Laravel - Get Data from Table where clause in other table - laravel

I have this following 2 tables:
Table: Products
+----+---------+-------------+
| id | fn_id | created_at |
+----+---------+-------------+
| 1 | 4 | SOME TIME |
| 2 | 5 | SOME TIME |
| 3 | 6 | SOME TIME |
| 4 | 10 | SOME TIME |
| 5 | 10 | SOME TIME |
+----+---------+-------------+
Table Fn
+----+---------+-------------+
| id | fn_id | created_at |
+----+---------+-------------+
| 1 | 10 | SOME TIME |
| 2 | 11 | SOME TIME |
| 3 | 12 | SOME TIME |
| 4 | 14 | SOME TIME |
+----+---------+-------------+
And a User Input which is giving me a timestamp ($user_timestamp).
Now I need to get all produtcs, where
products.fn_id is 10
fn.fn_id is 10
fn.created == $user_timestamp
The products model has this relation:
public function fn() {
return $this->hasMany('App\FN', 'fn_id', 'fn_id');
}
Now I've tried multiple things like a where query where I want to check if the fn_id on both are "10" and the created_at value of the fn table is equal to $user_timestamp.
However, I wasn't able to do it.
$products = Products::with('fn')->where('fn.fn_id', function ($query) use ($user_timestamp) {
$query->where([['fn_id', 10],['created_at', $user_timestamp]]);
})->get();

You would have to use whereHas to constrain Products based on fn.
$products = Products::with('fn')->whereHas('fn', function($q) use($user_timestamp){
$q->where('fn_id', 10)->where('created_at', $user_timestamp);
})->get();

try this
$id_to_search=10;
$products = Products::with('fn')->where('fbn_id',$id_to_search)->whereHas('fn', function($q) use($user_timestamp,$id_to_search){
$q->where('fn_id', $id_to_search)->where('created_at', $user_timestamp);
})->get();

Related

How Products is order by relation in Laravel?

How can I sort the products in table1 according to their connection with table2 i.e. sort the products in table1 by example_relation in table2?
Table1
| id | product |
|----|---------|
| 1 | pro1 |
| 2 | pro2 |
| 3 | pro3 |
| 4 | pro4 |
| 5 | pro5 |
Table2
| id | example_relation | product_id |
|----|------------------|------------|
| 1 | 700 | 1 |
| 2 | 800 | 2 |
| 3 | 900 | 3 |
| 4 | 850 | 2 |
| 5 | 600 | 4 |
| 6 | 125 | 5 |
Table1 model page:
public $belongsTo = [
'pro_relation' => [
'models\Model',
'key' => 'id',
'otherKey' => 'product_id',
],
Sorting section that needs to be arranged correctly:
$query->whereHas('pro_relation', function($q) use ($postFrom,$postTo){
$q->select('example_relation END AS expose');
})->orderBy("expose", DESC);
Okay, when you want to order the result of one table from another table then you can use orderBy() inside a closure of the relationship to another table.
So from your query, you can add orderBy() like so.
$query->whereHas('pro_relation', function($q) use ($postFrom,$postTo){
$q->select('example_relation END AS expose')
->orderBy('example_relation');
});
This is work
$query->join('table2', 'table1.id', '=', 'table2.yacht_id')
->orderBy(example_relation DESC);

Laravel - Eloquent filter where Left Join does not exist

I am trying to figure out how to make this query work. These two tables do not have a direct relation (i.e. hasOne, hasMany, etc). I am looking to only get back records from client_vendor_relationship that do NOT have a collection_opt_in. Since I don't have a way of doing ->whereDoesntHave(), I am not sure how to get this data back.
client_vendor_relationship
| id | client_id | vendor_id | active |
|----|-----------|-----------|--------|
| 1 | 23484 | 1872 | 1 |
| 2 | 5643 | 345 | 1 |
| 3 | 431 | 4443 | 1 |
collection_opt_in
| id | client_id | vendor_id | year |
|----|-----------|-----------|------|
| 1 | 23484 | 23484 | 2020 |
| 2 | 23484 | 23484 | 2019 |
| 3 | 431 | 4443 | 2019 |
Current Query
$relationships = ClietVendorRelationship::where('active', 1)
->leftJoin('collection_opt_in', function($join){
$join->on('client_vendor_relationship.client_id', '=', 'collection_opt_in.client_id')
->on('client_vendor_relationship.vendor_id', '=', 'collection_opt_in.vendor_id');
})
->where() // Not sure what to put here to ONLY get rows back that the left join didnt find entries for
->groupBy('client_vendor_relationship.id')
->get();
The end goal of this above query would to be to only get the row back from client_vendor_relationship with the id of 2. I need to do this in Eloquent. I know I could easily just do a collection filter but the front end table I am using requires an eloquent query to be returned.
why using left join? while there is another straightforward ways?
you can use 'whereNotExists':
$relationships = ClietVendorRelationship::where('active', 1)
->whereNotExists(function ( $query){
$query->select('collection_opt_in.id')->from('collection_opt_in')->
whereColumn('collection_opt_in.client_id', '=', 'client_vendor_relationship.client_id')->
whereColumn('collection_opt_in.vendor_id', '=', 'client_vendor_relationship.vendor_id');
})
->groupBy('client_vendor_relationship.id')
->get();
also i must say i don't recommend using group by without aggregation

Laravel eloquent whereHas where first date equals a specific date

I have two related tables:
projects:
| id | name |
| 1 | Test |
| 2 | Example |
project_dates:
| id | project_id | date |
| 1 | 1 | 2020-02-01 |
| 2 | 1 | 2020-02-10 |
| 3 | 1 | 2020-01-25 |
| 4 | 2 | 2020-01-10 |
| 5 | 2 | 2019-12-15 |
Now for example I would like to get all projects where the first date of project_dates is equal to 2020-01-25. So I tried the following:
$projects = Project::whereHas('dates', function($query) {
$query->whereRaw("MIN(date) = '2020-01-25'");
});
But this returns the following error:
SQLSTATE[HY000]: General error: 1111 Invalid use of group function
which revers to MIN(date). So my question remains how can I get all projects with the first date being equal to 2020-01-25 or any other specific date. From the example above I would expect to get the project with id 1 since the first date of 2 is 2019-12-15
I know that is possible to use a subqueryjoin however I feel like doing 2 queries shouldn't be required.
$firstDates = ProjectDate::groupBy('project_id')
->selectRaw('project_id, MIN(date) as first_date');
Project::joinSub($firstDates, 'first_dates', function($join){
$join->on('first_dates.project_id', '=', 'project.id')
->where('first_date', '=','2020-01-25');
})->get();
You cannot use where aggregate function with groupBy, try to use havingRaw instead:
$projects = Project::whereHas('dates', function($query) {
$query->havingRaw("MIN(date) = ?", ['2020-01-25']);
});
// Or
$projects = Project::whereHas('dates', function($query) {
$query->having(DB::raw("MIN(date)"), '2020-01-25');
});
$projects = Project::whereHas('dates', function($query) {
$query->having(DB::raw("MIN(date)"), '2020-01-25')
->groupBy( 'project_dates.id' ); // For sql_mode=only_full_group_by
});

Laravel: Query the models where the relationship is greater than 0

I'm doing a Laravel query to query a list of elements that his relationship is grater than 0.
The table concerts:
| ID | NAME |
|----|-----------|
| 1 | Concert A |
| 2 | Concert B |
| 3 | Concert C |
And the Position table.
| ID | concert_id | user_id | Content |
|----|----------------|------------|----------|
| 1 | 1 | 1 | xxx |
| 2 | 1 | 2 | yyy |
| 3 | 3 | 1 | zzz |
| 4 | 3 | 2 | www |
| 5 | 1 | 3 | xyx |
| 6 | 3 | 3 | rer |
The query that I need to do is, get the concerts where their position has in the content a value like $some_query$.
The code I've is the following:
$result = $this->model->whereHas('positions')
->with(['positions' => function ($query) {
$query->where('content', 'like', "%{$content}%");
}])->get();
But as far as I can tell, this will bring all the concerts, and also this is going to bring only the positions that has the desired content.
So I've two problems, the first one is I need to get the concerts that his queried positions are greather than 0.
And the second one is that also I need to bring all the positions, not only the queried ones.
Basically the query is just a way to know which concerts I need to bring.
Is there possible to achieve this on a single query?
You'll have to move your query to the whereHas.
If I understood well, this is what you want:
$result = $this->model
// Take the Concerts that has positions with a similar content
->whereHas('positions', function ($query) use ($content) {
$query->where('content', 'like', "%{$content}%");
})
// Take (all) the Positions of these concerts
->with('positions')
->get();

I need to write eloquent query that return messages having specific tag

messages Table
+----+----------+
| id | text |
+----+----------+
| 1 | message1 |
| 2 | message2 |
+----+----------+
tags table
+----+-----------+
| id | name |
+----+-----------+
| 1 | valentine |
| 2 | funny |
| 3 | santa |
+----+-----------+
message_tag
+----+------------+--------+
| id | message_id | tag_id |
+----+------------+--------+
| 1 | 1 | 1 |
| 2 | 2 | 1 |
| 3 | 2 | 2 |
+----+------------+--------+
I have written this query so far to get all messages but i cant return the
message where tag_id = 1;
Message::with([
'tags'=>function($q){
$q->select("name","tag_id");
}
])->select("id", "text")->paginate(10);
i have used where clause inside function($q){$q->where('tag_id',1)}. but it didn't worked.
You have to include use Illuminate\Support\Facades\DB; at the top of class
$tagId = 1;
$return = DB::table('message_tag')
->join('messages', 'messages.id', '=', 'message_tag.message_id')
->join('tags', 'tags.id', '=', 'message_tag.tag_id')
->where("message_tag.tag_id", "=", $tagId)
->select('messages.text', 'tags.text')
->get();
Try using whereHas(), assuming you set a many-to-many relationship properly:
$tag = 'Madhab452';
$messages = Message::whereHas('tags', function ($query) use ($tag) {
$query->where('name', '=', $tag)
->select('name', 'tag_id');
})->get();

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