I am doing exercise from the following link
Here is knowledge base:
house_elf(dobby).
witch(hermione).
witch(’McGonagall’).
witch(rita_skeeter).
magic(X):- house_elf(X).
magic(X):- wizard(X).
magic(X):- witch(X).
I am expecting the following query to return true:
?- magic(’McGonagall’).
However, my SWI-Prolog (AMD64, Multi-threaded, version 7.6.4) on Windows 7 returns the following:
ERROR: Stream user_input:450:4 Syntax error: Unexpected end of clause
?- magic('McGonagall').
ERROR: Undefined procedure: wizard/1
ERROR: In:
ERROR: [9] wizard('McGonagall')
ERROR: [8] magic('McGonagall') at c:/users/some_user/google drive/projects/nlp/prolog/code/ex2_2.pl:6
ERROR: [7] <user>
Exception: (9) wizard('McGonagall') ? creep
Exception: (8) magic('McGonagall') ? creep
?-
Why does it fail?
In the magic/1 predicate, you call wizard/1, which is not defined:
magic(X):- house_elf(X).
magic(X):- wizard(X).
magic(X):- witch(X).
The result is that Prolog errors, since it calls a predicate that is nowhere defined.
You can for example define a wizard/1 predicate that always fails:
% a world without wizards (if you do not specify extra wizards)
wizard(_) :- fail.
or populate your "world" with wizards, like:
wizard(dumbledore).
wizard(remus_lupin).
%% ...
Related
I am writing a predicate to print true if a list contains 3 copies of an element and also to print the element. Also the predicate should print alternate solutions if they exist.
The predicate which I have written -
hasTriplicate(List):-hasTriplicateAcc(List,Element,0).
%hasTriplicateAcc is wrapped by predicate hasTriplicate since I wanted the arity of hasTriplicate to be 1.
hasTriplicateAcc(_,Element,3):-write(Element).
hasTriplicateAcc([H|T],H,Ct):-hasTriplicateAcc(T,H,Ct1),Ct1 is Ct+1.
hasTriplicateAcc([Z|T],H,Ct):-hasTriplicateAcc(T,H,Ct),Z=\=H.
The output
hasTriplicate([1,1,1]).
11
ERROR: Arguments are not sufficiently instantiated
ERROR: In:
ERROR: [11] 3 is _10188+1
ERROR: [10] hasTriplicateAcc([1,1],1,_10218) at c:/users/user/desktop/code/hastriplicate.pl:3
ERROR: [9] hasTriplicateAcc([1,1|...],1,0) at c:/users/user/desktop/code/hastriplicate.pl:3
ERROR: [7] <user>
ERROR:
ERROR: Note: some frames are missing due to last-call optimization.
ERROR: Re-run your program in debug mode (:- debug.) to get more detail.
Exception: (10) hasTriplicateAcc([1, 1], 1, _10332)
I don't understand the error. It would be good if anyone tells me how to correct my code for the predicate.
I think this solution will work .
hascountminimal(_,_,0):-true,!.
hascountminimal([E|L],E,N):- ! , N1 is N - 1 , N >= 1 , hascountminimal(L,E,N1) .
hascountminimal([_|L],E,N):- hascountminimal(L,E,N).
intripple(L,E):-hascountminimal(L,E,3),write(E).
I got following code (from this tutorial)
main:-
open(’houses.txt’,read,Str),
read_houses(Str,Houses),
close(Str),
write(Houses), nl.
read_houses(Stream,[]):-
at_end_of_stream(Stream).
read_houses(Stream,[X|L]):-
\+ at_end_of_stream(Stream),
read(Stream,X),
read_houses(Stream,L).
houses.txt:
gryffindor.
hufflepuff.
ravenclaw.
slytherin.
I load it like this:
$ swipl -s flp18-log.pl
The problem comes when I want to start main "function" ->
?- main.
ERROR: Undefined procedure: main/1
ERROR: However, there are definitions for:
ERROR: main/0
ERROR:
ERROR: In:
ERROR: [9] main([])
ERROR: [8] prolog_main:main at /usr/local/Cellar/swi-prolog/HEAD-e6bbda4/libexec/lib/swipl-7.7.12/library/main.pl:82
ERROR: [7] <user>
Exception: (9) main([]) ?
I spent hours figuring out what's wrong. Unsuccessfully. Can you help?
Is:
open('houses.txt',read,Str)
with ', not with ’.
I am learning Prolog and .(a,[]) == [a]. should return true in SWI-Prolog, but it gives me an error saying
ERROR: Type error: `dict' expected, found `a' (an atom)
ERROR: In:
ERROR: [11] throw(error(type_error(dict,a),_4020))
ERROR: [10] '$type_error'(dict,a) at /Applications/SWI-
Prolog.app/Contents/swipl/boot/init.pl:3369
ERROR: [9] '$dicts':'.'(a,[],_4086) at /Applications/SWI-
Prolog.app/Contents/swipl/boot/dicts.pl:46
ERROR: [8] '<meta-call>'(user:(...,...)) <foreign>
ERROR: [7] <user>
Anyone knows how to fix this?
Start the SWI Prolog executable with the --traditional command line option (comment due to user:false).
Then it works:
1 ?- .(a,[]) == [a].
true.
2 ?- current_prolog_flag( traditional, X).
X = true.
3 ?- set_prolog_flag( traditional, false).
ERROR: set_prolog_flag/2: No permission to modify flag `traditional'
4 ?-
This is mentioned in the documentation here (see "traditional", near the bottom of the page).
As can be seen, attempting to change it from within the running SWI session, fails.
I am using gprolog allong with gplc and I get fatal error: redefining built-in predicate member/2 when I try to compile the following code. I also get uncaught exception: error(existence_error(procedure,member/0),member/0) when I try to consult the same code.
Code:
member(X,[X|T]).
member(X,[H|T]) :- member(X,T).
The query I give:
| ?- member(X,[a,b,c,d,e]).
X = a ? ;
uncaught exception: error(existence_error(procedure,member/0),member/0)
I am trying to use list constructor in SWI-Prolog, but am getting 'dict' expected error.
For example,
.(a, []) == [a].
ERROR: Type error: `dict' expected, found `a' (an atom)
ERROR: In:
ERROR: [11] throw(error(type_error(dict,a),_14808))
ERROR: [10] '$type_error'(dict,a) at /Applications/SWI-Prolog.app/Contents/swipl/boot/init.pl:3369
ERROR: [9] '$dicts':'.'(a,[],_14874) at /Applications/SWI-Prolog.app/Contents/swipl/boot/dicts.pl:46
ERROR: [8] '<meta-call>'(user:(...,...)) <foreign>
ERROR: [7] <user>
Exception: (9) '.'(a, [], _14200) ?
Could anyone help me configure this functionality?
SWI-Prolog 7.x uses a different list constructor, '[|]'/2, instead of the traditional ./2 Prolog constructor:
?- '[|]'(1,[]) == [1].
true.
The change was motivated to free ./2 for other uses, notably in dict terms, as hinted in the error message you got for your query.
Better to use | in conventional notation,
?- X = '[|]'(1,[0]).
X = [1, 0].
can be write like this
?- X = [1|[0]].
X = [1, 0].