Use Where in QueryBuilder - Laravel - laravel

Question

I have a table Products(id,category_id,name);
I want to get a result like this query:
SELECT * FROM Products WHERE category_id=$category_id OR $category_id=0;
When I assign $category_id with 0 value => above query will return all records.
How do I write that query in Laravel?
I've try this:
Products::where(function($query) use ($category_id){
$query->where("category_id",$category_id)
->orWhere($category_id,0)
})->get();
But, Error:
It look like:
SELECT
*
FROM
`products`
WHERE
( `product_category_id` = 0 OR `0` = 0 )
And Print Error: Column not found: 1054 Unknown column '0' in 'where clause'
How to fix: '0' = 0 to 0 = 0?
Thanks!

Answer 1

Use when():
$products = Product::when($categoryId, function ($query, $categoryId) {
$query->whereCategoryId($categoryId);
})->get();
This method will call the function only if the condition is truthy. You could achieve the same thing with simple if statement:
$products = Product::query();
if ($categoryId) {
$products->whereCategoryId($categoryId);
}
$products = $products->get();
What you gain by using when() is that you don't break the chain, so you can use conditional query changes in one expression. It's useful if you want to just return it, for example.

Answer 2

use it
Products::where(function($query) use ($category_id){
$query->where("category_id",$category_id)
->orWhere("category_id",0);
})->get();

Answer 3

what's wrong with your code is this:
->orWhere($category_id,0)
you made the column part as variable.
try this code:
Products::where(function($query) use ($category_id){
return $query->where("category_id", $category_id)
->orWhere("category_id", 0);
})->get();

Answer 4

$product = new Products;
if ($category_id != 0) {
$product = $product->where("category_id", $category_id);
}
$products = $product->get();