Opposite of required_if in laravel using multiple value evaluation - laravel

Question

How to validate must null if another field has specific value or not null
In my case it is the opposite of required_if with multiple values
$rule = array(
'selection' => 'required',
'stext' => 'required_if:selection,2|required_if:selection,3',// stext should be null if selection is 2 or 3
);
And if needed how to perform own validation?

Answer 1

So in your example you can do something like this:
$rule = array(
'selection' => 'required',
'stext' => 'required'
);
// override the rule
if(in_array(request('selection'), [2, 3]))
{
$rule['stext'] = 'nullable';
}
This means if the selection is 2 the field will be required and if the selection field has any other value the stext field will be required.
I am not sure if I understood your question correctly. In any case the opposite of required_if is required_without so you can use that one if you want this field to be required even if the selection is empty.
With custom rule your passes method should look like this:
namespace App\Rules;
use Illuminate\Contracts\Validation\Rule;
class CustomRule implements Rule
{
protected $selection;
public __construct($selection)
{
$this->selection = $selection;
}
public function passes($attribute, $value)
{
return $value === null && in_array($this->selection, [2, 3]);
}
}
You use it like this:
$rule['stext'] = [ new CustomRule(request('selection') ]

Answer 2

I try to extend the validation rule. put the following in AppServiceProvider:
Validator::extend('null_if', function ($attribute, $value, $parameters, $validator) {
$other = $parameters[0];
$other_value = array_get(request()->toArray(), $other);
if ($parameters[1] == $other_value) {
return empty($value);
}
return true;
});
Tell me if it's work or what error given to you.