Gradle: find and build all projects in folder - gradle

Question

I have a folder with a lot of projects inside it (too much to manually write build files for them)
The projects are mostly in a flat layout:
root
-project 1
-project 2
-project 3
-project 4
-project 5
( -project 5.1)
But can be nested as shown above, and I need to account for this.
Ideally the following should happen:
I can run user#user:/root gradle build and every project in the directory shoudl be built as long as it contains a gradle build file
if a build fails just continue with the next one
How can I make this possible ?

Answer 1

How about this one-liner (not tested):
find . -maxdepth 1 -type d \( ! -name . \) -exec bash -c "cd '{}' && gradle build || true" \;
Or, more verbose:
dirs=($(find . -type d))
for dir in "${dirs[#]}"; do
cd "$dir"
gradle build || true
done

Answer 2

I came up with a working solution:
def flist = []
// change to you workspace name
new File('./Workspace').eachDir {
//blacklist any folders you want
if (it.name !='.gradle' && it.name != 'master' && it.name!= 'Build-All') {
flist << it.name
}
}
// build task objects
flist.each { folder ->
task "${folder}"(type: GradleBuild) {
buildFile = "./Workspace/"+ folder + "/build.gradle"
dir = './' + folder
tasks = ['build']
}
}
// create super task
task (all, dependsOn: flist) {
}
You need to invoke it as such in the root directory: gradle :all --continue this has the benefit that any failing project builds will not halt the other builds.
Another bonus is that gradle gives a neat report about all failing builds.