Parse Strings in HIVE using Shell - bash

Question

I have a shell script that I use to parse a string variable into Hive, in order to filter my observations. I provide both the script and the hive code below.
In the following script I have a variable which has a string value and I try to parse it into hive, the example below:
Shell Script:
name1='"Maria Nash"' *(I use a single quote first and then a double)*
hive --hiveconf name=${name1} -f t2.hql
Hive code (t2.hql)
create table db.mytable as
SELECT *
FROM db.employees
WHERE emp_name='${hivevar:name}';
Conclusion
To be accurate, the final table is created but it does not contain any observation. The employees table contains observations which has emp_name "Maria Nash" though.
I think that I might not parse the string correctly from shell or I do not follow the correct syntax on how I should handle the parsed variable in the hive query.
I would appreciate your help!

Answer 1

you are passing variable in hiveconf namespace but in the sql script are using hivevar, you should also use hiveconf:
WHERE emp_name=${hiveconf:name} --hiveconf, not hivevar

Answer 2

Use of the CLI is deprecated
you can use beeline from a shell script
it should look something like
beeline << EOF
!connect jdbc:hive2://host:port/db username password
select *
from db.employees
where emp_name = "${1}"
EOF
assuming that $1 is the input from the script.
This is an example of how to do it rather than a production implementation. Generally,
Kerberos would be enabled so username and password wouldn't be there
and a valid token would be available
Validate the input parameters.
Given that you can do it in a single line
beeline -u jdbc:hive2://hostname:10000 -f {full Path to Script} --hivevar {variable}={value}