Allowing a wget to run as part of a command line parameter - bash

I'm writing a little script that takes several command line arguments and substitutes their values into some files.
I have a requirement where the user can either specify a file on their machine, or fetch it over http(s), but the problem is my script eats up the wget as a parameter, and doesn't actually execute it.
Here's what I'm using to parse the arguments:
while [[ "$#" -gt 0 ]] ; do
if [[ "$1" == '--ip-address' ]] ; then
shift
ip_address="$1"
fi
if [[ "$1" == '--hostname' ]] ; then
shift
hostname="$1"
fi
shift
done
What I'm looking for is something like
script.sh --file wget http://foo.bar/file.txt and it would first download the file and then pass it as a parameter.

What about something like:
if [[ "$1" == '--file' ]] ; then
shift
filename="$1"
if [ `echo $filename|grep '://'` != "" ]; then
wget --no-check-certificate -O /tmp/file "$filename"
filename=/tmp/file
fi
fi

Related

Run commands on same line as [[ ]] operator

I am attempting to use the [[ ]] operator in Bash and failing badly.
My script is:
#!/bin/bash
# Test driver for the ProtectDatae script
set -o xtrace
# [[ -z "$1" ]] || source="$1" && source=""
if [[ -z "%1" ]]
then
source=""
else
source=$1
fi
[[ -z "$2" ]] || target="$2" && target="" # This does not work
[[ -z "$3" ]] || sourceBackup="$3" && sourceBackup="/tmp/sourcebackup" # This does not work
source cmd.sh # Get a function to run a Linux command
if [[ -e "$sourceBackup" && "$sourceBackup" -ne "" ]]
then
# If a source backup directory is specified then get rid of any old directory and make a new backup
# and verify it. If OK, make the source directory be the source backup directory
# otherwise work directly in the source directory
if [[ -e "$sourceBackup" ]]
then
cmd "sudo rm -R $sourceBackup" "empty backup directory $sourceBackup failed"
cmd "cp -apu $source $sourceBackup" "backup home directory"
cmd "diff -aprN ~/$source/* $sourceBackup" "bad backup in $sourceBackup"
source="$sourceBackup"
fi
fi
exit 0
My command invocation is ./TestProtectData.sh "~" /tmp/jfghome /tmp/jfgbackup
The result of xtrace is:
+ source='~'
+ [[ -z /tmp/jfghome ]]
+ target=/tmp/jfghome
+ target=""
+ [[ -z /tmp/jfgbackup ]]
+ sourceBackup=/tmp/jfgbackup
+ sourceBackup=/tmp/sourcebackup
+ source cmd.sh
+ [[ -e /tmp/sourcebackup ]]
+ exit 0
What happens with the following line is the error. Both alternatives appear to be executed and the variable winds up being set incorrectly:
[[ -z "$2" ]] || target="$2" && target=""
I have tried both orders for && and || and they both give the same result with the variable target set to blank. On the next line, a similar thing happens with the variable sourceBackup set to the second alternative, and both alternatives appear to be executed. If I use the if then construct it works. What am I doing wrong?
What am I doing wrong?
Your intended logic doesn't match the bash constructs you're using. This line:
[[ -z "$2" ]] || target="$2" && target="" # This does not work
Breaks down to mean if 2 is not empty set target to $2. If that command succeeds, set target to "". The command to the left of && will always succeed - either the -z test succeeds or the target="$2" succeeds. Thus target="" always runs at the end.
You can use if ... ; then ...; else ...; fi or you can look at these ways to effect a ternary operator in bash, including:
#!/bin/bash -e
[[ -z "$3" ]] && sourceBackup="/tmp/sourcebackup" || sourceBackup="$3"
echo $sourceBackup
% ./t.sh 1 2 3
3
Here, if -z test succeeds we set sourceBackup to the default. If the test fails, $3 is not null and we set sourceBackup to $3.
To reiterate, this is not exactly the same as a tertiary operator. But if you get the order correct, it will work.
A plain assignement (foo=bar) always sets the status code to 0, so after target has been set to $2, it is immediately after set to empty. I would start by turning the logic inside out:
target= # Set to empty string
[[ -z $2 ]] && target=$2
However, this is redundant. You could easier simply just write
target=$2
without doing any [[...]]-test. If the second parameter is empty, target will be empty as well. If it is not empty, target will get that value.
There is one point to consider: In case you decide to turn on set -u, to catch uninitialized variables, a target=$2 would abort the script if there is no second parameter. Therefore, you could also write
target=${2:-}
which tells bash that a missing parameter is OK and should be treated as a null string.
Even though it is redundant, if you do not turn on -u, using ${2:-} shows your intent explicitly, and makes your program more maintainable.

How do I use round brackets in an 'if' condition

I'm creating a bash script and somewhere inside I have this code:
if [ $# -eq 2 -a (! -r "$2" -o ! -f "$2") ]; then
echo "rvf: bestand \""$2"\" bestaat niet of is onleesbaar" 1>&2
exit 2
fi
When i try to run this inside the script I get this error:
Syntax Error (bash -n):
rvf: line 14: syntax error in conditional expression
rvf: line 14: syntax error near `-a'
rvf: line 14: `if [[ $# -eq 2 -a (! -r "$2" -o ! -f "$2") ]]; then'
How does '()' work inside Bash scripts?
[[ doens't support -a, and it is considered obsolete and non portable for [. The correct solution using [ would be
if [ "$#" -eq 2 ] && { [ ! -r "$2" ] || [ ! -f "$2" ]; }; then
Grouping is done with { ... } rather than ( ... ) to avoid creating an unnecessary subshell.
Using [[ is simplifies to
if [[ "$#" -eq 2 && ( ! -r "$2" || ! -f "$2" ) ]]; then
Parentheses can be used for grouping inside [[; as a compound command, it uses separate parsing and evaluation rules, compared to an ordinary command like [ (which is just an alias for test, not syntax of any kind).
In either case, De Morgan's laws lets you refactor this to something a little simpler:
if [ "$#" -eq 2 ] && ! { [ -r "$2" ] && [ -f "$2" ] }; then
if [[ "$#" -eq 2 && ! ( -r "$2" && -f "$2" ) ]]; then
There are multiple points of confusion here.
[ can (as an optional XSI extension to the standard) support ( as a separate word (meaning there needs to be spaces around it), but the POSIX sh specification marks it (like -a and -o) as "obsolescent" and advises against its use.
[[ does support (, but again, it needs to always be a separate word.
Don't do that at all, though. You're using only well-supported and portable functionality if you keep each test its own simple command and combine them only with the shell's boolean logic support.
That is:
if [ "$#" -eq 2 ] && { [ ! -r "$2" ] || [ ! -f "$2" ]; }; then
echo "rvf: bestand \"$2\" bestaat niet of is onleesbaar" >&2
exit 2
fi
Restructure your logic.
"Not A or Not B" is just a more complicated way to say "not (A and B)".
In bash, try
if [[ "$#" == 2 ]] && ! [[ -r "$2" && -f "$2" ]]; then
Better,
if [[ "$#" == 2 && -r "$2" && -f "$2" ]]
then : all good code
else : nope code
fi
Even better,
if [[ "$#" == 2 ]] # correct args
then if [[ -r "$2" ]] # is readable
then if [[ if -f "$2" ]] # is a file
then echo "all good"
: do all good stuff
else echo "'$2' not a file"
: do not a file stuff
fi
else echo "'$2' not readable"
: do not readable stuff
fi
else echo "Invalid number of args"
: do wrong args stuff
fi
Clear error logging is worth breaking the pieces out.
Even better, imho -
if [[ "$#" != 2 ]]
then : wrong args stuff
fi
if [[ ! -r "$2" ]]
then : unreadable stuff
fi
if [[ ! -f "$2" ]]
then : do not a file stuff
fi
: do all good stuff

Bash - build URL query string by parsing script command arguments

I don't use Bash very frequently but I need to work on a bit of Bash that has to make a curl request to a web service with a query string tail built from command arguments contained in the script command arguments variable $#. So if the command argument string is something like -e something -v -s somethingelse, then the query string that must be produced is e=something&v=blank&s=somethingelse.
At the moment my test script looks like this:
#!/bin/bash
set -e
echo "${#}"
query_string=""
for arg in "${#}" ; do
if [[ "${arg}" =~ "-" ]] ; then
query_string+="${arg}="
else
if [ -z "${arg}" ] ; then
query_string+="blank&"
else
query_string+="${arg}&"
fi
fi
done
echo "${query_string}" | tr -d '-'
and produces the incorrect output
e=something&v=s=somethingelse&
I'm not sure where I'm going wrong. Any suggestions would be appreciated.
How about:
#!/bin/bash
set -e
echo "${#}"
option=true
query_string=""
for arg in "${#}" ; do
if $option ; then
query_string+="${arg}="
option=false
else
if [[ "${arg}" =~ "-" ]] ; then
query_string+="blank&${arg}="
else
query_string+="${arg}&"
option=true
fi
fi
done
echo "${query_string::-1}" | tr -d '-'
Every iteration you have to check the previous arg to see if it was a switch, not a value:
#!/bin/bash
set -e
echo "${#}"
prev_arg=""
query_string=""
for arg in "${#}" ; do
if [[ $arg == -* ]] ; then
# Current arg is a switch and the previous one was also a switch
# which means the value for it is blank
if [[ $prev_arg == -* ]] ; then
query_string+="blank&"
fi
query_string+="${arg}="
else
query_string+="${arg}&"
fi
prev_arg="$arg"
done
echo "${query_string::-1}" | tr -d '-'
This produces the following output:
something -v -s somethingelse
e=something&v=blank&s=somethingelse

How to check if arguments are legit?

I have to write a bash script which will count all the commands in a text file. Arguments to a script are -p, -n num, and a file. This means that commands like:
script.sh -n 3 -p file.txt
script -p -n 3 file.txt
and similar are all legit.
However, I have to echo an error for any commands that are not similar to this: script.sh -n -k file.txt for example.
Here is a link to my code.
I managed to make it work, but it is way too long and redundant. Is there a way I can do this in a short way?
You may want to have a look at one of the following standard commands:
getopts is a Bash builtin. It is newer and simple to use, but does not support long options (--option).
getopt is an external program which may involve a little more glue code. There are different implementations. getopt usually supports long options.
This is a small getopts example (modified one of the examples from this external site):
#!/bin/bash
flag=off
dir=
# iterate over each option with getopts:
while getopts fd: opt
do
case "$opt" in
f) flag=on;;
d) dir="$OPTARG";;
*) echo >&2 "usage: $0 [-f] [-d directory] [file ...]"
exit 1;;
esac
done
# remove all positional pararmeters we already
# handled from the command line:
shift $(( expr $OPTIND - 1 ))
# main part of your program, remaining arguments are now in
# $# resp. $0, $1, ...
I'd like to suggest another snippet that is a lot simpler to read than yours, because it exactly depicts the only two valid cases you specified in your comment:
If I want to "call" my script it has to look like this: script.sh -n +number -p file.txt. file.txt must be the last argument, however, -n and -p can be switched.
So the cases are ($0 to $4):
script.sh -n +number -p file.txt
script.sh -p -n +number file.txt
It uses only if and Bash's logical operators:
#!/bin/bash
if ! { [[ "$1" = "-n" ]] && [[ "$2" =~ ^-[0-9]+$ ]] && [[ "$3" = "-p" ]] && [[ "$4" =~ ".txt"$ ]] ; } &&
! { [[ "$2" = "-n" ]] && [[ "$3" =~ ^-[0-9]+$ ]] && [[ "$1" = "-p" ]] && [[ "$4" =~ ".txt"$ ]] ; }
then
echo "Error" && exit 1
fi
Notes:
The group ({, }) syntax expects a ; at the end of its list.
You have to use a regex to check for *.txt
The number regex you gave will require the number to start with a -, while in your specification you say +.

getops still performs default actions when arguments are provided

I've recently started working with the getopts command in bash. I am confused as to why my script runs the dafult action "cat ~bin/Temp/log.txt | ~bin/Scripts/report.pl" when arguments have been provided. I only want that to run if no arguments were passed to the shell script. I've used getopts:Std in perl where I was able to code somthing like:
unless ($opts{d}) {
do something...}
How would I code something like that in a shell script? Also, how would I code logic such as this:
if ($opts{c}) {
cat ~bin/Temp/mag.txt | ~bin/Scripts/report.pl -c
}
elsif ($opts{d} {
cat ~bin/Temp/mag.txt | ~bin/Scripts/report.pl -d
My code:
#!/bin/sh
while getopts cd name
do
case $name in
c)copt=1;;
d)dopt=1;;
*)echo "Invalid arg";;
esac
done
if [[ ! -z $copt ]] #Specifies what happens if the -c argument was provided
then
echo "CSV file created!"
cat "~/bin/Temp/log.txt" | ~/bin/Scripts/vpnreport/report.pl -c
fi
if [[ ! -z $dopt ]] #Specifies what happens if the -d argument was provided
then
echo "Debug report and files created"
cat ~bin/Temp/mag.txt | ~bin/Scripts/report.pl -d
fi
if [[ ! -z $name ]] #Specifies what happens if no argument was provided
then
echo "Running standard VPN report"
cat ~bin/Temp/log.txt | ~bin/Scripts/report.pl
fi
shift $(($OPTIND -1))
My Output:
[~/bin/Scripts/report]$ sh getoptstest.sh
Running standard report
[~/bin/Scripts/report]$ sh getoptstest.sh -d
Debug report and files created
Running standard report
[~/bin/Scripts/report]$
The two getopts commands are vasty different from bash to perl and I just can't seem to get the hang of the bash varient even after reading several tutorials. Any help would be greatly appreciated!
On the final run of getopts, your variable (name) will be set to "?".
#!/bin/bash
while getopts abc foo; do :; done
echo "<$foo>"
Output of the above:
$ ./mytest.sh
<?>
$ ./mytest.sh -a
<?>
Insead, use elif, which is like Perl's elsif:
if [[ ! -z $copt ]]
then
# ...
elif [[ ! -z $dopt ]]
then
# ...
else
# ...
fi
Or test if [[ -z $copt && -z $dopt ]], or so forth. Other notes:
See the official if and case documentation in the Bash manual under "Conditional Constructs".
[[ ! -z $name ]] means the same as the more-direct [[ -n $name ]].
Use #!/bin/bash instead of #!/bin/sh, or switch off of [[ in favor of [. The double square bracket (and your use thereof) is specific to bash, and rarely works with sh.
I took Jeff's answer and rewrote my script so it works now:
#!/bin/bash
while getopts cd name
do
case $name in
c)carg=1;;
d)darg=1;;
*)echo "Invalid arg";;
esac
done
#Specifies what happens if the -c argument was provided:
if [[ ! -z $carg ]]
then
if [[ -z $darg ]]
then
echo "CSV created"
cat ~bin/Temp/log.txt | ~bin/Scripts/report.pl -c
else
echo "Debug CSV created"
cat ~bin/Temp/log.txt | ~bin/Scripts/report.pl -cd
fi
fi
#Specifies what happens if the -d argurment was provided:
if [[ ! -z $darg ]]
then
echo "Debug report created"
cat ~bin/Temp/log.txt | ~bin/Scripts/report.pl -d
#Specifies what happens if no argument was provided:
else
echo "Standard report created"
cat ~bin/Temp/logs.txt | ~bin/Scripts/report.pl
fi
Thank you again for your assistance!

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