I am trying delete database data in Laravel. but this is not working my way.
my view page is
{{url('/deleteReview/'.$Review->id)}}
my web is
Route::post('/deleteReview/{id}','adminController#deleteReview');
my controller delete function is
public function deleteReview($id){
$deleteReview = Review::find($id);
$deleteReview->delete();
return redirect('/manageReview');
}
Are you trying to delete the review by opening the page /deleteReview/<id> in your browser? If so, this would be a GET request, so change the route to a get route:
Route::get('/deleteReview/{id}','adminController#deleteReview');
Please note as per the comments that a GET request should never change data server side. If data is changed using a GET request then there is a risk that spiders or browser prefetch will delete the data.
The correct way to do this in Laravel is using a POST request and use Form Method Spoofing to simulate a DELETE request. Your route entry would then look like this:
Route::delete('/deleteReview/{id}','adminController#deleteReview');
And your form would look like this:
<form action="/deleteReview/{{ $Review->id }}" method="POST">
<input type="hidden" name="_method" value="DELETE">
<input type="hidden" name="_token" value="{{ csrf_token() }}">
</form>
At Controller you should first set Validation for ID that you have to Delete. Create your own customize request handler such as DeleteRequest.
Once you get ID at Controller then used this code
public function deleteReview(DeleteRequest $id){
DB::table('reviews')->where('id', $id)->delete();
return redirect('/manageReview');
}
I hope it will work.
Related
I'm trying to set a logout route.
I found a lot of blade syntax (like that) but none with vuejs. So I tried to replicate the result of the blade syntax by inserting an input with the csrf token in value and the name set to "_token". (the csrf variable contains the string located in the XSRF-TOKEN cookie).
When I post, I have this error in console:
POST http: // localhost: 3000 / logout 419 (unknown status)
Can you tell me where my mistake is? How can I logout properly and be redirected to the page of my choice?
<form method="POST" :action="$route('logout')">
<input type="hidden" name="_token" :value="csrf">
<button type="submit">Logout</button>
</form>
I think there is a better way to do it. I will share an idea with you.
About the token
Share the token by the back-end to the front-end, as you did, isn't necessary.
About the code in the Vue Component
The logout wasn't working because of your form.
Your form POST
<form method="POST" :action="$route('logout')">
<input type="hidden" name="_token" :value="csrf">
<button type="submit">Logout</button>
</form>
The best way of form POST
<form #submit.prevent="logout()">
<button as="button" type="submit">
Logout
</button>
</form>
As you can see, when you submit the form it will call a method of the vue component called "logout". The method:
export default{
// Some code...
methods:{
logout() {
this.$inertia.post(route('logout'));
},
}
}
Doing the logout process in this way, all the logical logout will be taken care of by the server-side. You will not have to worry about the token.
I hope it be useful for you. I also thank you because I just found this solution because of your answer.
I found the solution.
My error was on the recovery of the csrf token which was not good.
I would retrieve the long string contained in the XSRF-TOKEN cookie, while I had to receive the token from my backend. These 2 strings are strictly different, for some reason that I don't know yet.
I just needed to send the csrf token to my front-end with the csrf_token() method
return Inertia::render('Dashboard', [
'publications' => $publications,
'users' => $users,
'csrf_token' => csrf_token()
]);
I didn't need to do the form manually either
Finally, I was able to grab the token as a prop and include it in my post request like this:
this.$inertia.post('/logout', {
_token: this.$props.csrf_token
})
This link helped me
I want to create update method and this is the code:
Route::get("/allProducts/edit/{id}","AllproductController#edit")->name('Allproduct.edit');
Route::post("/allProducts/update/{id}","AllproductController#update")->name('Allproduct.update');
<form class="form-horizontal tasi-form" method="post" enctype="multipart/form-data"
action="{{ route('allProducts.update' , [ 'id'=>$allproduct->id ]) }}">
{{ csrf_field()}}
public function update(Request $request, $id)
{
$data = Allproduct::find($id);
$data->name = $request->name;
$data->save();
return redirect(route('allProducts.index'));
}
when I click on submit button it shows me :
"The POST method is not supported for this route. Supported methods: GET, HEAD, PUT, PATCH, DELETE" error!
what is the problem?
Your route names do not match.
in routes:
name('Allproduct.update');
in the form:
allProducts.update
Also, you can always check the name of the routes thanks to the console command:
php artisan route:list
if you want use method PUT:
you can change method in routes:
Route::post to Route::put
and add next in form:
<input type="hidden" name="_method" value="PUT">
OR
#method('PUT')
this is if your laravel version is 6 and if your version another, check correct way to use PUT method in forms at laravel.com/docs/6.x/routing with your version.
As said here
HTML forms do not support PUT, PATCH or DELETE actions. So, when defining PUT, PATCH or DELETE routes that are called from an HTML form, you will need to add a hidden _method field to the form. The value sent with the _method field will be used as the HTTP request method:
So your form should look like this:
<form class="form-horizontal tasi-form" method="post" enctype="multipart/form-data"
action="{{ route('Allproduct.update' , [ 'id'=>$allproduct->id ]) }}">
#csrf
#method('PUT')
You had a typo in your route name and it was missing the method field.
Change your route to this:
Route::put("/allProducts/update/{id}","AllproductController#update")->name('Allproduct.update');
This will work, but
i strongly recommend you read this laravel naming conventions, and then change the name of your controller and model to AppProductController, AppProduct.
if the validation fails it's not clear to me how i could pass the old input to fill again the form.
I mean, I know how to pass the data when using the Validator class and redirecting after fail with the method withInput(), but I'm trying to learn how to use Form Requests provided in laravel 5. Thanks
$username = Request::old('username');
or in view:
{{ old('username') }}
Read more: http://laravel.com/docs/5.0/requests#old-input
You can redirect with old data like below with validation error
return redirect()->back()->withErrors($validator)->withInput();
<input type="text" name="username" value="{{ old('username') }}">
you must also define withInput() for the http route when redirecting to a page for example
return back()->withInput();
I have a simple form in my tmpl/default.php:
<form id='AddForm' action="<?php echo JRoute::_('index.php?option=com_mycomponent&task=addcam'); ?>" >
<p>
<label for="CamName">Name:
</label>
<input type="text" id="CamName" name="cam_name" />
</p>
<button type='submit' class='submit_cam' name='addcam' value='Add'>Add</button>
<button type='reset' class='cancel_changes' name='cancel_changes' value='Cancel'>Cancel</button>
</form>
In my controller.php file I'm trying to process the values:
function addcam()
{
$add_name=JRequest::getString('cam_name');
$model = &$this->getModel();
$model->AddWebcam($add_name); //send to model to add to DB
}
In my model I just return the result of the query. With this implementation I just get routed to an empty page. I'd like to have it refresh the current page. Typically you do this with action="" but in my case I need it to route to the function called addcam in the controller. Or is there a better way to do this?
A common technique in Joomla when directing to the task is to have that function do a full redirect to a view at the end. This prevents a page refresh from trying to resubmit the data and leads to a cleaner url for the client. To do this, try the following:
function addcam()
{
$add_name=JRequest::getString('cam_name');
$model = &$this->getModel();
$model->AddWebcam($add_name); //send to model to add to DB
JFactory::getApplication()->redirect(JRoute::_(index.php?option=com_mycomponent&view=whatever));
}
Obviously, update the JRoute bit to the url you actually need. You can also include a message if you would like (like "Saved!"): http://docs.joomla.org/JApplication::redirect/1.6
I know browsers only support POST and GET requests, and Laravel supports PUT requests using the following code:
<?= Form::open('/path/', 'PUT'); ?>
... form stuff ...
<?= Form::close(); ?>
This produces the following HTML
<form method="POST" action="http://example.com/home/" accept-charset="UTF-8">
<input type="hidden" name="_method" value="PUT" />
... form stuff ...
</form>
How does the framework handle this? Does it capture the POST request before deciding which route to send the request off to? Does it use ajax to send an actual PUT to the framework?
It inserts a hidden field, and that field mentions it is a PUT or DELETE request
See here:
echo Form::open('user/profile', 'PUT');
results in:
<input type="hidden" name="_method" value="PUT">
Then it looks for _method when routing in the request.php core file (look for 'spoofing' in the code) - and if it detects it - will use that value to route to the correct restful controller.
It is still using "POST" to achieve this. There is no ajax used.
Laravel uses the symfony Http Foundation which checks for this _method variable and changes the request to either PUT or DELETE based on its contents. Yes, this happens before routing takes place.
You can also use an array within your form open like so:
{{ Form::open( array('route' => array('equipment.update', $item->id ),
'role' => 'form',
'method' => 'put')) }}
Simply change the method to what you want.
While a late answer, I feel it is important to add this for anyone else who finds this and can't get their API to work.
When using Laravel's resource routes like this:
Route::resource('myRoute','MyController');
It will expect a PUT in order to call the update() method. For this to work normally (outside of a form submission), you need to make sure you pass the ContentType as x-www-form-urlencoded. This is default for forms, but making requests with cURL or using a tool like Postman will not work unless you set this.
PUT usually refers to update request.
When you open a form inside laravel blade template using,
{{ Form::open('/path/', 'PUT') }}
It would create a hidden field inside the form as follows,
<input type="hidden" name="_method" value="PUT" />
In order for you to process the PUT request inside your controller, you would need to create a method with a put prefix,
for example, putMethodName()
so if you specify,
{{ Form::open('controller/methodName/', 'PUT') }}
inside Form:open. Then you would need to create a controller method as follows,
class Controller extends BaseController {
public function putMethodName()
{
// put - usual update code logic goes here
}
}