How to delete line from CSV as they are read in Bash - bash

Question

I am currently doing this:
while read l
do
echo git add $l/
git add $l/
# sed -i -e '1,1d' data/commit-folders.csv
# echo git commit -am "'Autocommit'"
# git commit -uno -am "'Autocommit'"
# echo git push origin master
# git push origin master
done < data/commit-folders.csv
Essentially just git add <folder> for a list of folders in a CSV file. I would like for this to be more robust, in that every time it restarts it restarts from where it left off. So I added that commented out line which does an in-place delete sed -i -e '1,1d' data/commit-folders.csv. However, with while read line, it messes up with the current line if they are being deleted. So I'm wondering how to do this properly.
How to iterate through a CSV file with <path> on each line, and delete the path once it is successfully git added. It seems like you need to have a loop that selects the first line from a file, and then deletes it from the file afterwards, rather than using while read line.

Answer 1

Here a solution without sed.
#!/bin/bash
csv="data/commit-folders.csv"
done="$(mktemp)"
# autoremove tempfile at exit
trap 'rm "$done"' EXIT
# loop over all lines in csv
while read -r file; do
printf "git add %s\n" "$file"
git add "$file"
# write processed files in tempfile
printf "%s\n" "$file" >> "$done"
#...
done < "$csv"
# create tempfile for merge result
newfile="$(mktemp)"
# sort: merge and sort $cvs with $done
# uniq -u: write only unique files into tempfile
sort "$csv" "$done" | uniq -u > "$newfile"
# override $csv with tempfile
mv "$newfile" "$csv"

Answer 2

you can use sed -i "/${l}/d" , it will find the exact line and delete it. This assumes that there would be no duplicate lines.
while read l
do
echo git add $l/
git add $l/
# sed -i -e '1,1d' data/commit-folders.csv
sed -i "/${l}/d" data/commit-folders.csv
# echo git commit -am "'Autocommit'"
# git commit -uno -am "'Autocommit'"
# echo git push origin master
# git push origin master
done < data/commit-folders.csv