I'm a beginner in gradle need to implement multi-module spring boot rest micro-services
sample source code:git-hub
when I give a bootRun command
actual:
this task is running only demo1 module so that that rest API I can access
expected
Need to run both demo1 and demo2 project in a different port.
Environment: jdk8, spring-boot 2, gradle 5
This is a Maven project for running multiple Boot projects in different ports within a single JVM.
https://github.com/rameez4ever/springboot-demo/tree/master/springboot-multi-service-launcher
Changing Maven pom.xml to Gradle build.gradle might be sufficient. Hope this gives some idea.
Related
Let's say I have a Gradle Multi Project with 3 subprojects, 2 Spring Boot projects (auth and profile) and 1 Library project (commons).
The 2 Spring Boot projects include a dependency on the Library project: implementation project(":commons")
Actually, to run the 2 Spring Boot projects, I have to run this from the parent project:
gradlew auth:bootRun
gradlew profile:bootRun
If I run gradlew bootRun only, from each Spring Boot subproject, I get the Error like the :commons Library project is not found in the root project, which makes sense, because the :commons project is included only in the parent's settings.gradle file.
I have to push each Spring Boot subproject individually to Heroku.
How should I manage ?
I finally got it, just add this in each subproject's settings.gradle file, then build:
include ":commons"
project(':commons').projectDir = new File('../commons')
I have written application using spring boot + scala with sbt and now I need to divide build configurations for dev and prod.
What has been done: created configs application.yml and application(-dev/prod).yml to start application locally, on dev and prod respectively.
What need to be done: find a way to configure spring boot profile (dev, prod) in javaopts or directly write corresponding config, also in javaopts.
I've tried to use these opts:
sbt service/run -Dspring.profiles.active=...
sbt service/run -Dspring.config.location=...
The answer is to configure active profile like this:
sbt service/run --spring.profiles.active=...
Is there any way to execute the environment variables file .env along with maven commands such as mvn clean install or mvn clean deploy. The main idea behind the concept that I'm looking for similar kind of solution:
mvn clean install -DenvFile=/path/<filename>.env
OR
mvn clean deploy -DenvFile=/path/<filename>.env
OR
mvn clean package -DenvFile=/path/<filename>.env
Note: Not trying to produce the environment specific builds. In dev environment, my intention to run the junit tests with all the
environment variables configured from <filename>.env.
where, the above maven commands should set all the environment variables from <filename>.env and then execute the maven plugins. In IntelliJ, there's a envFile plugin which exactly do the same.
Don't want to have environment specific properties dev|staging|prod.properties in my project because it's messy and hard to manage. I'd rather prefer to have one single environment specific file filename.env which contains all the dynamic/changeable properties.
application.properties
spring:
cloud:
config:
uri: http://config-service:${CONFIG_SERVICE_PORT}
fail-fast: true
password: ${CONFIG_SERVICE_PASSWORD}
username: user
Environment File: .env
CONFIG_SERVICE_PORT=8080
CONFIG_SERVICE_PASSWORD=123
Now when I deploy the application in different environments like AWS, GCP and Azure. All I need to change the environment variables in the .env file and run the application java -DenvFile=/path/<fileName>.env -jar application.jar and it will do the magic.
My problem is related with maven-sure-fire plugin for testing in dev-mode, which require these environments variables for spring context.
Any help would be appreciated.
Ok from your comments it seems like you're looks for two different solutions:
Run the application in different environments with java -DenvFile=/path/<fileName>.env -jar application.jar
Solution for running tests.
These are different issues I'll try to address both
Issue 1
When you run java -jar this means that the artifact is already assembled (with the help of spring boot maven plugin as far as I understand).
This jar is a ready to go spring boot application and maven is basically irrelevant here - maven is a build system, spring is a runtime framework and we're talking about the runtime.
Spring boot has a lot of ways to achieve what you want. A "Native" spring boot way which is close to your situation is running the application with "--spring.config.location=file:// with all the required configurations
It looks like this (see here for complete documentation):
java -jar application.jar --spring.config.location=myprops.properties
Even if you have some properties defined in src/main/resources/application.properties this method allows to override them effectively providing a way to run different configurations in different environments.
This has an advantage over the .env files because it can run in the same way in all the OS-es, even Windows ;) Since Java is OS independent - I believe its the best you can achieve.
Of course you can wrap the java -jar line in some kind of bash script and load / execute a series of export commands before running the jvm, but again, its less "spring-y" way.
Issue 2
Maven runs the tests (unit/integration) in a way that spring boot maven plugin is irrelevant. Its all about surefire/failsafe and spring boot testing framework.
I'll assume you're asking about integration tests because I believe this is all irrelevant for unit tests, since those should not require any environment variables at all and should be run without spring at all (junit/mockito should do the job)
I'll also allow myself to keep the assumption that the way of overriding/configuring the spring boot application via yaml or properties file is better than .env and will provide spring test configuration solution here:
With these assumptions you can create a yaml file in the following path: src/test/resources/application-test.yml
This file can contain configurations relevant for tests and will override anything written in src/main/resources/application.yml. Note, since application-test.yml resides in test sources, spring boot maven plugin won't package it into the application.
Depending on the exact way of doing integration tests you might consider also using #TestPropertySource annotation to provide the custom properties/yaml file that doesn't follow spring boot's default convention. Its especially useful for spring driven tests that do not bootstrap with the spring boot full fledged support (read the tests that use junit's spring runner but don't have annotation #SpringBootTest)
Another possibly useful annotation is #ActiveProfile("myprofile"). This will cause spring boot tests to automatically load file src/test/resources/application-myprofile.yml (or application-myprofile.properties)
Last but not least I'll refer the second comment with "dev/prod/staging/properties" in the source.
When it comes to tests - there should be only one file application-test.yml. However note that when you're using yaml, its possible to define configurations for many spring boot profiles in the same file:
# default value
foo:
bar: 1
---
spring:
profiles: staging
foo:
bar: 2
---
spring:
profiles: prod
foo:
bar: 3
Some relevant SO thread
So I created a spring boot application. And I simply like to run it as a program from a Main class. No need for web controller access.
It runs great in my Intellij.
But how do I ship it as a jar?
It depends on your project structure. If you use maven just run "maven install" and find your jar in your local repository.
When you have it, run "java -jar your.jar"
While creating a spring boot project I define property in pom.xml as <packaging>war</packaging> with which I can create a war and thereafter deploy the war into server maybe tomcat or WAS.
But I came across a plugin named spring-boot-maven-plugin whose documentation states that it's use is to package executable jar or war archives and run an application in-place.
My query is why do we need this at all ?
If my packaging can tell me what to create and then can deploy it to run, what is the used of this plugin.
I am trying to understand a new project so wanted to be sure that every line makes sense
The maven plugin will create an "executable" archive. In the case of the war packaging, you would be able to execute your app with java -jar my-app.war. If you intend to deploy your Spring Boot application in an existing Servlet container, then this plugin is, indeed, not necessary.
The maven plugin does more things like running your app from the shell or creating build information.
Check the documentation
The Spring Boot Maven Plugin provides Spring Boot support in Apache Maven, letting you package executable jar or war archives and run an application “in-place”.
Refer this - https://www.javaguides.net/2019/02/use-of-spring-boot-maven-plugin-with.html