Compare two records and highlight the differences - oracle

Question

I have a oracle apex report which fetches two rows every time.
I want to highlight all the columns where data is different in two rows.
So when user looks at the comparison report he don't have to go through all the columns to identify where data has been changed.
I have tried to look at the apex features and some javascript code but was unable to do so reliably.
You can have a look at sample report here:
https://apex.oracle.com/pls/apex/f?p=128616:8:109311280077805:::::
go to page "help me with comparison"
I want to highlight the benefit name column as data is different in benefit name column.

Answer 1

if your table has id "test" you can try call this function on page load compareRows(document.getElementById('test'));
the function body:
function compareRows(table) {
var row1,row2, rows = table.rows;
var cell1,cell2;
var rowText;
row1=rows[1];
row2=rows[2];
cell1=row1.cells;
cell2=row2.cells;
for (var i=0; i<cell1.length; i++) {
if(cell1[i].textContent != cell2[i].textContent){
cell1[i].style.backgroundColor = "red";
cell2[i].style.backgroundColor = "red";
}
}
}

Answer 2

You can use the analytic function "LAG" to reference the previous row in your resultset.
So one possible solution is to (1) select the value of the current row and the value of the previous row, (2) compare the 2 columns and set a flag, only in row 2 because that is where you want to highlight, (3) use highlighting in apex to indicate which columns have different values. See example sql below for an example.
-- create tables
create table so_dummy_data (
id number generated by default on null as identity
constraint so_dummy_data_id_pk primary key,
name varchar2(100) not null,
email varchar2(100) not null
)
;
-- load data
insert into so_dummy_data (
id,
name,
email
) values (
1,
'John Doe',
'john.doe#mail.com'
);
insert into so_dummy_data (
id,
name,
email
) values (
2,
'John Doe',
'john.x.doe#mail.com'
);
commit;
WITH old_and_new AS
(SELECT
id,
name,
LAG(name,1)OVER(
ORDER BY
name
)AS new_name,
email,
LAG(email,1)OVER(
ORDER BY
1
)AS new_email,
row_number() over (order by 1) rn
FROM
so_dummy_data
)
SELECT
name,
CASE
WHEN rn = 1 THEN 'N'
WHEN name = new_name THEN
'N'
ELSE
'Y'
END AS name_changed,
email,
CASE
WHEN rn = 1 THEN 'N'
WHEN email = new_email THEN
'N'
ELSE
'Y'
END AS email_changed
FROM
old_and_new;