Vaadin 10 and springboot - How to package a jar? - maven

The question is simple, but I spent the last 2 days trying to deploy my app. And so far it doesn't.
I have a single CSS file for my style, and when I execute the jar, CSS is not found (404) or the jar won't package.
As stated here: Spring Boot Executable jar structure
"Do not use the src/main/webapp folder if your application will be packaged as a jar"
and
"You should place your static resources in src/main/resources instead."
so put the CSS here:
src/main/resources/styles.css
In Vaadin documentation (which is very pour on how to package...) I import the CSS like this:
#StyleSheet("styles.css")
Source : https://vaadin.com/docs/v11/flow/importing-dependencies/tutorial-include-css.html
Then I package my project:
mvn clean package -Pproduction
I get this error:
[ERROR] Failed to execute goal com.vaadin:vaadin-maven-plugin:11.0.0:package-for-production (default) on project importparcoursup: Execution default of goal com.vaadin:vaadin-maven-plugin:11.0.0:package-for-production failed: An import that ends with 'styles.css' cannot be resolved: the corresponding file 'C:\Workspace\lasteclipeandjava10\parcoursup\target\frontend\styles.css' was not found.
[ERROR] Double check the corresponding import and verify the following:
[ERROR] * the import string is correct
[ERROR] * the file imported is either present in 'frontend://' directory of the project or in one of the project WebJar dependencies or in one of the regular jar dependencies
[ERROR] * if the file is present in one of the regular jar dependencies, it should be located in META-INF/resources/frontend directory in the jar
Can someone provide a simple example of a 'springboot + Vaadin10' app packaged as a jar with static resources inside ?
I tried so many configurations (put the CSS in META-INF, include webapp resources in the maven build process...) but after 2 days, I still can't deploy my app on the server!

finally the solution
css has to be here:
src/main/resources/META-INF/resources/frontend/styles.css
then declared as:
#StyleSheet("frontend://styles.css")

This could be helpful too even though I still miss an example:
Vaadin 10 makes some changes to the way it loads static resources,
such as application templates, custom styles and any additional
JavaScript files. The gist of it is that such files should be put in
src/main/webapp/frontend/ when building a .war file and
src/main/resources/META-INF/resources/frontend/ when building a .jar
file.
Link to Vaadin Dokumentation: Vaadin 10 and static resources

Related

Generate and run Maven Kotlin jar

I'm trying to generate a jar file of my kotlin project.
I read Maven Kotlin and copied the code into my pom.xml but I don't understand what I'm supposed to insert at ${main.class}.
Here is my code architecture with MorisKt.java as my main class.
I tried MorisKt.class, /MorisKt.class, target/Moris.class(container folder of my compiled code)
And nothing worked. The jar is generated but I have Could not find or load main class when I try to run it.
If you can explain me where I'm doing it wrong
You need to put your main class file in a package and then reference it with the fully qualified name.
For instance if you put your Moris.kt in a package named app it would be :
<mainClass>app.MorisKt</mainClass>

Is there a simple way to access project resource files from a gradle task?

I am working on a Gradle task for a java project. The task needs to read files from a subfolder of the project’s resources directory. I was expecting to find a standard way for Gradle to access project resources but have been unable to find one. Does Gradle provide simple way to find and import resource files? Maybe through a plugin?
If you mean the src/main/resources folder, then no. That is by convention used by the Java plugin to hold resources for the actual module and not the build classpath. But if you just want to read a file in it from a task, just use normal Java, Groovy or Kotlin APIs. You don't need a plugin for that.
Here is one for Groovy:
task printMyResource {
doLast {
logger.quiet(file("src/main/resources/subfolder/my_file.txt").text)
}
}
(The file method resolves a path to a File object relative to the project folder.)

Could not get unknown property 'a.b.c' for root project

I got some source code and was asked to build it. It was a Gradle project. So I changed to the project directory and ran:
$ gradle clean assemble
and the following error came up:
...
* What went wrong:
A problem occurred evaluating root project 'pcase'.
> Could not get unknown property 'postgresql.jdbc' for root project 'pcase' of type org.gradle.api.Project.
...
There is a settings.gradle file in the project folder too. It contains:
rootProject.name = 'pcase'
I took a look at build.gradle and found lots of occurrences like
${project['x']}
For example:
buildscript {
dependencies {
...
// FlywayDB, JOOQ.
classpath "org.postgresql:postgresql:${project['postgresql.jdbc']}"
classpath "org.flywaydb:flyway-gradle-plugin:${project['flywaydb.plugin.version']}"
classpath "nu.studer:gradle-jooq-plugin:${project['jooq.plugin.version']}"
...
What could be ${project['x']}? Looks like associative array in bash and the build script tries to get the value of the key 'x'.
But I didn't find the place in code where this array would be declared and initialized.
The question is: Is the project buildable or is it better to consult the company that worked at it before me?
From the information provided, the project is perfectly buildable, to some certain extend. First of all, project['a.b.c'] is Groovy syntax to access properties from the project object. They're referred to as project properties.
They can be set via
Project properties via command line: gradle -Ppostgresql.jdbc=x.y.z
System properties via command line: gradle -Dorg.gradle.project.postgresql.jdbc=x.y.z
System properties via gradle.properties: org.gradle.project.postgresql.jdbc=x.y.z
All 3 properties (postgresql.jdbc, flywaydb.plugin.version, jooq.plugin.version) denote the version numbers of the particular build script dependencies. However, which versions to use best is beyond my knowledge. I would certainly consult the respective project websites, Maven artifact search or simply ask the company.
org.postgresql:postgresql is the database JDBC driver and certainly depends on the database version.
org.flywaydb:flyway-gradle-plugin is for database migrations. Try with the latest version.
I wasn't able to find gradle-jooq-plugin on Maven central. It's most likely available on the Gradle Plugin Portal.

Where to put external config files in a Kotlin Gradle project?

I use a standard Maven/Gradle project structure putting source code under src/main/kotlin and automatically collected resources under src/main/resources:
\myapp
-\src
-\main
-\kotlin
-\com
-\projectname
-\MyApp.kt
-\resources
- som_file.txt
This works fine to package my distribution with the distZip task and all resources end up in a jar which is then zipped into the following structure:
myapp
-\bin\
-\libs\
I am not sure where to put external config files in my Kotlin project (e.g. db.config) which the user could edit later. Is there a correct location for external config files in Gradle project?

Spring Tools Suite and Gradle - Setup to use correct resources from inside STS

I have a Spring Boot Gradle project setup in Spring Tools Suite (3.7.2 RELEASE) with the following source folders:
- src/integration-test/java
- src/integration-test/resources
- src/main/java
- src/main/resources
- src/test/java
- src/test/resources`
Whenever I run the application or unit tests from within STS, I see that STS is using the resources found under src/integration-test/resources.
I see a duplicate resource warning in STS for files which exist in all 3 resource source folders. For example, I have an application.properties in all 3 source folders and I see following:
The resource is a duplicate of src/integration-test/resources/application.properties and was not copied to the output folder
If I run the application as a JAR or unit tests/integration tests from the command line (via gradle build), everything seems to use the correct resources. This makes me believe it is a problem with how STS/Eclipse is handling gradle.
Does anybody know of how I can configure STS to use the correct resource source folders when using gradle?
I think my problem may be related to (or the same as?) Spring Boot incorrectly loads test configuration when running from eclipse+gradle, https://issuetracker.springsource.com/browse/STS-3882, https://issues.gradle.org/browse/GRADLE-1777
I also tried the solution found here, but that seems to only fix Maven builds:
Spring Tool Suite finds spring-boot integration test configuration and does not start main application
I think my problem may be related to...
Yes, it is related but in my opinion not the same. That problem is caused by the runtime classpath being incorrect. This problem is an error coming from the eclipse project builder so it is a compile-time issue.
The problems are closely related though. Depending on your point of view, you could say they are the same (incorrect mixing of test and compile-time classpaths).
Here, specifically, the problem is that the eclipse builder tries to copy all the resources it finds in source folders to the project's single output folder. Each source folder has a 'application.properties'. The builder warns that it could not copy some of them because one would overwrite the other.
I think there may be a solution for this problem. But it is a solution that really should come from Gradle + ( BuildShip | STS Gradle Tooling) than from you.
It is possible in Eclipse to configure each source-folder individually to target a specific outputfolder. Maven + M2E are doing this correcty, but Gradle + (BuildsShip | STS Gradle Tooling) combdos do not.
For example this is what maven puts into the eclipse .classpath file when it configures a test resources folder:
<classpathentry excluding="**" kind="src" output="target/test-classes" path="src/test/resources">
<attributes>
<attribute name="maven.pomderived" value="true"/>
</attributes>
</classpathentry>
Notice how it explicitly sets the output folder for that entry (to something different from the project's default output folder).
You may be able to address the problem yourself by modifying the .classpath for a gradle project in a similar way. Either by doing it manually or from your build.gradle.
I'm not sure this is worth it however as you will then likely still get hit by the runtime classpath issue (since these folders will still be added to your runtime classpath, your runtime classpath will end-up with two appication.properties resources, one which will 'shadow' the other. See: https://bugs.eclipse.org/bugs/show_bug.cgi?id=482315)
I would say, the right thing to do is add a comment to the issue I linked, and hope they fix it soon as there is only so much you can do yourself by hacking the build.gradle file to modify the .classpath (this can not solve the runtime classpath issue, but in order to solve the runtime classpath issue, they would have to configure source folders to target individual output folder similar to what m2e does).
I would add this as a comment to #Kris's answer but it's too long.
I have solved the runtime classpath issue by adding the code below to my build.gradle file. The code generates an Eclipse launch configuration for the Spring Boot application class and includes only the runtime classpath (i.e. no test JARs).
My project uses the Gradle 'eclipse' plugin to generate the Eclipse project files (which I then import into Eclipse). Running the eclipseClasspath Gradle target will generate the launch file in the project's root directory.
def mainClassName = "com.example.MyApplication"
task eclipseApplicationLaunch {
group "IDE"
description "Generate an Eclipse launch configuration file for the Spring Boot application class"
}
eclipseApplicationLaunch << {
def writer = new FileWriter("${mainClassName.substring(mainClassName.lastIndexOf(".")+1)}.launch")
def xml = new groovy.xml.MarkupBuilder(writer)
xml.doubleQuotes = true
xml.launchConfiguration(type: "org.eclipse.jdt.launching.localJavaApplication") {
listAttribute(key:"org.eclipse.debug.core.MAPPED_RESOURCE_PATHS") {
listEntry(value:"/${project.name}/src/main/java/${mainClassName.replace(".","/")}.java")
}
listAttribute(key:"org.eclipse.debug.core.MAPPED_RESOURCE_TYPES") {
listEntry(value:"1")
}
listAttribute(key:"org.eclipse.jdt.launching.CLASSPATH") {
listEntry(value:"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\"?>\r\n<runtimeClasspathEntry containerPath=\"org.eclipse.jdt.launching.JRE_CONTAINER/org.eclipse.jdt.internal.debug.ui.launcher.StandardVMType/JavaSE-1.8/\" javaProject=\"${project.name}\" path=\"1\" type=\"4\"/>\r\n")
listEntry(value:"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\"?>\r\n<runtimeClasspathEntry path=\"3\" projectName=\"${project.name}\" type=\"1\"/>\r\n")
configurations.runtime.resolvedConfiguration.resolvedArtifacts.each { artifact ->
def filePath = artifact.file.canonicalPath.replace("\\","/")
listEntry(value:"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\"?>\r\n<runtimeClasspathEntry externalArchive=\"${filePath}\" path=\"3\" type=\"2\"/>\r\n")
}
}
booleanAttribute(key:"org.eclipse.jdt.launching.DEFAULT_CLASSPATH", value:"false")
stringAttribute(key:"org.eclipse.jdt.launching.MAIN_TYPE", value:"${mainClassName}")
stringAttribute(key:"org.eclipse.jdt.launching.PROGRAM_ARGUMENTS", value:"--spring.profiles.active=local --spring.config.location=conf/")
stringAttribute(key:"org.eclipse.jdt.launching.PROJECT_ATTR", value:"${project.name}")
stringAttribute(key:"org.eclipse.jdt.launching.VM_ARGUMENTS", value:"-Djava.net.preferIPv4Stack=true")
}
writer.close()
}
eclipseClasspath.dependsOn eclipseApplicationLaunch
I haven't modified the Eclipse .classpath file as per Kris' suggestion. Instead, I have added #Profile("test") to my test application class and #ActiveProfiles("test") to my test classes.

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