Example links:
http://website.com/en/
http://website.com/en/post/16
Note: Instead of laravel app()->getLocale() method you can use your own Languages::getLangCode() method.
If you have more questions about this topic then let me know about it.
Maybe
Route::group([
'prefix' => Languages::getLangCode()
], function () {
Route::get('/', ['as' => 'main', 'uses' => 'IndexController#index']);
});
I like to use resource controllers in Laravel, as it makes me think when it comes to data modelling. Up to now I’ve got by, but I’m now working on a website that has a public front-end and a protected back-end (administration area).
I’ve created a route group which adds an “admin” prefix, like so:
Route::group(array('before' => 'auth', 'prefix' => 'admin'), function()
{
Route::resource('article', 'ArticleController');
Route::resource('event', 'EventController');
Route::resource('user', 'UserController');
});
And I can access the methods using the default URL structure, i.e. http://example.com/admin/article/1/edit.
However, I wish to use a different URL structure on the front-end, that doesn’t fit into what resource controllers expect.
For example, to access an article, I’d like to use a URL like: http://example.com/news/2014/06/17/some-article-slug. If this article has an ID of 1, it should (under the hood) go to /article/1/show.
How can I achieve this in Laravel? In there some sort of pre-processing I can do on routes to match dates and slugs to an article ID, and then pass that as a parameter to my resource controller’s show() method?
Re-visiting this, I solved it by using route–model binding and a pattern:
$year = '[12][0-9]{3}';
$month = '0[1-9]|1[012]';
$day = '0[1-9]|[12][0-9]|3[01]';
$slug = '[a-z0-9\-]+';
// Pattern to match date and slug, including spaces
$date_slug = sprintf('(%04d)\/(%02d)\/(%02d)\/(%s)', $year, $month, $day, $slug);
Route::pattern('article_slug', $date_slug);
// Perform the route–model binding
Route::bind('article_slug', function ($slug) {
return Article::findByDateAndSlug($date_slug);
});
// The actual route
Route::get('news/{article_slug}', 'ArticleController#show');
This then injects an Article model instance into my controller action as desired.
One simple solution would be to create one more route for your requirement and do the processing there to link it to the main route. So, for example:
//routes.php
Route::get('/arical/{date}/indentifier/{slug}', array (
'uses' => 'ArticleController#findArticle'
));
//ArticleContoller
public function findArticle($date,$slug){
$article = Article::where('slug','=','something')->first(); //maybe some more processing;
$article_id = $article->id;
/*
Redirect to a new route or load the view accordingly
*/
}
Hope this is useful.
It seems like if Laravel 4 supports (:all) in routing, you would be able to do it with ease, but unfortunately (:all) is not supported in Laravel 4.
However, Laravel 4 allows detecting routes by regular expression, so we can use ->where('slug', '.*').
routes.php: (bottom of the file)
Route::get('{slug}', 'ArticleController#showBySlug')->where('slug', '.*');
Since Laravel will try to match the top most route in routes.php first, we can safely put our wildcard route at the bottom of routes.php so that it is checked only after all other criteria are already evaluated.
ArticleController.php:
class ArticleController extends BaseController
{
public function showBySlug($slug)
{
// Slug lookup. I'm assuming the slug is an attribute in the model.
$article_id = Article::where('slug', '=', $slug)->pluck('id');
// This is the last route, throw standard 404 if slug is not found.
if (!$article_id) {
App::abort(404);
}
// Call the controller's show() method with the found id.
return $this->show($article_id);
}
public function show($id)
{
// Your resource controller's show() code goes here.
}
}
The code above assumes that you store the whole URI as the slug. Of course, you can always tailor showBySlug() to support a more advanced slug checking.
Extra:
You could also do:
Route::get('{category}/{year}/{slug}', 'ArticleController#showBySlug')->where('slug', '.*');
And your showBySlug() would just have additional parameters:
public function showBySlug($category, $year, $slug)
{
// code
}
Obviously you can extend to month and day, or other adaptations.
I have a multilingue website created using Laravel 4, and I have lot of pages such as : "policy, "terms", "how it works" in database, so to access thoses pages I use this route:
// Group by locale
Route::group(
array( 'prefix' => $locale ), function () {
Route::get('{slug}', array('uses' => 'PageController#show','as' => 'pages.show');
// Website routes
});
And then I search for the given slug and the current locale.
My is problem is that I can't add for example a page link in the footer because the slug is dynamic. so is there any solution to resolve that.
It's make a sense ?
Thanks
You are already catching the slug in
Route::get('{slug}', array('uses' => 'PageController#show','as' => 'pages.show');
part. all you need is to inject this slug into controller like this:
class PageController extends BaseController {
public function show($slug)
{
return 'showing slug ' . $slug;
}
}
and whatever value the route receive for {slug} part in route laravel will automatically inject that value into the controller.