Suppose I write:
SHELL:=/usr/bin/env bash
commands:
source sourceme.sh && alias
But I wanted to push that source sourceme.sh back into the SHELL declaration:
SHELL:=/usr/bin/env bash -c "source sourceme.sh" # or something along these lines
Can this be done, and if so, how?
No, you can't do that. Make takes your recipe lines and sends them to, effectively, $(SHELL) -c <recipeline> The shell, unfortunately, doesn't accept multiple -c options so to do what you want you'd need to have a way for make to insert that string at the beginning of every recipe line and there's no way to do that.
You can do it yourself, from outside your makefile, by writing your own wrapper:
$ cat wrapper.sh
#!/usr/bin/env bash
shift
source sourceme.sh
eval "$#"
$ cat Makefile
SHELL := wrapper.sh
commands:
alias
I have a directory with test inputs and outputs. I wanted make to automatically test my program against this directory after build, for convenience. Thus I needed to somehow force the test target of Makefile to depend on the entire testing directory (it's called good, because it contains valid inputs and outputs for the program)
I read this question and the accepted answer and the comments about deleted files under this answer: Makefile rule that depends on all files under a directory (including within subdirectories) And, incorporating advice from this answer & comments, I came out with this:
my#comp:~/wtfdir$ cat Makefile
test : test.sh $(shell find good)
./test.sh
my#comp:~/wtfdir$
For the sake of MCVE, test.sh is very rudimentary:
my#comp:~/wtfdir$ cat test.sh
echo "blah"
my#comp:~/wtfdir$
However, I noticed, this behaves in a rather unexpected way:
my#comp:~/wtfdir$ ls good
test1 test1.out
my#comp:~/wtfdir$ make
./test.sh
blah
my#comp:~/wtfdir$ touch good/test1
my#comp:~/wtfdir$ make
cp good/test1 good/test1.out
./test.sh
blah
my#comp:~/wtfdir$
Why (expletive redacted) does modifying test1 cause make to overwrite test1.out with test1??? I'm not a big fan of data losses, you know.
What's going on here?
Your Make appears to be GNU Make. Here's why this happens. Your recipe:
test : test.sh $(shell find good)
./test.sh
adds to the prerequisites of test every file and directory that is listed
by find good in the current directory, which happen to be:
good
good/test1
good/test1.out
So to make target test, Make begins by determining if any of the specified
or built-in recipes require it to rebuild any of the prerequsities:
test.sh good good/test1 good/test1.out
Among its built-in recipes it finds:
%.out: %
# recipe to execute (built-in):
#rm -f $#
cp $< $#
as you can verify by running:
$ make --print-data-base | grep -A4 '%.out'
The rule for this recipe is matched by:
good/test1.out: good/test1
and by doing:
$ touch good/test1
you have made good/test1.out out of date with respect to good/test1.
So make executes the recipe:
#rm -f good/test1.out
cp good/test1 good/test1.out
the visible output of which is what you observed:
cp good/test1 good/test1.out
Then it proceeds with the recipe for test:
./test.sh
blah
There is always a risk of such booby-traps if you write a makefile that blindly
generates at runtime some set of preqrequisites or targets you don't know beforehand.
You could avoid this one in particular by explicitly deleting the offending
implicit pattern rule in your makefile by writing:
%.out: %
with no recipe. And you can avoid all possible booby-traps of this sort by disabling all
built-in recipes, with:
$ make --no-builtin-rules ...
but that will require you to write for yourself any builtin-recipes that your
makefile relies on.
The best solution for you is probably to amend your makefile as follows:
PREREQS := $(shell find good)
test : test.sh $(PREREQS)
./test.sh
$(PREREQS): ;
Then the last line explicitly specifies an empty recipe
for each of the $(PREREQS), and Make will not consult any pattern rules for targets
that have explicit recipes.
You should additionally make test a phony target:
.PHONY: test
for the avoidance of the booby-trap where something creates a file called test in the build directory.
I have a Makefile that has this kind of command:
browserify:
rm -rf ./dist
mkdir dist
# Browserify
echo -n "/* ${NPM_PACKAGE} ${NPM_VERSION} ${GITHUB_PROJ} */" \
> dist/pica.js
So when I do make browserify it should output the comment to the top of the file without \n. But for some reasons... the output looks like this
-n /* package 0.0.0 */
...more things...
I'm using zsh on osx.
It doesn't matter what shell you are using. Make will always use /bin/sh as the shell it invokes (unless you specifically set the SHELL make variable to something else). Think what a disaster it would be if make used whatever shell the user was using to invoke recipes!
On many GNU/Linux systems, /bin/sh is actually a link to bash. On other GNU/Linux systems, /bin/sh is a link to dash which is a small, POSIX-standard shell without all the extensions bash uses (dash is good for running portable shell scripts fast, but not good for a user's interactive shell as it's missing too many expected features). On non-GNU-based systems (like OSX) /bin/sh might be ksh or something else even.
There is no portable, standard way to invoke echo in such a way that it doesn't print the trailing newline. There is an echo program, and different ones work differently. Many shells, including bash and zsh also have an echo built-in to the shell:
$ type -a echo
echo is a shell builtin
echo is /bin/echo
and these versions of echo also work differently than the program echo. Some versions have no way to suppress newlines. Some use the -n flag. Some use \c at the end to suppress printing the newline. Some support a combination of them.
The short answer is that if you want to print a line in the shell without a newline in a portable and reliable way, you should use the printf program to do it, not echo:
browserify:
rm -rf ./dist
mkdir dist
# Browserify
printf %s "/* ${NPM_PACKAGE} ${NPM_VERSION} ${GITHUB_PROJ} */" \
> dist/pica.js
Is there a better way to source a script, which sets env vars, from within a makefile?
FLAG ?= 0
ifeq ($(FLAG),0)
export FLAG=1
/bin/myshell -c '<source scripts here> ; $(MAKE) $#'
else
...targets...
endif
Makefile default shell is /bin/sh which does not implement source.
Changing shell to /bin/bash makes it possible:
# Makefile
SHELL := /bin/bash
rule:
source env.sh && YourCommand
To answer the question as asked: you can't.
The basic issue is that a child process can not alter the parent's environment. The shell gets around this by not forking a new process when source'ing, but just running those commands in the current incarnation of the shell. That works fine, but make is not /bin/sh (or whatever shell your script is for) and does not understand that language (aside from the bits they have in common).
Chris Dodd and Foo Bah have addressed one possible workaround, so I'll suggest another (assuming you are running GNU make): post-process the shell script into make compatible text and include the result:
shell-variable-setter.make: shell-varaible-setter.sh
postprocess.py #^
# ...
else
include shell-variable-setter.make
endif
messy details left as an exercise.
If your goal is to merely set environment variables for Make, why not keep it in Makefile syntax and use the include command?
include other_makefile
If you have to invoke the shell script, capture the result in a shell command:
JUST_DO_IT=$(shell source_script)
the shell command should run before the targets. However this won't set the environment variables.
If you want to set environment variables in the build, write a separate shell script that sources your environment variables and calls make. Then, in the makefile, have the targets call the new shell script.
For example, if your original makefile has target a, then you want to do something like this:
# mysetenv.sh
#!/bin/bash
. <script to source>
export FLAG=1
make "$#"
# Makefile
ifeq($(FLAG),0)
export FLAG=1
a:
./mysetenv.sh a
else
a:
.. do it
endif
Using GNU Make 3.81 I can source a shell script from make using:
rule:
<tab>source source_script.sh && build_files.sh
build_files.sh "gets" the environment variables exported by source_script.sh.
Note that using:
rule:
<tab>source source_script.sh
<tab>build_files.sh
will not work. Each line is ran in its own subshell.
This works for me. Substitute env.sh with the name of the file you want to source. It works by sourcing the file in bash and outputting the modified environment, after formatting it, to a file called makeenv which is then sourced by the makefile.
IGNORE := $(shell bash -c "source env.sh; env | sed 's/=/:=/' | sed 's/^/export /' > makeenv")
include makeenv
Some constructs are the same in the shell and in GNU Make.
var=1234
text="Some text"
You can alter your shell script to source the defines. They must all be simple name=value types.
Ie,
[script.sh]
. ./vars.sh
[Makefile]
include vars.sh
Then the shell script and the Makefile can share the same 'source' of information. I found this question because I was looking for a manifest of common syntax that can be used in Gnu Make and shell scripts (I don't care which shell).
Edit: Shells and make understand ${var}. This means you can concatenate, etc,
var="One string"
var=${var} "Second string"
I really like Foo Bah's answer where make calls the script, and the script calls back to make. To expand on that answer I did this:
# Makefile
.DEFAULT_GOAL := all
ifndef SOME_DIR
%:
<tab>. ./setenv.sh $(MAKE) $#
else
all:
<tab>...
clean:
<tab>...
endif
--
# setenv.sh
export SOME_DIR=$PWD/path/to/some/dir
if [ -n "$1" ]; then
# The first argument is set, call back into make.
$1 $2
fi
This has the added advantage of using $(MAKE) in case anyone is using a unique make program, and will also handle any rule specified on the command line, without having to duplicate the name of each rule in the case when SOME_DIR is not defined.
If you want to get the variables into the environment, so that they are passed to child processes, then you can use bash's set -a and set +a. The former means, "When I set a variable, set the corresponding environment variable too." So this works for me:
check:
bash -c "set -a && source .env.test && set +a && cargo test"
That will pass everything in .env.test on to cargo test as environment variables.
Note that this will let you pass an environment on to sub-commands, but it won't let you set Makefile variables (which are different things anyway). If you need the latter, you should try one of the other suggestions here.
My solution to this: (assuming you're have bash, the syntax for $# is different for tcsh for instance)
Have a script sourceThenExec.sh, as such:
#!/bin/bash
source whatever.sh
$#
Then, in your makefile, preface your targets with bash sourceThenExec.sh, for instance:
ExampleTarget:
bash sourceThenExec.sh gcc ExampleTarget.C
You can of course put something like STE=bash sourceThenExec.sh at the top of your makefile and shorten this:
ExampleTarget:
$(STE) gcc ExampleTarget.C
All of this works because sourceThenExec.sh opens a subshell, but then the commands are run in the same subshell.
The downside of this method is that the file gets sourced for each target, which may be undesirable.
Depending on your version of Make and enclosing shell, you can implement a nice solution via eval, cat, and chaining calls with &&:
ENVFILE=envfile
source-via-eval:
#echo "FOO: $${FOO}"
#echo "FOO=AMAZING!" > $(ENVFILE)
#eval `cat $(ENVFILE)` && echo "FOO: $${FOO}"
And a quick test:
> make source-via-eval
FOO:
FOO: AMAZING!
An elegant solution found here:
ifneq (,$(wildcard ./.env))
include .env
export
endif
If you need only a few known variables exporting in makefile can be an option, here is an example of what I am using.
$ grep ID /etc/os-release
ID=ubuntu
ID_LIKE=debian
$ cat Makefile
default: help rule/setup/lsb
source?=.
help:
-${MAKE} --version | head -n1
rule/setup/%:
echo ID=${#F}
rule/setup/lsb: /etc/os-release
${source} $< && export ID && ${MAKE} rule/setup/$${ID}
$ make
make --version | head -n1
GNU Make 3.81
. /etc/os-release && export ID && make rule/setup/${ID}
make[1]: Entering directory `/tmp'
echo ID=ubuntu
ID=ubuntu
--
http://rzr.online.fr/q/gnumake
Assuming GNU make, can be done using a submake. Assuming that the shell script that exports the variables is include.sh in the current directory, move your Makefile to realmake.mk. Create a new Makefile:
all:
#. ./include.sh; \
$(MAKE) -f realmake.mk $(MAKECMDGOALS)
$(MAKECMDGOALS):
+#. ./include.sh; \
$(MAKE) -f realmake.mk $(MAKECMDGOALS)
Pay attention to the ./ preceding include.sh.
Another possible way would be to create a sh script, for example run.sh, source the required scripts and call make inside the script.
#!/bin/sh
source script1
source script2 and so on
make
target: output_source
bash ShellScript_name.sh
try this it will work, the script is inside the current directory.
In my GNUmakefile, I would like to have a rule that uses a temporary directory. For example:
out.tar: TMP := $(shell mktemp -d)
echo hi $(TMP)/hi.txt
tar -C $(TMP) cf $# .
rm -rf $(TMP)
As written, the above rule creates the temporary directory at the time that the rule is parsed. This means that, even I don't make out.tar all the time, many temporary directories get created. I would like to avoid my /tmp being littered with unused temporary directories.
Is there a way to cause the variable to only be defined when the rule is fired, as opposed to whenever it is defined?
My main thought is to dump the mktemp and tar into a shell script but that seems somewhat unsightly.
In your example, the TMP variable is set (and the temporary directory created) whenever the rules for out.tar are evaluated. In order to create the directory only when out.tar is actually fired, you need to move the directory creation down into the steps:
out.tar :
$(eval TMP := $(shell mktemp -d))
#echo hi $(TMP)/hi.txt
tar -C $(TMP) cf $# .
rm -rf $(TMP)
The eval function evaluates a string as if it had been typed into the makefile manually. In this case, it sets the TMP variable to the result of the shell function call.
edit (in response to comments):
To create a unique variable, you could do the following:
out.tar :
$(eval $#_TMP := $(shell mktemp -d))
#echo hi $($#_TMP)/hi.txt
tar -C $($#_TMP) cf $# .
rm -rf $($#_TMP)
This would prepend the name of the target (out.tar, in this case) to the variable, producing a variable with the name out.tar_TMP. Hopefully, that is enough to prevent conflicts.
A relatively easy way of doing this is to write the entire sequence as a shell script.
out.tar:
set -e ;\
TMP=$$(mktemp -d) ;\
echo hi $$TMP/hi.txt ;\
tar -C $$TMP cf $# . ;\
rm -rf $$TMP ;\
I have consolidated some related tips here: Multi-line bash commands in makefile
Another possibility is to use separate lines to set up Make variables when a rule fires.
For example, here is a makefile with two rules. If a rule fires, it creates a temp dir and sets TMP to the temp dir name.
PHONY = ruleA ruleB display
all: ruleA
ruleA: TMP = $(shell mktemp -d testruleA_XXXX)
ruleA: display
ruleB: TMP = $(shell mktemp -d testruleB_XXXX)
ruleB: display
display:
echo ${TMP}
Running the code produces the expected result:
$ ls
Makefile
$ make ruleB
echo testruleB_Y4Ow
testruleB_Y4Ow
$ ls
Makefile testruleB_Y4Ow
I dislike "Don't" answers, but... don't.
make's variables are global and are supposed to be evaluated during makefile's "parsing" stage, not during execution stage.
In this case, as long as the variable local to a single target, follow #nobar's answer and make it a shell variable.
Target-specific variables, too, are considered harmful by other make implementations: kati, Mozilla pymake. Because of them, a target can be built differently depending on if it's built standalone, or as a dependency of a parent target with a target-specific variable. And you won't know which way it was, because you don't know what is already built.