I need to arrange the below data in a particular format
Code Qty
R 200
R 0
A 100
A 0
Required Output Format
Active (A) with stock (Qty > 0)
Reserve (R) with stock (Qty > 0)
Active (A) without stock (Qty = 0)
Reserve (R) without stock (Qty = 0)
In above case
A 100
R 200
A 0
R 0
Please help me on this guys. i tried using case in order by but couldnt eventually figure out the answer.
You were right to try an ORDER BY CASE. The following will give the results you're looking for:
ORDER BY CASE
WHEN CODE = 'A' AND QTY > 0 THEN 1
WHEN CODE = 'R' AND QTY > 0 THEN 2
WHEN CODE = 'A' AND QTY = 0 THEN 3
WHEN CODE = 'R' AND QTY = 0 THEN 4
END;
dbfiddle here
Best of luck.
EDIT
To accomplish the additional requirement mentioned by OP in a comment a second sort could be added to the ORDER BY:
ORDER BY CASE
WHEN CODE = 'A' AND QTY > 0 THEN 1
WHEN CODE = 'R' AND QTY > 0 THEN 2
WHEN CODE = 'A' AND QTY = 0 THEN 3
WHEN CODE = 'R' AND QTY = 0 THEN 4
END ASC,
CASE
WHEN CODE = 'A' AND QTY > 0 THEN QTY
ELSE NULL
END DESC;
new dbfiddle here
For the specific data and requirement you presented, you don't really need a case expression. (Actually I am lying - sign() is a form of case, of course.)
There is ambiguity if you have more than one row with the same combination of code and either positive qty or qty = 0; exactly the same ambiguity you left open with your problem statement.
with
inputs as (
select 'R' code, 200 qty from dual union all
select 'R' , 0 from dual union all
select 'A' , 100 from dual union all
select 'A' , 0 from dual
)
select *
from inputs
order by sign(qty) desc, code
;
CODE QTY
---- ----
A 100
R 200
A 0
R 0
Related
In Oracle I have a query that uses conditional aggregation to display totals.
See http://sqlfiddle.com/#!4/ab1915/2
select ts.description,
sum(case when ta.group_number = 1 then 1 else 0 end) group_one
,sum(case when ta.group_number = 2 then 1 else 0 end) group_two
,sum(case when ta.group_number = 3 then 1 else 0 end) group_three
from ta
join ts on ta.status_id=ts.status_id
group by ts.description;
However, I need the results to also show another row for the status "cancelled", which is not currently showed because there are not any record with that status, but I need to display "cancelled" with 0 counts anyway,
Any idea how I would do that?
The DDL for this example is
create table ta (group_number number, status_id number);
create table ts (status_id number, description varchar(111));
insert into ta (group_number,status_id) values (1,1);
insert into ta (group_number,status_id) values (2,1);
insert into ta (group_number,status_id) values (3,2);
insert into ta (group_number,status_id) values (3,3);
insert into ta (group_number,status_id) values (3,3);
Use an outer join so you pick up all of the ts valueswhich means you need to reverse the order of the tables; and I'd use count() instead of sum():
select ts.description,
count(case when ta.group_number = 1 then 1 end) group_one
,count(case when ta.group_number = 2 then 1 end) group_two
,count(case when ta.group_number = 3 then 1 end) group_three
,count(case when ta.group_number = 4 then 1 end) group_four
from ts
left join ta on ta.status_id=ts.status_id
group by ts.description;
DESCRIPTION GROUP_ONE GROUP_TWO GROUP_THREE
-------------------- ---------- ---------- -----------
started 1 1 0
finished 0 0 2
cancelled 0 0 0
progressing 0 0 1
Updated SQL Fiddle
The case expression can evaluate to anything when matched, it just has to be non-null. From the docs:
If you specify expr, then COUNT returns the number of rows where expr is not null.
so where the case is not matched it evaluates to null, which is not counted. (You can have else null if you prefer to be explicit, but I tend to prefer brevity...)
I'm using sub-query factoring and I have a query that returns invoice lines, and in the end I have this final sub-query:
I've already tried Partition but without success
SELECT
COUNT(CASE WHEN PC <> 0 THEN 1 END) AS A_LINECOUNT,
SUM(CASE WHEN PC > 0 THEN NR ELSE 0 END) AS B_PRODUCTCOUNT,
COUNT(CASE WHEN ALLOW_PAY = 1 THEN 1 END) AS C_INVOICECOUNT, --- ERROR
SUM(CASE WHEN ALLOW_PAY = 1 THEN MISSING_VALUE ELSE 0 END) AS D_INVOICETOTAL, --- ERROR
COUNT(CASE WHEN IS_NON_LIQUIDABLE_PRODUCT = 1 THEN 1 END) AS E_CONDITIONCOUNT,
COUNT(CASE WHEN IS_LIQUIDABLE_PRODUCT = 1 THEN 1 END) AS F_CONDITIONCOUNT
FROM MAIN_Q
The calculation of C_INVOICECOUNT and D_INVOICETOTAL is not correct because their values are repeated within each line of the invoice. Please consider that um MAIN_Q i also have a document_id where i can group by.
thanks
Maybe I understood correctly, maybe not, but this is too long for comment. If yes, C_INVOICECOUNT can be count as:
count(distinct case when allow_pay = 1 then document_id end)
But the problem is with D_INVOICETOTAL. You have repeated values for each invoice here and details which do not repeat. If so, add row numbering to your query:
select main_q.*, row_number() over (partition by document_id) rn from main_q
and then in problematic places use rn = 1:
select ...
count(case when rn = 1 and allow_pay = 1 then 1 end),
sum(case when rn = 1 and allow_pay = 1 then missing_value else 0 end)
...
from (select main_q.*, row_number() over (partition by document_id) rn from main_q)
Only first rows for each invoice will be analysed. Of course you can add row_number in earlier step.
I have a scenario where I have to display a row 'n' number of times depending on the value in its quantity column.
Item Qty
abc 2
cde 1
Item Qty
abc 1
abc 1
cde 1
I am looking to convert the first table to the second.
I came across the site that I should be using the recursive WITH query.
My anchor member returns the original table.
SELECT ITEM, QTY
FROM lines
WHERE
JOB = TO_NUMBER ('1')
AND ITEM IN
(SELECT PART
FROM PICK
WHERE DELIVERY = '2')
My recursive member is as follows.
SELECT CTE.ITEM, (CTE.QTY - 1) QTY
FROM CTE
INNER JOIN
(SELECT ITEM, QTY
FROM LINES
WHERE JOB_ID = TO_NUMBER ('1')
AND ITEM IN
(SELECT PART
FROM PICK
WHERE DELIVERY = '2'
)) T
ON CTE.ITEM = T.ITEM
WHERE CTE.QTY > 1
My goal is to get all the parts and quantities first then and then for all parts with qty > 1 in the recursive step generate new rows to be added to the original result set and qty displayed in the new rows would be (original qty for that part - 1). The recursion would go on until qty becomes 1 for all the parts.
So this is what I had in the end.
WITH CTE (ITEM, QTY)
AS (
SELECT ITEM, QTY
FROM lines
WHERE
JOB = TO_NUMBER ('1')
AND ITEM IN
(SELECT PART
FROM PICK
WHERE DELIVERY = '2')
UNION ALL
SELECT CTE.ITEM, (CTE.QTY - 1) QTY
FROM CTE
INNER JOIN
(SELECT ITEM, QTY
FROM LINES
WHERE JOB_ID = TO_NUMBER ('1')
AND ITEM IN
(SELECT PART
FROM PICK
WHERE DELIVERY = '2'
)) T
ON CTE.ITEM = T.ITEM
WHERE CTE.QTY > 1)
SELECT ITEM, QTY
FROM CTE
ORDER BY 1, 2 DESC
I get the following error when I try the above
"ORA-32044: cycle detected while executing recursive WITH query"
How is it getting into a cycle? What did I miss in its working?
Also, Upon reading from another website If I used a "cycle clause". I was able to stop the cycle.
The clause I used was.
CYCLE
QUANTITY
SET
END TO '1'
DEFAULT '0'
If I used this before the select statement. I'm getting the desired output but I don't feel this is the right way of going about it. What exactly is the clause doing? What is the right way of using it?
Oracle Setup:
CREATE TABLE lines ( Item, Qty ) AS
SELECT 'abc', 2 FROM DUAL UNION ALL
SELECT 'cde', 1 FROM DUAL;
CREATE TABLE pick ( part, delivery ) AS
SELECT 'abc', 2 FROM DUAL UNION ALL
SELECT 'cde', 2 FROM DUAL;
Query 1: Using a hierarchical query:
SELECT Item,
COLUMN_VALUE AS qty
FROM lines l
CROSS JOIN
TABLE(
CAST(
MULTISET(
SELECT 1
FROM DUAL
CONNECT BY LEVEL <= l.Qty
)
AS SYS.ODCINUMBERLIST
)
) t
WHERE item IN ( SELECT part FROM pick WHERE delivery = 2 )
Query 2: Using a recursive sub-query factoring clause:
WITH rsqfc ( item, qty ) AS (
SELECT item, qty
FROM lines l
WHERE item IN ( SELECT part FROM pick WHERE delivery = 2 )
UNION ALL
SELECT item, qty - 1
FROM rsqfc
WHERE qty > 1
)
SELECT item, 1 AS qty
FROM rsqfc;
Output:
ITEM | QTY
:--- | --:
abc | 1
abc | 1
cde | 1
db<>fiddle here
I have a table like this:
col | status
----+-------
1 | 0
1 | 1
2 | 1
2 | 2
3 | 1
3 | 0
I want to select only the row with having max status value. But also want to ignore if there is any 0 in status. So expected rows would be as follows (I am ignoring 1 and 3 for having status = 0).
col | status
----+-------
2 | 2
I only can pick the rows based on max(). But when I add another clause to filter the zero, it doesn't work.
SELECT col, max(status)
FROM my_table
WHERE
(select count(*)
from my_table t1
where t1.col = col
and status = 0) = 0
GROUP BY col;
Any guide will do for me.
Use HAVING clause:
SELECT col, MAX(STATUS)
FROM tab
GROUP BY col
HAVING SUM(CASE WHEN STATUS = 0 THEN 1 ELSE 0 END) = 0;
DBFiddle
If your minimal value for STATUS is 0 then you could use:
SELECT col, MAX(STATUS)
FROM tab
GROUP BY col
HAVING MIN(STATUS) > 0;
I'm a novice at SQL, but I'm sure rank() will serve the purpose.
select tabl.col, tabl.status from
(select col, status, rank over(status desc) as rnk
from tab where status = 0) tabl
where tabl.rnk = 1
and rownum = 1;
I am trying to count all the distinct ids based on conditions. But I am unable to figure out where I am going wrong with the syntax. The logic is
COUNTD(IF ([column_name1] = 1) THEN [DATAPAGEID] END)
This is the formula I used in Tableau. However when writing it in a PL/SQL query as
Select FT.NAME, COUNT(DISTINCT FT.pageID IF FT."column_name" = 1 )
as total_expected
FROM
( Sub Query) FT
Group by FT.Name
Order by FT.Name
Needless to say its throwing errors. Now I can write separate queries which can give me each number using a where condition. For example, if I wanted a count of distinct pageid where column_name1 = 1, I would write something like this
Select FT.SITENAME, COUNT(DISTINCT DATAPAGEID) as Datapage
from
(sub query)
WHERE FT."column_name" = 1
but the problem with that is that I have other calculated columns in the query which will all need to be part of the same row. To illustrate here's what the table would look like
name Calculated_Column1 Calculated_Column2 Calculated_column3
abc 781 811 96.54%
pqr 600 800 75.00%
where calculated_column3 is the result of 781/811. Therefore I can't have a new query for each column. I thought using an if condition when calculating columns will solve this, but I can't get the syntax right somehow.
Therefore, I need to know how can I create conditional calculated columns within the select query. If I have not explained this well, please let me know and I will try to clarify further.
You can use a CASE block inside the count (DISTINCT ) as shown.
SELECT FT.NAME,
COUNT(DISTINCT
CASE
WHEN DATAPAGEID = 1
THEN 1
ELSE 0
END ) Calculated_Column1,
COUNT(DISTINCT
CASE
WHEN DATAPAGEID = 2
THEN 1
ELSE 0
END ) Calculated_Column2,
( COUNT(DISTINCT
CASE
WHEN DATAPAGEID = 1
THEN 1
ELSE 0
END ) / COUNT(DISTINCT
CASE
WHEN DATAPAGEID = 2
THEN 1
ELSE 0
END ) ) * 100||'%' Calculated_Column3
FROM
( SELECT 'abc' name, 1 DATAPAGEID FROM dual
UNION ALL
SELECT 'abc' name, 1 DATAPAGEID FROM dual
UNION ALL
SELECT 'pqr' name, 2 DATAPAGEID FROM dual
UNION ALL
SELECT 'pqr' name, 2 DATAPAGEID FROM dual
UNION ALL
SELECT 'pqr' name, 3 DATAPAGEID FROM dual
) FT
GROUP BY FT.Name
ORDER BY FT.Name;
Output is
abc 1 1 100%
pqr 1 2 50%