How to make empty values have a default value? - laravel

Im trying to give model attribute values another value when they are blank,
At the moment this is what I'm working with in my model:
public function getAttribute($property){
if(blank($this->attributes[$property])){
return $this->attributes[$property] = '-';
}else{
return $this->attributes[$property];
}
}
It works, but I dont think this is the right way to do it.
Im looking for a proper way of doing this.
example:
lets say the value in the database is NULL,
I want it to show "-" when displaying, but I dont want to save "-" in the database.
(I also don't want to use "get...Value" mutators for every value)

Solution 1
Since PHP 7 there is a new feature called the Null Coalescing operator. It returns the first operator when it exists and is not NULL:
{{ $model->attribute ?? '-' }}
Which is the same as this:
{{ isset($model->attribute) ? $model->attribute : '-' }}
Solution 2
Another solution would be a little bit harder, but doable:
Create a base model to which you extend all the other models:
class BaseModel extends Model {
protected $emptyAttributes = [];
protected function getAttribute($property)
{
if (in_array($property, $this->emptyAttributes) && blank($this->attributes[$property])) {
return '-';
}
else {
return $this->attributes[$property];
}
}
}
Now extend all the models you want to this new class and create an array of 'attributes to replace':
class User extends BaseModel {
protected $emptyAttributes = ['name', 'email'];
}
This should automatically replace the attributes name and email when they are empty, NULL or a string of only spaces.
Side note:
You could also move the functionality to a trait (which could be a more elegant solution, but that's up to you).

Related

Add attribute to Laravel model

I have user model, and I want to add if this user is qualified or not, I have some query to determine that,
User.php
....
public function getIsQualifiedAttribute($value)
{
return $this->qualified()->first() ? true : false;
}
public function scopeQualified($query)
{
return $query->where("years_of_experience",">=",5);
}
and this is how I want to print it
{{$user->is_qualified}}
but I can't make it work, it keeps giving me wrong value.
Laravel accessors does not have parameter
try to change your method like this
public function getIsQualifiedAttribute()
{
return $this->qualified()->first() ? true : false;
}
You don't need to do another query to this same table if you already have the model instance you want to check an attribute for. Just have the accessor check the years_of_experience field of the model:
public function getIsQualifiedAttribute()
{
return $this->years_of_experience >= 5;
}
{{ $user->is_qualified ? 'Y' : 'N' }}
With your current setup you are doing a query to the database to get the first record which has years_of_experience >= 5 every time the accessor was hit. If any record in that table has years_of_experience >= 5 that will return true.

a problem with using accessors in laravel

I need to use created_at field in two different type
public function getCreatedAtAttribute($value)
{
$time = new \Verta($value);
return $time->formatDifference();
}
this is my code and I need to use default created_at value as well
please help me
You can try to make another accessor with a different name (created_at_diff perhaps) for your special format:
public function getCreatedAtDiff()
{
return (new \Verta($this->attributes['created_at']))->formatDifference();
// or $this->created_at instead of $this->attributes['created_at']
}
Then you can access it via $model->created_at_diff.

Yii2: How to set default attribute values in ActiveRecord?

This may seem like a trivial question, however all of the obvious solutions that I can think of have their own flaws.
What we want is to be able to set any default ActiveRecord attribute value for new records only, in a way that makes it readable before and during validation and does not interfere with derived classes used for search.
The default values need to be set and ready as soon as we instantiate the class, so that (new MyModel)->attr returns the default attr value.
Here are some of the possibilities and the problems they have:
A) In MyModel override the init() method and assign default value when isNewRecord is true like so:
public function init() {
if ($this->isNewRecord) {
$this->attr = 'defaultValue';
}
parent::init();
}
Problem: Search. Unless we explicitly unset our default attribute in MySearchModel (very error-prone because it is too easy to forget), this will also set the value before calling search() in the derived MySearchModel class and interfere with searching (the attr attribute will already be set so search will be returning incorrect results). In Yii1.1 this was resolved by calling unsetAttributes() before calling search(), however no such method exists in Yii2.
B) In MyModel override the beforeSave() method like so:
public function beforeSave($insert) {
if ($insert) {
$this->attr = 'defaultValue';
}
return parent::beforeSave();
}
Problem: Attribute is not set in unsaved records. (new MyModel)->attr is null. Worse yet, even other validation rules that rely on this value will not be able to access it, because beforeSave() is called after validation.
C) To ensure the value is available during validation we can instead override the beforeValidate() method and set the default values there like so:
public function beforeValidate() {
if ($this->isNewRecord) {
$this->attr = 'defaultValue';
}
return parent::beforeValidate();
}
Problem: Attribute is still not set in unsaved (unvalidated) records. We need to at least call $model->validate() if we want to get the default value.
D) Use DefaultValidator in rules() to set a default attribute value during validation like so:
public function rules() {
return [
[
'attr', 'default',
'value' => 'defaultValue',
'on' => 'insert', // instantiate model with this scenario
],
// ...
];
}
Problem: Same as B) and C). Value is not set until we actually save or validate the record.
So what is the right way to set default attribute values? Is there any other way without the outlined problems?
There's two ways to do this.
$model => new Model();
Now $model has all the default attributes from the database table.
Or in your rules you can use:
[['field_name'], 'default', 'value'=> $defaultValue],
Now $model will always be created with the default values you specified.
You can see a full list of core validators here http://www.yiiframework.com/doc-2.0/guide-tutorial-core-validators.html
This is a hangup with Yii's bloated multi-purpose ActiveRecords
In my humble opinion the form models, active records, and search models would be better off split into separate classes/subclasses
Why not split your search models and form models?
abstract class Creature extends ActiveRecord {
...
}
class CreatureForm extends Creature {
public function init() {
parent::init();
if ($this->isNewRecord) {
$this->number_of_legs = 4;
}
}
}
class CreatureSearch extends Creature {
public function search() {
...
}
}
The benefits of this approach are
You can easily cater for different validation, set up and display cases without resorting to a bunch of ifs and switches
You can still keep common code in the parent class to avoid repetition
You can make changes to each subclass without worrying about how it will affect the other
The individual classes don't need to know about the existence of any of their siblings/children to function correctly
In fact, in our most recent project, we are using search models that don't extend from the related ActiveRecord at all
I know it is answered but I will add my approach.
I have Application and ApplicationSearch models. In Application model I add init with a check of the current instance. If its ApplicationSearch I skip initializations.
public function init()
{
if(!$this instanceof ApplicationSearch)
{
$this->id = hash('sha256', 123);
}
parent::init();
}
also as #mae commented below you can check for existence of search method in current instance, assuming you didn't add any method with name search to the non-search base model so the code becomes:
public function init()
{
// no search method is available in Gii generated Non search class
if(!method_exists($this,'search'))
{
$this->id = hash('sha256', 123);
}
parent::init();
}
I've read your question several times and I think there are some contradictions.
You want the defaults to be readable before and during validation and then you try init() or beforeSave(). So, assuming you just want to set the default values in the model so they can be present during the part of the life cycle as long as possible and not interfere with the derived classes, simply set them after initialising the object.
You can prepare separate method where all defaults are set and call it explicitly.
$model = new Model;
$model->setDefaultValues();
Or you can create static method to create model with all default values set and return the instance of it.
$model = Model::createNew();
Or you can pass default values to constructor.
$model = new Model([
'attribute1' => 'value1',
'attribute2' => 'value2',
]);
This is not much different from setting the attributes directly.
$model = new Model;
$model->attribute1 = 'value1';
$model->attribute2 = 'value2';
Everything depends on how much transparent would you like your model be to your controller.
This way attributes are set for the whole life cycle except the direct initialisation and it's not interfering with derived search model.
Just override __construct() method in your model like this:
class MyModel extends \yii\db\ActiveRecord {
function __construct(array $config = [])
{
parent::__construct($config);
$this->attr = 'defaultValue';
}
...
}
If you want to load default value from database you can put this code in your model
public function init()
{
parent::init();
if(!method_exists($this,'search')) //for checking this code is on model search or not
{
$this->loadDefaultValues();
}
}
You can prepare separate method where all defaults are set and call it explicitly.
$model = new Model;
if($model->isNewRecord())
$model->setDefaultValues();

One to many relationship count - difference in accessing relationship

I have one to many relation - Entry can have many Visits.
In my Entry model I have the following methods:
public function visits() {
return $this->hasMany ('Visit', 'entry_id','id');
}
public function visitsCount() {
return $this->hasMany('Visit', 'entry_id','id')
->selectRaw('SUM(number) as count')
->groupBy('entry_id');
}
In Blade I can get number of visits for my entry using:
{{$entry->visits()->count() }}
or
{{ $entry->visitsCount()->first()->count }}
If I want to create accessor for getting number of visits I can define:
public function getNrVisitsAttribute()
{
$related = $this->visitsCount()->first();
return ($related) ? $related->count : 0;
}
and now I can use:
{{ $entry->nr_visits }}
Questions:
In some examples I saw defining such relation this way:
public function getNrVisitsAttribute()
{
if (!array_key_exists('visitsCount', $this->relations)) {
$this->load('visitsCount');
}
$related = $this->getRelation('visitsCount')->first();
return ($related) ? $related->count : 0;
}
Question is: what's the difference between this and the "simple method" I showed at the beginning? Is it quicker/use less resource or ... ?
Why this method doesn't work in this case? $related is null so accessor return 0 whereas using "simple method" it returns correct number of visits
I've tried also changing in visitsCount method relationship from hasMany to hasOne but it doesn't change anything.
1 Your relation won't work because you didn't select the foreign key:
public function visitsCount() {
// also use hasOne here
return $this->hasOne('Visit', 'entry_id','id')
->selectRaw('entry_id, SUM(number) as count')
->groupBy('entry_id');
}
2 Your accessor should have the same name as the relation in order to make sense (that's why I created those accessors in the first place):
public function getVisitsCountAttribute()
{
if ( ! array_key_exists('visitsCount', $this->relations)) $this->load('visitsCount');
$related = $this->getRelation('visitsCount');
return ($related) ? $related->count : 0;
}
This accessor is just a handy way to call the count this way:
$entry->visitsCount;
instead of
$entry->visitsCount->count;
// or in your case with hasMany
$entry->visitsCount->first()->count;
So it has nothing to do with performance.
Also mind that it is not defining the relation differently, it requires the relation to be defined like above.
Assuming your schema reflects one record / model per visit in your visits table, The best method would be to get rid of the visitsCount() relation and only use $entry->visits->count() to retrieve the number of visits to the entry.
The reason for this is that once this relation is loaded, it will simply count the models in the collection instead of re-querying for them (if using a separate relationship)
If your concern is overhead and unnecessary queries: My suggestion would be to eager-load these models in a base controller somewhere as children of the user object and cache it, so the only time you really need to re-query for any of it is when there have been changes.
BaseController:
public function __construct(){
if(!Cache::has('user-'.Auth::user()->id)){
$this->user = User::with('entries.visits')->find(Auth::user()->id);
Cache::put('user-'.Auth::user()->id, $this->user, 60);
} else {
$this->user = Cache::get('user-'.Auth::user()->id);
}
}
Then set up an observer on your Entry model to flush the user cache on save. Another possibility if you are using Memcached or Reddis would be to use cache tags so you don't have to flush the whole user's cache every time an Entry model is added or modified.
Of course, this also assumes that each Entry is related to a user, however, if it isn't and you need to use Entry alone as the parent, the same logic could apply, by moving the Cache class calls in your EntryController

Laravel Has One Relation changing the identifier value

I'm not sure this is a real relation. I will try to explain the best way I can.
So first of all, I have three models :
Appartement,
AppartementPrice
The AppartementPrice depends on :
- appartement_id
I would like the AppartementPrice to be retrieve like that :
If there is a specific price for the appartement, then retrieve it, If not retrieve the price for all appartement which is stored in the database with an appartement_id = 0.
So basically what I would like is to do something like that :
public function price()
{
if(isset($this->hasOne('AppartementPrice')->price) // Check that relation exists
return $this->hasOne('AppartementPrice');
else
return $this->hasOne('AppartementPrice')->where('appartement_id', '0');
}
But this is not working.
It does not retrive me the default price.
I guess anyway this is not a best practice ?
I first tried to get the informations like that :
//Check if appartment has a specific price or retrieve default
if($priceAppartement = AppartementPrice::getPriceByCompanyAppartement($this->id))
return $priceAppartement;
else
return AppartementPrice::getDefaultPrice();
But I had this error :
Relationship method must return an object of type Illuminate\Database\Eloquent\Relations\Relation
when doing :
echo $app->price->price;
How can I check that a relation exists ? And is there a way to do as I describe ?
Thank you
You can't replace relation like this, as what you intend is not logical - you want to retrieve relation that doesn't exist.
Instead you can do this:
public function getPriceAttribute()
{
return ($this->priceRelation) ?: $this->priceDefault();
}
public function priceDefault()
{
// edit: let's cache this one so you don't call the query everytime
// you want the price
return AppartmentPrice::remember(5)->find(0);
}
public function priceRelation()
{
return $this->hasOne('AppartementPrice');
}
Then you achieve what you wanted:
$app->price; // returns AppartmentPrice object related or default one
HOWEVER mind that you won't be able to work on the relation like normally:
$price = new AppartmentPrice([...]);
$app->price()->save($price); // will not work, instead use:
$app->priceRelation()->save($price);
First of all something really important in Laravel 4.
When you do not use parentheses when querying relationship it means you want to retreive a Collention of your Model.
You have to use parentheses if you want to continue your query.
Ex:
// for getting prices collection (if not hasOne). (look like AppartementPrice)
$appartment->price;
// for getting the query which will ask the DB to get all
//price attached to this appartment, and then you can continue querying
$priceQuery = $appartment->price();
// Or you can chain your query
$appartment->price()->where('price', '>', 0)->get() // or first() or count();
Secondly, your question.
//Appartement Model
// This function is needed to keep querying the DB
public function price()
{
return $this->hasOne('AppartementPrice')
}
// This one is for getting the appartment price, like you want to
public function getAppartmentPrice()
{
$price_object = $this->price;
if (!$price_object) // Appartment does not have any price {
return AppartementPrice->where('appartement_id', '=', 0)->get();
}
return $price_object;
}

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