Laravel: How to create link buttons on a view dynamically? - laravel

I'm making a College Administration website where a professor can log in.
I have a dashboard, where my dynamically generated button should be placed: (right now it just has dummy buttons!)
Generated by this view file, which I will have to modify soon:
<div class="container d-flex flex-column align-items-center justify-content-center">
<h1>IA DASHBOARD</h1>
<br>
<div class="grid2">
SUBCODE 1</button>
SUBCODE 2</button>
SUBCODE 3</button>
</div>
Tables in the Database:
the table iamarks contains the data (student info, and marks) that is to be displayed after /subcode/{subcode} narrows it down to records of just the students that are in the class assigned to current logged-in professor.
classroom_mappers is a table used to map a professor to a classroom with a subject. It makes sure that one classroom only has one professor for a particular subject.
the routes currently in my web.php:
route::get('/ia', 'IAController#show')->middleware('auth');
Route::get('/subcode/{subcode}', 'IAController#showTable')->middleware('auth');
...and these are the methods inside my controller:
//shows buttons to the user:
public function show(){
$subcodes = DB::table('classroom_mappers')
->select('subcode')
->where([['PID','=', auth()->user()->PID]])
->get();
return view('ia',compact('subcodes'));
}
//when user clicks a button, subcode is to be generated and a table is to be shown:
//it works, I tried it by manually typing in subcode value in URL.
public function showTable($subcode){
$sem = DB::table('classroom_mappers')
->where([['PID','=', auth()->user()->PID],
['subcode','=',$subcode]])
->pluck('semester');
$division = DB::table('classroom_mappers')
->where([['PID','=', auth()->user()->PID],
['semester','=',$sem],
['subcode','=',$subcode]])
->pluck('division');
$data = DB::table('iamarks')
->where([['semester','=',$sem],
['division','=',$division],
['subcode','=',$subcode]])
->get();
return view('subcode',compact('data'));
}
My Problem:
To be able to generate the {subcode} in the URL dynamically, I want to create buttons in the dashboard using the data $subcodes. The controller hands over the $subcodes (an array of subject codes which belong to logged in professor) which are to be made into buttons from the show() method.
The buttons should have the name {subcode} and when clicked, should append the same subject code in the URL as {subcode}.
How do I make use of $subcodes and make the buttons dynamically?
How do I make sure the buttons made for one user are not visible to another user?

I managed to find the solution, thanks to Air Petr.
Apparently, you can't nest blade syntax like {{some_stuff {{ more_stuff }} }} and it generates a wrong php code. I modified the solution by Air Petr to:
<div class="grid2">
#foreach ($subcodes as $subcode)
<a href="<?php echo e(url('/subcode/'.$subcode->subcode));?>">
<button class="btn btn-outline-primary btn-custom-outline-primary btn-custom">
<?php
echo e($subcode->subcode);
?>
</button>
</a>
#endforeach
</div>
It generates the buttons perfectly. The buttons for one user are not visible to another, since I'm using PID constraint in a query (['PID','=', auth()->user()->PID]).

Pass the passcodes array to view:
$subcodes = []; // Array retrieved from DB
return view('subcode', compact('subcodes'));
And in subcode.blade.php, loop through each subcode:
<div class="grid2">
#foreach($subcodes as $subcode)
<a href="{{ url('/subcode/' . $subcode->subcode) }}">
<button class="btn btn-outline-primary btn-custom-outline-primary btn-custom">SUBCODE {{ $subcode->subcode }}</button>
</a>
#endforeach
</div>

You can loop your codes to create buttons. Something like this (it's for "blade" template engine):
<div class="grid2">
#foreach ($subcodes as $subcode)
{{ $subcode->subcode }}</button>
#endforeach
</div>
Since you're using PID constrain in a query (['PID','=', auth()->user()->PID]), you'll get buttons for that specific PID. So there's no problem.

Related

Getting id value from url in controller and displaying values associated laravel

I'm trying to create a ticket management system with laravel jetstream and livewire. In the user page there's a table with all tickets that the user created. When the user clicks on the button to open one specific ticket, it should pass the id of the ticket and redirect to another page where it receives the data of that ticket he clicked, like title, message, etc..
The id is passed through the url, but my main problem is that whenever I try to display that data in the view, nothing shows, no errors either. I think that something might be wrong with my controller.
Here's my route:
Route::get('tickets.answers/{id}', [TicketsController::class, 'answers']);
The button to redirect to that specific ticket:
<a href="{{ url('tickets.answers' . '/'. $ticket->id ) }}" > <x-jet-secondary-button >
See Answer
</x-jet-secondary-button></a>
AnswersController:
public function render(Request $request)
{
$tickets = Ticket::where('id', $request->url('id'));
return view('livewire.tickets.answers', [
'tickets' => $tickets,
]);
}
And how I'm trying to display in my blade:
#foreach($tickets as $key => $ticket)
<!-- This example requires Tailwind CSS v2.0+ -->
<div class="bg-white shadow overflow-hidden sm:rounded-lg">
<div class="px-4 py-5 sm:px-6">
<h3 class="text-lg leading-6 font-medium text-gray-900">
Ticket nº {{$ticket->id}} - {{$ticket->title}}
</h3>
</div>
</div>
#endforeach
In your TicketsController you can fetch the id like this
public function answer(Request $request, int $id)
{
// Use the find() method, instead of where(), when searching for the primary key
$tickets = Ticket::find($id);
// .. more
}
In your routes files you specify an answer method, so use this in your TicketsController.
// See how to name a route
Route::get('tickets.answers/{id}', [TicketsController::class, 'answers'])->name('tickets.answers');
Then use the named route in your view like this:
<a href="{{ route('tickets.answers', ['id' => $ticket->id]) }}">
You can see a similar example in the Laravel docs.

How do I use a row count in an #if in a Laravel view?

I am brand new to Laravel and I'm running Version 6.
I want my view to display a button if one of my MySQL tables has rows that meet a specific condition but I'm having trouble figuring out how to code it - and even WHERE to code it - within my Laravel application.
My MySQL table is called diary_entries and various users of the system will contribute zero to n rows to it. Each row of the table contains a user id called client. When a given user goes to the Welcome view, I want the view to determine if that user currently has any rows in the diary_entries table. If he does, I want to display a button that will take him to another page where the entries can be displayed or edited or deleted.
I think I want to construct an #if that counts the number of records for that user; if the count is greater than zero, I want to display the button, otherwise the button is not displayed.
The problem is that I can't figure out how to code this. I've looked at the examples in the Eloquent section of the manual but they aren't particularly clear to me. I found a note near the top that said the count() function expects a Collection as an argument and that the result of an Eloquent statement is always a Collection so I guessed that I just have to execute an Eloquent query, then apply count() to the resulting Collection. But every variation of that idea which I've tried has thrown exceptions.
Here was the guess that seemed most logical to me:
#extends('layout');
#section('content');
<div class="content">
<img class="centered" src="/images/sleeping-cat.jpg" alt="sleeping cat" height="250">
<div class="title m-b-md">
<h1> Sleep Diary </h1>
</div>
<div>
<h3>{{Auth::user()->name }}</h3>
</div>
<div>
#if (count(App\DiaryEntry::select('*')->where('client', Auth::user()->name) > 0))
<p>
<a class="btn btn-primary"> View / edit existing sleep diary entries </a>
</p>
#endif
</div>
<div>
<p>
<a class="btn btn-primary" href="/diaryEntries"> Create a new sleep diary entry </a>
</div>
</div>
#endsection
This is obviously wrong because it throws an exception so how do I make it right? Does the building of the collection have to move into the Controller? If so, how do I invoke the method and see its result? Or can I do something like I have already done but just adjust the syntax a bit?
EDIT
I've imitated Sehdev's suggestion but I get this error:
$count is undefined
Make the variable optional in the blade template. Replace {{ $count }} with {{ $count ?? '' }}
Here is my welcome view:
#extends('layout');
#section('content');
<div class="content">
<img class="centered" src="/images/sleeping-cat.jpg" alt="sleeping cat" height="250">
<div class="title m-b-md">
<h1>Sleep Diary</h1>
</div>
<div>
<h3>{{ Auth::user()->name }}</h3>
</div>
<div>
#if ($count) > 0))
<p>
<a class="btn btn-primary">View/edit existing sleep diary entries</a>
</p>
#endif
</div>
<div>
<p><a class="btn btn-primary" href="/diaryEntries">Create a new sleep diary entry</a>
</div>
</div>
#endsection
And this is the relevant function from DiaryEntryController:
public function countEntriesOneUser()
{
$count = DiaryEntry::select('*')->where('client', Auth::user()->name)->count();
view("welcome", compact("count"));
}
Should the compact function be returning $count instead of count? I can't find the compact function in the manual with the search function so I'm not clear what it does or what the proper syntax is. I just tried changing the last line of the function to
view("welcome", $count);
but that produced the same error.
Try this,
#php
$count=\App\DiaryEntry::where('client', Auth::user()->name)->count();
#endphp
#if($count>1)
<p><a class="btn btn-primary">View/edit existing sleep diary entries</a></p>
#endif
Using App\DiaryEntry::select('*')->where('client', Auth::user()->name) directly on your blade template is a bad practise.
You can execute your question in your controllers method and then pass the result on your view file
Your function
function test(){
$count = DiaryEntry::select('*')->where('client', Auth::user()->name)->count(); // get the total no of records using count
view("index", compact("count")) // pass your count variable here
}
then you can directly use $count in your #if condition
Your blade template
<div>
#if ($count > 0)
<p><a class="btn btn-primary">View/edit existing sleep diary entries</a></p>
#endif
</div>

to get data in a modal in Laravel

Is there any way to get the data inside a modal? I know that it is possible to work with this through Jquery, but I would like to know if there is any way to work with Laravel itself. In a view, we can do this:
return view ('admin/users/index', ['datas1' => $ datas1, 'datas2' => $datas2];
but for a modal, is it possible to do something like this? to send my data through the controller and within my modal I check if this data are coming empty or filled, as this answer I just want to show different things, like this:
$dep = User::query()->where('dep_link', $id)->get();
 return['status' => 'success', 'dep' => $dep];
only my validation in the modal:
<div class="row" style="padding: 28px 20px;">
<div class="col-12">
#if(empty($dep))
<div class="position-relative">
<label for="rg_titular">Selecione o RG do titular (.png .jpg .pdf)</label><br>
<input type="file" name="rg_titular" class="file-input"/>
<button type="button" class="file-button">Selecionar arquivo</button>
<span class="text-arquivo">Arquivo selecionado!</span>
</div>
#else
<a href="link" target="_blank">
Visualizar RG do titular
</a>
#endif
</div>
</div>
Is there any way I can get this data inside the modal window and work with them? I just want to check if it's coming empty or not, that's all.
You can write a view composer for the modal blade file.
https://laravel.com/docs/5.8/views#view-composers
In your service provider (app, or a custom one you make)
public function boot()
{
view()->composer('myBladeFileName', function ($view) {
$activeUsers = \App\User::where('active', true)->get();
$view->with(compact('activeUsers'));
});
}

Pagination is not showing

I'm trying to get pagination into my view. I don't know where is the problem, the code doesn't show any errors.
Here is my controller function
public function apakskategorijas($id)
{
$apakskat = apakskategorijas::with('prece')->where('id',$id)->paginate(2);
return view ('kategorijas.apakskategorijas',compact('apakskat'));
}
View
#section('content')
#foreach($apakskat as $apk)
#foreach($apk->prece as $prec)
<div class="col-md-4 kat">
<a href="{{ url('kategorija/apakskategorija/preces/'.$prec->id) }}">
<div>
<img src="{{ URL::to($prec->path) }}">
</div>
<div class="nos">
<p>{{$prec->nosaukums}}</p>
</div></a>
<div class="price-box-new discount">
<div class="label">Cena</div>
<div class="price">{{ $prec->cena }} €</div>
</div>
<div><span>Ielikt grozā</span></div>
</div>
#endforeach
#endforeach
<center>{{$apakskat->links()}}</center> <--pagination
#endsection
dd($apakskat)
UPDATE
when i changed code in my controller to $apakskat = apakskategorijas::paginate(1); then it showed me pagination, but this doesn't work for me since i need to display items in each subcategory, with this code it just displays every item i have,it doesn't filter which subcategory is selected.
This is why i need this $apakskat = apakskategorijas::with('prece')->where('id',$id)->paginate(1); with is a function that i call which creates a relation between tables, so that it would display every item with its related subcategory.
That's the behavior of paginator in current Laravel version. When you have just one page, pagination links are not displayed.
To test this, just change the code to something like this to get more pages:
$apakskat = apakskategorijas::paginate(1);
If you want to show the first page if there is only one page, you need to customize pagination views. Just publish pagination views and remove this #if/#endif pair from the default.blade.php but keep the rest of the code as is:
#if ($paginator->hasPages())
....
#endif

Is it possible to delete record without using forms in laravel 5.4

I want to delete a record but I haven't been successful, apparently my code is wrong. Solutions i came across say i have to use a post in my form method and add the method_field helper. This would mean my view having a form in it, i want to avoid this if possible. Is it then possible to do my delete another way. Below is my code
snippet of my view
<div class="backbtn">
<a class="btn btn-savvy-delete" href="/tasks/{{$task->id}}" data-toggle="tooltip" title="Delete"><i class="fa fa-trash-o" aria-hidden="true"> Delete</i></a>
</div>
<div class="panel-body">
<p><strong>Owner:</strong> {{ ucfirst($task->employee->firstname) }} {{" "}} {{ ucfirst($task->employee->lastname) }}</p>
<p><strong>Task:</strong> {{ $task->title }}</p>
<p><strong>Description:</strong> {{ $task->description }}</p>
</div>
TaskController
public function destroy($id)
{
Task::destroy($id);
Session::flash('status', "Task was successfully deleted.");
return redirect('/tasks');
}
web.php
Route::delete('/tasks/{id}', 'TaskController#delete');
Im not sure what error you are getting, but i can point out a few things. For one use Route::get instead of ::delete, you are calling it via a link not a form method.
Secondly to delete follow what the laravel doc says here eg.
$task = App\Task::find(1);
$task->delete();

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