How to convert this SQL statement to laravel code? - laravel

Question

So I have two tables Animals and Adoptions
The animal table holds [animalID, name, DOB]
Adoptions hold [id, animalID, userID, approved]
I need to write a statement which would match the animalID in both the tables and would return the name and DOB of the animal where approved is 0.
I have hardly any previous experience with either mySQL or Laravel so my assumption would be that the SQL query would look like this:
SELECT animalName, DOB
FROM animal
INNER JOIN
Adoption ON adoption.animalID = animal.animalID
WHERE
Adoption.approved = 0
Currently I am returning all of the animals in the table. So I need to add the join and do the checking to see if the animalID in the adoptions table has a value of 0
public function available ()
{
//JOIN ANIMAL AND ADOPTION TABLES
//RETURN ALL ANIMALS WHERE APPROVED = 0
$animalQuery = Animal::all();
return view('/available', array('animals'=>$animalQuery));
}

Answer 1

public function available ()
{
//JOIN ANIMAL AND ADOPTION TABLES
//RETURN ALL ANIMALS WHERE APPROVED = 0
$animalQuery = Animal::select('animals.id','animals.name', 'animals.DOB')
->join('adoptions', 'adoptions.animalid', '=', 'animals.id')
->where('adoptions.approved', 0)
->get();
return view('/available', array('animals'=>$animalQuery));
}
This is my answer which worked for me

Answer 2

First of all, you would need two models. An Animal model and an Adoption model. Laravel uses models to access your database table.
Using the Animal model you could create a query like this:
\App\Animal::with('adoption')->select('name','dob')->get();
Then inside your Animal model, you would need to create the relationship between the animal and adoption:
public function adoption()
{
return $this->hasOne('App\Animal', 'animalID', 'animalID');
}
This would be one way to get an animal, with the adoption information.
I really recommend reading through the Laravel documentation for relationships and eloquent, and possibly read up on some SQL.
https://laravel.com/docs/5.8/eloquent
https://laravel.com/docs/5.8/eloquent-relationships

Answer 3

Assuming you have an Adoption model, and adoption relation on your Animal model, you can do the following:
$animals = Animal::select('animalName`, `DOB`)
->with(['adoption' => function($query) {
$query->where('approved', false);
})->get();