When i run this on Pycharm it opens than closes immediately. Whereas in the video tutorial it just stays open, why?
import pygame
pygame.init()
win = pygame.display.set_mode((500, 500))
pygame.display.set_caption("hello")
i am using windows os, python version 3.7.2, and pygame 1.9.4
I don't know which tutorial you talk about, but if the process that created the window finishes, the window will be closed.
E.g. when you create the window via a python shell, the window will stay open as long as the shell is open.
If you open the window via a script (a file), you need to keep the script from finishing. You do this by creating what is called a main loop and usually looks like this:
import pygame
def main():
pygame.init()
win = pygame.display.set_mode((500, 500))
pygame.display.set_caption("hello")
clock = pygame.time.Clock()
while True:
for e in pygame.event.get():
if e.type == pygame.QUIT:
return
win.fill((30, 30, 30))
pygame.display.update()
clock.tick(60)
if __name__ == '__main__':
main()
pygame.quit()
I had the same problem as you (and I was following the same tutorial) and i found that if you enclose the whole thing in a while loop (excluding import pygame, pygame.init() and the variable you use for the while loop) it works quite well.
import pygame
pygame.init()
Game = True
while Game is True:
window1 = pygame.display.set_mode((500, 500))
pygame.display.set_caption("First Game")
I have just started learning Python so this might not be the best way to do it but I hope it helps in some way :)
Related
I loaded up Anaconda and realized there is more stuff there than I can absorb in my lifetime. However, I did load Spyder and pasted in a working program that runs without error in PyCharm and Thonny.
"""Create a 2 button window"""
import tkinter as tk
from tkinter import *
from tkinter import messagebox
#write slogan out in a message box
def write_slogan():
messagebox.showinfo("our message",
"tkinter is easy to use")
#set up the window
root = tk.Tk() #get the window
root.geometry("100x100+300+300") #x, y window size and position
#create Hello button
slogan = Button(root,
text="Hello",
command=write_slogan)
slogan.pack(side=LEFT, padx=10)
#create exit button with red letters
button = Button(root,
text="QUIT",
fg="red",
command=quit)
button.pack(side=RIGHT, padx=10)
#start running the tkinter loop
root.mainloop()
It may not surprise Spyder mavens, but I was surprised to see that it did not recognize "quit" However, I replaced it with
command=sys.exit
and that at least compiled.
However, when I ran it, the window appeared UNDER the Spyder window. I found it in the task bar. BUT, when I clicked in the Quit button, the program just hung. I had to go to the console and and type
quit
to stop the process.
I guess Spyder isn't really intended for GUI programming.
I have QSystemTrayIcon with a QMenu. In order to fill the menu, I need to fetch some things from the network, so I want to do that in the background.
So I have a QThread with a slot that is connected to the activated signal of the tray icon. Then the thread fetches the resources and updates the menu using another signal.
However, these updates do not show until I close and reopen the menu.
This seems to be a Mac specific problem. I ran my code on Windows, and there it updated more or less correctly. Is there any workaround?
Below is an extracted version of the problem. When the menu is opened, it will sleep 1 second in a thread and then change the menu. This change is not seen.
import sys
import time
from PySide import QtCore, QtGui
class PeerMenu(QtGui.QMenu):
def __init__(self):
QtGui.QMenu.__init__(self)
self.set_peers("prestine")
#QtCore.Slot(object)
def set_peers(self, label):
self.clear()
self.addAction(QtGui.QAction(label, self))
self.addSeparator()
self.addAction(QtGui.QAction("Hello", self))
class GUIListener(QtCore.QObject):
files = QtCore.Signal(object)
def __init__(self):
QtCore.QObject.__init__(self)
self.counter = 0
#QtCore.Slot()
def check(self):
time.sleep(1)
self.counter += 1
self.files.emit(str(self.counter))
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
icon = QtGui.QSystemTrayIcon(QtGui.QIcon('images/glyphicons-206-electricity.png'), app)
listener = GUIListener()
t = QtCore.QThread()
t.start()
listener.moveToThread(t)
menu = PeerMenu()
icon.activated.connect(listener.check)
listener.files.connect(menu.set_peers)
icon.setContextMenu(menu)
icon.show()
app.exec_()
After a few hours of extensive googling I finally figured it out.
You can create a borderless window using QtGui.QMainWindow(parent=None, flags=QtCore.Qt.Popup) and then find the location of the icon with icon.geometry().center() and finally move the window there with window.move(icon_point).
There is some hackery involved in deciding how to place the window relative to the icon. Full code can be found at https://github.com/pepijndevos/gierzwaluw/blob/master/gui.py
I am creating a game to run inside a GUI (text area, button, menu etc) I've created a GUI with wxpython. I create a panel inside the main window, which runs a pygame thread.
Problem:
On Windows, the pygame thread runs perfectly inside the main window. But on Linux, the pygame pop up on a new window. How can I set this such that both windows and Linux run the thread in the main window?
Code:
class SDLPanel(wx.Panel):
def __init__(self,parent,ID,tplSize):
global pygame
global pygame_init_flag
wx.Panel.__init__(self, parent, ID, size=tplSize)
self.Fit()
if (sys.platform == 'win32'):
os.environ['SDL_WINDOWID'] = str(self.GetHandle())
os.environ['SDL_VIDEODRIVER'] = 'windib'
else:
os.environ['SDL_VIDEODRIVER'] = 'x11'
#here is where things change if pygame has already been initialized
#we need to do so again
if pygame_init_flag:
#call pygame.init() on subsaquent windows
pygame.init()
else:
#import if this is the first time
import pygame
pygame_init_flag = True #make sure we know that pygame has been imported
pygame.display.init()
window = pygame.display.set_mode(tplSize)
self.thread = SDLThread(window)
self.thread.Start()
def __del__(self):
self.thread.Stop()
print "thread stoped"
#very important line, this makes sure that pygame exits before we
#reinitialize it other wise we get errors
pygame.quit()
Solved problem.
In main window we must self.Show()
Idk why in linux the main window must be showed . Same code.
Tks all
This is a disclaimer alert, according to https://forums.libsdl.org/viewtopic.php?p=39332, the solution works only with SDL 1.2 and not 2.0.
I'm rather unfamiliar with Python, but am attempting to make a simple gui with tkinter (Python 2.7.x). I have one fully functional button, but I can only get the script to work in iPython. When I try to run it outside of the iPython environment, I see some text run down the command prompt but nothing happens (ie no gui appears, no action happens).
My code:
import Tkinter
from Tkinter import *
import os
#define frame
root = Tk()
frame = Frame(root)
frame.pack()
#define buttons
button = Button(frame, text="Action", command= lambda: os.system("Action.py"))
button.pack(side=LEFT)
Add root.mainloop() to the end of your code.
As the title suggests, when I create a push button, or a menu option for ending the program, the window doesn't close.
so I'm trying to figure out to end the program and close the window simultaneously. I've been using the tutorial:
http://zetcode.com/tutorials/pyqt4/
which is great otherwise. So how do i connect the push button with ending & closing a widget?
Here is some sample code (copied from the tutorial) that I have been using. I cant seem to get the ending to copy exactly, but I don't think that's the issue anyways:
#!/usr/bin/python
# -*- coding: utf-8 -*-
"""
ZetCode PyQt4 tutorial
This program creates a quit
button. When we press the button,
the application terminates.
author: Jan Bodnar
website: zetcode.com
last edited: October 2011
"""
import sys
from PyQt4 import QtGui, QtCore
class Example(QtGui.QWidget):
def __init__(self):
super(Example, self).__init__()
self.initUI()
def initUI(self):
qbtn = QtGui.QPushButton('Quit', self)
qbtn.clicked.connect(QtCore.QCoreApplication.instance().quit)
qbtn.resize(qbtn.sizeHint())
qbtn.move(50, 50)
self.setGeometry(300, 300, 250, 150)
self.setWindowTitle('Quit button')
self.show()
def main():
app = QtGui.QApplication(sys.argv)
ex = Example()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
Thanks!
The code works. I have the same issue, but running it outside IDLE it works. No need to change the code to call the quit method on the QtGui module.
Your app is a QtGui.QApplication, so why are you connecting to the quit signal using QtCore.QCoreApplication? Changing that to QtGui.QApplication.instance().quit works.
replace qbtn.clicked.connect(QtCore.QCoreApplication.instance().quit) with
qbtn.clicked.connect(self.close)
I too faced the same problem (trying to learn Qt4 from the same zetcode tutorials) and came here to look for a solution