I'm new to Django so apologies if this is a really stupid question but I'm trying to get a table to reload database values and when I open the page in a browser it loads ok initially but when it tries to reload nothing appears to happen. When I look in the network section of inspect element I can see repeated 404 page not found errors. I've been searching stack exchange etc. for a few days and I've tried various types of quotes etc. round the url tag but no joy. I'd really appreciate any help anyone can give me on this. I'm using python 3 and django2.
Project level urls.py
project level urls
App Level urls.py
App level urls
App views
App views
HTML
html
Directory Structure
directory structure
Terminal
enter image description here
Thanks in advance
The problem is a simple typo: you have a space between the { and the % in your url tag. This is causing Django to not recognise it as a tag, so the Ajax is using the literal string "{ % url ... }" as the URL which explains the mess you see in the terminal. Remove the space.
(Note, you still might not get the result you expect, since your Ajax function returns a complete HTML page but you are inserting that result inside a div in an existing page; you probably either want to replace the whole page or return a template fragment from your view.)
Related
Okay I do not know how to explain this to you, It may be just my internet, or maybe my site is slower, or they really have a technique for doing this.
If you visit Facebook, Reddit, Youtube, Twitter, and if you click on links or any actions on those websites, the url changes but the browser tab doesn't show any loading circle.
How do they do that?
I am pretty sure my website is fast enought and at times it loads even faster than the bigger sites, but mine shows the loading circle on the browser tab.
Okay so I found the answer. Here is the technique for changing the url without reloading the page.
Updating address bar with new URL without hash or reloading the page
How do I modify the URL without reloading the page?
I am still trying to figure out though how to redirect the actual page without reloading the entire page. I am guessing they are loading it via ajax or something similar upon url change. I'll update this once I figure it out.
Edit: I am currently working on this feature for my site. The technique is to use ajax to load the content based on the url. I'll update this thread more as I update my site with this feature.
Edit 2: Damn, you will probably face the same problem I had trying to detect the url change without using onhashchange. If so, here you go:
How to detect URL change in JavaScript
This literally took me 4 hours just to figure that one out.....
Edit 3: I have now integrated this feature on my site. You can check it at
Grandweb
It is quite simple, but lots of work in appending the content once retrieved via ajax. So here is the process:
I am using pushState(); to change the url without reloading the page.
var url = $(this).attr('href');
var split_url = url.split('/');
var new_url = url.replace('https://grandweb.net/','');
window.history.pushState("object or string", "Title", "/write");
Using 'mouseup' was a bad idea, I changed my mind.
I then have to trigger the first function using 'mouseup' to retreieve the content via ajax, and then listen to succeeding onpopstate() for the next ones, because some mouse actions such as Mouse 4 or Mouse 5 are bound to the browser's Back and Forward button, and does not trigger via 'mouseup'.
$(window).on('mouseup', function(evt) {
get_content();
}
window.onpopstate = function(event) {
get_content();
}
The first one is responsible for triggering the function on first try because onpopstate only listens only when the browser's history API is populated.
Using mouseup was a bad idea, basically, don't use it unless you really want to detect mouse action from anywhere on the document.
I instead use the anchor tags/links to trigger the first function for retrieveng content.
example:
<a class="dynamic_btn" href="website.com/post">Home</a>
then
$(document).on('click','.dynamic_btn',function(e){
e.preventDefault();
get_content();
});
Using onhashchange is possible IF you have hashes on your url. I do not use hashes on my url so basically onhashchange is useless in my use case, unless I do not know something.
After retrieving the contents, I append them via creating DOM elements to existing containers from the page.
This is much easier to do if you are planning to change few elements or containers in your pages. If you plan on doing this to change a full page layout, goodluck. It's doable, but it's a really pain in tha *ss.
Upon observing Facebook, I learned that they do not implement this technique in all of their links/features. It makes sense because this is harder to maintain most especially because most of the work here is being done client side. It is very nice though because the page doesn't load.
I have implemented it on a few 'essential' functions of my website such as the viewing of posts and returning to the homepage. I can implement it on the whole site, but I am still deciding on that. That is all, thank you very much for reading internet stranger.
On my page I would like to output all records of a specific folder
but the number should initially be limited to a certain quantity (to reduce the loading times). With a "Load more" button further records should be loaded.
Does anyone have a hint on how I can achieve this?
I have already found several approaches on the web in connection with AJAX, but since I'm not familiar with this yet, more questions than answers have emerged ...
For info: I use an own Template Extension / Distribution under Typo3 9.5.8
Thank you in advance for any help!!
The state of the art solution is the AJAX solution, where you load only the required records from the server and modify the page on the fly.
Another option would be an URL parameter which is evaluated by your extension.
With the parameter the full list is shown,
without only the first N and a button with the link to the same URL including the parameter for the full list.
Make sure the paramter is handled correctly and generates another cached version of the page. (keywords: cHash)
As you now have two pages with partially identical content: don't forget to tell the searchengines that the short variant should not be indexed.
You could use the Paginate Widget like documented here: https://docs.typo3.org/other/typo3/view-helper-reference/9.5/en-us/typo3/fluid/latest/Widget/Paginate.html
By overriding the paginate template file and only rendering the pagination.nextPage link, you could load the nextpage via AJAX.
I am trying to get TinyMCE 4's image_list to work with a URL returning JSON data as specified in the example here.
I have setup a GET endpoint http://demo.com/media on my server which gives back a JSON response consisting of a list of objects with their title and value attributes set, for example:
[{"title":"demo.jpg","value":"http://demo.com/demo.jpg"}]
I have also specified the option image_list: "http://demo.com/media" when initializing the plugin.
However, when I click the image icon in the toolbar, nothing pops up. All I can see in the network tab is an OPTIONS request with status 200, but then nothing. The GET request I was expecting never happens.
What is the correct way of using image_list in TinyMCE 4? Also, does anyone have a working demo example? I couldn't find anything.
It is somewhat hard to say what the issue is without seeing the exact data your URL is returning. I have created a TinyMCE Fiddle to show (in general) how this is supposed to work:
http://fiddle.tinymce.com/pwgaab
There is a JavaScript variable at the top (pretendFetchedData) that simulates what you would grab from the server (an array of JavaScript objects) and that is referenced via image_list.
If you enter your URL (http://demo.com/media) into a browser window what is returned? Are you sure its an array of JavaScript objects?
I have the identical problem. No matter what I do with the detail of the format (e.g. putting quotes round title and value), nothing happens.
I guess the only way (for me anyway) is to insert the list into the script with php before sending the web page.
I have searched the net for a solution but can't seem to get anywhere.
My page (php) is loading with one url (let's say www.mysite.com)
in the page several search options on music (albums) can be done and the tracks are shown. (without refreshing the page). the info comes from a database.
So the url stays the same.
In this search process the facebook meta tags (description, url, title) stay the same also because I never reload the page, I only load content into div's.
I would like to be able to 'like' the album, and backlink to it. So I have created the function to load the album by using the url: www.mysite.com?album=12345
I can show a popup with this url to share this.
So, if you go to this url, the content is automatically loaded based on the url parameter.
And on this spot (where you can see the url with the parameter ?album=12345) I would like to show the 'like' button as well. (I generated the url, so I use this in the code:)
echo '<div style="overflow:visable" class="fb-like" data-href="http://mysite.com/?album='.$albumid.'" data-send="false" data-width="300" data-show-faces="false">?</div>';
it works so far... (after I added the parse code to enable the button)
However the like button takes the default meta tags description and title etc.
Not particular on this album or artist - so it's not unique.
Note: if I remove the meta[property=og:url] from the header I can make the button backlink to the right url with the ?album parameter. Otherwise it would go back to the default root of the site mysite.com (this does make the lint tool give an error on the missing meta)
I have tried to add into this same function something like:
$("meta[property=og\\:url]").attr("content", "http://mysite.com/?album=<?php echo $albumid; ?>");
$("meta[property=og\\:title]").attr("content", "<?php echo $artistname; ?>");
$("meta[property=og\\:description]").attr("content", "<?php echo $albumname; ?>");
I did this so the meta tags will be changed, just to let the like button show the right description etc. However this doesn't work.
I understand that facebook scrapes the page (I used the lint tool etc.) but I will never executes javascript, so the meta tags wil stay as default (when first loading the page)
What can I do to make a unique like button, with it's own description (albumname etc) without making a html page for each one of them (millions of albums in the database...)
I hope it makes sense.
I can't seem to figure this one out, help please :-)
Based on the comments below I used the following solution:
you should create the right fb meta tags when the url (with the params ?alb_id=12345) is opened.
That's enough for the like button to do its job.
Your logic is fine, up to the point where you're setting the meta tags using jquery.
They should be set using PHP. As you can imagine the scraper won't execute the jquery, but if it's fed the already PHP-customized meta tags it will use them (as provided).
Just have the og:tags prepared server-side, depending on the albumId requested, and it should work. It might not work right away, I remember there used to be occasional caching issues with the scraper before.
In short, index.php?album=123 will send a different set of og:tags to the scraper than say index.php?album=321. Just set them up server-side.
<meta property="og:title" content="<?php echo $artistTitle; ?>"/>
What can I do to make a unique like button, with it's own description (albumname etc) without making a html page for each one of them (millions of albums in the database...)
You can’t, because Open Graph objects are URLs (resp. are represented/identified by their URL).
One URL == one Open Graph object.
But where’s the problem in having one URL for each album? Since it all works using parameters, it’s not like you have to create a page for each album URL manually …
I'll explain:
I have a picture gallery, the first page is display.php.
Users can flip through pictures using arrows, when you click an arrow it sends an Ajax request to retrieve the next picture from the db. Now I want the URL to change according to the picture displayed.
So if the first picture is:
www.mydomain.com/display.php?picture=Paris at night
I'll flip to the next one and the URL would be
www.mydomain.com/display.php?picture=The Big Ben
How do I do this?
The trick here are uri's with an anchor fragment.
The part before '#' points to a resource on the internet, and after normally designates to a anchor on the page.
The browser does not refresh if the resource is the same but moves to the anchors position when present.
This way you can keep the convenience of browser history from a usability point of view while replacing certain parts on the page with ajax for a fast and responsive user interface.
Using a plugin like jQuery history (as suggested by others) is really easy: you decorate certain elements with a rel attribute by which the plugin takes care of the rest.
Also kinda related to this topic is something called 'hijax', and it's something I really like.
This means generating html just like you would in the old days before ajax. Then you hijack certain behavior like links and request the content with ajax, only replacing the necessary parts. This in combination with the above technique allows really SEO friendly and accessible webpages.
You can use the jQuery history plugin for example.
changing the search of the url will load the changed url.
See also: stackoverflow, javascript changing the get parameter without redirecting
Do you really want to use AJAX here?
A traditional web request would work like this...
User navigates to display.php
User clicks "next" and location is updated to "display.php?picture=Big-Ben"
Big Ben is shown to user, along with a link to "display.php?picture=Parliment"
User clicks "next" and location is updated to "display.php?picture=Parliment"
And so on.
With AJAX, you essentially replace the GET with a "behind the scenes" GET, that just replaces a portion of your page. You would do this to make things faster... for example...
User navigates to display.php
User clicks "next" and the next image location is obtained using an AJAX request
The image (and image description) is changed to the next image
What you are suggesting is that you retrieve the "next url" using AJAX and then also perform a GET on the whole page. You would be much better off sending the "next" image when you send each page and not using AJAX at all.
this best describes everything i think: http://ajaxpatterns.org/Unique_URLs