How to format a number with XPath in Tibco BW 5 - xpath

I've managed to format the following lines in XPath, from this format:
1000.50
30
to this:
100050
3000
The solution I've adopted is:
concat(substring-before([number], '.'), substring-after([number], '.'))
If the . is not present I directly multiply the number by 100.
I'm wondering if there is any better way to do that. My second thought was using Java.

What goes wrong if you just multiply by 100? So long as the result of multiplying by 100 is an exact integer, it should be formatted without a "." when converted to a string. If there are rounding errors that mean the result is not an exact integer, you might want to use round().
The concat() approach seems fragile to me: what if someone gives you input like 1000.5 or perhaps 1000.500?

Related

Qtp add more than 15 strings or convert more than 15 strings

Can someone please guide me on how to convert more than 6 characters into int? Because I need to do sum after convert to int. I tried so many ways like CInt, CLng, etc still throw exponential value.
Stroutput = 2018050302216556
Sum = Stroutput + 1
I tried to divide into sveral chuck using right function but it doesnt look good. Can be manage but I need another option. Thanks
You seem to be working with a Date Structure, which as VBS says - hard to represent as numbers only. Use the CDate to get a date object from the string (If needed change the representation of that string to (YYYY-mm-dd ...). With the DateAdd method you can add days, years etc; and finally the FormatDateTime will create an output of your wish.

rounding a number in ruby

I would like to round this figure to the nearest whole number. I am generating an xml based on an excel file, and would like to round the figure.
Here is my code:
xml.POS110 “wert”: “#{row[18]}”
I have tried:
xml.POS110 “wert”: “#{row[18]}”.round(0)
Move the round inside the quotes. Before, you were just trying to round a string. Also the default argument for round is 0 so you don't need to specify it (but you can if you really want to).
“#{row[18].round(0)}"

How can I combine comma format with scientific format in SAS?

I have data that I would like to represent as comma10.2 when less than 1,000,000 and e10. when greater than or equal to 1,000,000. It seems like there might be a way to do this using the picture format, so I thought I might also making missing values show up as --. This is what I've got so far:
proc format;
picture DashMiss . = '--' (noedit)
low - <1000000 = "000,009.99"
1000000 - high = ????;
run;
I'm not sure how to represent scientific notation using picture (hence the question marks). I don't have to just use picture if there's an easier way to do it.
I figured out how to use brackets to add the conditional format:
proc format;
picture DashMiss . = '--' (noedit)
low - <1000000 = "000,009.99"
1000000 - high = [e10.];
run;
I believe you could've simply used the best6. format or bestd6.2 to achieve the same results. It naturally uses scientific notation whenever the length is beyond the first of the 2 integers.

Format statement with unknown columns

I am attempting to use fortran to write out a comma-delimited file for import into another commercial package. The issue is that I have an unknown number of data columns. My output needs to look like this:
a_string,a_float,a_different_float,float_array_elem1,float_array_elem2,...,float_array_elemn
which would result in something that might look like this:
L1080,546876.23,4325678.21,300.2,150.125,...,0.125
L1090,563245.1,2356345.21,27.1245,...,0.00983
I have three issues. One, I would prefer the elements to be tightly grouped (variable column width), two, I do not know how to define a variable number of array elements in the format statement, and three, the array elements can span a large range--maybe 12 orders of magnitude. The following code conceptually does what I want, but the variable 'n' and the lack of column-width definition throws an error (of course):
WRITE(50,900) linenames(ii),loc(ii,1:2),recon(ii,1:n)
900 FORMAT(A,',',F,',',F,n(',',F))
(I should note that n is fixed at run-time.) The write statement does what I want it to when I do WRITE(50,*), except that it's width-delimited.
I think this thread almost answered my question, but I got quite confused: SO. Right now I have a shell script with awk fixing the issue, but that solution is...inelegant. I could do some manipulation to make the output a string, and then just write it, but I would rather like to avoid that option if at all possible.
I'm doing this in Fortran 90 but I like to try to keep my code as backwards-compatible as possible.
the format close to what you want is f0.3, this will give no spaces and a fixed number of decimal places. I think if you want to also lop off trailing zeros you'll need to do a good bit of work.
The 'n' in your write statement can be larger than the number of data values, so one (old school) approach is to put a big number there, eg 100000. Modern fortran does have some syntax to specify indefinite repeat, i'm sure someone will offer that up.
----edit
the unlimited repeat is as you might guess an asterisk..and is evideltly "brand new" in f2008
In order to make sure that no space occurs between the entries in your line, you can write them separately in character variables and then print them out using theadjustl() function in fortran:
program csv
implicit none
integer, parameter :: dp = kind(1.0d0)
integer, parameter :: nn = 3
real(dp), parameter :: floatarray(nn) = [ -1.0_dp, -2.0_dp, -3.0_dp ]
integer :: ii
character(30) :: buffer(nn+2), myformat
! Create format string with appropriate number of fields.
write(myformat, "(A,I0,A)") "(A,", nn + 2, "(',',A))"
! You should execute the following lines in a loop for every line you want to output
write(buffer(1), "(F20.2)") 1.0_dp ! a_float
write(buffer(2), "(F20.2)") 2.0_dp ! a_different_float
do ii = 1, nn
write(buffer(2+ii), "(F20.3)") floatarray(ii)
end do
write(*, myformat) "a_string", (trim(adjustl(buffer(ii))), ii = 1, nn + 2)
end program csv
The demonstration above is only for one output line, but you can easily write a loop around the appropriate block to execute it for all your output lines. Also, you can choose different numerical format for the different entries, if you wish.

SSRS 2008: Using StDevP from multiple fields / Combining multiple fields in general

I'd like to calculate the standard deviation over two fields from the same dataset.
example:
MyFields1 = 10, 10
MyFields2 = 20
What I want now, is the standard deviation for (10,10,20), the expected result is 4.7
In SSRS I'd like to have something like this:
=StDevP(Fields!MyField1.Value + Fields!MyField2.Value)
Unfortunately this isn't possible, since (Fields!MyField1.Value + Fields!MyField2.Value) returns a single value and not a list of values. Is there no way to combine two fields from the same dataset into some kind of temporary dataset?
The only solutions I have are:
To create a new Dataset that contains all values from both fields. But this is very annoying because I need about twenty of those and I have six report parameters that need to filter every query. => It's probably getting very slow and annoying to maintain.
Write the formula by hand. But I don't really know how yet. StDevP is not that trivial to me. This is how I did it with Avg which is mathematically simpler:
=(SUM(Fields!MyField1.Value)+SUM(Fields!MyField2.Value))/2
found here: http://social.msdn.microsoft.com/Forums/is/sqlreportingservices/thread/7ff43716-2529-4240-a84d-42ada929020e
Btw. I know that it's odd to make such a calculation, but this is what my customer wants and I have to deliver somehow.
Thanks for any help.
CTDevP is standard deviation.
Such expression works fine for me
=StDevP(Fields!MyField1.Value + Fields!MyField2.Value) but it's deviation from one value (Fields!MyField1.Value + Fields!MyField2.Value) which is always 0.
you can look here for formula:
standard deviation (wiki)
I believe that you need to calculate this for some group (or full dataset), to do this you need set in the CTDevP your scope:
=StDevP(Fields!MyField1.Value + Fields!MyField2.Value, "MyDataSet1")

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