into a Laravel Lumen API project, I give back a paginated result.
....
"next_page_url" is "http://example.com/something?pg=2"
....
How can I add to all links the parameters, which are included into the requested url?
Sample:
http://example.com/something?pg=1&color=red&limit=2
next_page_url should then look like this:
http://example.com/something?pg=2&color=red&limit=2
$queryStrings = Input::except('limit', 'order_by', 'order', 'page', 'count', 'current_page', 'last_page', 'next_page_url', 'per_page', 'previous_page_url', 'total', 'url', 'from', 'to', 'pg');
$limit = (Input::get('limit') ? Input::get('limit') : '10');
$order_by = (Input::get('order') ? Input::get('order') : 'id');
$order = (Input::get('order_by') ? Input::get('order_by') : 'asc');
$page = (Input::get('pg') ? Input::get('pg') : 1);
$query = DB::table('cars');
foreach ($queryStrings as $key => $value) {
$query->where($key, '=', $value);
}
$query->select('id', 'car', 'color', 'active');
$query->orderBy($order_by, $order);
$paginated = $query->paginate($limit, ['*'], 'pg', $page);
return response()->json($paginated,200);
Thanks for help.
You can use the appends() method available from the LengthAwarePaginator returned by the paginate() method. So you can simply add this line:
$paginated = $query->paginate($limit, ['*'], 'pg', $page);
$paginated->appends(Input::all());
return response()->json($paginated,200);
This will get all input values passed and append them to the links generated by the paginator. The appends() method mutates the instance on which it is called, that's why you simply need to call it on the result you get from paginate().
Related
i have object given below and i wanted to pagination in this how can i get
$productListArray = array();
$productListObject = ((object)[
"id"=>$productList->id,
"title"=>$productList->title,
"slug"=>$productList->slug,
'categoryName'=>$categoryName[0]->cat_title,
'brand'=>$brandName[0]->brandname,
'minMrp'=>$minMrp,
'maxMrp' =>$maxMrp,
'minSellingPrice' => $minSellingPrice,
'maxSellingPrice' => $maxSellingPrice,
'rating'=>$productList->rating,
'rating_count' => $productList->rating_count,
'image' => $img[0]
])->paginate();
array_push($productListArray, $productListObject);
}
return response()->json($productListArray, 200);
Hi you can get the Current page using laravel paginator Paginator::currentPageResolver
public function index()
{
$currentPage = 3; // You can set this to any page you want to paginate to
// Make sure that you call the static method currentPageResolver()
// before querying users
Paginator::currentPageResolver(function () use ($currentPage) {
return $currentPage;
});
$users = \App\User::paginate(5);
return view('user.index', compact('users'));
}
thanks for your support i found solution,
first add on your header
use Illuminate\Pagination\Paginator;
use Illuminate\Support\Collection;
use Illuminate\Pagination\LengthAwarePaginator;
then make an other function
public function paginate($items, $perPage = 5, $page = null, $options = [])
{
$page = $page ?: (Paginator::resolveCurrentPage() ?: 1);
$items = $items instanceof Collection ? $items : Collection::make($items);
return new LengthAwarePaginator($items->forPage($page, $perPage), $items->count(), $perPage, $page, $options);
}
after than call this function where you want in class
$data = $this->paginate($productListArray);
return response()->json($data, 200);
last 2 lines already mentioned in my questions
thanks again
I try to add some new values to each user from foreach, but because I use get, now I can't use paginate on response, but I also need to add that values to each user. Any ideas?
public function statistics()
{
$users = User::select(['id', 'name'])->get();
foreach ($users as $key => $user) {
$history = AnswerHistory::where('user_id', '=', $user->id)->get();
$user->total_votes = count($history);
$user->total_time = gmdate("H:i:s", ($history->sum('answer_time')));
}
return response()->json($users);
}
what you want is not possible in laravel by default, however there are a few things you can do.
Solution one you can return paginator first and then modify the collection.
$users = User::select(['id', 'name'])->paginate(4)->toArray();
$users['data'] = array_map(function ($user) {
$history = AnswerHistory::where('user_id', '=', $user->id)->get();
$user->total_votes = count($history);
$user->total_time = gmdate("H:i:s", ($history->sum('answer_time')));
return $user;
}, $users['data']);
return $users;
Solution two The macro way. If you prefer, add the Collection macro to a Service Provider. That way you can call paginate() on any collection:
See AppServiceProvider.php for a sample implementation.
public function boot()
{
Collection::macro('paginate', function ($perPage, $total = null, $page = null, $pageName = 'page') {
$page = $page ?: LengthAwarePaginator::resolveCurrentPage($pageName);
return new LengthAwarePaginator(
$this->forPage($page, $perPage),
$total ?: $this->count(),
$perPage,
$page,
[
'path' => LengthAwarePaginator::resolveCurrentPath(),
'pageName' => $pageName,
]
);
});
}
and then your code will be like this
$users = User::select(['id', 'name'])->get();
foreach ($users as $key => $user) {
$history = AnswerHistory::where('user_id', '=', $user->id)->get();
$user->total_votes = count($history);
$user->total_time = gmdate("H:i:s", ($history->sum('answer_time')));
}
return response()->json($users->paginate(4));
Solution three The subclass way. Where you want a "pageable" collection that is distinct from the standard Illuminate\Support\Collection, implement a copy of Collection.php in your application and simply replace your use Illuminate\Support\Collection statements at the top of your dependent files with use App\Support\Collection:
<?php
namespace App\Support;
use Illuminate\Pagination\LengthAwarePaginator;
use Illuminate\Support\Collection as BaseCollection;
class Collection extends BaseCollection
{
public function paginate($perPage, $total = null, $page = null, $pageName = 'page')
{
$page = $page ?: LengthAwarePaginator::resolveCurrentPage($pageName);
return new LengthAwarePaginator(
$this->forPage($page, $perPage),
$total ?: $this->count(),
$perPage,
$page,
[
'path' => LengthAwarePaginator::resolveCurrentPath(),
'pageName' => $pageName,
]
);
}
}
and your code will be like this
// use Illuminate\Support\Collection
use App\Support\Collection;
$users = User::select(['id', 'name'])->get();
foreach ($users as $key => $user) {
$history = AnswerHistory::where('user_id', '=', $user->id)->get();
$user->total_votes = count($history);
$user->total_time = gmdate("H:i:s", ($history->sum('answer_time')));
}
return response()->json((new Collection($users))->paginate(4);
According to your post, User has many AnswerHistory. You can build relationship between them.
So getting the total_votes and total_time by withCount:
$users = User::withCount('answerHistories AS total_votes')
->withCount(['answerHistories AS total_time' => function($query) {
$query->select(DB::raw("SUM(answer_time)"));
}])->paginate(10);
And you can get the pagination datas by getCollection, and change the datas inside:
$users->getCollection()->transform(function ($data) {
$data->total_time = gmdate('H:i:s', $data->total_time);
return $data;
});
You can create pagination by yourself look to this Laravel doc https://laravel.com/docs/7.x/pagination#manually-creating-a-paginator.
I will suggest to use LengthAwarePaginator
Here is some code example with array
// creating pagination
$offset = max(0, ($page - 1) * $perPage);
$resultArray = array_slice($result, $offset, $perPage);
$paginator = new LengthAwarePaginator($resultArray, count($result), $perPage, $page);
$paginator->setPath(url()->current());
$paginator->appends(['per_page' => $perPage]);
return response()->json([
'message' => 'Success',
'data' => $paginator
]);
But I think your case have better "good" solution, you can load AnswerHistory with hasMany Laravel relation and with function.
I am copying this code in Codeigniter official docs, but I don't know why this will throw an error
public function acceptChangeRequest($id,$data1,$accept) {
$data = array(
'status' => $accept,
'approve_by' => $data1,
);
$this->db->where('id', $id);
$this->db->update('change_request',$data);
//return true;
}
Error Number: 1054
Unknown column 'Array' in 'field list'
UPDATE change_request SET status = 'Y', approve_by = Array WHERE id = '22'
It sounds wierd since this code works in my other function. Any idea?
Read The Documentation Clearly
Read About Update Records In Codeigniter
Here IS Demo Function For You
public function updateBasic($data,$user_id){
$userData=array(
'marital_status'=>$data['marital_status'],
'country'=>$data['stateofresidence'],
'city'=>$data['city'],
'caste'=>$data['caste'],
'residential_status'=>$data['residencystatus']
);
$this->db->WHERE('user_id',$user_id)->update('basic_profile',$userData);
return true;
}
You Must Check Through Print_r();what Is coming To your Function In Your Case $data1 Is Coming In the From OF array You Must Extract The Array To Update The Record
Use this function in your model to update the record.
public function acceptChangeRequest($where, $table, $data){
$this->db->where($where);
$this->db->update($table, $data);
return $this->db->affected_rows() > 0;
}
use this code in your controller.
$where = array('id'=>$id);
$data = array(
'status' => $accept,
'approve_by' => $data1,
);
$this->User_model->update($where,'table_name',$data);
What is in your $data1 variable? I can see that it's an array, and that is the problem.
If your $data1 stores indexes like in your table's row, than this is the possible solution for you:
public function acceptChangeRequest($id,$data1,$accept) {
$data1["status"] = $accept;
$this->db->where('id', $id);
$this->db->update('change_request', $data1);
return true;
}
But if your $data1 variable stores only the approve_by information, than your possible solution is:
public function acceptChangeRequest($id,$data1,$accept) {
$data = array(
'status' => $accept,
'approve_by' => $data1["approve_by"]
);
$this->db->where('id', $id);
$this->db->update('change_request', $data);
return true;
}
First of all, you need to know what you expect from $data1, than you can move forward to the solution.
You can see your $data1 variable in your Controller's function:
print "<pre>";
print_r($data1);
print "<pre>";
die();
My Laravel pagination output is like laravel pagination used to be, but I need to change the data array for each object.
My output is:
As you can see, the data object has 2 items, which I need to change.
My code is:
$items = $this->items()
->where('position', '=', null)
->paginate(15);
Which returns the user items with pivot table, but I don't like the way the pivot table is shown in the JSON, so I decided to change the items and organize each item with the pivot before the item.
For this purpose, I tried to use foreach
foreach ($items->data as $item)
{
}
which giving my an error, for a reason I don't know:
Undefined property: Illuminate\Pagination\LengthAwarePaginator::$data"
status_code: 500
Any help?
The paginator's items is a collection. You can grab it and transform the data like so:
$paginator = $this->items()->where('position', '=', null)->paginate(15);
$paginator->getCollection()->transform(function ($value) {
// Your code here
return $value;
});
If you are familiar with tap helper here is the snippet that does exact same.
$paginator = tap($this->items()->where('position', '=', null)->paginate(15),function($paginatedInstance){
return $paginatedInstance->getCollection()->transform(function ($value) {
return $value;
});
});
We can't chain method getCollection to paginator instance because AbstractPaginator will return paginator's underlying collection. so the paginator instance will be transformed to Collection. So fix that we can use tap helper.
If you'd like to keep items paginated:
$itemsPaginated = $this->items()
->paginate(15);
$itemsTransformed = $itemsPaginated
->getCollection()
->map(function($item) {
return [
'id' => $item->id,
];
})->toArray();
$itemsTransformedAndPaginated = new \Illuminate\Pagination\LengthAwarePaginator(
$itemsTransformed,
$itemsPaginated->total(),
$itemsPaginated->perPage(),
$itemsPaginated->currentPage(), [
'path' => \Request::url(),
'query' => [
'page' => $itemsPaginated->currentPage()
]
]
);
There is a setCollection method for such purpose.
$items = Model::paginate(10);
$updatedItems = $items->getCollection();
// data manipulation
// ...
$items->setCollection($updateItems);
From the source code of /Illuminate/Pagination/AbstractPaginator.php
/**
* Set the paginator's underlying collection.
*
* #param \Illuminate\Support\Collection $collection
* #return $this
*/
public function setCollection(Collection $collection)
{
$this->items = $collection;
return $this;
}
Source
I could make shorter way. This returns edited $array instead of simple $paginated. This example modify file names.
This doc was useful for me.
$paginated=$query->paginate(12);
$array=$paginated->toArray();
foreach ($array['data'] as $r=>$record) {
$array['data'][$r]->gif=$array['data'][$r]->gif.".gif";
}
return $array;
Sample Example :
$franchiseData=[ 'id'=>1 ,'name'=>'PAnkaj'];
$models = $bookingsQuery->paginate(10);
$models->setCollection(collect($franchiseData));
return $models;
Note that $models->setCollection(collect($franchiseData)); you have to use collect() else you will get error.
getCollection
is one way to get the items. Another way is to use this
For ex- Assuming, user doesn't have name param and only have first_name and last_name
$userPaginatedData = User::paginate(15);
$users = $userPaginatedData->items();
foreach($users as $user) {
$user->name = $user->first_name . ' ' . $user->last_name;
}
return $userPaginatedData;
Now in the data key, you would see that each user has name param with it.
Laravel 8.9.0 has added the through method to AbstractPaginator.
It transforms each item in the slice of items using a callback, and keeps the items paginated.
$paginator = $this->items()->where('position', '=', null)->paginate(15);
$paginator->through(function ($value) {
// Your code here
return $value;
});
The source code:
/**
* Transform each item in the slice of items using a callback.
*
* #param callable $callback
* #return $this
*/
public function through(callable $callback)
{
$this->items->transform($callback);
return $this;
}
-Laravel 5.4
// example update column "photo"
// from "/path/to/photo.png"
// to "abc.com/path/to/photo.png"
foreach ($items as $item)
{
$path = $item->photo;
// Remove
$item->offsetUnset("photo");
// Set
$item->offsetSet("photo", url($path));
}
Laravel AbstractPaginator has methods setCollection() and getCollection()
<?php
$itemsPaginated = $this->items()->paginate(15);
$itemsPaginated->setCollection(
$itemsPaginated->getCollection()->transform(function ($item) {
// Your code here
return $item;
})
)
This is your paginated items...
$items = $this->items()
->where('position', '=', null)
->paginate(15);
I am using Laravel 8, can simply use each
$items->each(function ($item) {
// your code here
$item->custom_data = calcSomeData(); // sample
});
It does the same as this...
$items->getCollection()->transform(function ($item) {
// your code here
$item->custom_data = calcSomeData(); // sample
});
<?php
$itemsPaginated = $this->items()->paginate(15);
$itemsPaginated = json_encode($itemsPaginated);
foreach ($itemsPaginated->data as $key => $item) {
$results->data[$key]; //Modify
}
$itemsPaginated = json_encode($results);
you have to use below code in your blade
{!! $items->render() !!}
Ignore the pagination in laravel and hit the normal data
foreach ($items as $item)
{
}
I have the following code in PHP controller:
public function getMainAdminBackend(){
$user_info = \DB::table('users')
->select('role_id', \DB::raw('count(*) as total'))
->groupBy('role_id')
->get();
return view('admin.main')->with('userInfo',$user_info);
}
In the view I have this chart.js:
<?php
$data = array(
'Jan' => array(33),
'Feb' => array(32),
'Mar' => array(12)
);
?>
{!! app()->chartbar->render("BarChart", $data) !!}
How can I convert the array of controller with the format required to JS Chart ?
EDIT
Now I receive the following format , the graphic show the number 1,2,3 but cant't print the lines of the graphics.
array(3) { [1]=> int(35) [2]=> int(20) [3]=> int(35) }
In your controller you call return view('admin.main')->with('userInfo',$user_info);
with('userInfo',$user_info) sets a $userInfo variable in your view with the content of $user_info, so just something like that should do the trick
{!! app()->chartbar->render("BarChart", $userInfo) !!}
EDIT: i assumed $user_info was already in the correct format but you couldn't figure out how to display it. Reading your comments i better understand your needs.
I don't know which data format chartJS and what you want to display. Looking $data example and your DB query, i assume you want to display data in the format "role_id" => count(*)
so, in that case, i would do something like
$userArray = array();
foreach($user_info as $row) {
$userArray[$row->role_id] = $row->total;
}
return view('admin.main')->with('userInfo',$userArray);
Looks like you need to put the data in the right format:
public function getMainAdminBackend() {
$user_info = \DB::table('users')
->select('role_id', \DB::raw('count(*) as total'))
->groupBy('role_id')
->get();
$data = [];
if ($user_info) {
foreach ($user_info as $month => $value) {
$data[date("M", mktime(0, 0, 0, $month, 1, 0))] = [$value];
}
}
return view('admin.main')->with('userInfo', $data);
}