Hello Guys I am new with the query builder of laravel.
I want to convert this query into laravel query builder. Thank you in advance.
$bo_facilities = ' SELECT
a.bo_facility_code,
a.bo_facility_groupcode,
a.bo_number,
a.bo_indYesOrNo,
a.bo_indLogic,
b.bo_content_facility_description
FROM
bo_facilities AS a
RIGHT JOIN bo_content_facilities AS b
ON b.bo_content_facility_code = a.bo_facility_code AND b.bo_content_facility_facilityGroupCode = a.bo_facility_groupcode
WHERE a.bo_hotel_code = "1" GROUP BY b.bo_content_facility_description';
My groupBy method didnt work..
$join->groupBy('b.bo_content_facility_description');
this is my whole code
I didn't know the best way.
DB::table('bo_facilities AS a')
->select("a.bo_facility_code", "a.bo_facility_groupcode", "a.bo_number", "a.bo_indYesOrNo", "a.bo_indLogic", "b.bo_content_facility_description")
->join('bo_content_facilities AS b', function ($join) {
$join->on('b.bo_content_facility_code', '=', 'a.bo_facility_code');
$join->on('b.bo_content_facility_facilityGroupCode', '=', 'a.bo_facility_groupcode');
$join->groupBy('b.bo_content_facility_description');
})
->where('a.bo_hotel_code', $hotelCode)
->get();
Finally I already fixed my problem.
$bo_facilities_raw = DB::table('bo_facilities AS a')
->join('bo_content_facilities AS b', function ($join) {
$join->on([['b.bo_content_facility_code', '=', 'a.bo_facility_code'], ['b.bo_content_facility_facilityGroupCode', '=', 'a.bo_facility_groupcode']]);
})
->select("a.bo_hotel_code","a.bo_facility_code", "a.bo_facility_groupcode", "a.bo_number", "a.bo_indYesOrNo", "a.bo_indLogic", "b.bo_content_facility_description", "b.bo_content_facility_code", "b.bo_content_facility_facilityGroupCode")
->where('a.bo_hotel_code', 1)
->get();
$bo_facilities_decode = json_decode($bo_facilities_raw, true);
$remove_dupli = array_unique(array_column($bo_facilities_decode, 'bo_content_facility_description'));
$bo_facilities = array_intersect_key($bo_facilities_decode, $remove_dupli);
the duplication of records was inside the multidimensional array thats why i use array unique and array intersect key for removing the duplicate descriptions.
Related
I am trying to search with a column on a connected table using with. According to laravel the following should work.
$lineItems = Invoice::with(['invoiceHeader' => function ($query) {
$query->where('community_id', '=', 1);
}, 'invoiceLineItems'])
->limit(10)
->get()
->toArray();
However, I don't get anything from the invoiceHeader table and I get all the invoices available. If I take out the function I get the same but with invoiceHeader's table values showing up.
$lineItems = Invoice::with(['invoiceHeader', 'invoiceLineItems'])
->limit(10)
->get()
->toArray();
It seems I might be doing something of a right join where I get all the Invoices but then only the invoiceHeader values when applicable to the foreign key.
Edit:
I put ->toSql(); after the limit() and it shows I only get the following.
"select * from `invoice` limit 10"
You should use whereHas mixing with with:
$lineItems = Invoice::with(['invoiceHeader', 'invoiceLineItems'])
->whereHas('invoiceHeader', function ($query) {
return $query->where('community_id', 1);
})
->limit(10)
->get()
->toArray();
Can anyone help me out to convert this SQL to query builder!
SELECT topwords.*,
mw.word AS my_word
FROM topwords
LEFT JOIN (SELECT DISTINCT words.word
FROM definition_word
JOIN words
ON words.id = definition_word.word_id
WHERE definition_word.user_id = $user) AS mw
ON topwords.word = mw.word
I have a problem with how to use a subquery in leftjoin!
I tried something like this but it has error!
See error as image
DB::table('topwords')
->leftJoin(DB::raw("SELECT DISTINCT
words.word
FROM definition_word
JOIN words ON words.id = definition_word.word_id
WHERE definition_word.user_id = $user as mw"),"topwords.word", "=", "mw.word" )
->select(
"topwords.*",
"mw.word AS my_word"
)->orderBy('id','desc')->paginate(15);
you can use Join Sub query official document subquery-joins
$mw = DB::table('words')
->select('DISTINCT words.word')
->join('definition_word', function($join) use ($user)
{
$join->on('wordss.id', '=', 'definition_word.word_id')
->where('definition_word.user_id', $user);
});
$topwords = DB::table('topwords')
->joinSub($mw, 'mw',function ($join) {
$join->on('topwords.word', '=', 'mw.word');
})
->select('topwords.*','mw.word AS my_word')
->orderBy('id','desc')
->paginate(15);
You have this error because of paginate and aggregation
Try to make custom pagination, using LengthAwarePaginator
Here is example: Laracast
So you need to make something like this:
$query = DB::table('topwords')
->leftJoin(DB::raw("SELECT DISTINCT
words.word
FROM definition_word
JOIN words ON words.id = definition_word.word_id
WHERE definition_word.user_id = $user as mw"),"topwords.word", "=", "mw.word" )
->select(
"topwords.*",
"mw.word AS my_word"
);
$paginator = new LengthAwarePaginator($query->get(), $query->count(), $request->input('per_page', 15), $request->input('page', 1));
And then you can use it in the collection
I have a function to get a pass a language number to get language categories record for API purpose. I use a database query statement to select categories table and join the category language table to get category id, parent_id and name (specified language). When execute return error and select the underlying SQL converted the language value to string (e.g. languages_id = 1). I google a lot and no ideas what's wrong. Can anyone advise how to resolve. Thanks a lot.
I tried to copy the underlying SQL to MySQL Workbench and remove the languages_id = 1 --> languages_id = 1 can working properly. I guess the 1 caused error.
Code Sample:
private function getCategories($language) {
$categories = DB::table('categories')
->select(DB::raw('categories.id, categories.parent_id, categories_translation.name'))
->join('categories_translation', function($join) use ($language) {
$join->on('categories_translation.categories_id', '=', 'categories.id');
$join->on('categories_translation.languages_id', '=', $language);
})
->where([
['parent_id' ,'=', '0'],
['categories.id', '=', $id]
])
->get();
return $categories;
}
Error return the converted SQL:
"SQLSTATE[42S22]: Column not found: 1054 Unknown column '1' in 'on
clause' (SQL: select categories.id, categories.parent_id,
categories_translation.name from categories inner join
categories_translation on categories_translation.categories_id =
categories.id and categories_translation.languages_id = 1
where (parent_id = 0 and categories.id = 1))"
You are trying to join using a comparison to an scalar value, instead of a column. I think you actually want to put that comparison as a "where" condition, rather than a "join on"
->where([
['parent_id' ,'=', '0'],
['categories.id', '=', $id],
['categories_translation.languages_id', '=', $language]
])
there is another thing i just discover with your code. when joining table, you are suppose to be joining 'categories_translation.languages_id' with another table id field. in your case, it is not so. you are not joining 'categories_translation.languages_id' with any table field. so ideally, what you are going to do is this
private function getCategories($language) {
$categories = DB::table('categories')
->select(DB::raw('categories.id, categories.parent_id, categories_translation.name'))
->join('categories_translation', function($join) use ($language) {
$join->on('categories_translation.categories_id', '=', 'categories.id');
})
->where([
['parent_id' ,'=', '0'],
['categories.id', '=', $id]
['categories_translation.languages_id', '=', $language]
])
->get();
return $categories;
}
hope this helps
i have made a scope
public function scopeCollaborative($query){
return $query->leftJoin('collaborative', function($join){
$join->on('imms.phone2', '=', 'collaborative.phone')
->orOn('imms.phone', '=', 'collaborative.phone')
->where('collaborative.user_id', '=', App('CURUSER')->id);
});
}
in Query log this scope adds:
left join `cs_collaborative` on
`cs_imms`.`phone2` = `cs_collaborative`.`phone` or
`cs_imms`.`phone` = `cs_collaborative`.`phone` and
`cs_collaborative`.`user_id` = 3
but i need to have:
left join `cs_collaborative` on
(`cs_imms`.`phone2` = `cs_collaborative`.`phone` or
`cs_imms`.`phone` = `cs_collaborative`.`phone`) and
`cs_collaborative`.`user_id` = 3
i didn't found a good solution, JoinClause have functions: On, orOn, where, orWhere.
but non of all can take function as input and to group query...
someone ideals?
Laravel doesn't let you build such join clause, so you need this to make it work:
public function scopeCollaborative($query){
return $query->leftJoin('collaborative', function($join){
$join->on('imms.phone2', '=', 'collaborative.phone')
->where('collaborative.user_id', '=', App('CURUSER')->id)
->orOn('imms.phone', '=', 'collaborative.phone')
->where('collaborative.user_id', '=', App('CURUSER')->id);
});
}
you can consider to use Doctrine ORM is more powerfull, bur less easy in the beginning...
I'm trying to add a condition using a JOIN query with Laravel Query Builder.
<?php
$results = DB::select('
SELECT DISTINCT
*
FROM
rooms
LEFT JOIN bookings
ON rooms.id = bookings.room_type_id
AND ( bookings.arrival between ? and ?
OR bookings.departure between ? and ? )
WHERE
bookings.room_type_id IS NULL
LIMIT 20',
array('2012-05-01', '2012-05-10', '2012-05-01', '2012-05-10')
);
I know I can use Raw Expressions but then there will be SQL injection points. I've tried the following with Query Builder but the generated query (and obviously, query results) aren't what I intended:
$results = DB::table('rooms')
->distinct()
->leftJoin('bookings', function ($join) {
$join->on('rooms.id', '=', 'bookings.room_type_id');
})
->whereBetween('arrival', array('2012-05-01', '2012-05-10'))
->whereBetween('departure', array('2012-05-01', '2012-05-10'))
->where('bookings.room_type_id', '=', null)
->get();
This is the generated query by Laravel:
select distinct * from `room_type_info`
left join `bookings`
on `room_type_info`.`id` = `bookings`.`room_type_id`
where `arrival` between ? and ?
and `departure` between ? and ?
and `bookings`.`room_type_id` is null
As you can see, the query output doesn't have the structure (especially under JOIN scope). Is it possible to add additional conditions under the JOIN?
How can I build the same query using Laravel's Query Builder (if possible) Is it better to use Eloquent, or should stay with DB::select?
$results = DB::table('rooms')
->distinct()
->leftJoin('bookings', function($join)
{
$join->on('rooms.id', '=', 'bookings.room_type_id');
$join->on('arrival','>=',DB::raw("'2012-05-01'"));
$join->on('arrival','<=',DB::raw("'2012-05-10'"));
$join->on('departure','>=',DB::raw("'2012-05-01'"));
$join->on('departure','<=',DB::raw("'2012-05-10'"));
})
->where('bookings.room_type_id', '=', NULL)
->get();
Not quite sure if the between clause can be added to the join in laravel.
Notes:
DB::raw() instructs Laravel not to put back quotes.
By passing a closure to join methods you can add more join conditions to it, on() will add AND condition and orOn() will add OR condition.
If you have some params, you can do this.
$results = DB::table('rooms')
->distinct()
->leftJoin('bookings', function($join) use ($param1, $param2)
{
$join->on('rooms.id', '=', 'bookings.room_type_id');
$join->on('arrival','=',DB::raw("'".$param1."'"));
$join->on('arrival','=',DB::raw("'".$param2."'"));
})
->where('bookings.room_type_id', '=', NULL)
->get();
and then return your query
return $results;
You can replicate those brackets in the left join:
LEFT JOIN bookings
ON rooms.id = bookings.room_type_id
AND ( bookings.arrival between ? and ?
OR bookings.departure between ? and ? )
is
->leftJoin('bookings', function($join){
$join->on('rooms.id', '=', 'bookings.room_type_id');
$join->on(DB::raw('( bookings.arrival between ? and ? OR bookings.departure between ? and ? )'), DB::raw(''), DB::raw(''));
})
You'll then have to set the bindings later using "setBindings" as described in this SO post:
How to bind parameters to a raw DB query in Laravel that's used on a model?
It's not pretty but it works.
The sql query sample like this
LEFT JOIN bookings
ON rooms.id = bookings.room_type_id
AND (bookings.arrival = ?
OR bookings.departure = ?)
Laravel join with multiple conditions
->leftJoin('bookings', function($join) use ($param1, $param2) {
$join->on('rooms.id', '=', 'bookings.room_type_id');
$join->on(function($query) use ($param1, $param2) {
$query->on('bookings.arrival', '=', $param1);
$query->orOn('departure', '=',$param2);
});
})
I am using laravel5.2 and we can add joins with different options, you can modify as per your requirement.
Option 1:
DB::table('users')
->join('contacts', function ($join) {
$join->on('users.id', '=', 'contacts.user_id')->orOn(...);//you add more joins here
})// and you add more joins here
->get();
Option 2:
$users = DB::table('users')
->join('contacts', 'users.id', '=', 'contacts.user_id')
->join('orders', 'users.id', '=', 'orders.user_id')// you may add more joins
->select('users.*', 'contacts.phone', 'orders.price')
->get();
option 3:
$users = DB::table('users')
->leftJoin('posts', 'users.id', '=', 'posts.user_id')
->leftJoin('...', '...', '...', '...')// you may add more joins
->get();
For conditional params we can use where,
$results = DB::table('rooms')
->distinct()
->leftJoin('bookings', function($join) use ($param)
{
$join->on('rooms.id', '=', 'bookings.room_type_id')
->where('arrival','=', $param);
})
->where('bookings.room_type_id', '=', NULL)
->get();
There's a difference between the raw queries and standard selects (between the DB::raw and DB::select methods).
You can do what you want using a DB::select and simply dropping in the ? placeholder much like you do with prepared statements (it's actually what it's doing).
A small example:
$results = DB::select('SELECT * FROM user WHERE username=?', ['jason']);
The second parameter is an array of values that will be used to replace the placeholders in the query from left to right.
My five cents for scheme LEFT JOIN ON (.. or ..) and (.. or ..) and ..
->join('checks','checks.id','check_id')
->leftJoin('schema_risks', function (JoinClause $join) use($order_type_id, $check_group_id, $filial_id){
$join->on(function($join){
$join->on('schema_risks.check_method_id','=', 'check_id')
->orWhereNull('schema_risks.check_method_id')
;
})
->on(function($join) use ($order_type_id) {
$join->where('schema_risks.order_type_id', $order_type_id)
->orWhereNull('schema_risks.order_type_id')
;
})
->on(function($join) use ($check_group_id) {
$join->where('schema_risks.check_group_id', $check_group_id)
->orWhereNull('schema_risks.check_group_id')
;
})
->on(function($join) use($filial_id){
$join->whereNull('schema_risks.filial_id');
if ($filial_id){
$join->orWhere('schema_risks.filial_id', $filial_id);
}
})
->on(function($join){
$join->whereNull('schema_risks.check_risk_level_id')
->orWhere('schema_risks.check_risk_level_id', '>' , CheckRiskLevel::CRL_NORMALLLY );
})
;
})