How can I put the port and host in the property file in Spring? - spring

Question

I have this url
private static final String PRODUCTS_URL = "http://localhost:3007/catalog/products/";
And this methods:
public JSONObject getProductByIdFromMicroservice(String id) throws IOException, JSONException {
return getProductsFromProductMicroservice(PRODUCTS_URL + id);
}
public JSONObject getProductsFromProductMicroservice(String url) throws IOException, JSONException {
CloseableHttpClient productClient = HttpClients.createDefault();
HttpGet getProducts = new HttpGet(url);
CloseableHttpResponse microserviceResponse = productClient.execute(getProducts);
HttpEntity entity = microserviceResponse.getEntity();
BufferedReader br = new BufferedReader(new InputStreamReader((entity.getContent())));
StringBuilder sb = new StringBuilder();
String line;
while ((line = br.readLine()) != null) {
sb.append(line);
}
br.close();
System.out.println(sb.toString());
JSONObject obj = new JSONObject(sb.toString());
System.out.println(obj);
return obj;
}
I want to put the port and host in a separate property file. I have already seen examples using properties and the yml file. But I do not understand how then my methods will work using this port when creating an instance of the class, which I will indicate in the properties file. Can you tell?

Answer 1

You can put your properties in a properties file in the resource directory for example
PRODUCTS_URL="http://localhost:3007/catalog/products/"
and add #PropertySource("YOUR_RESOURCE_FILE_HERE.properties") in your main class (Application.java)
#SpringBootApplication
#PropertySource("products.properties")
public class Application {...}
and then use #Value("${YOUR_PROPERTY_NAME}") to load it:
#Value("${PRODUCTS_URL}")
private String PRODUCTS_URL;
Check this tutorial

Answer 2

This is how i do it :
CONFIG FILE
#Database Server Properties
dbUrl=jdbc:sqlserver://localhost:1433;database=Something;
dbUser=sa
dbPassword=SomePassword
Then i annotate a config class with this :
#PropertySource("file:${ENV_VARIABLE_TO_PATH}/config.properties")
Then autowire this field :
#Autowired
private Environment environment;
Then create the data source :
#Bean
public DataSource dataSource()
{
HikariDataSource dataSource = new HikariDataSource();
try
{
dataSource.setDriverClassName("com.microsoft.sqlserver.jdbc.SQLServerDriver");
dataSource.setConnectionTestQuery("SELECT 1");
dataSource.setMaximumPoolSize(100);
String dbUrl = environment.getProperty("dbUrl");
if (dbUrl != null)
{
dataSource.setJdbcUrl(dbUrl);
}
else
{
throw new PropertyNotFoundException("The dbUrl property is missing from the config file!");
}
String dbUser = environment.getProperty("dbUser");
if (dbUser != null)
{
dataSource.setUsername(dbUser);
}
else
{
throw new PropertyNotFoundException("The dbUser property is missing from the config file!");
}
String dbPassword = environment.getProperty("dbPassword");
if (dbPassword != null)
{
dataSource.setPassword(dbPassword);
}
else
{
throw new PropertyNotFoundException("The dbPassword property is missing from the config file!");
}
logger.debug("Successfully initialized datasource");
}
catch (PropertyNotFoundException ex)
{
logger.fatal("Error initializing datasource : " + ex.getMessage());
}
return dataSource;
}
I know this is not exactly your scenario but perhaps you can find inspiration from this code to suit your specific needs?

Answer 3

Other answers here mention using #PropertySource annotation to specify path of config files. Also if this is a test code (unit/integration) you can also make use of another annotation #TestPropertySource.
With this, we can define configuration sources that have higher precedence than any other source used in the project.
See here: https://www.baeldung.com/spring-test-property-source