So I use this function to handle android back button :
this._page.on(Page.loadedEvent, event => {
if (application.android) {
application.android.on(application.AndroidApplication.activityBackPressedEvent, (args:AndroidActivityBackPressedEventData) => {
args.cancel = true;
this._ngZone.run(() => {
this.router.navigate(['/parameters']);
});
});
}
})
on different pages (angular components). So on page1.ts I have navigate(['/parameters]) and on page2.ts I have console.log("test"). Problem is wherever I am in the app, pressing back button always do navigate(['/parameters]), also the console.log if i'm on the right page, but it should do console.log only.
It seems to be global, any idea how to override activityBackPressedEvent ?
activityBackPressedEvent is not specific to a page, it's global to your Activity which holds all the pages. Generally, You will not add more than one event listener to this event.
You could do something like below to handle this on page level, probably in app module / main.ts
application.android.on(application.AndroidApplication.activityBackPressedEvent,
(args: application.AndroidActivityBackPressedEventData) => {
const page = frame.topmost().currentPage;
if (page.hasListeners(application.AndroidApplication.activityBackPressedEvent)) {
args.cancel = true;
page.notify({
eventName: application.AndroidApplication.activityBackPressedEvent,
object: page
});
}
});
With above code, activityBackPressedEvent willl be triggered on every page that has a listener.
Now in your page / component in which you want to customise the behaviour you do this,
// Inject Page
constructor(private page: Page) {
this.page.on(application.AndroidApplication.activityBackPressedEvent, this.onBackButtonTap, this);
}
onBackButtonTap(data: EventData) {
this._ngZone.run(() => {
this.router.navigate(['/parameters']);
});
}
I think since you added the handle back button in the event pageLoaded that's why it does not work on other page.
The code that handle back button should be placed in the app starter. I'm using NS Vue & I place this code in my main.js. I think it could be similar in NS angular.
application.android.on(application.AndroidApplication.activityBackPressedEvent, (args:AndroidActivityBackPressedEventData) => {
args.cancel = true;
this._ngZone.run(() => {
this.router.navigate(['/parameters']);
});
});
Related
As we know, in mobile web-browser, if you click back button, the web-app will go to previous page, right?
But what if I want to make a certain condition which will prevent the web-app to go to previous page.
For example, if a SweetAlert2 dialog is popped-up, the back button will close the SweetAlert2 dialog.. but if there is no SweetAlert2 dialog, the back button will go to previous page..
The code I expected is like below:
export default {
mounted() {
document.addEventListener("backbutton", function(){
if(is_swal_open){
close_swal_dialog();
return false; // NOTE: i expected this should prevent from go to previous page
}
});
},
}
What you can do is warn the user:
if(is_swal_open)
{
window.onbeforeunload = function() { return "Your warning here."; };
}
or add an event listener like so:
window.addEventListener('beforeunload', function (e) {
if(is_swal_open)
{
// Cancel the event
e.preventDefault();
// Chrome requires returnValue to be set
e.returnValue = '';
}
});
I´m having a hard time understanding what am i missing here when the user receives a push notification and then hits the button in order to see it and navigate to the proper page inside the app, so my code is this and by the way it works very well in ios:
So if the application is android, i use this code below... i receive the content and pass it to a function called handleOpenURL
if (application.android) {
application.on(application.launchEvent, (args) => {
try {
TnsOneSignal.startInit(application.android.context).setNotificationOpenedHandler(new TnsOneSignal.NotificationOpenedHandler({
// notificationOpened: function (result: com.onesignal.OSNotificationOpenResult) {
notificationOpened: function (result) {
const imovelAndroid = JSON.parse(result.stringify()).notification.payload.additionalData;
handleOpenURL(imovelAndroid);
}
})).init();
TnsOneSignal.setInFocusDisplaying(TnsOneSignal.OSInFocusDisplayOption.Notification);
TnsOneSignal.startInit(application.android.context).init();
}
catch (error) {
console.error('error', error);
}
});
}
I´m actually entering the function below, but the problem is when navigating, it simply does not work:
function handleOpenURL(argImovel) {
const precoToNumber = +argImovel['imovel'].preco;
const precoFormated = Number(precoToNumber).toLocaleString("pt-PT", { minimumFractionDigits: 0 });
const navigationOptions = {
moduleName: "detail/detail-page",
context:{ //my context here which is big so i´m not putting it.
}
};
frameModule.topmost().navigate(navigationOptions);
}
Everything works as expected in ios, it is suppose to receive the push, and when the user hits it, the app should navigate to a detail page where the content receive is showned.
What am i missing? thanks for your time, regards.
EDIT
Thanks to Manoj, i fixed the issue adding this to my handleOpenURL function:
setTimeout(() => {
frameModule.topmost().navigate(navigationOptions);
}, 2);
Make sure your Frame is ready for navigation, try logging frameModule.topmost() and see if that is a valid frame.
May be you could try a timeout of 1 or 2 secs and see whether that fixes the issue.
I have the following navigation structure in my React Native app:
StackNavigator configured with 3 routes:
Splash screen (React Component)
StackNavigator for my login flow
DrawerNavigator for my core app screens.
The DrawerNavigator has some dynamic multiple routes, but also one static route which is another StackNavigator.
Everything seems to be working as expected:
The store is being updated accordingly.
Navigation between screen works.
Go back between screen works when configured within each component, with the following command:
this.props.navigation.goBack();
My question is - is there a way for me to handle back button on Android globally? Currently when I click on the back button, nothing happens (due to the fact I'm using Redux). Should I handle the back button in each component or is there a way of doing it using Redux?
A bit late, but there is a way to handle this with redux. In your index.js file where you create your store you can make export a class and add a componentWillMount call to handle dispatching a call to your redux actions. Just remember to import the actions you need above.
const store = configureStore();
export default class Index extends Component {
componentWillMount = () => {
BackHandler.addEventListener('hardwareBackPress', () => {
const { nav: { routes } } = store.getState();
const currentRouteName = routes[routes.length-1].routeName;
if (currentRouteName === 'EditCoupleProfile') {
store.dispatch(editCoupleActions.navigateBack())
} else if ( currentRouteName === 'EditInterests' ) {
store.dispatch(interestsActions.navigateBack())
} else {
store.dispatch(popFromStack());
}
return true;
})
};
componentWillUnmount = () => {
BackHandler.removeEventListener('hardwareBackPress');
};
render() {
return (
<Provider store={store}>
<AppWithNavigation />
</Provider>
);
}
}
I have a page that is built around a wrapper with some very defined logic. There is a Save button on the bottom of the wrapped form that looks like this:
<form>
... my page goes here...
<input id="submitBtnSaveId" type="button" onclick="submitPage('save', 'auto', event)" value="Save">
</form>
This cannot change...
Now, I'm writing some javascript into the page that gets loaded in "...my page goes here...". The code loads great and runs as expected. It does some work around the form elements and I've even injected some on-page validation. This is where I'm stuck. I'm trying to "intercept" the onclick and stop the page from calling "submitPage()" if the validation fails. I'm using prototype.js, so I've tried all variations and combinations like this:
document.observe("dom:loaded", function() {
Element.observe('submitBtnSaveId', 'click', function (e) {
console.log('Noticed a submit taking place... please make it stop!');
//validateForm(e);
Event.stop(e);
e.stopPropagation();
e.cancelBubble = true;
console.log(e);
alert('Stop the default submit!');
return false;
}, false);
});
Nothing stops the "submitPage()" from being called! The observe actually works and triggers the console message and shows the alert for a second. Then the "submitPage()" kicks in and everything goes bye-bye. I've removed the onclick attached to the button in Firebug, and my validation and alert all work as intended, so it leads me to think that the propagation isn't really being stopped for the onclick?
What am I missing?
So based on the fact that you can't change the HTML - here's an idea.
leave your current javascript as is to catch the click event - but add this to the dom:loaded event
$('submitBtnSaveId').writeAttribute('onclick',null);
this will remove the onclick attribute so hopefully the event wont be called
so your javascript will look like this
document.observe("dom:loaded", function() {
$('submitBtnSaveId').writeAttribute('onclick',null);
Element.observe('submitBtnSaveId', 'click', function (e) {
console.log('Noticed a submit taking place... please make it stop!');
//validateForm(e);
Event.stop(e);
e.stopPropagation();
e.cancelBubble = true;
console.log(e);
alert('Stop the default submit!');
return false;
submitPage('save', 'auto', e);
//run submitPage() if all is good
}, false);
});
I took the idea presented by Geek Num 88 and extended it to fully meet my need. I didn't know about the ability to overwrite the attribute, which was great! The problem continued to be that I needed to run submitPage() if all is good, and that method's parameters and call could be different per page. That ended up being trickier than just a simple call on success. Here's my final code:
document.observe("dom:loaded", function() {
var allButtons = $$('input[type=button]');
allButtons.each(function (oneButton) {
if (oneButton.value === 'Save') {
var originalSubmit = oneButton.readAttribute('onclick');
var originalMethod = getMethodName(originalSubmit);
var originalParameters = getMethodParameters(originalSubmit);
oneButton.writeAttribute('onclick', null);
Element.observe(oneButton, 'click', function (e) {
if (validateForm(e)) {
return window[originalMethod].apply(this, originalParameters || []);
}
}, false);
}
});
});
function getMethodName(theMethod) {
return theMethod.substring(0, theMethod.indexOf('('))
}
function getMethodParameters(theMethod) {
var parameterCommaDelimited = theMethod.substring(theMethod.indexOf('(') + 1, theMethod.indexOf(')'));
var parameterArray = parameterCommaDelimited.split(",");
var finalParamArray = [];
parameterArray.forEach(function(oneParam) {
finalParamArray.push(oneParam.trim().replace("'","", 'g'));
});
return finalParamArray;
}
I need to avoid the double click submitting behavior. I'm using the client validation with the unobtrusive library. I have the following code for avoiding the double clic:
jQuery.fn.preventDoubleSubmit = function () {
var alreadySubmitted = false;
return jQuery(this).submit(function () {
if (alreadySubmitted)
return false;
else {
alreadySubmitted = true;
}
});
};
jQuery('form').preventDoubleSubmit();
Unfortunately, if my form has some validable fields (for example, a required field), the code above is still being fired, hence, even if I correct any mistakes on the form, I won't be able to submit it again.
How can I fire the double click code after the validation has been succesfully done?
You can also use the JQuery One event.
I have found that I could get past most guards against double-clicks by double-clicking fast. Using the one event is the only true way to make sure the event is only fired once. I don't think this technique will work "out of the box" with an input type=submit tag. Instead, you can simply use an input type=button or JQueryUI's .button().
$("#submitButton").one("click", function(event) {
$('#theForm').submit();
});
If you need to re-wire the event on a validation error (or other circumstance), I recommend that you create a function for the event handler. The function isn't necessary in this example because all the event handler does is submit the form, but in more complicated scenarios you may want to avoid repeating yourself.
function submitClick(event) {
$('#theForm').submit();
}
$("#submitButton").one('click', function(event) {
submitClick(event);
});
// This handler will re-wire the event when the form is invalid.
$('#theForm').submit(function(event) {
if (!$(this).valid()) {
event.preventDefault();
$('#submitButton').one('click', function(event) { submitClick(event); });
}
});
You could obviously add the disabling code here if you wanted to give feedback to the user that the button doesn't work anymore. One great side-effect of using the One event is that you don't actually have to make the button disabled, you can use a style of your own.
function submitClick(event) {
$('#submitButton').addClass('disabledButton');
$('#theForm').submit();
}
$("#submitButton").one('click', function(event) {
submitClick(event);
});
// This handler will re-wire the event when the form is invalid.
$('#theForm').submit(function(event) {
if (!$(this).valid()) {
event.preventDefault();
$('#submitButton').one('click', function(event) { submitClick(event); });
$('#submitButton').removeClass('disabledButton');
}
});
JQuery One Event: http://api.jquery.com/one/
I solved it with the following code:
var tryNumber = 0;
jQuery('input[type=submit]').click(function (event) {
var self = $(this);
if (self.closest('form').valid()) {
if (tryNumber > 0) {
tryNumber++;
alert('Your form has been already submited. wait please');
return false;
}
else {
tryNumber++;
}
};
});
NOTE: You can also replace the:
return false;
line, for:
self.attr('disabled', true);
BUT, if you use the name of your submit buttons on your controller for extra logic, they will be sent as null. (you can use an additional hidden field to charge them before submitting)
that's it, hope it helps
Rodrigo
EDIT: Thanks to these posts:
jquery newbie: combine validate with hidding submit button
Why not just use:
function disableButtons() {
var form = $(this);
var btns = $("input:submit", form);
if (!form.valid()) {
// allow user to correct validation errors and re-submit
btns.removeAttr("disabled");
} else {
btns.attr("disabled", "disabled");
}
}
to disable your buttons and activate it using:
$("form").bind("submit", disableButtons);
Based on Ryan P's popular answer I created the following generic solution that also works with my ajax form.
decorate your custom submit button with the following class:
<button type="button" class="one-click-submit-button">Submit</button>
Add the following to your javascript file:
function OneClickSubmitButton() {
$('.one-click-submit-button').each(function () {
var $theButton = $(this);
var $theForm = $theButton.closest('form');
//hide the button and submit the form
function tieButtonToForm() {
$theButton.one('click', function () {
$theButton.hide();
$theForm.submit();
});
}
tieButtonToForm();
// This handler will re-wire the event when the form is invalid.
$theForm.submit(function (event) {
if (!$(this).valid()) {
$theButton.show();
event.preventDefault();
tieButtonToForm();
}
});
});
}
OneClickSubmitButton();
since this is an ajax form we want to reload the handlers if we fail server validation.
function MyForm_OnSuccess() {
if (true if your form passed validation logic) {
//do something since your form submitted successfully
} else { //validation failed on server
OneClickSubmitButton(); //reinitialize the button logic
}
}
Obviously if you don't have ajax forms you can omit the whole OneClickSubmitButton function business and run $('.one-click-submit-button').each(... directly.
I have a form that uses MVC3 unobtrusive validation, and a viewmodel with a [RemoteAttribute].
It looks to me like the form's submit event only fires after all validation has passed. I'm currently using this, and it seems to work:
<input type="submit" value="Submit the Form"
data-app-disable-on-submit="true" />
$('form').live('submit', function() {
$(this).find('input[type="submit"][data-app-disable-on-submit="true"]')
.attr('disabled', 'disabled');
})
;
I set breakpoints on both the remote attribute validation action method and the HttpPost action method. Clicking the submit button the first time hits the breakpoint on the validation action method. At this point, the button is still enabled. I can click it multiple times, and after resuming the validation method, the HttpPost is hit only once. When the HttpPost is hit, the submit button is disabled.
Update
Right you are Alex. So an updated version of the above would look like this:
$('form').on('submit', function() {
$(this).find('input[type="submit"][data-app-disable-on-submit="true"]')
.attr('disabled', 'disabled');
})
$('form').submit(function () {
$('input[type="submit"]', this).attr('disabled', 'disabled');
});
I use a different approach to this. Not wiring to the click event of the button, but to the submit event of the form. Works like a charm to prevent multiple simultaneous submits of forms.
function initFormsToPreventSimultaneousSubmits(selector) {
if (!selector) {
selector = 'form'; // No selector supplied, apply to all forms on the page
}
// Make sure all forms that conform to selector are marked as not submitting
$(selector).each(function()
{
var $form = $(this);
$form.data('submitting', false);
});
// Attach to submit event of all forms that conform to selector
$(selector).off('submit').on('submit', function (e) {
var $form = $(this);
if (!$form.valid || $form.valid()) { // Make sure to only process when the form is valid or jquery validation is not used
if ($form.data('submitting')) {
// form is already submitting. Classic case of double click on one of the submit buttons of the form. Stop the submit
e.preventDefault();
return false;
} else {
// All ok, mark the form as submitting and let the form perform the submit
$form.data('submitting', true);
return true;
}
}
});
}
On document ready i call initFormsToPreventSimultaneousSubmits() to init all forms on the page.
Only thing to remember is that when u use a ajax form post is to call the initFormsToPreventSimultaneousSubmits('#formId') on the OnComplete event of the AjaxOptions settings. Because otherwise the form will still be marked as submitting when its done. When a 'normal' form post is used this is not an issue.
Extends answers by Alex and Ryan P to accounts for situations where jQuery Validation might be missing and where multiple submit buttons exist in a single form.
oneClickSubmitButton = function () {
$('input[type=submit], button[type=submit], input[type=image]').each(function () {
var $theButton = $(this);
var $theForm = $theButton.closest('form');
//hide the button and submit the form
function tieButtonToForm() {
$theButton.one('click', function () {
$theButton.addClass('ui-state-disabled');
});
}
tieButtonToForm();
$theForm.submit(function (event) {
// Only proceed for the clicked button
if (!$theButton.hasClass("ui-state-disabled"))
return;
// If jQuery Validation is not present or the form is valid, the form is valid
if (!$theForm.valid || $theForm.valid())
return;
// Re-wire the event
$theButton.removeClass('ui-state-disabled');
event.preventDefault();
tieButtonToForm();
});
});
};
I was able to fix a similar issue with a couple of lines of code. I prefer this if you don't want to "alert" to user that they double clicked and just silently ignore the second click.
I just made a global javascript variable that I toggled when my function was executing during a critical section. This kept subsequent function calls from re-executing the same section.
var criticalSection = false;
SomeOnClickEventFired = function () {
if (!criticalSection)
{
criticalSection = true;
//Ajax Time
criticalSection = false;
}
}