How to convert integer to string in yaml. I have seen simply need to put quote . But not working. Still getting value as integer
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This question already has answers here:
How to convert an int value to string in Go?
(10 answers)
Closed last year.
this is my day 1 using goLang, I am currently trying to consume a data but I encounter an error, and that's converting integer to string
func createLink(title string, page int) string {
url := url.URL{
Scheme: "https",
Host: "jsonmock.hackerrank.com",
Path: "/api/movies/search/",
}
query := url.Query()
query.Set("page", string(page))
query.Set("title", title)
url.RawQuery = query.Encode()
return url.String()
}
you can try that code, and the result is
actual result :
https://jsonmock.hackerrank.com/api/movies/search/?page=%01&title=spiderman
expected result :
https://jsonmock.hackerrank.com/api/movies/search/?page=1&title=spiderman
There's %01 , an that's something that I do not want. i believe that I made a mistake in converting an integer to string
You should use strconv.Itoa() method to format your integers as strings. This is better explained in the linked answer. For the sake of completeness, here's how you end up with %01 in your result:
first, int 1 gets "plain-converted" to string by following this conversion rule:
Converting a signed or unsigned integer value to a string type yields
a string containing the UTF-8 representation of the integer. Values
outside the range of valid Unicode code points are converted to
"\uFFFD".
then the resulting string (with character of unicode code point equal to 1) gets URL-encoded, ending up with %01 as its representation.
As a sidenote, you're warned about this if you run go vet over your code:
hello.go:19:20: conversion from int to string yields a string of one
rune, not a string of digits (did you mean fmt.Sprint(x)?)
While this doesn't always give you absolutely the best advice on how to fix your error, it at least pushed you into the right direction. And it's strongly recommended to get used to the idea of running this (or similar) kind of checks from day 1 of learning language.
I am trying to convert a single byte value to a string in golang. When I do a typecast of a byte to string like string(byte) and print the value I get "{" in response. I read other answers that the correct way to convert a byte to string would be strconv.Itoa(int(bytevalue)). Why does the former not work and why is the latter approach correct.
The expression string(bytevalue) is a conversion, not a typecast.
The specification says this about conversions from numeric types to a string:
Converting a signed or unsigned integer value to a string type yields a string containing the UTF-8 representation of the integer.
The expression string(byte(123)) evaluates to the string "{" because { is the the string containing the UTF-8 representation of the rune 123.
Use the strconv package to get the decimal representation of the byte. The expression strconv.Itoa(int(byte(123))) evaluates to the string "123".
I am trying to convert small strings into their respective ascii decimal values. Like converting the string "Ag" to "065103".
I tried using
integer_variable : Integer := Integer'Value(Ag);
but that gives me constraint error: bad input for 'Value: "Ag".
Is there something else I can use to make this work? Could I just use enumeration?
Strings in Ada are arrays of Characters, thus if you want to convert String to Integer values you have to do this for each Character separately, by taking its position in enumeration (as suggested in the comment to your question). In your example it could be:
integer_variable1 : Natural := Character'Pos('A');
integer_variable2 : Natural := Character'Pos('g');
I have the double value
EX. 2.77555756156289E-17
-8.48087032699772E-18
I would like to convert it so that the E-XX is gone and zeros are used instead.
How would I do that , please?
I have "\001\022" as value of a. my desired decimal value is 274.
I tried following function . but I get ["0112"]
a.unpack("H*") ==> ["0112"]
When I convert this "0112" to decimal using calculator it gives me 274. How can i get like
this using ruby methods.
Thanks
The format string in your question: "H*", is for "hex string (high nibble first)". Therefore it decoded your string as an array of 4-bit hexadecimal elements.
You need a different format.
Try this, which decodes it as a "16-bit unsigned, network (big-endian) byte order" integer:
a.unpack("n") # => [274]
For full details on what characters you can use in the format string, check the Ruby Documentation for String#unpack.