my data looks like
JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC
22.60 24.60 30.60 34.60 36.20 35.70 32.10 30.20 31.40 31.60 28.00 24.80
25.40 27.60 32.40 34.60 36.50 38.10 31.70 31.40 30.30 30.20 27.00 23.90
and there are like hundreds of rows! I want to find a maximum value in each row and write it in different column next to data along with month
so my out put will be
36.20 MAY
38.10 JUN
.
.
I want to use maxloc function, but i have no idea how to use it!
Try
index = maxloc(myTable(3,:))
print *, myTable((/1,3/), index)
It should select the highest value from the third row and display the first and third value at this index.
Related
I want to display the short name for each month, 12 months back from the previous month, but with the below I get an error on mon1 and mon2 and I guess since that is last year?
mon1=MonthName(Month(Now())-11,1)
mon2=MonthName(Month(Now())-10,1)
mon3=MonthName(Month(Now())-9,1)
mon4=MonthName(Month(Now())-8,1)
mon5=MonthName(Month(Now())-7,1)
mon6=MonthName(Month(Now())-6,1)
mon7=MonthName(Month(Now())-5,1)
mon8=MonthName(Month(Now())-4,1)
mon9=MonthName(Month(Now())-3,1)
mon10=MonthName(Month(Now())-2,1)
mon11=MonthName(Month(Now())-1,1)
mon12=MonthName(Month(Now()),1)
So how can I display now,dec,jan,feb,mar,apr,may,jun,jul,aug,sep,oct
Thanks.
The problem here is the Month() function returns an integer between 1 and 12 to represent each month. Instead you want to minus the number of months from the Now() value before wrapping it with Month().
Below is an example that does this using a For loop and a single dimension Array.
Dim dt: dt = Now()
Dim i, mon(12)
Const numOfMonths = 12
For i = 1 To numOfMonths
mon(i) = MonthName(Month(DateAdd("m", i - numOfMonths, dt)), True)
Next
Call Response.Write(Join(mon, vbCrLf))
Output:
Sep
Aug
Jul
Jun
May
Apr
Mar
Feb
Jan
Dec
Nov
Oct
I would like my watcher to run from Monday to Friday only. So I'm trying to use this schedule:
"trigger": {
"schedule" : { "cron" : "0 0 0/4 * * MON-FRI" }
},
"input": {
...
However, I'm getting
Error
Watcher: [parse_exception] could not parse [cron] schedule
when I'm trying to save the watcher. Removing MON-FRI does helps but I need it.
This expression works:
0 0 0/4 ? * MON-FRI
But I'm not sure I understand why ? is required for either the day_of_week or day_of_month
Thank you!
I believe this is what you are looking for:
"0 0 0/4 ? * MON-FRI"
You can use croneval to check your cron expressions 1:
$ /usr/share/elasticsearch/bin/x-pack/croneval "0 0 0/4 ? * MON-FRI"
Valid!
Now is [Mon, 20 Aug 2018 13:32:26]
Here are the next 10 times this cron expression will trigger:
1. Mon, 20 Aug 2018 09:00:00
2. Mon, 20 Aug 2018 13:00:00
3. Mon, 20 Aug 2018 17:00:00
4. Mon, 20 Aug 2018 21:00:00
5. Tue, 21 Aug 2018 01:00:00
6. Tue, 21 Aug 2018 05:00:00
7. Tue, 21 Aug 2018 09:00:00
8. Tue, 21 Aug 2018 13:00:00
9. Tue, 21 Aug 2018 17:00:00
10. Tue, 21 Aug 2018 21:00:00
For the first expression you'll get following java exception:
java.lang.IllegalArgumentException: support for specifying both a day-of-week AND a day-of-month parameter is not implemented.
You can also use Crontab guru to get human readable descriptions like:
At every minute past every 4th hour from 0 through 23 on every day-of-week from Monday through Friday.
The question mark means 'No Specific value'. From the documentation on Quartz's website:
? (“no specific value”) - useful when you need to specify something in one of the two fields in which the character is allowed, but not the other. For example, if I want my trigger to fire on a particular day of the month (say, the 10th), but don’t care what day of the week that happens to be, I would put “10” in the day-of-month field, and “?” in the day-of-week field. See the examples below for clarification.
http://www.quartz-scheduler.org/documentation/quartz-2.x/tutorials/crontrigger.html
I suppose since you want your schedule to run every 4 hours, mon-fri, the actual day of the month is irrelevant, so the ? specifies that. * on teh other hand would be 'all values' which would not make sense since you are specifying only mon-fri for day of the week.
Hope that helps!
I create a hash with months as keys and timelaps as values
biens_delai[bien_date.mon] = b.delai
I get this result without month parsing
{Wed, 18 Jan 2017=>3.0, Sat, 25 Feb 2017=>2.0, Fri, 17 Mar 2017=>3.0, Sat, 25 Mar 2017=>5.0, Tue, 18 Apr 2017=>2.0, Thu, 29 Jun 2017=>2.0}
In March i have 2 values but when i parse by month i get the most high value and i want a addition of 2 values for March not the most high
{1=>3.0, 2=>2.0, 3=>5.0, 4=>2.0, 6=>2.0}
That's not the high value which you are getting, the values are getting overwritten, try the following
biens_delai[bien_date.mon] = biens_delai[bien_date.mon].to_f + b.delai
I have a collection, that I would like to achieve group by the year and month.
2014
jan
2nd
5th
...
feb
11th
12th
...
mar
...
2013
jan
feb
mar
...
2012
jan
feb
mar
...
this is my current collection but only by year. I couldn't get what I really wanted with this.
$collection =$model->orderBy('date', 'desc')->get()->groupBy(function($item) {
return $item->date->format('Y');
});
Do a Group By on DB::raw('MONTH(your date variable)')
For example, try this:
$model->orderBy('date')->groupBy(DB::raw('MONTH(date)'))->selectRaw('DATE_FORMAT(date, "%M %Y") as Month)->get();
What can i add to this script that will cause it to not print out the duplicate lines from the txt file
The Script is
class TestKeyword
file = File.new("test.txt", "r")
while (line = file.gets)
if line['MAY_DAY']
date = line[/\w+ +\d+ +\d+:\d+:\d+/]
puts "#{date}"
end
end
end
this is the test file:
Oct 15 12:54:01 WHERE IS THE LOVIN MAY_DAY
Oct 16 23:15:44 WHAT THE HECK CAN I DO ABOUT IT HUMP_DAY
Oct 16 14:16:09 I LOVE MY BABY GIRL MAY_DAY
Oct 16 08:25:18 CAN WAIT UNTIL MY BABY RECOVERS CRYSTAL_WIFE
Oct 18 17:48:38 I HOPE HE STOP MESSING WITH THESE FOOLISH CHILDREN TONY_SMITH
Oct 19 05:17:58 GAME TIME GO HEAD AND GET ME MAY_DAY
Oct 20 10:23:33 GAMESTOP IS WHERE ITS AT GAME_DAY
Oct 21 03:54:27 WHAT IS GOING ON WITH MY LUNCH HUNGRY_MAN
Oct 15 12:54:01 WHERE IS THE LOVIN MAY_DAY
Oct 16 23:15:44 WHAT THE HECK CAN I DO ABOUT IT HUMP_DAY
Oct 16 14:16:09 I LOVE MY BABY GIRL MAY_DAY
Oct 16 08:25:18 CAN WAIT UNTIL MY BABY RECOVERS CRYSTAL_WIFE
Oct 18 17:48:38 I HOPE HE STOP MESSING WITH THESE FOOLISH CHILDREN TONY_SMITH
Oct 19 05:17:58 GAME TIME GO HEAD AND GET ME MAY_DAY
Oct 20 10:23:33 GAMESTOP IS WHERE ITS AT GAME_DAY
Oct 21 03:54:27 WHAT IS GOING ON WITH MY LUNCH HUNGRY_MAN
Currently when i execute the script i get the following(which is the date and time of the lines that have the keyword "MAY_DAY":
1: Oct 15 12:54:01
1: Oct 16 14:16:09
1: Oct 19 05:17:58
1: Oct 15 12:54:01
1: Oct 16 14:16:09
1: Oct 19 05:17:58
The output i need is:
1: Oct 15 12:54:01
1: Oct 16 14:16:09
1: Oct 19 05:17:58
Which doesn't have the duplicates
You're going to have to remember what lines you have already output with a little array, e.g.
class TestKeyword
found = []
file = File.new("test.txt", "r")
while (line = file.gets)
if line['MAY_DAY']
date = line[/\w+ +\d+ +\d+:\d+:\d+/]
if !found.include? date
found << date
puts "#{counter}: #{date}"
end
end
end
end
See what I'm doing there? If the date isn't in the array, we add it to it and output the date. Otherwise we ignore it.
Edit: if you want to be a bit more advanced you can use a Set rather than an array. Sets are designed for fast lookup of unique elements. If the only question you want to ask is 'is this element in this set?' and you don't care about order, use a Set. To do that, just change this line:
found = []
To this:
found = Set.new
If the file isn't huge, this will print out the unique lines that match:
file.readlines.select{|l| l.include? "MAY_DAY"}.uniq
It doesn't apply the counter, but that is easily added.