Make sort built-in function - makefile

gnu make https://www.gnu.org/software/make/manual/make.html#toc-Functions-for-Transforming-Text has sort function. The description for the sort function states that sort function
Sorts the words of list in lexical order, removing duplicate words. The output is a list of words separated by single spaces.
I created a test makefile like this
TEST="this is a test test test test test"
all:
#echo $(sort $(TEST))
My output is This is a test test
The duplicates were not entirely removed from the string!
Am I interpreting the sort function incorrectly? Or is it a bug with gnu make?

The double quotes are in no way special. So the TEST variable contains the words "This, is, a, test, test, test and test" which are then sorted with duplicate removed as "This, a, is, test and test" and thus the shell gets(1) echo "This a is test test", interprets the double quote as string markers and outputs This a is test test (and not This is a test test see the place of the a).
(1) A useful tip to debug make issue like this is to set the SHELL variable to /bin/echo so you can see what the shell gets. For instance you'd have had as a result -c echo "this a is test test" with the Makefile
TEST="this is a test test test test"
SHELL=/bin/echo
all:
#echo $(sort $(TEST))

Related

GNU Make - Variable Expansion in Recipes

Say in the working directory, I have:
$ find . | grep testfile
./testfile1
This is my Makefile:
list_files:
#echo "Show Files..."
#echo $(shell find . | grep testfile)
#touch testfile2
#echo $(shell find . | grep testfile)
#rm testfile2
With make, I got this:
$ make list_files
Show Files...
./testfile1
./testfile1
Why this happened? I expected it to be something like this:
Show Files...
./testfile1
./testfile1 ./testfile2
Then my question is:
Why all the variables/function in recipes inside a rule, are expanded likely simultaneously after target is invoked?
I have found an explanation from this answer that is pretty close to the truth:
The reason your attempt doesn't work is that make will evaluate all lines of the recipe before it starts the first line.
But there is no references provided there, I just cannot convinced myself of this working mechanism of GNU Make.
Could anyone give some clues? Thanks!
Why this happened?
Because, with one caveat that does not apply to your case, make functions such as $(shell ...) are evaluated when the makefile is parsed, not during the execution of recipes.
Why all the variables/function in recipes inside a rule, are expanded likely simultaneously after target is invoked?
They're not. They are expanded before the target's recipe runs. In fact, before make even determines whether the recipe should be run.
But there is no references provided
This is covered in the manual. See in particular section 8.14, The shell function:
The commands run by calls to the shell function are run when the function calls are expanded (see How make Reads a Makefile).
... which refers to section 3.7, How make Reads a Makefile, in particular:
GNU make does its work in two distinct phases. During the first phase it reads all the makefiles, included makefiles, etc. and internalizes all the variables and their values and implicit and explicit rules, and builds a dependency graph of all the targets and their prerequisites. During the second phase, make uses this internalized data to determine which targets need to be updated and run the recipes necessary to update them.
It also relies on section 8.1, Function Call Syntax:
A function call resembles a variable reference. It can appear anywhere a variable reference can appear, and it is expanded using the same rules as variable references.
"The same rules" of course includes the rules for when expansions are performed.
Your recipes should be written in the language of the target shell, usually /bin/sh. All make functions and variable references in each recipe will be expanded before any recipe runs, so their expansions cannot reflect the results of running any recipe during the current make run. It's particularly peculiar to try to use the $(shell ...) function to do that, because you can just use shell code directly in a recipe.
As explained in the comments, all $(shell ...) and other functions are executed (expanded) before executing any lines from the recipe. But you can delay the expansion:
list_files:
#echo "Show Files..."
#echo $$(shell find . | grep testfile)
#touch testfile2
#echo $$(shell find . | grep testfile)
#rm testfile2
This yields the expected output. Note the double $$. Make will still expand all variables/functions first before executing the recipe, and remove one of the dollar signs. The expressions will be expanded again, when executing the recipe lines.
Of course, you're better off without the $(shell) in this example. However, it's not inherently a bad idea. Sometimes you need to execute shell commands before expanding other variables, and then $(shell) is the trivial solution.

Multi-line define in GNU make

I'm trying to make sense out of the multi-line define directive of GNU make and I cannot. Example:
define A
1
2
endef
all:
#echo W=$(word 1,$(A))
Running make produces a result I have expected the least:
W=1
make: 2: Command not found
make: *** [all] Error 127
It appears that part of $(A) has spilled outside the $(word) function.
Is it a bug or intended behavior? If the "spill" is intentional, how does it really works?
P.S. GNU make v3.81 on Linux/x64
The thing to remember here is that make stores each recipe as a single recursive variable. At the point that make decides that it must run your recipe, it expands that variable. Make then passes each line in the resulting expansion to a separate shell, stopping if any of those shell executions return an error.
In your example, before running anything make expands #echo W=$(word 1,$(A)).
$(A) becomes 1¶2 (dunno what this looks like on your browser, but I'm using ¶ to represent a newline character)
Now, 1¶2 is a single word as far as make is concerned, so $(word 1,1¶2) naturally expands to 1¶2 (can you see where this is going yet?)
This leaves make with the string #echo W=1¶2. Make dutifully passes the first line of this to the shell (without the # as that is special to make). The shell executes echo W=1.
make executes 2 in a new shell.
The second shell complains that it can't find the command 2.
So, yes, expected behaviour.
[Warning: slight simplification in the above where I gloss over the bit where make is able to elide the shell and invoke the command itself if the string has no shell metacharacters in it]
The $(word) function is splitting on spaces. Not whitespace, spaces.
There are no spaces in your A macro so nothing gets split.
Add a trailing space on the 1 line or a leading space on the 2 line and you get your expected behaviour.
This is consistent across GNU make 3.81, 3.82, 4.0, and 4.1 in some quick testing here.
The reason you see the "spill" as you called it is because of how the define is expanded. It is expanded literally, newline and all. (Think template expansion.)
So make expands the define into the call to $(word 1,...) then expands that result (the whole define including the newline) into the recipe template and ends up with two lines that it executes as the recipe.
Consider a macro like this:
define somecommands
echo foo
echo bar
echo baz
endef
all:
$(somecommands)
What would you expect to happen here? How many lines is the body of all? How many shells are run here? What commands are executed? The answer is three lines, three shells and three echo commands.
If the newlines weren't counted then you would effectively run echo foo echo bar echo baz in one command and get foo echo bar echo baz as output instead of the expected (and far more useful) foo, bar, and baz on three different lines.

How to print out a variable in makefile

In my makefile, I have a variable 'NDK_PROJECT_PATH', my question is how can I print it out when it compiles?
I read Make file echo displaying "$PATH" string and I tried:
#echo $(NDK_PROJECT_PATH)
#echo $(value NDK_PROJECT_PATH)
Both gives me
"build-local.mk:102: *** missing separator. Stop."
Any one knows why it is not working for me?
You can print out variables as the makefile is read (assuming GNU make as you have tagged this question appropriately) using this method (with a variable named "var"):
$(info $$var is [${var}])
You can add this construct to any recipe to see what make will pass to the shell:
.PHONY: all
all: ; $(info $$var is [${var}])echo Hello world
Now, what happens here is that make stores the entire recipe ($(info $$var is [${var}])echo Hello world) as a single recursively expanded variable. When make decides to run the recipe (for instance when you tell it to build all), it expands the variable, and then passes each resulting line separately to the shell.
So, in painful detail:
It expands $(info $$var is [${var}])echo Hello world
To do this it first expands $(info $$var is [${var}])
$$ becomes literal $
${var} becomes :-) (say)
The side effect is that $var is [:-)] appears on standard out
The expansion of the $(info...) though is empty
Make is left with echo Hello world
Make prints echo Hello world on stdout first to let you know what it's going to ask the shell to do
The shell prints Hello world on stdout.
As per the GNU Make manual and also pointed by 'bobbogo' in the below answer,
you can use info / warning / error to display text.
$(error text…)
$(warning text…)
$(info text…)
To print variables,
$(error VAR is $(VAR))
$(warning VAR is $(VAR))
$(info VAR is $(VAR))
'error' would stop the make execution, after showing the error string
from a "Mr. Make post"
https://www.cmcrossroads.com/article/printing-value-makefile-variable
Add the following rule to your Makefile:
print-% : ; #echo $* = $($*)
Then, if you want to find out the value of a makefile variable, just:
make print-VARIABLE
and it will return:
VARIABLE = the_value_of_the_variable
If you simply want some output, you want to use $(info) by itself. You can do that anywhere in a Makefile, and it will show when that line is evaluated:
$(info VAR="$(VAR)")
Will output VAR="<value of VAR>" whenever make processes that line. This behavior is very position dependent, so you must make sure that the $(info) expansion happens AFTER everything that could modify $(VAR) has already happened!
A more generic option is to create a special rule for printing the value of a variable. Generally speaking, rules are executed after variables are assigned, so this will show you the value that is actually being used. (Though, it is possible for a rule to change a variable.) Good formatting will help clarify what a variable is set to, and the $(flavor) function will tell you what kind of a variable something is. So in this rule:
print-% : ; $(info $* is a $(flavor $*) variable set to [$($*)]) #true
$* expands to the stem that the % pattern matched in the rule.
$($*) expands to the value of the variable whose name is given by by $*.
The [ and ] clearly delineate the variable expansion.
You could also use " and " or similar.
$(flavor $*) tells you what kind of variable it is. NOTE: $(flavor)
takes a variable name, and not its expansion.
So if you say make print-LDFLAGS, you get $(flavor LDFLAGS),
which is what you want.
$(info text) provides output.
Make prints text on its stdout as a side-effect of the expansion.
The expansion of $(info) though is empty.
You can think of it like #echo,
but importantly it doesn't use the shell,
so you don't have to worry about shell quoting rules.
#true is there just to provide a command for the rule.
Without that,
make will also output print-blah is up to date. I feel #true makes it more clear that it's meant to be a no-op.
Running it, you get
$ make print-LDFLAGS
LDFLAGS is a recursive variable set to [-L/Users/...]
All versions of make require that command lines be indented with a TAB (not space) as the first character in the line. If you showed us the entire rule instead of just the two lines in question we could give a clearer answer, but it should be something like:
myTarget: myDependencies
#echo hi
where the first character in the second line must be TAB.
#echo $(NDK_PROJECT_PATH) is the good way to do it.
I don't think the error comes from there.
Generally this error appears when you mistyped the intendation : I think you have spaces where you should have a tab.
No need to modify the Makefile.
$ cat printvars.mak
print-%:
#echo '$*=$($*)'
$ cd /to/Makefile/dir
$ make -f ~/printvars.mak -f Makefile print-VARIABLE
Run make -n; it shows you the value of the variable..
Makefile...
all:
#echo $(NDK_PROJECT_PATH)
Command:
export NDK_PROJECT_PATH=/opt/ndk/project
make -n
Output:
echo /opt/ndk/project
This makefile will generate the 'missing separator' error message:
all
#echo NDK_PROJECT_PATH=$(NDK_PROJECT_PATH)
done:
#echo "All done"
There's a tab before the #echo "All done" (though the done: rule and action are largely superfluous), but not before the #echo PATH=$(PATH).
The trouble is that the line starting all should either have a colon : or an equals = to indicate that it is a target line or a macro line, and it has neither, so the separator is missing.
The action that echoes the value of a variable must be associated with a target, possibly a dummy or PHONEY target. And that target line must have a colon on it. If you add a : after all in the example makefile and replace the leading blanks on the next line by a tab, it will work sanely.
You probably have an analogous problem near line 102 in the original makefile. If you showed 5 non-blank, non-comment lines before the echo operations that are failing, it would probably be possible to finish the diagnosis. However, since the question was asked in May 2013, it is unlikely that the broken makefile is still available now (August 2014), so this answer can't be validated formally. It can only be used to illustrate a plausible way in which the problem occurred.
The problem is that echo works only under an execution block. i.e. anything after "xx:"
So anything above the first execution block is just initialization so no execution command can used.
So create a execution blocl
If you don't want to modify the Makefile itself, you can use --eval to add a new target, and then execute the new target, e.g.
make --eval='print-tests:
#echo TESTS $(TESTS)
' print-tests
You can insert the required TAB character in the command line using CTRL-V, TAB
example Makefile from above:
all: do-something
TESTS=
TESTS+='a'
TESTS+='b'
TESTS+='c'
do-something:
#echo "doing something"
#echo "running tests $(TESTS)"
#exit 1
This can be done in a generic way and can be very useful when debugging a complex makefile. Following the same technique as described in another answer, you can insert the following into any makefile:
# if the first command line argument is "print"
ifeq ($(firstword $(MAKECMDGOALS)),print)
# take the rest of the arguments as variable names
VAR_NAMES := $(wordlist 2,$(words $(MAKECMDGOALS)),$(MAKECMDGOALS))
# turn them into do-nothing targets
$(eval $(VAR_NAMES):;#:))
# then print them
.PHONY: print
print:
#$(foreach var,$(VAR_NAMES),\
echo '$(var) = $($(var))';)
endif
Then you can just do "make print" to dump the value of any variable:
$ make print CXXFLAGS
CXXFLAGS = -g -Wall
You could create a vars rule in your make file, like this:
dispvar = echo $(1)=$($(1)) ; echo
.PHONY: vars
vars:
#$(call dispvar,SOMEVAR1)
#$(call dispvar,SOMEVAR2)
There are some more robust ways to dump all variables here: gnu make: list the values of all variables (or "macros") in a particular run.
if you use android make (mka) #echo $(NDK_PROJECT_PATH) will not work and gives you error *** missing separator. Stop."
use this answer if you are trying to print variables in android make
NDK_PROJECT_PATH := some_value
$(warning $(NDK_PROJECT_PATH))
that worked for me
I usually echo with an error if I wanted to see the variable value.(Only if you wanted to see the value. It will stop execution.)
#echo $(error NDK_PROJECT_PATH= $(NDK_PROJECT_PATH))
The following command does it for me on Windows:
Path | tr ; "\n"

How do I process extremely long lists of files in a make recipe?

Because GNU make allows variables to be as large as memory allows, it has no problem building massive dependency lists. However, if you want to actually use these lists of files in a recipe (sequence of shell commands for building a target), you run into a problem: the command might exceed the shell's command line length limit, producing an error such as "Argument list too long".
For example, suppose I want to concatenate several files contained in the list $(INPUTS) to produce a file combined.txt. Ordinarily, I could use:
combined.txt: $(INPUTS)
cat $^ > $#
But if $(INPUTS) contains many thousands of files, as it does in my case, the call to cat is too long and fails. Is there a way to get around this problem in general? It's safe to assume that there exists some sequence of commands that have identical behaviour to the one enormous command -- in this case, a series of cat commands, one per input file, that use >> to append to combined.txt would work. But how can make be persuaded to generate those commands?
In looking for the answer, about the best suggestion I could find was to break up the list into a series of smaller lists and process them using shell for loops. But you can't always do that, and even when you can it's a messy hack: for example, it's not obvious how to get the usual make behaviour of stopping as soon as a command fails. Luckily, after much searching and experimentation, it turns out that a general solution does exist.
Subshells and newlines
make recipes invoke a separate subshell for each line in the recipe. This behaviour can be annoying and counterintuitive: for example, a cd command on one line will not affect subsequent commands because they are run in separate subshells. Nevertheless it's actually what we need to get make to perform actions on very long lists of files.
Ordinarily, if you build a "multiline" list of files with a regular variable assignment that uses backslashes to break the statement over multiple lines, make removes all newlines:
# The following two statements are equivalent
FILES := a b c
FILES := \
a \
b \
c
However, using the define directive, it's possible to build variable values that contain newlines. What's more, if you substitute such a variable into a recipe, each line will indeed be run using a separate subshell, so that for example running make test from /home/jbloggs with the makefile below (and assuming no file called test exists) will produce the output /home/jbloggs, because the effect of the cd .. command is lost when its subshell ends:
define CMDS
cd ..
pwd
endef
test:
$(CMDS)
If we create a variable that contains newlines using define, it can be concatenated with other text as usual, and processed using all the usual make functions. This, combined with the $(foreach) function, allows us to get what we want:
# Just a single newline! Note 2 blank lines are needed.
define NL
endef
combined.txt: $(INPUTS)
rm $#
$(foreach f,$(INPUTS),cat $(f) >> $#$(NL))
We ask $(foreach) to convert each filename into a newline-terminated command, which will be executed in its own subshell. For more complicated needs, you could instead write out the list of filenames to a file with a series of echo commands and then use xargs.
Notes
The define directive is described as optionally taking a =, := or += token on the end of the first line to determine which variable flavour is to be created -- but note that that only works on versions of GNU make 3.82 and up! You may well be running the popular version 3.81, as I was, which silently assigns nothing to the variable if you add one of these tokens, leading to much frustration. See here for more.
All recipe lines must begin with a literal tab character, not the 8 spaces I have used here.

How to assign the output of a command to a Makefile variable

I need to execute some make rules conditionally, only if the Python installed is greater than a certain version (say 2.5).
I thought I could do something like executing:
python -c 'import sys; print int(sys.version_info >= (2,5))'
and then using the output ('1' if ok, '0' otherwise) in a ifeq make statement.
In a simple bash shell script it's just:
MY_VAR=`python -c 'import sys; print int(sys.version_info >= (2,5))'`
but that doesn't work in a Makefile.
Any suggestions? I could use any other sensible workaround to achieve this.
Use the Make shell builtin like in MY_VAR=$(shell echo whatever)
me#Zack:~$make
MY_VAR IS whatever
me#Zack:~$ cat Makefile
MY_VAR := $(shell echo whatever)
all:
#echo MY_VAR IS $(MY_VAR)
Beware of recipes like this
target:
MY_ID=$(GENERATE_ID);
echo $MY_ID;
It does two things wrong. The first line in the recipe is executed in a separate shell instance from the second line. The variable is lost in the meantime. Second thing wrong is that the $ is not escaped.
target:
MY_ID=$(GENERATE_ID); \
echo $$MY_ID;
Both problems have been fixed and the variable is useable. The backslash combines both lines to run in one single shell, hence the setting of the variable and the reading of the variable afterwords, works.
I realize the original post said how to get the results of a shell command into a MAKE variable, and this answer shows how to get it into a shell variable. But other readers may benefit.
One final improvement, if the consumer expects an "environment variable" to be set, then you have to export it.
my_shell_script
echo $MY_ID
would need this in the makefile
target:
export MY_ID=$(GENERATE_ID); \
./my_shell_script;
Hope that helps someone. In general, one should avoid doing any real work outside of recipes, because if someone use the makefile with '--dry-run' option, to only SEE what it will do, it won't have any undesirable side effects. Every $(shell) call is evaluated at compile time and some real work could accidentally be done. Better to leave the real work, like generating ids, to the inside of the recipes when possible.
Wrapping the assignment in an eval is working for me.
# dependency on .PHONY prevents Make from
# thinking there's `nothing to be done`
set_opts: .PHONY
$(eval DOCKER_OPTS = -v $(shell mktemp -d -p /scratch):/output)
With GNU Make, you can use shell and eval to store, run, and assign output from arbitrary command line invocations. The difference between the example below and those which use := is the := assignment happens once (when it is encountered) and for all. Recursively expanded variables set with = are a bit more "lazy"; references to other variables remain until the variable itself is referenced, and the subsequent recursive expansion takes place each time the variable is referenced, which is desirable for making "consistent, callable, snippets". See the manual on setting variables for more info.
# Generate a random number.
# This is not run initially.
GENERATE_ID = $(shell od -vAn -N2 -tu2 < /dev/urandom)
# Generate a random number, and assign it to MY_ID
# This is not run initially.
SET_ID = $(eval MY_ID=$(GENERATE_ID))
# You can use .PHONY to tell make that we aren't building a target output file
.PHONY: mytarget
mytarget:
# This is empty when we begin
#echo $(MY_ID)
# This recursively expands SET_ID, which calls the shell command and sets MY_ID
$(SET_ID)
# This will now be a random number
#echo $(MY_ID)
# Recursively expand SET_ID again, which calls the shell command (again) and sets MY_ID (again)
$(SET_ID)
# This will now be a different random number
#echo $(MY_ID)
Here's a bit more complicated example with piping and variable assignment inside recipe:
getpodname:
# Getting pod name
#eval $$(minikube docker-env) ;\
$(eval PODNAME=$(shell sh -c "kubectl get pods | grep profile-posts-api | grep Running" | awk '{print $$1}'))
echo $(PODNAME)
I'm writing an answer to increase visibility to the actual syntax that solves the problem. Unfortunately, what someone might see as trivial can become a very significant headache to someone looking for a simple answer to a reasonable question.
Put the following into the file "Makefile".
MY_VAR := $(shell python -c 'import sys; print int(sys.version_info >= (2,5))')
all:
#echo MY_VAR IS $(MY_VAR)
The behavior you would like to see is the following (assuming you have recent python installed).
make
MY_VAR IS 1
If you copy and paste the above text into the Makefile, will you get this? Probably not. You will probably get an error like what is reported here:
makefile:4: *** missing separator. Stop
Why: Because although I personally used a genuine tab, Stack Overflow (attempting to be helpful) converts my tab into a number of spaces. You, frustrated internet citizen, now copy this, thinking that you now have the same text that I used. The make command, now reads the spaces and finds that the "all" command is incorrectly formatted. So copy the above text, paste it, and then convert the whitespace before "#echo" to a tab, and this example should, at last, hopefully, work for you.
In the below example, I have stored the Makefile folder path to LOCAL_PKG_DIR and then use LOCAL_PKG_DIR variable in targets.
Makefile:
LOCAL_PKG_DIR := $(shell eval pwd)
.PHONY: print
print:
#echo $(LOCAL_PKG_DIR)
Terminal output:
$ make print
/home/amrit/folder
From the make manual
The shell assignment operator ‘!=’ can be used to execute a shell script and set a >variable to its output. This operator first evaluates the right-hand side, then passes >that result to the shell for execution. If the result of the execution ends in a >newline, that one newline is removed; all other newlines are replaced by spaces. The >resulting string is then placed into the named recursively-expanded variable. For >example:
hash != printf '\043'
file_list != find . -name '*.c'
source

Resources