I'm trying to assign a variable in bash to the file in this directory with the largest number before the '.tar.gz' and I'm drawing a complete blank on the best way to approach this:
ls /dirname | sort
daily-500-12345.tar.gz
daily-500-12345678.tar.gz
daily-500-987654321.tar.gz
weekly-200-1111111.tar.gz
monthly-100-8675309.tar.gz
sort -Vrt - -k3,3
-V Natural sort
-r Reverse, so you can use head -1 to get the first line only
-t - Use hyphen as field separator
-k3,3 Sort using only the third field
Output:
daily-500-987654321.tar.gz
daily-500-12345678.tar.gz
monthly-100-8675309.tar.gz
weekly-200-1111111.tar.gz
daily-500-12345.tar.gz
I am trying to write a BASH script to sort the contents of a file numerically according to a specific field in the file.
The file is under /etc/group. All of the fields are colon-separated :. I have to sort the contents of /etc/group numerically based on the 3rd field.
Example field: daemon:*:1:root
What I'm trying so far:
#!/bin/bash
sort /etc/group -n | cut -f 3-3 -d ":" /etc/group
This is getting me really close, but it only prints out a sorted list of 3rd field values (since cut literally cuts out the rest of the line). I'm trying to keep the rest of the line but still have it sorted by the 3rd field contents.
You can use sort -t like this:
sort -t : -nk3 /etc/group
-t : tells sort to use field delimiter as :
-nk3 tells sort to sort data numerically on field #3
I have a list of files in a folder.
The names are:
1-a
100-a
2-b
20-b
3-x
and I want to sort them like
1-a
2-b
3-x
20-b
100-a
The files are always a number, followed by a dash, followed by anything.
I tried a ls with a col and sort and it works, but I wanted to know if there's a simpler solution.
Forgot to mention: This is bash running on a Mac OS X.
Some ls implementations, GNU coreutils' ls is one of them, support the -v (natural sort of (version) numbers within text) option:
% ls -v
1-a 2-b 3-x 20-b 100-a
or:
% ls -v1
1-a
2-b
3-x
20-b
100-a
Use sort to define the fields.
sort -s -t- -k1,1n -k2 filenames.txt
The -t tells sort to treat - as the field separator in input items. -k1,1n instructs sort to first sort on the first field numerically; -k2 sorts using the remaining fields as the second key in cade the first fields are equal. -s keeps the sort stable (although you could omit it since the entire input string is being used in one field or another).
(Note: I'm assuming the file names do not contain newlines, so that something like ls > filenames.txt is guaranteed to produce a file with one name per line. You could also use ls | sort ... in that case.)
I have a text file:
$ cat text
542,8,1,418,1
542,9,1,418,1
301,34,1,689070,1
542,9,1,418,1
199,7,1,419,10
I'd like to sort the file based on the first column and remove duplicates using sort, but things are not going as expected.
Approach 1
$ sort -t, -u -b -k1n text
542,8,1,418,1
542,9,1,418,1
199,7,1,419,10
301,34,1,689070,1
It is not sorting based on the first column.
Approach 2
$ sort -t, -u -b -k1n,1n text
199,7,1,419,10
301,34,1,689070,1
542,8,1,418,1
It removes the 542,9,1,418,1 line but I'd like to keep one copy.
It seems that the first approach removes duplicate but not sorts correctly, whereas the second one sorts right but removes more than I want. How should I get the correct result?
The problem is that when you provide a key to sort the unique occurrences are looked for that particular field. Since the line 542,8,1,418,1 is displayed, sort sees the next two lines starting with 542 as duplicate and filters them out.
Your best bet would be to either sort all columns:
sort -t, -nk1,1 -nk2,2 -nk3,3 -nk4,4 -nk5,5 -u text
or
use awk to filter duplicate lines and pipe it to sort.
awk '!_[$0]++' text | sort -t, -nk1,1
When sorting on a key, you must provide the end of the key as well, otherwise sort uses all following keys as well.
The following should work:
sort -t, -u -k1,1n text
I use the following 'grep' command to get the count of the string alert in each of my files at the given path:
grep 'alert' -F /usr/local/snort/rules/* -c
How do I sort the resulting output in desired order- say ascending order, descending order, ordered by name, etc. An answer specific to these cases is sufficient.
You may freely suggest a command other than grep as well.
Pipe it into sort. Assuming your filenames have no colons, use the "-t" option to specify the colon as field saparator. Use -n for numerical sorting.
Example:
grep 'alert' -F /usr/local/snort/rules/* -c | sort -t: -n -k2
should split lines into fields separated by ":", use the second field for sorting, and treat this as numbers (so 21 is actually later than 3).