I need to fetch all rows from an oracle sql query and then loop through each rows using PERL.
Below is some sample data and table
create table t1 (col1 varchar2(30));
insert into t1 values ('row1');
insert into t1 values ('row2');
insert into t1 values ('row3');
insert into t1 values ('row4');
insert into t1 values ('row5');
commit;
i have written PERL script like below to fetch above table --
# connexion a la base
my $dbh = DBI->connect( 'dbi:Oracle:'.$dbname,
$dbusername,
$pass,
{ PrintError => 0,
RaiseError => 1
}
) || die "Erreur lors de la connexion: $DBI::errstr";
print ("Connexion à la base de données $dbname avec $dbusername OK \n");
$requete = "select col1 from t1";
$sth_sql = $dbh->prepare($requete);
$sth_sql->execute(#row);
#row=$sth_sql->fetchrow_array;
my $size = #row;
print $size;
#$first=#row[0];
#$sec=#row[1];
print $sec;
print $first;
foreach $script_name (#row) {
print "$script_name\n";
}
the above code is returning only one row and size of the array is showing only 1 element in it.
I need to fetch all fives rows and then loop through them one by one.
please suggest what i am missing here !!
I am using oracle database.
Thanks
EDIT :
I have made some changes and it is working fine now
$requete = "select col1 from t1";
$sth_sql = $dbh->prepare($requete);
$sth_sql->execute();
##row=$sth_sql->fetchrow_array;
$sth_sql->bind_columns(undef, \$script_name);
print $sec;
print $first;
while ($sth_sql->fetch()) {
$script_sql=$script_name.".sql";
print "$script_sql\n";
}
The ->fetchrow_array function is documented in DBI. There you'll see documented that you can either use it within a loop:
$sth = $dbh->prepare("SELECT foo, bar FROM table WHERE baz=?");
$sth->execute( $baz );
while ( #row = $sth->fetchrow_array ) {
print "#row\n";
}
to retrieve all rows sequentially, or that you can use the ->fetchall_arrayref method to retrieve the complete resultset in one go:
$sth = $dbh->prepare("SELECT foo, bar FROM table WHERE baz=?");
$sth->execute( $baz );
my $rows = $sth->fetchall_arrayref;
for my $row (#$rows) {
print "#row\n";
}
Related
Hi I got a db dump from a mysql testdatabase and I want to insert it into an oracle database with the same table structure but I am getting the following error:
[42000][972] ORA-00972: identifier is too long
this is the statement
INSERT INTO aic.keystore (id, alias, keystore_bytes, password, type, description) VALUES (61, 'test', hextoraw(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null);
if I remove the keystore_bytes insertion the insert does complete successfully. So why am I getting an identifier is too long? I haven't any identifiers that exceed 30 characters...
You can have a logic of something like below by using dbms_lob package.
if($stringlen >= 32000) {
for(my $i = 1; $i <= int(($querylen/32000) + 0.99); $i++) {
$temptext = substr($sql, 0 + (32000*($i-1)), 32000);
$sqltext .= "dbms_lob.append(my_sqltext,'$temptext');" . "\n";
}
}
else {
$sqltext = "my_sqltext := '$sql';" . "\n";
}
Once you get the lob you can insert by using dbms_lob.write.
I have a perl code which queries the Oracle 11G database to pull the count of the 'values' from a table.
$sqlStatement="SELECT count(values) FROM Table WHERE values IN ('value1','value2','value3',.... 'valuen')"
How can I pass the values in query through a subroutine's argument?
For example:
$sqlStatement="SELECT count(values) FROM Table WHERE values IN ($values)
subroutine($values)
Wouldn't it make more sense to pass in the values using an array rather than a scalar?
count_values(#values);
Then the subroutine could start like this:
sub count_values {
my #values = #_;
my $sql = 'select count(values) from table where values in (';
$sql .= join ',', ('?') x #values;
$sql .= ')';
my $sth = $dbh->prepare($sql);
$sth->execute(#values);
my $count = ($sth->fetchrow_array)[0];
}
Consider these as my input files,
Input 1: (File 1)
12,23,14,15,9
1,2,3,4,5
34,17,8
.
.
Input 2: (File 2)
12 Twelve
23 TwentyThree
34 ThirtyFour
.
.
I will be reading each line from "Input 1" file using my PIG script and I would like to get the results as below, based on the "Input 2" file.
Output:
Twelve,TwentyThree,Fourteen,Fifteen,Nine
One,Two,Three,Four,Five
.
.
Is it possible to achieve this without UDF ? Please let me know your suggestions.
Thanks in Advance !
This violates your criteria of 'No UDF' but the UDF is built-in so I suspect it will suffice.
Query:
data1 = LOAD 'file1' AS (val:chararray);
data2 = LOAD 'file2' AS (num:chararray, desc:chararray);
A = RANK data1; /* creates row number*/
B = FOREACH A GENERATE rank_data1, FLATTEN(TOKENIZE(val, ',')) AS num;
C = RANK B; /* used to keep tuple elements sorted in bag*/
D = JOIN C BY num, data2 BY num;
E = FOREACH D GENERATE C::rank_data1 AS rank_1:long
, C::rank_B AS rank_2:long
, data2::desc AS description;
grpd = GROUP E BY rank_1;
F = FOREACH grpd {
sorted = ORDER E BY rank_2;
GENERATE sorted;
};
X = FOREACH F GENERATE FLATTEN(BagToTuple(sorted.description));
DUMP X;
Output:
(Twelve,TwentyThree,Fourteen,Fifteen,Nine)
(One,Two,Three,Four,Five)
(ThirtyFour,Seventeen,Eight)
Here is a Hive solution:
--Load the data into Hive
CREATE TABLE file1 (
line array<string>
)
ROW FORMAT DELIMITED
COLLECTION ITEMS TERMINATED BY ',';
LOAD DATA INPATH '/tmp/test2/file1' OVERWRITE INTO TABLE file1;
CREATE TABLE file2 (
name string,
value string
)
ROW FORMAT DELIMITED FIELDS TERMINATED BY ' ';
LOAD DATA INPATH '/tmp/test2/file2' OVERWRITE INTO TABLE file2;
--explode the rows from the first table and create a newid to use for correlation
CREATE TABLE file1_exploded
AS
WITH tmp
AS
(SELECT RAND() newid, line from file1)
SELECT newid, item FROM tmp
LATERAL VIEW EXPLODE (line) a AS item;
--apply substitions using the second table, then join lines back together
SELECT CONCAT_WS(',', COLLECT_LIST(value))
FROM
file1_exploded
JOIN file2 ON item = name
GROUP BY newid;
I tried to send SQL request with LEFT JOIN but it doesn't display data from table2 table.
public static function top($limit)
{
return self::findBySql("
SELECT * FROM table 1 g1
LEFT JOIN table2 s1
ON (g1.id = s1.g_id AND s1.id = (
SELECT MAX(id)
FROM table2 s2 WHERE s2.g_id = g1.id
))
LIMIT :limit",
[':limit' => $limit]
)->all();
}
It seems you are adding this function to the model and self represents the model itself.
Yii will not return results from another table and will be limited to the model only if you are calling the find on a model, instead you need to use a db query as below:
$query = new \yii\db\Query;
$query->select('*')
->from('table 1 g1')
->leftJoin('table2 s1', 's1.g_id AND s1.id = (SELECT MAX(id) FROM table2 s2 WHERE s2.g_id = g1.id')
->limit($Limit);
$command = $query->createCommand();
$resp = $command->queryAll();
The correct SQL query is
SELECT * FROM table 1 g1
LEFT JOIN table2 s1
ON g1.some_field = s1.some_field
where g1.some_field = s1.some_field are the fields that define the join.
I have working code something like...:)
with user and user_friend_list
$query = new Query;
$query ->select(['user.id AS user_id', 'user_friend_list.id'])
->from('user')
->innerJoin('user_friend_list', 'user.email = user_friend_list.email');
$command = $query->createCommand();
$data = $command->queryAll();
foreach($data as $datakey)
{
//echo $datakey['id'];
$friendfind = UserFriendList::findOne($datakey['id']);
$friendfind->is_app_using_user_id=$datakey['user_id'];
$friendfind->save();
}
I have a an sqlite database with the table test. Several processes are accessing this database from bash. The table has the following fields:
CREATE TABLE mytable (id NUMERIC,
start JULIAN,
finish JULIAN)
I obtain an unique id by:
id=$(sqlite test.db <<EOF
BEGIN EXCLUSIVE;
SELECT id FROM mytable WHERE start IS NULL ORDER BY RANDOM() LIMIT 1;
COMMIT;
EOF
)
My question is, how can update the field start with:
UPDATE mytable set start=julianday('now') where id="SELECTED ID FROM ABOVE";
In the same statement?
Based on the comments that you supplied above, my solution would look something like follows (in perl with a raw DBI connection, also i didn't do a lot of error checking or anything either, something that you should probably do):
my $dbh = DBI->connect(...);
$dbh->do("BEGIN EXCLUSIVE");
my $stm = $dbh->prepare("SELECT id FROM mytable WHERE start IS NULL ORDER BY RANDOM() LIMIT 1");
$stm->execute();
my $row = $stm->fetchrow_hashref();
my $id = undef;
if ( $row ) {
$id = $row->{ID};
my $ustm = $dbh->prepare("UPDATE mytable set start=julianday('now') where id=?");
$ustm->execute($id);
}
$dbh->do("COMMIT");
# Still have the id at this point.