How to add enum field in postgres? - spring

In my model there is an enum field, trying to add an enum field to the database, but does not work, can you comment?
public class ChatMessage {
private MessageType messageType;
private String content;
private String sender;
public enum MessageType {
CHAT,
JOIN,
LEAVE
}
my postgre code
CREATE TYPE messageType AS ENUM ('CHAT', 'JOIN', 'LEAVE');
CREATE TABLE "chatMessage" (
id SERIAL UNIQUE PRIMARY KEY,
messageType messageType,
content VARCHAR(255) NOT NULL,
sender VARCHAR(255) NOT NULL
);
I suppose that I incorrectly declare the variable enum in postgres

Use Enumerated Annotation and Spring will handle this for you.
But in general Enums will be VARCHAR(X) in Postgres (see second link)
public class ChatMessage {
#Enumerated(EnumType.STRING)
private MessageType messageType;
private String content;
private String sender;
}
http://tomee.apache.org/examples-trunk/jpa-enumerated/
https://vladmihalcea.com/the-best-way-to-map-an-enum-type-with-jpa-and-hibernate/

If I get it right, according to the documentation your doing fine.
Although in their example they choose a different name for the column that references the Enum Type.
Try change it, like, messages messageType.
Another example: https://tapoueh.org/blog/2018/05/postgresql-data-types-enum/#postgresql-enum-data-type

Related

QueryDSL Predicate for use with JPARepository where field is a JSON String converted using an AttributeConverter to a List<Object>

I have a JPA Entity (Terminal) which uses an AttributeConverter to convert a Database String into a list of Objects (ProgrmRegistration). The converter just uses a JSON ObjectMapper to turn the JSON String into POJO objects.
Entity Object
#Entity
#Data
public class Terminal {
#Id
private String terminalId;
#NotEmpty
#Convert(converter = ProgramRegistrationConverter.class)
private List<ProgramRegistration> programRegistrations;
#Data
public static class ProgramRegistration {
private String program;
private boolean online;
}
}
The Terminal uses the following JPA AttributeConverter to serialize the Objects from and to JSON
JPA AttributeConverter
public class ProgramRegistrationConverter implements AttributeConverter<List<Terminal.ProgramRegistration>, String> {
private final ObjectMapper objectMapper;
private final CollectionType programRegistrationCollectionType;
public ProgramRegistrationConverter() {
this.objectMapper = new ObjectMapper().setSerializationInclusion(JsonInclude.Include.NON_EMPTY);
this.programRegistrationCollectionType =
objectMapper.getTypeFactory().constructCollectionType(List.class, Terminal.ProgramRegistration.class);
}
#Override
public String convertToDatabaseColumn(List<Terminal.ProgramRegistration> attribute) {
if (attribute == null) {
return null;
}
String json = null;
try {
json = objectMapper.writeValueAsString(attribute);
} catch (final JsonProcessingException e) {
LOG.error("JSON writing error", e);
}
return json;
}
#Override
public List<Terminal.ProgramRegistration> convertToEntityAttribute(String dbData) {
if (dbData == null) {
return Collections.emptyList();
}
List<Terminal.ProgramRegistration> list = null;
try {
list = objectMapper.readValue(dbData, programRegistrationCollectionType);
} catch (final IOException e) {
LOG.error("JSON reading error", e);
}
return list;
}
}
I am using Spring Boot and a JPARepository to fetch a Page of Terminal results from the Database.
To filter the results I am using a BooleanExpression as the Predicate. For all the filter values on the Entity it works well, but the List of objects converted from the JSON string does not allow me to easily write an Expression that will filter the Objects in the list.
REST API that is trying to filter the Entity Objects using QueryDSL
#GetMapping(path = "/filtered/page", produces = MediaType.APPLICATION_JSON_VALUE)
public Page<Terminal> findFilteredWithPage(
#RequestParam(required = false) String terminalId,
#RequestParam(required = false) String programName,
#PageableDefault(size = 20) #SortDefault.SortDefaults({ #SortDefault(sort = "terminalId") }) Pageable p) {
BooleanBuilder builder = new BooleanBuilder();
if (StringUtils.isNotBlank(terminalId))
builder.and(QTerminal.terminal.terminalId.upper()
.contains(StringUtils.upperCase(terminalId)));
// TODO: Figure out how to use QueryDsl to get the converted List as a predicate
// The code below to find the programRegistrations does not allow a call to any(),
// expects a CollectionExpression or a SubqueryExpression for calls to eqAny() or in()
if (StringUtils.isNotBlank(program))
builder.and(QTerminal.terminal.programRegistrations.any().name()
.contains(StringUtils.upperCase(programName)));
return terminalRepository.findAll(builder.getValue(), p);
}
I am wanting to get any Terminals that have a ProgramRegistration object with the program name equal to the parameter passed into the REST service.
I have been trying to get CollectionExpression or SubQueryExpression working without success since they all seem to be wanting to perform a join between two Entity objects. I do not know how to create the path and query so that it can iterate over the programRegistrations checking the "program" field for a match. I do not have a QProgamRegistration object to join with, since it is just a list of POJOs.
How can I get the predicate to match only the Terminals that have programs with the name I am searching for?
This is the line that is not working:
builder.and(QTerminal.terminal.programRegistrations.any().name()
.contains(StringUtils.upperCase(programName)));
AttributeConverters have issues in Querydsl, because they have issues in JPQL - the query language of JPA - itself. It is unclear what actually the underlying query type of the attribute is, and whether the parameter should be a basic type of that query type, or should be converted using the conversion. Such conversion, whilst it appears logical, is not defined in the JPA specification. Thus a basic type of the query type needs to be used instead, which leads to new difficulties, because Querydsl can't know the type it needs to be. It only knows the Java type of the attribute.
A workaround can be to force the field to result into a StringPath by annotating the field with #QueryType(PropertyType.STRING). Whilst this fixes the issue for some queries, you will run into different issues in other scenarios. For more information, see this thread.
Although the following desired QueryDsl looks like it should work
QTerminal.terminal.programRegistrations.any().name().contains(programName);
In reality JPA would never be able to convert it into something that would make sense in terms of SQL. The only SQL that JPA could convert it into could be as follows:
SELECT t.terminal_id FROM terminal t where t.terminal_id LIKE '%00%' and t.program_registrations like '%"program":"MY_PROGRAM_NAME"%';
This would work in this use case, but be semantically wrong, and therefore it is correct that it should not work. Trying to select unstructured data using a structured query language makes no sense
The only solution is to treat the data as characters for the DB search criteria, and to treat it as a list of Objects after the query completes and then perform filtering of the rows in Java. Although This makes the paging feature rather useless.
One possible solution is to have a secondary read only String version of the column that is used for the DB search criteria, that is not converted to JSON by the AttributeConverter.
#JsonIgnore
#Column(name = "programRegistrations", insertable = false, updatable = false)
private String programRegistrationsStr;
The real solution is do not use unstructured data when you want structured queries on that data Therefore convert the data to either a database that supports the JSON natively for queries or model the data correctly in DDL.
To have a short answer: the parameter used in the predicate on attribute with #QueryType must be used in another predicate on attribute of type String.
It's a clearly known issue describe in this thread: https://github.com/querydsl/querydsl/issues/2652
I simply want to share my experience about this bug.
Model
I have an entity like
#Entity
public class JobLog {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private String id;
#QueryType(PropertyType.STRING)
private LocalizedString message;
}
Issue
I want to perform some predicate about message. Unfortunately, with this configuration, I can't do this:
predicates.and(jobLog.message.likeIgnoreCase(escapedTextFilter));
because I have the same issues that all people!
Solution
But I find a way to workaround :)
predicates.and(
(jobLog.id.likeIgnoreCase(escapedTextFilter).and(jobLog.id.isNull()))
.or(jobLog.message.likeIgnoreCase(escapedTextFilter)));
Why it workaround the bug?
It's important that escapedTextFilter is the same in both predicate!
Indeed, in this case, the constant is converter to SQL in the first predicate (which is of String type). And in the second predicate, we use the conterted value
Bad thing?
Add a performance overflow because we have OR in predicate
Hope this can help someone :)
I've found one way to solve this problem, my main idea is to use mysql function cast(xx as char) to cheat hibrenate. Below is my base info. My code is for work , so I've made an example.
// StudentRepo.java
public interface StudentRepo<Student, Long> extends JpaRepository<Student, Long>, QuerydslPredicateExecutor<Student>, JpaSpecificationExecutor<Student> {
}
// Student.java
#Data
#AllArgsConstructor
#NoArgsConstructor
#EqualsAndHashCode(of = "id")
#Entity
#Builder
#Table(name = "student")
public class Student {
#Convert(converter = ClassIdsConvert.class)
private List<String> classIds;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
}
// ClassIdsConvert.java
public class ClassIdsConvert implements AttributeConverter<List<String>, String> {
#Override
public String convertToDatabaseColumn(List<String> ips) {
// classid23,classid24,classid25
return String.join(",", ips);
}
#Override
public List<String> convertToEntityAttribute(String dbData) {
if (StringUtils.isEmpty(dbData)) {
return null;
} else {
return Stream.of(dbData.split(",")).collect(Collectors.toList());
}
}
}
my db is below
id
classIds
name
address
1
2,3,4,11
join
北京市
2
2,31,14,11
hell
福建省
3
2,12,22,33
work
福建省
4
1,4,5,6
ouy
广东省
5
11,31,34,22
yup
上海市
-- ----------------------------
-- Table structure for student
-- ----------------------------
DROP TABLE IF EXISTS `student`;
CREATE TABLE `student` (
`id` int(11) NOT NULL,
`classIds` varchar(255) CHARACTER SET utf8mb4 COLLATE utf8mb4_general_ci NULL DEFAULT NULL,
`name` varchar(255) CHARACTER SET utf8mb4 COLLATE utf8mb4_general_ci NULL DEFAULT NULL,
`address` varchar(255) CHARACTER SET utf8mb4 COLLATE utf8mb4_general_ci NULL DEFAULT NULL,
PRIMARY KEY (`id`) USING BTREE
) ENGINE = InnoDB CHARACTER SET = utf8mb4 COLLATE = utf8mb4_general_ci ROW_FORMAT = Dynamic;
SET FOREIGN_KEY_CHECKS = 1;
Use JpaSpecificationExecutor solve the problem
Specification<Student> specification = (root, query, criteriaBuilder) -> {
String classId = "classid24"
String classIdStr = StringUtils.wrap(classId, "%");
var predicate = criteriaBuilder.like(root.get("classIds").as(String.class), classIdStr);
return criteriaBuilder.or(predicate);
};
var students = studentRepo.findAll(specification);
log.info(new Gson().toJson(students))
attention the code root.get("classIds").as(String.class)
In my opinion, if I don't add .as(String.class) , hibernate will think the type of student.classIds is list and throw an Exception as below.
SQL will like below which runs correctly in mysql. But hibnerate can't work.
org.springframework.dao.InvalidDataAccessApiUsageException: Parameter value [%classid24%] did not match expected type [java.util.List (n/a)]; nested exception is java.lang.IllegalArgumentException: Parameter value [%classid24%] did not match expected type [java.util.List (n/a)]
SELECT
student0_.id AS id1_0_,
student0_.class_ids AS class_ids2_0_
FROM
student student0_
WHERE
student0_.class_ids LIKE '%classid24%' ESCAPE '!'
if you add .as(String.class) , hibnerate will think the type of student.classIds as string and won't check it at all.
SQL will be like below which can run correct in mysql. Also in JPA.
SELECT
student0_.id AS id1_0_,
student0_.class_ids AS class_ids2_0_
FROM
student student0_
WHERE
cast( student0_.class_ids AS CHAR ) LIKE '%classid24%' ESCAPE '!'
when the problem is solved by JpaSpecificationExecutor, so I think this can be solve also in querydsl. At last I find the template idea in querydsl.
String classId = "classid24";
StringTemplate st = Expressions.stringTemplate("cast({0} as string)", qStudent.classIds);
var students = Lists.newArrayList<studentRepo.findAll(st.like(StringUtils.wrap(classId, "%"))));
log.info(new Gson().toJson(students));
it's sql is like below.
SELECT
student0_.id AS id1_0_,
student0_.class_ids AS class_ids2_0_
FROM
student student0_
WHERE
cast( student0_.class_ids AS CHAR ) LIKE '%classid24%' ESCAPE '!'

How to validate DTO string field is one of specified values

My spring boot application has a DTO class for creating a task.
public class CreateTaskDTO {
#NotBlank
private String status;
}
I want the type field to be one of these values: "DONE", "IN_PROGRESS", "OPEN".
Is there hibernate constraints or any other workarounds I can validate thie field?
public enum Status() {
DONE, IN_PROGRESS, OPEN
}
public class CreateTaskDTO {
#NotNull
private Status status;
}
Enum must be created. The created enum should also be used in the DTO.

Spring data mongo - unique random generated field

I'm using spring data mongo. I have a collection within a document that when I add an item to it I would like to assign a new automatically generated unique identifier to it e.g. (someGeneratedId)
#Document(collection = "questionnaire")
public class Questionnaire {
#Id
private String id;
#Field("answers")
private List<Answer> answers;
}
public class Answer {
private String someGeneratedId;
private String text;
}
I am aware I could use UUID.randomUUID() (wrapped in some kind of service) and set the value, I was just wondering if there was anything out of the box that can handle this? From here #Id seems to be specific to _id field in mongo:
The #Id annotation tells the mapper which property you want to use for
the MongoDB _id property
TIA
No there is no out of the box solution for generating ids for properties on embedded documents.
If you want to keep this away from your business-logic you could implement a BeforeConvertCallback which generates the id's for your embedded objects.
#Component
class BeforeConvertQuestionnaireCallback implements BeforeConvertCallback<Questionnaire> {
#Override
public Questionnaire onBeforeConvert(#NonNull Questionnaire entity, #NonNull String collection) {
for (var answer : entity.getAnswers()) {
if (answer.getId() == null) {
answer.setId(new ObjectId().toString());
}
}
return entity;
}
}
You could also implement this in a more generic manner:
Create a new annotation: #AutogeneratedId.
Then listen to all BeforeConvertCallback's of all entities and iterate through the properties with reflection. Each property annotated with the new annotation gets a unique id if null.

Why doesn't Mybatis map a simple ENUM correctly?

I'm not doing anything out of the ordinary from what I can tell. I have a spring boot application using mybatis:
implementation 'org.mybatis.spring.boot:mybatis-spring-boot-starter:2.1.1'
I have an application.properties config for mybatis that is pretty simple:
## MyBatis ##
mybatis.configuration.map-underscore-to-camel-case=true
mybatis.configuration.default-statement-timeout=30
My database table looks like this:
CREATE TABLE workspace_external_references (
id CHAR(36) PRIMARY KEY,
workspace_id CHAR(36) NOT NULL,
site VARCHAR(255) NOT NULL,
external_id VARCHAR(255) NOT NULL,
created_at DATETIME(6) NOT NULL DEFAULT NOW(6),
updated_at DATETIME(6) NOT NULL DEFAULT NOW(6),
FOREIGN KEY (workspace_id) REFERENCES workspaces (id) ON DELETE CASCADE
)
With just a single entry like this:
'a907c0af-216a-41e0-b16d-42107a7af05f', 'e99e4ab4-839e-405a-982b-08e00fbfb2d4', 'ABC', '6', '2020-06-09 00:19:20.135822', '2020-06-09 00:19:20.135822'
In my mapper file I'm doing a select of all references like this:
#Select("SELECT * FROM workspace_external_references WHERE workspace_id = #{workspaceId}")
List<WorkspaceExternalReference> findByWorkspace(#Param("workspaceId") final UUID workspaceId);
And the java object that this is supposed to map to looks like this:
public class WorkspaceExternalReference {
private UUID id;
private UUID workspaceId;
private Sites site;
private String externalId;
private LocalDateTime createdAt;
private LocalDateTime updatedAt;
public WorkspaceExternalReference(
final Sites site,
final UUID workspaceId,
final String externalId) {
this.site = site;
this.workspaceId = workspaceId;
this.externalId = externalId;
}
}
public enum Sites {
ABC, XYZ;
}
Sooooo why doesn't this work? I get this error back:
Caused by: org.apache.ibatis.executor.result.ResultMapException: Error attempting to get column 'id' from result set. Cause: java.lang.IllegalArgumentException: No enum constant com.acme.Sites.a907c0af-216a-41e0-b16d-42107a7af05f
When there is no default constructor, you need to let MyBatis know which columns to pass to the constructor explicitly (in most cases).
With annotations, it would look as follows.
You can use <resultMap> and <constructor> in XML mapper.
#ConstructorArgs({
#Arg(column = "site", javaType = Sites.class),
#Arg(column = "workspace_id", javaType = UUID.class),
#Arg(column = "external_id", javaType = String.class)
})
#Select("SELECT * FROM workspace_external_references WHERE workspace_id = #{workspaceId}")
List<WorkspaceExternalReference> findByWorkspace(#Param("workspaceId") final UUID workspaceId);
Other columns (i.e. id, created_at, updated_at) will be auto-mapped via setters (if there are) or reflection.
Alternatively, you can just add the default (no-arg) constructor to the WorkspaceExternalReference class. Then all columns will be auto-mapped after the class is instantiated.
Note: To make it work, there needs to be a type handler registered for UUID, but you seem to have done it already (otherwise the parameter mapping wouldn't work).

How to query a database having a composite key, which accepts queries where parts of the composite key are null in Spring JPA?

I have a webapp that uses a database with a composite key. I need to create an API which will accept the parameters of the composite key wherein each paramenter can be null.
(for eg. If all the parameters of the composite key are set as null and query is done, then it should just return all rows in db)
I have used QueryByExampleExeccutor but it keeps throwing a null pointer exception.
Below is the model indicative of 1 row of the DB
public class Row
{
#EmbeddedId
private RowKey rowkey;
#Column
private String rowAttribute;
//getters and setters for rowkey and rowAttribute
}
Below is the model indicative of RowKey
public class RowKey
{
#Column(name = "rowBlock")
private String rowBlock;
#Column(name = "rowSection")
private String rowSection;
//getters and setters for above fields
}
I'm using QueryByExampleExecutor by extending my Repository(or DAO) with it as
public interface RowRepo extends CrudRepository<Row, RowKey>, QueryByExampleExecutor<Row> {
}
In my service layer I use the following statement to call repo methods to return a list of matched rows from DB
public List<Row> getRowRangeQuery(rowBlock,rowSection,rowAttribute)
{
Row row = new Row(new RowKey(rowBlock,rowSection),rowAttribute);
List<Row> Result = (List<Row>)getRowRepository().findAll(Example.of(row));
return Result;
}
I get an InvocationTargetException which when unrolled reveals a null pointer Exception at rowSection.

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