How to get a device's serial no with Nativescript? - nativescript

Question

Does anybody know how to get the serial number of a device?
I know I can do this in a NativeScript-5 application (TypeScript):
import { Page } from "tns-core-modules/ui/page";
import * as platformModule from "tns-core-modules/platform";
export function onNavigatingTo(args: EventData) {
let page = <Page>args.object;
console.log("Manufacturer:" + platformModule.device.manufacturer);
console.log("Model:" + platformModule.device.model);
console.log("UUID:" + platformModule.device.uuid);
}
But I couldnt find any property for the device's serial number.
Anybody an idea? It's alright if your solution only covers Android (since my project is targeting Android tablets only).
Thanks!
Update:
Manoj pointed me to some Java code that probably solves my problem. However, I wasn't able to marshal the following code to TypeScript.
public static String getManufacturerSerialNumber() {
String serial = null;
try {
Class<?> c = Class.forName("android.os.SystemProperties");
Method get = c.getMethod("get", String.class, String.class);
serial = (String) get.invoke(c, "ril.serialnumber", "unknown");
} catch (Exception ignored) {}
return serial;
}
Maybe anybody could help me? That would be awesome!

Answer 1

iOS never allows any confidential information to be accessed by apps, that applies to serial number too. With Android, you may read the serial number with
android.os.Build.SERIAL
I had it tested with Playground
Edit 1:
Manufactures like Samsung seems to have a different serial number which is not same as android.os.Build.SERIAL. Here is another SO thread that seems very relevant for Samsung, the sample code is written in Java.
Edit 2:
Here is how you may get serial number on Samsung devices
let serialNumber = '';
try {
const cl = application.android.context.getClassLoader();
const SystemProperties = cl.loadClass('android.os.SystemProperties');
const paramTypes = (<any>Array).create(java.lang.Class, 2);
paramTypes[0] = java.lang.String.class;
paramTypes[1] = java.lang.String.class;
const getMethod = SystemProperties.getMethod('get', paramTypes);
const params = (<any>Array).create(java.lang.Object, 2);
params[0] = new java.lang.String('ril.serialnumber');
params[1] = new java.lang.String('unknown');
serialNumber = getMethod.invoke(SystemProperties, params);
} catch (err) {
console.error(err);
}
Updated Playground

Answer 2

You can check properties 'ro.serialno', 'ril.serialnumber', 'gsm.sn1', 'sys.serialnumber'
Android: How to programmatically access the device serial number shown in the AVD manager (API Version 8)
In my case Samsung TAB S2 has 2 serials. Property 'ro.serialno' more accurate then 'ril.serialnumber'. So i check it first.
getSerial() {
if (isAndroid) {
let serialNumber = null;
try {
const cl = application.android.context.getClassLoader();
const SystemProperties = cl.loadClass('android.os.SystemProperties');
const paramTypes = (<any>Array).create(java.lang.Class, 2);
paramTypes[0] = java.lang.String.class;
paramTypes[1] = java.lang.String.class;
const getMethod = SystemProperties.getMethod('get', paramTypes);
const params = (<any>Array).create(java.lang.Object, 2);
// Reorder if needed
const props = ['ro.serialno', 'ril.serialnumber', 'gsm.sn1', 'sys.serialnumber'];
for(let i = 0, len = props.length; i < len; i++) {
params[0] = new java.lang.String(props[i]);
serialNumber = getMethod.invoke(SystemProperties, params);
if (serialNumber !== '') {
return serialNumber;
}
}
} catch (err) {
console.error(err);
}
return serialNumber;
}
}
Full code: https://play.nativescript.org/?template=play-tsc&id=ViNo6g&v=6