How can save order detail associated with the user and How can I return order data associated with the user details based the url parameters? - spring

Question

I have created the User and Order entities as bellow. What I want to achieve is that if http://localhost:8080/users/username? is given I want to return only the user detail based on username provided. if http://localhost:8080/users/username?detail=true, I want to return user detail and order details for the username provided. How can I achieve this?
User.java
#Entity
public class User {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private long id;
private String userName;
private String password;
private String firstName;
private String lastName;
private String gender;
private String lastLoggedIn;
#OneToMany
List<Order> listOfOrder;
//constructors
//getter and setter
}
Order.java
#Entity
public class Order
{
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private long id;
private float amount;
private String createdAt;
private String deliveredDate;
//constructors
//getter and setter
}
Controller.java
//CREATE CUSTOMER
#RequestMapping(method = POST, value = "/create")
public ResponseEntity createCustomerDetails(#RequestParam String userName, String password, String firstName,
String lastName, String gender) {
String lastLogged = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss").format(Calendar.getInstance().getTime());
User user = new User(userName, password, firstName, lastName, gender, lastLogged);
userRepository.save(user);
return ResponseEntity.status(OK).body(user.getId() + " User were successfully saved");
}
//CREATE ORDER
#RequestMapping(method = POST, value = "/order/{userName}")
public ResponseEntity createOrder(#PathVariable ("userName") String userName, #RequestParam float amount)
{
String createdAt = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss").format(Calendar.getInstance().getTime());
String deliveredDate = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss").format(Calendar.getInstance().getTime());
User user = orderService.findUser(userName);
if (!user.equals(null))
{
Order order = new Order(amount,createdAt,deliveredDate);
user.getListOfOrder().add(order);
return ResponseEntity.status(OK).body("order details were saved under "+user.getUserName() + " "+user.getFirstName());
}
return ResponseEntity.status(NOT_FOUND).body(null + " was not found");
}
//GET THE USER DETAILS
#RequestMapping(method = GET, value = "/users/{userName}")
public ResponseEntity getUserDetail(#PathVariable("userName") String userName,
#RequestParam(defaultValue ="none", required = false) String detail) {
if (!detail.equals("none")){
return .....;
}else {
return ........;
}
}
UserRepository
#Repository
public interface UserRepository extends CrudRepository<User, Long> {
User findByUserName(String userName);
}

Answer 1

If you're ok with doing the serialization manually, you can employ JsonView to determine what gets serialized.
https://www.baeldung.com/jackson-json-view-annotation
User.java
import com.fasterxml.jackson.annotation.JsonView;
public class User {
#JsonView(Views.Lite.class)
private String name;
#JsonView(Views.Full.class)
private List<Order> orders;
}
Views.java
public class Views {
public static class Lite {}
public static class Full extends Lite {}
}
UserController.java
import com.fasterxml.jackson.databind.ObjectMapper;
import org.springframework.web.bind.annotation.RestController;
#RestController
public class UserController {
#Autowired
private UserRepository userRepository;
#Autowired
private ObjectMapper mapper;
#GetMapping("/user/{username}")
public ResponseEntity<String> getUserDetail(#PathVariable String username, #RequestParam(required = false) String detail) throws JsonProcessingException {
User user = userRepository.findByUserName(username);
Class viewClass = Views.Lite.class;
if (!StringUtils.isEmpty(detail)) {
viewClass = Views.Full.class;
}
return ResponseEntity.status(HttpStatus.OK)
.body(mapper.writerWithView(viewClass).writeValueAsString(user));
}
}