how to awk pattern as variable and loop the result? - shell

Question

I assign a keyword as variable, and need to awk from a file using this variable and loop. The file has millions of lines.
i have tried the code below.
DEVICE="DEV2"
while read -r line
do
echo $line
X_keyword=`echo $line | cut -d ',' -f 2 | grep -w "X" | cut -d '=' -f2`
echo $X_keyword
done <<< "$(grep -w $DEVICE $config)"
log="Dev2_PRT.log"
while read -r file
do
VALUE=`echo $file | cut -d '|' -f 1`
HEADER=`echo $VALUE | cut -c 1-4`
echo $file
if [[ $HEADER = 'PTR:' ]]; then
VALUE=`echo $file | cut -d '|' -f 4`
echo $VALUE
XCOORD+=($VALUE)
((X++))
fi
done <<< "awk /$X_keyword/ $log"
expected result:
the log files content lots of below:
PTR:1|2|3|4|X_keyword
PTR:1|2|3|4|Y_rest .....
Filter the X_keyword and get the field no 4.

Answer 1

Unfortunately your shell script is simply the wrong approach to this problem (see https://unix.stackexchange.com/q/169716/133219 for some of the reasons why) so you should set it aside and start over.
To demonstrate the solution, lets create a sample input file:
$ seq 10 | tee file
1
2
3
4
5
6
7
8
9
10
and a shell variable to hold a regexp that's a character list of the chars 5, 6, or 7:
$ var='[567]'
Now, given the above input, here is the solution for how to g/re/p pattern as variable and count how many results:
$ awk -v re="$var" '$0~re{print; c++} END{print "---" ORS c+0}' file
5
6
7
---
3
If that's not all you need then please edit your question to clarify your requirements and provide concise, testable sample input and expected output.