How to pass arguments directy to a class without calling new method? - ruby

In Ruby a Hash can be created by:
Hash(a: 5, b: 6)
An Array can be created like this:
Array(100)
Sets can be created with the code:
require 'set'
Set[1,2,3]
So, how can I define a class that can accept arguments without calling the initialize method?

So, how can I define a class that can accept arguments without calling the initialize method?
You can't. In your examples, Hash and Array are actually methods.
And example with Set uses Set::[], naturally. And so it's not any different from any other class method that returns you instances of that class. For instance, User::create (or what-have-you).

In Ruby a Hash can be created by:
Hash(a: 5, b: 6)
Hash() is actually a method of the Kernel module:
p defined?(Hash()) # => "method"
p defined?(Kernel.Hash()) # => "method"
But without parentheses, Hash, Array, String, etc. all are just classes:
defined?(Hash) # => "constant"
defined?(Array) # => "constant"
In Ruby 2.6.3, the same goes for Arrays(), Complex(), Float(), Hash(), Integer(), Rational(), String(), and URI() - they all are methods.
But Set is a class:
require 'set'
p defined?(Set) # => "constant"
p set = Set[1,2,3] # => #<Set: {1, 2, 3}>
p set.to_a # => [1, 2, 3]
So, Set[1,2,3] is actually calling the [] method of Set. It looks kind of like this:
class Something
def initialize(*a)
#hash = {}
a.each { |v| #hash.store(v, nil) }
end
def self.[](*a) new(*a) end
define_method(:to_a) { #hash.keys }
define_method(:inspect) { "#<#{self.class}: {#{#hash.keys.to_s[1..-2]}}>" }
alias :to_s :inspect
end
p defined?(Something) # => "constant"
p set = Something[1,2,3] # => #<Something: {1, 2, 3}>
p set1 = Something[[1, 2, 3], 2, 2, 3, 4, {4 => :a}, 5] # => #<Something: {[1, 2, 3], 2, 3, 4, {4=>:a}, 5}>
p set.to_a # => [1, 2, 3]
p set1.to_a # => [[1, 2, 3], 2, 3, 4, [4, 4], 5]
Back to the question:
So, how can I define a class that can accept arguments without calling
the initialize method?
I don't think it's possible!

Related

How to create a function in Ruby that take a average of an array?

I tried something like this:
def average_array_float(&array)
array.inject{ |sum, el| sum + el }.to_f / array.size
end
no success
array = [1, 2, 3]
def even_numbers(array)
array.select { |num| num.even? }
end
p array.even_numbers
reply:
$ bundle exec ruby main.rb
Traceback (most recent call last):
main.rb:7:in `<main>': private method `even_numbers' called for [1, 2, 3]:Array (NoMethodError)
exit status 1
what i am doing wrong?
You have to pass the array to the method:
def even_numbers(array)
array.select { |num| num.even? }
end
array = [1, 2, 3, 4, 5, 6]
even_numbers(array)
#=> [2, 4, 6]
The NoMethodError in your example happens because if you define a method on the top-level, it becomes a private method of Object:
Object.private_methods
#=> [:initialize, :inherited, :method_added, :method_removed, :method_undefined,
# :remove_const, :initialize_copy, :initialize_clone, :using, :public,
# :ruby2_keywords, :protected, :private, :included, :extended, :prepended,
# :even_numbers, :sprintf, :format, ...]
# ^^^^^^^^^^^^^
And since array is an Object, it can access that method (privately).
If you really wanted to add the method to Array, you could open the corresponding class:
class Array
def even_numbers
select { |num| num.even? }
end
end
Which gives you:
[1, 2, 3, 4, 5, 6].even_numbers
#=> [2, 4, 6]
However, although this works, it's not advised to alter objects that are not your own, let alone Ruby's core classes.
Regarding your other method, you could use sum and fdiv:
def average(array)
array.sum.fdiv(array.size)
end
average([1, 2, 4])
#=> 2.3333333333333335
Or quo if you prefer a precise result:
def average(array)
array.sum.quo(array.size)
end
average([1, 2, 4])
#=> (7/3)

How to get reference to object you're calling in method?

I am trying to create a method for objects that I create. In this case it's an extension of the Array class. The method below, my_uniq, works. When I call puts [1, 1, 2, 6, 8, 8, 9].my_uniq.to_s it outputs to [1, 2, 6, 8].
In a similar manner, in median, I'm trying to get the reference of the object itself and then manipulate that data. So far I can only think of using the map function to assign a variable arr as an array to manipulate that data from.
Is there any method that you can call that gets the reference to what you're trying to manipulate? Example pseudo-code that I could replace arr = map {|n| n} with something like: arr = self.
class Array
def my_uniq
hash = {}
each do |num|
hash[num] = 0;
end
hash.keys
end
end
class Array
def median
arr = map {|n| n}
puts arr.to_s
end
end
Thanks in advance!
dup
class Array
def new_self
dup
end
def plus_one
arr = dup
arr.map! { |i| i + 1 }
end
def plus_one!
arr = self
arr.map! { |i| i + 1 }
end
end
array = [1, 3, 5]
array.new_self # => [1, 3, 5]
array.plus_one # => [2, 4, 6]
array # => [1, 3, 5]
array.plus_one! # => [2, 4, 6]
array # => [2, 4, 6]
dup makes a copy of the object, making it a safer choice if you need to manipulate data without mutating the original object. You could use self i.e. arr = self, but anything you do that changes arr will also change the value of self. It's a good idea to just use dup.
If you do want to manipulate and change the original object, then you can use self instead of dup, but you should make it a "bang" ! method. It is a convention in ruby to put a bang ! at the end of a method name if it mutates the receiving object. This is particularly important if other developers might use your code. Most Ruby developers would be very surprised if a non-bang method mutated the receiving object.
class Array
def median
arr = self
puts arr.to_s
end
end
[1,2,3].median # => [1,2,3]

Can the Ruby &: operator take arguments? [duplicate]

You're probably familiar with the following Ruby shorthand (a is an array):
a.map(&:method)
For example, try the following in irb:
>> a=[:a, 'a', 1, 1.0]
=> [:a, "a", 1, 1.0]
>> a.map(&:class)
=> [Symbol, String, Fixnum, Float]
The syntax a.map(&:class) is a shorthand for a.map {|x| x.class}.
Read more about this syntax in "What does map(&:name) mean in Ruby?".
Through the syntax &:class, you're making a method call class for each array element.
My question is: can you supply arguments to the method call? And if so, how?
For example, how do you convert the following syntax
a = [1,3,5,7,9]
a.map {|x| x + 2}
to the &: syntax?
I'm not suggesting that the &: syntax is better.
I'm merely interested in the mechanics of using the &: syntax with arguments.
I assume you know that + is a method on Integer class. You can try the following in irb:
>> a=1
=> 1
>> a+(1)
=> 2
>> a.send(:+, 1)
=> 2
You can create a simple patch on Symbol like this:
class Symbol
def with(*args, &block)
->(caller, *rest) { caller.send(self, *rest, *args, &block) }
end
end
Which will enable you to do not only this:
a = [1,3,5,7,9]
a.map(&:+.with(2))
# => [3, 5, 7, 9, 11]
But also a lot of other cool stuff, like passing multiple parameters:
arr = ["abc", "babc", "great", "fruit"]
arr.map(&:center.with(20, '*'))
# => ["********abc*********", "********babc********", "*******great********", "*******fruit********"]
arr.map(&:[].with(1, 3))
# => ["bc", "abc", "rea", "rui"]
arr.map(&:[].with(/a(.*)/))
# => ["abc", "abc", "at", nil]
arr.map(&:[].with(/a(.*)/, 1))
# => ["bc", "bc", "t", nil]
And even work with inject, which passes two arguments to the block:
%w(abecd ab cd).inject(&:gsub.with('cde'))
# => "cdeeecde"
Or something super cool as passing [shorthand] blocks to the shorthand block:
[['0', '1'], ['2', '3']].map(&:map.with(&:to_i))
# => [[0, 1], [2, 3]]
[%w(a b), %w(c d)].map(&:inject.with(&:+))
# => ["ab", "cd"]
[(1..5), (6..10)].map(&:map.with(&:*.with(2)))
# => [[2, 4, 6, 8, 10], [12, 14, 16, 18, 20]]
Here is a conversation I had with #ArupRakshit explaining it further:
Can you supply arguments to the map(&:method) syntax in Ruby?
As #amcaplan suggested in the comment below, you could create a shorter syntax, if you rename the with method to call. In this case, ruby has a built in shortcut for this special method .().
So you could use the above like this:
class Symbol
def call(*args, &block)
->(caller, *rest) { caller.send(self, *rest, *args, &block) }
end
end
a = [1,3,5,7,9]
a.map(&:+.(2))
# => [3, 5, 7, 9, 11]
[(1..5), (6..10)].map(&:map.(&:*.(2)))
# => [[2, 4, 6, 8, 10], [12, 14, 16, 18, 20]]
Here is a version using Refinements (which is less hacky than globally monkey patching Symbol):
module AmpWithArguments
refine Symbol do
def call(*args, &block)
->(caller, *rest) { caller.send(self, *rest, *args, &block) }
end
end
end
using AmpWithArguments
a = [1,3,5,7,9]
a.map(&:+.(2))
# => [3, 5, 7, 9, 11]
[(1..5), (6..10)].map(&:map.(&:*.(2)))
# => [[2, 4, 6, 8, 10], [12, 14, 16, 18, 20]]
For your example can be done a.map(&2.method(:+)).
Arup-iMac:$ pry
[1] pry(main)> a = [1,3,5,7,9]
=> [1, 3, 5, 7, 9]
[2] pry(main)> a.map(&2.method(:+))
=> [3, 5, 7, 9, 11]
[3] pry(main)>
Here is how it works :-
[3] pry(main)> 2.method(:+)
=> #<Method: Fixnum#+>
[4] pry(main)> 2.method(:+).to_proc
=> #<Proc:0x000001030cb990 (lambda)>
[5] pry(main)> 2.method(:+).to_proc.call(1)
=> 3
2.method(:+) gives a Method object. Then &, on 2.method(:+), actually a call #to_proc method, which is making it a Proc object. Then follow What do you call the &: operator in Ruby?.
As the post you linked to confirms, a.map(&:class) is not a shorthand for a.map {|x| x.class} but for a.map(&:class.to_proc).
This means that to_proc is called on whatever follows the & operator.
So you could give it directly a Proc instead:
a.map(&(Proc.new {|x| x+2}))
I know that most probably this defeats the purpose of your question but I can't see any other way around it - it's not that you specify which method to be called, you just pass it something that responds to to_proc.
There is another native option for enumerables which is pretty only for two arguments in my opinion. the class Enumerable has the method with_object which then returns another Enumerable.
So you can call the & operator for a method with each item and the object as arguments.
Example:
a = [1,3,5,7,9]
a.to_enum.with_object(2).map(&:+) # => [3, 5, 7, 9, 11]
In the case you want more arguments you should repeat the proccess but it's ugly in my opinion:
a = [1,3,5,7,9]
a.to_enum.with_object(2).map(&:+).to_enum.with_object(5).map(&:+) # => [8, 10, 12, 14, 16]
Short answer: No.
Following #rkon's answer, you could also do this:
a = [1,3,5,7,9]
a.map &->(_) { _ + 2 } # => [3, 5, 7, 9, 11]
if all your method needs as argument is an element from the array, this is probably the simplest way to do it:
def double(x)
x * 2
end
[1, 2, 3].map(&method(:double))
=> [2, 4, 6]
Instead of patching core classes yourself, as in the accepted answer, it's shorter and cleaner to use the functionality of the Facets gem:
require 'facets'
a = [1,3,5,7,9]
a.map &:+.(2)
I'm surprised no one mentioned using curry yet, which has been in Ruby since Ruby 2.2.9. Here's how it can be done in the way OP wants using the standard Ruby library:
[1,3,5,7,9].map(&:+.to_proc.curry(2).call(11))
# => [12, 14, 16, 18, 20]
You need to supply an arity to curry that matches the call, though. This is because the interpreter doesn't know which object the + method refers to yet. This also means you can only use this when all the objects in map have the same arity. But that's probably not an issue if you're trying to use it this way.
I'm not sure about the Symbol#with already posted, I simplified it quite a bit and it works well:
class Symbol
def with(*args, &block)
lambda { |object| object.public_send(self, *args, &block) }
end
end
(also uses public_send instead of send to prevent calling private methods, also caller is already used by ruby so this was confusing)

What is `&method` called? How to pass multiple arguments in it? [duplicate]

You're probably familiar with the following Ruby shorthand (a is an array):
a.map(&:method)
For example, try the following in irb:
>> a=[:a, 'a', 1, 1.0]
=> [:a, "a", 1, 1.0]
>> a.map(&:class)
=> [Symbol, String, Fixnum, Float]
The syntax a.map(&:class) is a shorthand for a.map {|x| x.class}.
Read more about this syntax in "What does map(&:name) mean in Ruby?".
Through the syntax &:class, you're making a method call class for each array element.
My question is: can you supply arguments to the method call? And if so, how?
For example, how do you convert the following syntax
a = [1,3,5,7,9]
a.map {|x| x + 2}
to the &: syntax?
I'm not suggesting that the &: syntax is better.
I'm merely interested in the mechanics of using the &: syntax with arguments.
I assume you know that + is a method on Integer class. You can try the following in irb:
>> a=1
=> 1
>> a+(1)
=> 2
>> a.send(:+, 1)
=> 2
You can create a simple patch on Symbol like this:
class Symbol
def with(*args, &block)
->(caller, *rest) { caller.send(self, *rest, *args, &block) }
end
end
Which will enable you to do not only this:
a = [1,3,5,7,9]
a.map(&:+.with(2))
# => [3, 5, 7, 9, 11]
But also a lot of other cool stuff, like passing multiple parameters:
arr = ["abc", "babc", "great", "fruit"]
arr.map(&:center.with(20, '*'))
# => ["********abc*********", "********babc********", "*******great********", "*******fruit********"]
arr.map(&:[].with(1, 3))
# => ["bc", "abc", "rea", "rui"]
arr.map(&:[].with(/a(.*)/))
# => ["abc", "abc", "at", nil]
arr.map(&:[].with(/a(.*)/, 1))
# => ["bc", "bc", "t", nil]
And even work with inject, which passes two arguments to the block:
%w(abecd ab cd).inject(&:gsub.with('cde'))
# => "cdeeecde"
Or something super cool as passing [shorthand] blocks to the shorthand block:
[['0', '1'], ['2', '3']].map(&:map.with(&:to_i))
# => [[0, 1], [2, 3]]
[%w(a b), %w(c d)].map(&:inject.with(&:+))
# => ["ab", "cd"]
[(1..5), (6..10)].map(&:map.with(&:*.with(2)))
# => [[2, 4, 6, 8, 10], [12, 14, 16, 18, 20]]
Here is a conversation I had with #ArupRakshit explaining it further:
Can you supply arguments to the map(&:method) syntax in Ruby?
As #amcaplan suggested in the comment below, you could create a shorter syntax, if you rename the with method to call. In this case, ruby has a built in shortcut for this special method .().
So you could use the above like this:
class Symbol
def call(*args, &block)
->(caller, *rest) { caller.send(self, *rest, *args, &block) }
end
end
a = [1,3,5,7,9]
a.map(&:+.(2))
# => [3, 5, 7, 9, 11]
[(1..5), (6..10)].map(&:map.(&:*.(2)))
# => [[2, 4, 6, 8, 10], [12, 14, 16, 18, 20]]
Here is a version using Refinements (which is less hacky than globally monkey patching Symbol):
module AmpWithArguments
refine Symbol do
def call(*args, &block)
->(caller, *rest) { caller.send(self, *rest, *args, &block) }
end
end
end
using AmpWithArguments
a = [1,3,5,7,9]
a.map(&:+.(2))
# => [3, 5, 7, 9, 11]
[(1..5), (6..10)].map(&:map.(&:*.(2)))
# => [[2, 4, 6, 8, 10], [12, 14, 16, 18, 20]]
For your example can be done a.map(&2.method(:+)).
Arup-iMac:$ pry
[1] pry(main)> a = [1,3,5,7,9]
=> [1, 3, 5, 7, 9]
[2] pry(main)> a.map(&2.method(:+))
=> [3, 5, 7, 9, 11]
[3] pry(main)>
Here is how it works :-
[3] pry(main)> 2.method(:+)
=> #<Method: Fixnum#+>
[4] pry(main)> 2.method(:+).to_proc
=> #<Proc:0x000001030cb990 (lambda)>
[5] pry(main)> 2.method(:+).to_proc.call(1)
=> 3
2.method(:+) gives a Method object. Then &, on 2.method(:+), actually a call #to_proc method, which is making it a Proc object. Then follow What do you call the &: operator in Ruby?.
As the post you linked to confirms, a.map(&:class) is not a shorthand for a.map {|x| x.class} but for a.map(&:class.to_proc).
This means that to_proc is called on whatever follows the & operator.
So you could give it directly a Proc instead:
a.map(&(Proc.new {|x| x+2}))
I know that most probably this defeats the purpose of your question but I can't see any other way around it - it's not that you specify which method to be called, you just pass it something that responds to to_proc.
There is another native option for enumerables which is pretty only for two arguments in my opinion. the class Enumerable has the method with_object which then returns another Enumerable.
So you can call the & operator for a method with each item and the object as arguments.
Example:
a = [1,3,5,7,9]
a.to_enum.with_object(2).map(&:+) # => [3, 5, 7, 9, 11]
In the case you want more arguments you should repeat the proccess but it's ugly in my opinion:
a = [1,3,5,7,9]
a.to_enum.with_object(2).map(&:+).to_enum.with_object(5).map(&:+) # => [8, 10, 12, 14, 16]
Short answer: No.
Following #rkon's answer, you could also do this:
a = [1,3,5,7,9]
a.map &->(_) { _ + 2 } # => [3, 5, 7, 9, 11]
if all your method needs as argument is an element from the array, this is probably the simplest way to do it:
def double(x)
x * 2
end
[1, 2, 3].map(&method(:double))
=> [2, 4, 6]
Instead of patching core classes yourself, as in the accepted answer, it's shorter and cleaner to use the functionality of the Facets gem:
require 'facets'
a = [1,3,5,7,9]
a.map &:+.(2)
I'm surprised no one mentioned using curry yet, which has been in Ruby since Ruby 2.2.9. Here's how it can be done in the way OP wants using the standard Ruby library:
[1,3,5,7,9].map(&:+.to_proc.curry(2).call(11))
# => [12, 14, 16, 18, 20]
You need to supply an arity to curry that matches the call, though. This is because the interpreter doesn't know which object the + method refers to yet. This also means you can only use this when all the objects in map have the same arity. But that's probably not an issue if you're trying to use it this way.
I'm not sure about the Symbol#with already posted, I simplified it quite a bit and it works well:
class Symbol
def with(*args, &block)
lambda { |object| object.public_send(self, *args, &block) }
end
end
(also uses public_send instead of send to prevent calling private methods, also caller is already used by ruby so this was confusing)

Can you supply arguments to the map(&:method) syntax in Ruby?

You're probably familiar with the following Ruby shorthand (a is an array):
a.map(&:method)
For example, try the following in irb:
>> a=[:a, 'a', 1, 1.0]
=> [:a, "a", 1, 1.0]
>> a.map(&:class)
=> [Symbol, String, Fixnum, Float]
The syntax a.map(&:class) is a shorthand for a.map {|x| x.class}.
Read more about this syntax in "What does map(&:name) mean in Ruby?".
Through the syntax &:class, you're making a method call class for each array element.
My question is: can you supply arguments to the method call? And if so, how?
For example, how do you convert the following syntax
a = [1,3,5,7,9]
a.map {|x| x + 2}
to the &: syntax?
I'm not suggesting that the &: syntax is better.
I'm merely interested in the mechanics of using the &: syntax with arguments.
I assume you know that + is a method on Integer class. You can try the following in irb:
>> a=1
=> 1
>> a+(1)
=> 2
>> a.send(:+, 1)
=> 2
You can create a simple patch on Symbol like this:
class Symbol
def with(*args, &block)
->(caller, *rest) { caller.send(self, *rest, *args, &block) }
end
end
Which will enable you to do not only this:
a = [1,3,5,7,9]
a.map(&:+.with(2))
# => [3, 5, 7, 9, 11]
But also a lot of other cool stuff, like passing multiple parameters:
arr = ["abc", "babc", "great", "fruit"]
arr.map(&:center.with(20, '*'))
# => ["********abc*********", "********babc********", "*******great********", "*******fruit********"]
arr.map(&:[].with(1, 3))
# => ["bc", "abc", "rea", "rui"]
arr.map(&:[].with(/a(.*)/))
# => ["abc", "abc", "at", nil]
arr.map(&:[].with(/a(.*)/, 1))
# => ["bc", "bc", "t", nil]
And even work with inject, which passes two arguments to the block:
%w(abecd ab cd).inject(&:gsub.with('cde'))
# => "cdeeecde"
Or something super cool as passing [shorthand] blocks to the shorthand block:
[['0', '1'], ['2', '3']].map(&:map.with(&:to_i))
# => [[0, 1], [2, 3]]
[%w(a b), %w(c d)].map(&:inject.with(&:+))
# => ["ab", "cd"]
[(1..5), (6..10)].map(&:map.with(&:*.with(2)))
# => [[2, 4, 6, 8, 10], [12, 14, 16, 18, 20]]
Here is a conversation I had with #ArupRakshit explaining it further:
Can you supply arguments to the map(&:method) syntax in Ruby?
As #amcaplan suggested in the comment below, you could create a shorter syntax, if you rename the with method to call. In this case, ruby has a built in shortcut for this special method .().
So you could use the above like this:
class Symbol
def call(*args, &block)
->(caller, *rest) { caller.send(self, *rest, *args, &block) }
end
end
a = [1,3,5,7,9]
a.map(&:+.(2))
# => [3, 5, 7, 9, 11]
[(1..5), (6..10)].map(&:map.(&:*.(2)))
# => [[2, 4, 6, 8, 10], [12, 14, 16, 18, 20]]
Here is a version using Refinements (which is less hacky than globally monkey patching Symbol):
module AmpWithArguments
refine Symbol do
def call(*args, &block)
->(caller, *rest) { caller.send(self, *rest, *args, &block) }
end
end
end
using AmpWithArguments
a = [1,3,5,7,9]
a.map(&:+.(2))
# => [3, 5, 7, 9, 11]
[(1..5), (6..10)].map(&:map.(&:*.(2)))
# => [[2, 4, 6, 8, 10], [12, 14, 16, 18, 20]]
For your example can be done a.map(&2.method(:+)).
Arup-iMac:$ pry
[1] pry(main)> a = [1,3,5,7,9]
=> [1, 3, 5, 7, 9]
[2] pry(main)> a.map(&2.method(:+))
=> [3, 5, 7, 9, 11]
[3] pry(main)>
Here is how it works :-
[3] pry(main)> 2.method(:+)
=> #<Method: Fixnum#+>
[4] pry(main)> 2.method(:+).to_proc
=> #<Proc:0x000001030cb990 (lambda)>
[5] pry(main)> 2.method(:+).to_proc.call(1)
=> 3
2.method(:+) gives a Method object. Then &, on 2.method(:+), actually a call #to_proc method, which is making it a Proc object. Then follow What do you call the &: operator in Ruby?.
As the post you linked to confirms, a.map(&:class) is not a shorthand for a.map {|x| x.class} but for a.map(&:class.to_proc).
This means that to_proc is called on whatever follows the & operator.
So you could give it directly a Proc instead:
a.map(&(Proc.new {|x| x+2}))
I know that most probably this defeats the purpose of your question but I can't see any other way around it - it's not that you specify which method to be called, you just pass it something that responds to to_proc.
There is another native option for enumerables which is pretty only for two arguments in my opinion. the class Enumerable has the method with_object which then returns another Enumerable.
So you can call the & operator for a method with each item and the object as arguments.
Example:
a = [1,3,5,7,9]
a.to_enum.with_object(2).map(&:+) # => [3, 5, 7, 9, 11]
In the case you want more arguments you should repeat the proccess but it's ugly in my opinion:
a = [1,3,5,7,9]
a.to_enum.with_object(2).map(&:+).to_enum.with_object(5).map(&:+) # => [8, 10, 12, 14, 16]
Short answer: No.
Following #rkon's answer, you could also do this:
a = [1,3,5,7,9]
a.map &->(_) { _ + 2 } # => [3, 5, 7, 9, 11]
if all your method needs as argument is an element from the array, this is probably the simplest way to do it:
def double(x)
x * 2
end
[1, 2, 3].map(&method(:double))
=> [2, 4, 6]
Instead of patching core classes yourself, as in the accepted answer, it's shorter and cleaner to use the functionality of the Facets gem:
require 'facets'
a = [1,3,5,7,9]
a.map &:+.(2)
I'm surprised no one mentioned using curry yet, which has been in Ruby since Ruby 2.2.9. Here's how it can be done in the way OP wants using the standard Ruby library:
[1,3,5,7,9].map(&:+.to_proc.curry(2).call(11))
# => [12, 14, 16, 18, 20]
You need to supply an arity to curry that matches the call, though. This is because the interpreter doesn't know which object the + method refers to yet. This also means you can only use this when all the objects in map have the same arity. But that's probably not an issue if you're trying to use it this way.
I'm not sure about the Symbol#with already posted, I simplified it quite a bit and it works well:
class Symbol
def with(*args, &block)
lambda { |object| object.public_send(self, *args, &block) }
end
end
(also uses public_send instead of send to prevent calling private methods, also caller is already used by ruby so this was confusing)

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