How to count rows from two columns? - oracle

Question

I try to create the function login that takes customer number(pnr) and password from same table. Its fine to create function but test crashes with following eror:
ORA-00904: "P_PASSWD": invalid identifier
create or replace function logga_in(
p_pnr bankkund.pnr%type,
p_passwd bankkund.passwd%type
)
return number
as
v_resultat number(1);
begin
select count(pnr) into v_resultat
from bankkund
where p_pnr = pnr
and p_passwd = passwd;
return 1;
exception
when no_data_found then
return 0;
end;

Answer 1

There is one other problem with your code not suggested in the comments, A count function from a select into will not raise a NO_DATA_FOUND exception. You may use an IF condition on count or do something like this, which is preferable
CREATE OR REPLACE FUNCTION logga_in (
p_pnr bankkund.pnr%TYPE,
p_passwd bankkund.passwd%TYPE
) RETURN NUMBER AS
v_resultat NUMBER(1);
BEGIN
SELECT 1 --do not use count if you wish to handle no_data_found
INTO v_resultat FROM
bankkund WHERE pnr = p_pnr AND
passwd = p_passwd
AND ROWNUM = 1; --Add this
RETURN 1;
EXCEPTION
WHEN no_data_found THEN
RETURN 0;
END;
Now, as far as calling the procedure is concerned, there are various options available including using bind variable
VARIABLE p_pnr number --use the datatype of bankkund.pnr%TYPE
VARIABLE p_passwd VARCHAR2(10) --use the datatype of bankkund.passwd
SELECT logga_in(:p_pnr,:p_passwd) FROM dual;
Or substitution variable
SELECT logga_in('&p_pnr','&p_passwd') FROM dual;
Give inputs when prompted.
Or use PL/SQL block
DECLARE
v_res INT;
v_pnr bankkund.pnr%type := 12892; --or appropriate value
p_passwd bankkund.passwd%type := some_passwd';
BEGIN
v_res := logga_in();
If v_res = 1 THEN
do_something_u_want; --call or execute appropriate action.
END IF;
END;
/