Looking for a way to get specific columns from Laravel Eloquent with custom column names.
E.g. get example_name as name.
I am trying to replicate SQL Alias like SELECT column_name AS alias_name but without using custom attributes.
Here is and example query in Laravel:
Table::get(['column1', 'column2', 'column3'])->all()
And what I would like it to get would look something like this:
Table::get(['column1', 'column2 AS column4', 'column3'])->all()
for example in user model email as emailAddress u want to get then in your user model do like that
protected $appends = ['emailAddress']; //add custom column here..
public function getEmailAddressAttribute()
{
return $this->email;
}
or u can use by query like that
User::select('id','name','email as emailAddress')->get();
Table::select('column1', 'column2 AS column4', 'column3')->get()
for more detail read https://laravel.com/docs/5.8/eloquent-mutators
Related
I have a model User with fileds like - colorhair_id, nationality_id, etc. Of course I have a relationship to other model. Problem is that I want to return nationality from User i must do that:
User::find(1)->colorhair->name
In next time I need to use
User::find(1)->nationality->name
It works but it's not look professional and it's dirty. How can I change query or something else to return object with repleace field like nationality_id to nationality with name of that. Any idea?
You can use Laravel Mutators. Put below two functions into the User model
public function getHairColorNameAttribute(){
return $this->colorhair->name
}
public function getNationalityNameAttribute(){
return $this->nationality->name
}
Then when you simply access it.
User::find(1)->hair_color_name;
The next time
User::find(1)->nationality_name;
If you want to get these values by default use $append in the model. Put the following line to the top of the User model
protected $appends = ['hair_color_name','nationality_name'];
Note: In laravel 9 mutators little bit different from the above method.
Bonus Point :
if you access values in the same scopes don't use find() method in each statement.
$user = User::find(1);
then
$user->hair_color_name;
$user->nationality_name;
I'm trying to get the numbers of records from my notifications, where the candidate_user_id column from inside the data attribute is the same as the UserId (Authenticated User).
After I dd, I was able to get the data from all of the records in the table by using the pluck method (Line 1). I then tried to use the Where clause to get the items that I need
but this just didn't work, it was still returning all of the records in the table.
DashboardController.php:
public function index()
{
$notifications = Notification::all()->pluck('data');
$notifications->where('candidate_user_id', Auth::user()->id);
dd($notifications);
}
Here is a partial screenshot of the data that is being plucked.
How can I get the data from this, in a way like this ->where('candidate_user_id', Auth::user()->id);?
If data was a JSON field on the table you could try to use a where condition to search the JSON using the -> operator:
Notification::where('data->candidate_user_id', Auth::id())->pluck('data');
Assuming you only want this data field and not the rest of the fields, you can call pluck on the builder directly. There isn't much reason to hydrate Model instances with all the fields to then just pluck a single field from them if it is just a table field, so you can ask the database for just the field you want.
The data in the data field is a json string, so you can tell Laravel to automatically cast it as an array using the $casts property on each of the models that is notifiable.
For instance, if you have a User model which uses the trait (ie has use Notifiable), add this:
protected $casts = [
'data' => 'array',
];
If you want to access all notifications for the auth user.
$user = auth()->user();
dd($user->notifications->pluck('data'));
If you really want to do in your question way, here is how.
$notifications = Notification::all()->pluck('data');
$notifications = $notifications->where('candidate_user_id', Auth::user()->id)
->all();
This assumes you that you did not modify the default laravel notifications relationship and database migration setup. If you have modified some of the default ones, you need to provide how you modify it.
I am developing a Web application using Laravel. For the admin panel, I am using Laravel Nova. What I am trying to do now is that I need to use data from the table which has relationship through another table. To be, clear, see my database structure below.
items
=====
id
name
price
sub_category_id
sub_categories
==============
id
name
parent_category_id
parent_categories
=================
id
name
What I am trying to achieve inside the Nova is that I want to display the parent category name of the item on the item index/list page. The first thing is that I do not want to create custom attribute something like this in the model
protected $appends = [
'parent_category_name'
];
function getParentCategoryNameAttribute()
{
//code here
}
Therefore, there are two solutions I can think of. The first solution is using the HasThrough relationship. But I cannot find it in Nova. So, I cannot use it. The second solution is that overriding the field value on render. Something like this.
Text::make("fieldname")->fillUsing(function($request, $model, $attribute, $requestAttribute) {
//$model->sub_category->parent_category - then I can return a value
return "Parent category name";
})->onlyOnIndex()
But the above code is not working. So, what would be the best approach to handle the has-through relationship in Nova?
Assuming you have defined the relationship sub_category & parent_category properly.
Define the relationship in Item model as below
public function parent_category()
{
return $this->sub_category->parent_category();
}
Then use it in Item resource as below.
BelongsTo::make('Parent Category')
->hideWhenCreating()
->hideWhenUpdating(),
I have this table relationship:
I already made all the relationships in my models properly, but i don't know how to get the name from worktypes table
when i do
dd($shift->shift_workers);
i get this:
but i want also somehow to get the name from worktype table for each worker...
This should be done somehow withPivot() function or what?
So i could have something like this:
$foreach ($shift->shift_workers as $w => $worker)
echo $worker->name;
but i don't know how to do this...anyone can help?
It is obvious and logically right that the pivot table should be skipped so the result is achieved by:
$worker->worktypes->first()->name; // to get the name of the first work type
$worker->worktypes->pluck('name'); // to get all names as an array
To achieve this result, follow Laravel's naming convention and set up model relationsips right.
Rename your worker_worktype_pivot table to worker_worktype
Set up the relationship in the Worker model:
`
class Worker extends Model {
...
public function workTypes()
{
return $this->belongsToMany(WorkType::class);
}
}
I have a custom module and I am loading a collection like following
$collection = Mage::getModel('module/product')->getCollection()
->addFieldToFilter('sku',$sku);
There is field named as prod_id in the database. Can I get this as entity_id while loading the collection?
If yes. Please help how to do this.
First of all all
addAttributeToFilter() is used to filter EAV collections.
addFieldToFilter() is used to filter Non-EAV collections.
EAV-models are for example product, customer, sales, etc so you can use use addAttributeToFilter() for those entities.
addFieldToFilter() is mapped to `addAttributeToFilter()` for `EAV` entities. So you can just use `addFieldToFiler().`
You can have a look in app/code/core/Mage/Eav/Model/Entity/Collection/Abstract.php where the Mapping is done:
public function addFieldToFilter($attribute, $condition = null) {
return $this->addAttributeToFilter($attribute, $condition);
}
If you are using custom module then you can directly use addFieldToFilter() with your column name
Like
$collection = Mage::getModel('module/model')->getCollection()
->addFieldToFilter('column_name',$data);
Let me know if you have any query