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,"some values1","some values2",Not Processed,0,
Is there any way I could replace the above pattern, irrespective of whatever values come in some values1 or some values2 with the lines below,
,,,Not Processed,0,
This string is just a part of a large file I have.
This solves the problem I believe:
test_data() {
cat <<EOF
,"val1,val2...","val1,val2,val3..",Not Processed,0,
,"val1,val2..","",Not Processed,0,
,"","val1,val2,val3....",Not Processed,0,
EOF
}
test_data | sed -e 's/\(.*\),"[^"]*","[^"]*",\(Not Processed,0,\)\(.*\)/\1,,,\2\3/g'
Output:
▶ bash data.sh
,,,Not Processed,0,
,,,Not Processed,0,
,,,Not Processed,0,
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i want to copy some files from ../soft to ../copu_new. The name of that tests are in ../sim/soft.txt.
I had en error : cp:cannot stat '../soft/file1.txt\file2.txt\file3.txt': File too long
Follow the code below:
input="../sim/soft.txt"
while read line
do
##to skip the first line of the file
a=$(tail -n +1)
##From string to table
for i in $a
do
table_soft[$i]="$i"
done
for i in "${tabke_soft[#]}"
do
cp ../soft/$i ../copy_new
done
done < $input
The file Soft.txt is :
###This all tests:
file1.txt
file2.txt
file3.txt
It's most likely the classic bash issue where trying to run an array through a for loop gives you all the content unless you wrap it in double quotes first. Try this..
a="$(tail -n +1)"
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I have a '.GS3' file with multiple lines like this one:
0123456789 aaa.aaa3456
I want to separate it like this:
01234;56789 ;aaa.aaa;3456
I know the start and end of each part of the line. Is it possible to do this considering multiple lines? For example:
0123456789 aaa.aaa3456
aaaaabbbbbbbxxxxxxxwwww
Into
01234;56789 ;aaa.aaa;3456
aaaaa;bbbbbbb;xxxxxxx;wwww
.. but if it does have fixed lengths you can do it this way:
$ sed -r 's/^(.{5})(.{7})(.{7})(.{4})$/\1;\2;\3;\4/' test.txt
01234;56789 ;aaa.aaa;3456
aaaaa;bbbbbbb;xxxxxxx;wwww
I think .{5} is self explanatory. Due to the -r option the first group (.{5}) can be referenced by \1. It's a group due to ( and ).
The characters ^ and $ represent the beginning and ending of every line in the file test.txt.
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This is my text file and I want to remove every first line:
aaaa
bbbb/bbbb
/cccc/cccc
/Dddd/zzzz/wwww
.gggg
.oooo/sssss
/.vvvvv
!#%#/$%
How can I remove all first "/" from my text file?
I want the result text file to be like:
aaaa
bbbb/bbbb
cccc/cccc
Dddd/zzzz/wwww
.gggg
.oooo/sssss
.vvvvv
!#%#/$%
if it's any help, I'm using sed command.
sed can be instructed to replace the first / of each line with nothing:
sed 's_^/__' 'my text file name'
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I have lots of different strings that look like redhat-ubi-ubi7-7.8
I want to use the string to make variables so that I end up having something like
vendor=redhat
product=ubi
image=ubi7
tag=7.8
How can I do this?
With bash and a here string:
string='redhat-ubi-ubi7-7.8'
IFS=- read -r vendor product image tag <<< "$string"
echo "$vendor"
Output:
redhat
Using P.E. parameter expansion.
string='redhat-ubi-ubi7-7.8'
vendor=${string%%-*}
tag=${string##*-}
image=${string%-*}
product=${image#*-}
product=${product%-*}
image=${image##*-}
printf '%s\n' vendor=$vendor product=$product image=$image tag=$tag
Output
vendor=redhat
product=ubi
image=ubi7
tag=7.8
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I have many tsv files that are headerless, and would like to add the same header to each of them. How can I do this through the terminal or bash?
Thanks!
sed -i '1i \here comes header' files
files could be glob exp, like *.txt
Assume you have header in "head", tsv files as "body", how about cat head body | tee body