Overriding generic.ListView methods for AJAX requests DJANGO - ajax

I recently started using django's inbuilt generic views (Create, Update, etc) So I'm updating most of my old views to use them, one of them is the ListView, with pagination. So now, it works right,when i GET that page, it displays the objects as directed, and the pagination works fine. But i want to use AJAX on the pagination so that i just click a "More" button and it gets the next page's objects via ajax and are appended onto the end of the . So i've modified some generic views before to incorporate AJAX like the:
class Delete(LoginRequiredMixin, UserPassesTestMixin, DeleteView):
login_url = LOGIN_URL
model = Items
success_url = reverse_lazy('web:member-area')
def test_func(self):
return not self.request.user.is_superuser and self.get_object().created_by == self.request.user
def delete(self, request, *args, **kwargs):
response = super().delete(request)
if self.request.is_ajax():
return JsonResponse({'success': 1}, status=200)
else:
return response
In the above snippet you can see i included the part where it returns something different if the request is AJAX
The current View that i'm working on is as follows:
class Items(ListView):
model = Items
paginate_by = 5
context_object_name = 'items'
template_name = 'web/items/index.html'
which works fine on normal GET requests, so the problem is i dont know which super() method(s) to override and return a different response if its AJAX on that ListView

Use dispatch
class Items(ListView):
def dispatch(request, *args, **kwargs):
response = super().dispatch(request, *args, **kwargs)
if request.is_ajax():
return JsonResponse({'success': 1}, status=200)
else:
return response

Related

Is there a way to use inheritance in django viewsets or do I have to rewrite the functions?

I am writting an API in Django Rest Framework. I am using viewsets however regular methods create() and update() do not do it for me and I have to rewrite them.
Suppose that I need to do just one check to test if creation of an instance is legit, do I still have to rewrite the whole create function?
Currently I have this:
class LocationViewSet(viewsets.ModelViewSet):
permission_classes = (IsAuthenticated,)
serializer_class = LocationSerializer
def create(self, request, *args, **kwargs):
user = request.user
serializer = self.get_serializer(data=request.data)
serializer.is_valid(raise_exception=True)
if user.can_create_location():
serializer.save()
return Response(serializer.data)
else:
raise exceptions.PermissionDenied('You dont have permission to create this.')
Instead of rewritting the whole thing, is it possible to somehow use inheritance and do something like this?
class LocationViewSet(viewsets.ModelViewSet):
permission_classes = (IsAuthenticated,)
serializer_class = LocationSerializer
def create(self, request, *args, **kwargs):
user = request.user
if user.can_create_location():
return super().create(self, request, *args, **kwargs)
else:
raise exceptions.PermissionDenied('You dont have permission to create this.')
The above does not work as I get this error. I feel like this should be possible to do, but I don't know how. Thanks for your help!
AttributeError at /api/0/location
LocationViewSet' object has no attribute 'data'
Request Method: POST
Request URL: http://127.0.0.1:8000/api/0/location
Django Version: 2.1.7
Yes, it does work, and you're doing it almost correctly... as per your error: the function is trying to access LocationViewSet.data as you're passing self in the first argument, change that call to:
super().create(request, *args, **kwargs)
Python standard docs has some info on super() and a link to a more in depth explanation.

Django - Custom decorator to allow only ajax request

I have few views in my project which are called only by ajax and I need to put in a check that the views are processed only if the request is ajax. So I thought of writing a decorator. Upon searching for similar type of decorators I hit upon few but couldn't understand anything.
I make use of class based views and will use this decorator on get/post methods. I did find few snippets but all were written for function based views which made it more difficult for me to understand as I have never worked upon function based views.
I just need to know what is idea behind decorators and how it works.
from functools import wraps
from django.core.exceptions import PermissionDenied
def require_ajax(view):
#wraps(view)
def _wrapped_view(request, *args, **kwargs):
if request.is_ajax():
return view(request, *args, **kwargs)
else:
raise PermissionDenied()
return _wrapped_view
After a google search I've found this:
from django.http import HttpResponseBadRequest
def ajax_required(f):
"""
AJAX request required decorator
use it in your views:
#ajax_required
def my_view(request):
....
"""
def wrap(request, *args, **kwargs):
if not request.is_ajax():
return HttpResponseBadRequest()
return f(request, *args, **kwargs)
wrap.__doc__=f.__doc__
wrap.__name__=f.__name__
return wrap
Didn't tried it, so you have to try it. The essential part is request.is_ajax() which checks if the request is made through AJAX. Check also the docs for more info on is_ajax() method.
EDIT
To decorate a view class in django see Decorating the class in the documentation. Basically the decorator function wraps a method of the class. So you can use the django #method_decorator() to wrap a method in your decorator function (ajax_required):
#method_decorator(ajax_required)
def method_you_want_to_get_only_AJAX_requests():
......

login_required decorator on ajax views to return 401 instead of 302

While writing some views to respond to ajax requests i find it somewhat strange that the login_required decorator always returns a 302 status code for not authenticated users. As these views are ajax views, this seems somewhat inappropriate. I do not want the user to log in in such a case, but i want Django to tell the client that authentication is required to access such a view (a 401 should be the right status code, i think).
To achieve this, i started to write my own decorator login_required_ajax, but somehow this is beyond my skills. This is what i have come up with so far:
def login_required_ajax(function=None,redirect_field_name=None):
"""
Just make sure the user is authenticated to access a certain ajax view
Otherwise return a HttpResponse 401 - authentication required
instead of the 302 redirect of the original Django decorator
"""
def _decorator(view_func):
def _wrapped_view(request, *args, **kwargs):
if request.user.is_authenticated():
return view_func(request, *args, **kwargs)
else:
return HttpResponse(status=401)
if function is None:
return _decorator
else:
return _decorator(function)
When using this decorator on a view, i get a ViewDoesNotExist exception as soon as i try to access any page on the site.
I first thought that the problem could be the direct return of an HttpResponse when a user is not authenticated, because a response object is not a callable. But then the decorator should work as long as i do not try to access the view in question, shouldn't it? And if this really is the crux, how can i write a decorator that returns a HttpResponse with a status code of 401?
That's a pretty good attempt. Here's a couple of problems I spotted:
Your _decorator function should return _wrapped_view.
The indentation for your if function is None block is a bit off -- the login_required_ajax function needs to return the decorated function.
Here's the decorator with those changes made:
def login_required_ajax(function=None,redirect_field_name=None):
"""
Just make sure the user is authenticated to access a certain ajax view
Otherwise return a HttpResponse 401 - authentication required
instead of the 302 redirect of the original Django decorator
"""
def _decorator(view_func):
def _wrapped_view(request, *args, **kwargs):
if request.user.is_authenticated():
return view_func(request, *args, **kwargs)
else:
return HttpResponse(status=401)
return _wrapped_view
if function is None:
return _decorator
else:
return _decorator(function)

How do I check that user already authenticated from tastypie?

When user authenticates in Django, how do I check that from tastypie?
Once user logs on, the view includes some JS that pulls data from API, which is backed by tastypie.
I have basic authentication/djangoauthorisation set up on my resources, so the browser pops up http auth window. Is there any way to avoid this?
My idea so far is to extend BasicAuthentication so that it first checks session data and when it doesn't find it, it falls back to http auth? AFAIK AJAX calls include session cookies, so this in theory should work? Has anybody done something similar?
I have this solution so far:
class MyBasicAuthentication(BasicAuthentication):
def __init__(self, *args, **kwargs):
super(MyBasicAuthentication, self).__init__(*args, **kwargs)
def is_authenticated(self, request, **kwargs):
from django.contrib.sessions.models import Session
if 'sessionid' in request.COOKIES:
s = Session.objects.get(pk=request.COOKIES['sessionid'])
if '_auth_user_id' in s.get_decoded():
u = User.objects.get(id=s.get_decoded()['_auth_user_id'])
request.user = u
return True
return super(MyBasicAuthentication, self).is_authenticated(request, **kwargs)
which seems to do what I want. If user is logged on, then session contains _auth_user_id, if not, the key is missing.
Anyone can think of any problems this approach may cause?
You may want to check out this ticket on tastypie's GitHub:
https://github.com/toastdriven/django-tastypie/issues/197
The author suggests a very clean approach to authenticate the call with both the session and the API key methods.
There goes the snippet:
class ApiKeyPlusWebAuthentication(ApiKeyAuthentication):
def is_authenticated(self, request, **kwargs):
if request.user.is_authenticated():
return True
return super(ApiKeyPlusWebAuthentication, self).is_authenticated(request, **kwargs)
def get_identifier(self, request):
if request.user.is_authenticated():
return request.user.username
else:
return super(ApiKeyPlusWebAuthentication, self).get_identifier(request)
Once the user is logged in through your API, you have a Django user session. If you want to check if the user is still logged in (on page refresh for example). You can do:
from tastypie.resources import Resource
class LoggedInResource(Resource):
class Meta:
pass
def get_list(self, request, **kwargs):
from django.http import HttpResponse
if request.user.is_authenticated():
return HttpResponse(status=200)
else:
return HttpResponse(status=401)
Client check:
$.ajax({
type: "GET",
url: '/api/loggedin/',
success: function(data) {
// logged in
},
error: function() {
// not logged in
}
});
Pulegium
Why not just as simple as the following:
class CommAuthentication(BasicAuthentication):
def __init__(self, *args, **kwargs):
super(CommAuthentication, self).__init__(*args, **kwargs)
def is_authenticated(self, request, **kwargs):
return request.user.is_authenticated()
I just start to learn tastypie. the above code seemed works for me. Any advantage of your solution ?

How to use Httpresponse in view in django while using Ajax

I am using this
def ajax_create( request ):
if request.is_ajax():
form = SourceForm()
template = 'ajax_form.html'
data = {
'form': form,
}
return render_to_response( template, data,
context_instance = RequestContext( request ) )
I get this error
ajax_create didn't return an HttpResponse object
Are you sure your request is an ajax call ? It doesn't look like it.
Try:
if request.is_ajax():
...
else:
# If the request is not an ajax call, it will return a 400 Error.
return HttpResponseBadRequest()
Perhaps if request.is_ajax(): is returning False, if that's your entire view function?
Typically, you should follow this pattern when making Django view functions:
def my_view(request):
if request.method == 'POST':
form = MyForm(data=request.POST, files=request.FILES)
if form.is_valid():
# do something with form...
else:
initial = {...}
form = MyForm(initial=initial)
context = {'form':form, ...}
return render_to_response('path/to/template.html', context, context_instance=RequestContext(request))
It's not entering to your "if" scope. it returns None
https://docs.djangoproject.com/en/1.3/ref/request-response/#django.http.HttpRequest.is_ajax
Check your ajax call and make sure it returns something in case the request is not ajax

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