In Laravel Eloquent, how to check for multiple relationship existence in one "has"? - laravel

So, in order to check the existence of a relationship on a model, we use the has function on the relationship like model1->has('relationship1').
While it is possible to supply the model1->with() function with an array of relations to eager load them all, both has and whereHas functions do not accept arrays as parameters. How to check for the existence of multiple relationships?
Right now, I am running multiple has functions on the same model (The relations are not nested):
model1->has('relationship1')
->has('relationship2')
->has('relationship3')
But that is tedious and error-prone. Solution anyone?

There unfortunately isn't a way to pass an array of relationships to has() or whereHas(), but you can use a QueryScope instead. On your Model, define the following:
public function scopeCheckRelationships($query){
return $query->has("relationship1")->has("relationship2")->has("relationship3");
}
Then, when querying your Model in a Controller, simply run:
$result = Model::checkRelationships()->get();
The function name to use a Scope is the name of the function, minus the word scope, so scopeCheckRelationships() is used as checkRelationships().
Also, it's actually possible to pass the relationships you want to query as a param:
public function scopeCheckRelationships($query, $relationships = []){
foreach($relationships AS $relationship){
$query->has($relationship);
// Might need to be `$query = $query->has(...);`, but I don't think so.
}
return $query;
}
...
$result = Model::checkRelationships(["relationship1", "relationship2", "relationship3"])->get();
In case you need this to be dynamic.
Here's the documentation for Query Scopes if you need more info: https://laravel.com/docs/5.8/eloquent#query-scopes

Related

How to access one relation inside another relation in laravel?

I have a query in which I have eagar loaded two models using with function like this:
ModelA::with(['relationB', 'relationC.relationC.A'])->where(condition)->get();
So, ModelA has two relations like this:
public function B(){ return $this->blongsTo(B::class);}
public function C(){ return $this->blongsTo(C::class);}
Now, my requirement is that I want to add a condition in B() function like this:
public function C() {
if($this->B->status) {
return $this->blongsTo(C::class)->withTrashed();
}
return $this->blongsTo(C::class);
}
But it return null on line this statement:
if($this->B->status)
Here is the error message
Trying to get property 'status' of non-object
My ultimate requirement is that using one relation function I want to fetch deleted records and non deleted based on the condition, but somehow it is not working.
My laravel application version is 7.30.4.
A relational function (such as your public function C()) works a bit of magic under the hood. This is because really it is designed to be called in a query way like you show already with the ::with(['relationB', ...]).
However, because of this, if you were to eager load C, then $this is not yet loaded as the full model, and therefore B is not defined (this is assuming that modelA always has a B relation). If you were to dd($this) while performing your query, you'd see that the result would be a model without any attributes.
Getting this to work from within a relational function (with the goal of eager loading) is very difficult. You're probably better off doing the logic elsewhere, with a second query for example. This is because within the relational function, there is no way to know who or what the potential target is. However, if you only use it after modelA is loaded, then it works without issues.
You can do some things with a whereHas, but then you'd still have to do 2 queries, or you can try and see if you can get it done with an SQL IF statement, but that will not result in a relation.

Error Call to a member function where() on array Laravel

I want to do filtering from the data that I display, but there is a problem when I add where to my data.
the plan in the future I want to add if isset $request name, date and others. but was constrained at this one point.
Thank you for helping to answer in advance
$matchs =Matchs::where('type', 'sparring')->where('status','Pending')->whereNull('deleted_at')->get()->toArray();
$data=[];
foreach ($matchs as $key) {
$lawan = Matchs::where('id', $key['id'])->first()->ToArray();
$pertandingan = Sparring::where('match_id', $key['id'])->first()->ToArray();
$dua_arah = MatchTwoTeam::where('match_id', $key['id'])->first()->ToArray();
$tim = Team::where('id', $dua_arah['home_team'])->first()->ToArray();
$transfer['name']=$tim['name'];
$transfer['city']=$lawan['city'];
$transfer['field_cost']=$pertandingan['field_cost'];
$transfer['referee_cost']=$pertandingan['referee_cost'];
$transfer['logo_path']=$tim['logo_path'];
$transfer['nama_lapangan']=$lawan['nama_lapangan'];
$transfer['date']=$lawan['date'];
array_push($data,$transfer);
array_push($data,$pertandingan);
}
$data->where('name', 'LIKE', '%'.'football'.'%')->get()->toArray();
$data = array_search('football', array_column($data, 'name'));
$tittle="Sparring";
return view('mode.sparring',[
'tittle' => $tittle,
'data' => $data,
]);
You are trying to call where in an array which is not possible.
As you can see in the first line of your code you are calling where method in your model class. Like Matchs::where('type', 'sparring'), this is possible because Matchs is a Model class.
Now you can run where even if you are using array. You can convert that day in collection and then use array on that collection.
As below:
collect($data)->where('name', 'football')->toArray();
Here collect() will convert the $data array to collectio and then run the where() method in collectio then toArray() will change it back to array. But unfortunately there is no like operator possible in collection class. See the list of available method in Laravel collection here: https://laravel.com/docs/8.x/collections#available-methods
There is a way to do what you are trying to do. As far as I understand you want to filter the Matches where the Team name has footbal in it. You can do it like this:
Matchs::where('type', 'sparring')
->where('status','Pending')
->whereNull('deleted_at')
->whereHas('team', function($team) {
return $team->where('name', 'LIKE', '%'.'football'.'%')
})
->get()
->toArray();
So, here we can get the only those Mathes that has the Team that has the name contains football.
Few suggestion for you as seems you are new in Laravel:
Model name should be singular instead of plural, so the model class Matchs should be Match. Your name for team's model is Team is correct.
Avoid using toArray() because you won't need it. When you call get() it will return object of collection which more readable and powerful then array in most cases.
The code I suggested to use the like using whereHas will only work if you have propery defined your team relation in your Matchs class. So, defining your relationships in model is also important. If you do so, you don't even need the for loop and all those where in other model in that loop. You can do it in one query with all the relationships.

How to dissociate elements from a HasMany relation?

There's the save and saveMany methods on the HasMany relation class, but where are the dissociate(Many)/detach(Many) methods? There's also no built-in way to get the inverse relationship method, so what's the best way to dissociate an array of id's/models from a HasMany relationship object.
Currently I'm using:
$hasMany = $parent->theRelationship(); // Get the relationship object.
$child = $hasMany->getRelated(); // Get an empty related model.
$key = $hasMany->getForeignKeyName(); // Get the name of the column on the child to set to NULL.
$child->findMany($IDs)->each(function($model) use ($key) {
$model->$key = NULL;
$model->save();
});
This could be alot shorter with something like:
$hasMany = $parent->theRelationship();
$hasMany->dissociate($IDs);
Bonus points if you have any official answers from Taylor as to why he hasn't implemented this, I've seen him close feature requests of this kind on GitHub.
I am not sure why there isn't a function, but to be more performant than your example, you could use the DB class like:
\DB::table('child_table')->where('parent_id', $parent->id)->update(['parent_id' => null]);
You could use detach like so;
$parent->theRelationship()->detach([1,2,3])
Where you pass an array of IDs.
From Laravel documentation:
"For convenience, attach and detach also accept arrays of IDs as input"
The performatic way (1 db update):
$partent->theRelationship()->update(['parent_id' => null]);
The readable way (multiple db updates):
$parent->theRelationship->each->parentRelationship()->dissociate();

Laravel whereDoesntHave() - multiple OR conditions

In Laravel 4.2 I have a model called Product with many-to-many relationshis to other models like Country or Category. I want to filter out products that are "incomplete", which means they have no connected countries or no connected categories. I can use whereDoesntHave() method to filter out one relation. When I use it two times in one query it creates AND condition, but I need OR. I can't find orWhereDoesntHave() method in API documentation. I can't pass multiple relations as arguments because it expects first argument to be a string.
I need something like this:
$products = Product::whereDoesntHave('categories')->orWhereDoesntHave('countries')->get();
Is there any way to achive whereDoesntHave() with multiple OR conditions?
You can use doesntHave and specify the boolean operator:
$products = Product::doesntHave('categories')->doesntHave('countries', 'or')->get();
Actually you only need whereDoesntHave if you want to pass in a closure to filter the related models before checking if any of them exist. In case you want to do that you can pass the closure as third argument:
$products = Product::doesntHave('categories', 'or', function($q){
$q->where('active', false);
})->doesntHave('countries', 'or')->get();
Since Laravel 5.5 there is an orWhereDoesntHave function.
You may use it like this
Product::whereDoesntHave('categories', function($q){ //... })
->orWhereDoesntHave('countries', function($q){//...})
->get();
From you example it seems that you are not using a where clause, so you may just use
Product::doesntHave('categories')
->orDoesntHave('countries')
->get();
Use
Product::whereDoesntHave('categories')->doesntHave('countries', 'or')->get();
Laravel Source Code:
whereDoesntHave https://github.com/illuminate/database/blob/master/Eloquent/Builder.php#L654
calls
https://github.com/illuminate/database/blob/master/Eloquent/Builder.php#L628
internally.
Let’s say we have Authors and Books, with 1-n relationship – one Author can have one or many Books. Here’s how it looks in app\Author.php:
public function books()
{
return $this->hasMany(\App\Book::class, 'author_id');
}
Now, what if we want to show only those Authors that have at least one book? Simple, there’s method has():
$authors = Author::has('books')->get();
Similarly, there’s an opposite method – what if we want to query only the authors without any books? Use doesnthave():
$authors = Author::doesnthave('books')->get();
It’s not only convenient, but also super-easy to read and understand, even if you’re not a Laravel developer, right?

Is it possible to eager load arbitrary queries in Eloquent?

I'm working in Laravel 4, and I have a Child model with multiple EducationProfiles:
class Child extends EloquentVersioned
{
public function educationProfiles()
{
return $this->hasMany('EducationProfile');
}
}
If I wanted to get all the EducationProfiles for each kid under age 10 it would be easy:
Child::where('date_of_birth','>','2004-03-27')->with('educationProfiles')->all();
But say (as I do) that I would like to use with() to grab a calculated value for the Education Profiles of each of those kids, something like:
SELECT `education_profiles`.`child_id`, GROUP_CONCAT(`education_profiles`.`district`) as `district_list`
In theory with() only works with relationships, so do I have any options for associating the district_list fields to my Child models?
EDIT: Actually, I was wondering whether with('educationProfiles') generates SQL equivalent to:
EducationProfile::whereIn('id',array(1,2,3,4))
or whether it's actually equivalent to
DB::table('education_profiles')->whereIn('id',array(1,2,3,4))
The reason I ask is that in the former I'm getting models, if it's the latter I'm getting unmodeled data, and thus I can probably mess it up as much as I want. I assume with() generates an additional set models, though. Anybody care to correct or confirm?
Ok, I think I've cracked this nut. No, it is NOT possible to eager load arbitrary queries. However, the tools have been provided by the Fluent query builder to make it relatively easy to replicate eager loading manually.
First, we leverage the original query:
$query = Child::where('date_of_birth','>','2004-03-27')->with('educationProfiles');
$children = $query->get();
$eagerIds = $query->lists('id');
Next, use the $eagerIds to filterDB::table('education_profile') in the same way that with('educationProfiles') would filter EducationProfile::...
$query2 = DB::table('education_profile')->whereIn('child_id',$eagerIds)->select('child_id', 'GROUP_CONCAT(`education_profiles`.`district`) as `district_list`')->groupBy('child_id');
$educationProfiles = $query2->lists('district_list','child_id');
Now we can iterate through $children and just look up the $educationProfiles[$children->id] values for each entry.
Ok, yes, it's an obvious construction, but I haven't seen it laid out explicitly anywhere before as a means of eager loading arbitrary calculations.
You can add a where clause to your hasMany() call like this:
public function educationProfilesUnderTen() {
$ten_years_ago = (new DateTime('10 years ago'))->format('Y-m-d');
return $this->hasMany('EducationProfile')->where('date_of_birth', '>', $ten_years_ago)
}

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