I'm now using Ubuntu, and increasingly using terminal.
I would like to delete files from Trash via command line.
So, I've gotta delete files from ~/.local/share/Trash/files dir.
All right, here's the question:
When I move some file to trash, it also creates a file_name.trashinfo file in ~/.local/share/Trash/info.
How could I automatically delete the corresponding .trashinfo file when I delete something in ../files?
You can use the following script to delete both files simultaneously. Save it in some file in the ~/.local/share/Trash directory, and call then bash <script.sh> <path-to-file-to-be-deleted-in-files-dir>.
A sample call to delete the file test if you named the script del.sh: bash del.sh files/test
#!/bin/bash
file=$1
if [ -e "$file" ] # check if file exists
then
rm -rf "$file" # remove file
base=$(basename "$file")
rm -rf "info/$base.trashinfo" # remove second file in info/<file>.trashinfo
echo 'files deleted!'
fi
Related
I am trying to make a bash script to create directories with the same name as each file in a given directory, then move said files to their respective directories, and then rename the files.
Basically - a quantum chemistry program that I use requires that the input files be named "ZMAT". So, if I have multiple jobs, I currently need to manually create directories, and then move the ZMAT files into them (can only run one job per folder).
When I run my code, I get "binary operator expected". I am not sure what this means. Some help please.
Here is what I have so far:
#!/bin/bash
if [ -e *.ZMAT ];
then
echo "CFOUR Job Detected"
for INPFILE in *.ZMAT; do
BASENAME=$(basename $INPFILE )
INPFILE=$BASENAME.ZMAT
OUTFILE=$BASENAME.out
XYZFILE=$BASENAME.xyz
ERRORFILE=$BASENAME.slu
if [ ! -e $ERRORFILE ];
then
# Create folder in scratch directory with the basename
mkdir /scratch/CFOUR/$BASENAME
# Move the file to its directory
mv -f $INPFILE /scratch/CFOUR/$BASENAME
# cd to the new directory
cd /scratch/CFOUR/$BASENAME
# Change the file name to just ZMAT
mv -f $INPFILE ZMAT
echo "Submitting CFOUR Job"
# Submit to scheduler
#RUN_COMMAND="sbatch -J $BASENAME _CFOUR_MRCC_SLURM.SUB"
#eval $RUN_COMMAND
else
echo "Error File Detected - Not Submitting Job"
fi
done
fi
An alternative would be to create symlinks to the original files.
As you said before, each ZMAT symlink would need to be in its own directory.
The upside is that the original data doesn't move, so less risk of breaking it, but the tool you want to use should read the symlinks as if they are the files it is looking for.
This one-liner creates an out directory in the current folder that you could subsequently move wherever you want it. You could easily create it where you do want it by replacing "out" with whatever absolute path you wanted
for i in *.ZMAT; do mkdir -p out/$i ; ln -s $PWD/$i out/$i/ZMAT ; done
I believe I have solved my problem. Here is the new script, which appears to be working fine. Any input is welcome though!
#!/bin/bash
SUBDIR=$(pwd)
for i in *.ZMAT; do
BASENAME=$(basename $i .ZMAT)
INPFILE=$BASENAME.ZMAT
OUTFILE=$BASENAME.out
XYZFILE=$BASENAME.xyz
ERRORFILE=$BASENAME.slu
if [ ! -e $ERRORFILE ];
then
mkdir /scratch/CFOUR/$BASENAME # Create Scratch Folder
cp $INPFILE /scratch/cdc/CFOUR/$BASENAME # Move Input to Scratch
cd /scratch/CFOUR/$BASENAME #cd to Scratch Folder
mv -f $INPFILE ZMAT # Change Input Name
echo "Submitting CFOUR Job"
# Submit to scheduler
#RUN_COMMAND="sbatch -J $BASENAME _CFOUR_MRCC_SLURM.SUB"
#eval $RUN_COMMAND
cd $SUBDIR #Go back to SUBDIR
else
echo "Error File Already Exists"
fi
done
So I have been trying to rename about 5000 folders based on a CSV (Old name, Newname)
This is a one time operation, once hdkjsh2-2f8c-46b9-bbdb_doc is converted to 3 then it will not need to be touched again.
I have tried the solution here (Setting up an automator workflow with a command script) but found that it does not do a great deal when it comes to folder/directory names and all the guides/documentation is around file names and not folder.
Any suggestions would be much appreciated
Example of CSV
Doc_Location, New_ID
hdkjsh2-2f8c-46b9-bbdb_doc , 3
Please make a backup before trying the following.
Save the following script in your HOME directory as renamer:
#!/bin/bash
cat "file.csv" | while IFS=' ,' read dir new ; do
if [ -d "$dir" ]; then
echo Rename $dir as $new
#mv "$dir" "$new"
else
echo "ERROR: Directory $dir not found - ignored"
fi
done
Then start Terminal and make the script executable by running:
chmod +x $HOME/renamer
Then change directory to where your directories are that need renaming:
cd path/to/things/needing/renaming
Make sure you have your CSV, called file.csv saved in that directory, then run with:
$HOME/renamer
It doesn't actually do anything, it just tells you what it would do. If it looks correct, edit $HOME/renamer and remove the single # on the line that says:
#mv "$dir" "$new"
so that is looks like:
mv "$dir" "$new"
Then be doubly sure you have made a backup and run the script again:
$HOME/renamer
Go to the folder where the other folders you want to rename are located. Select all the folders you want to rename. Then click on the action icon at the top of finder window. This will open a window where one option is to rename x items. See image below.
When you select "Rename x items" you get a box like the one shown below where you can specify the new names.
I have small script to copy the all the files from one directory (SRC) to another directory (DES). This below script is running perfectly.
#!/bin/bash
SRC="/home/user/dir1/*"
DES="/home/user/dir2/"
for file in "$SRC"
do
if [ -f "$file" ]
then
cp "$file" "$DES"
echo "$file -----> file copied"
fi
done
Now what i am thinking while copying files from one directory to another directory, how to skip the copying file if that file has already exist in (DES) directory with same name of (SRC) directory and continue the remaining file as usual from source to destination?
Here how to i use break and continue looping to perform this action?
Thanks,
I recommend to use rsync:
src="/home/user/dir1/"
dst="/home/user/dir2/"
rsync -rav --ignore-existing "${src}" "${dst}"
The switch --ignore-existing tells rsync to skip files which exist at the destination.
Why not just reduce the entire script to a oneliner?
cp -n /home/user/dir1/* /home/user/dir2/
The -n flag (--no-clobber) prevents cp from overwriting existing files.
If your real situation is more complicated, you can also take a look at rsync.
for i in *.txt
do
#Text files
echo $i
#checking for existing files
if [ -f ~/txt/$i ]
then
j=1
#Stripping .txt from the files
temp=${i%".txt"}
#appending filaname with counter "($j)"
i=$temp\($j\).txt
#move to folder /txt
mv $i ~/txt
else
mv $i ~/txt
fi
done
My loop checks a folder for an existing file, if that file name exists, the file name is appended (ex (1), (2) etc.
Once the file name has been renamed and it is held in $i I try to mv it but I'm getting:
mv: cannot stat 'list(1).txt': No such file or directory
I tried mv {$i} ~/txt, mv [$i] ~/txt etc...no luck. Any ideas?
You are overwriting the actually name of the file here:
i=$temp\($j\).txt
Instead, use a new variable for the new name. Something like this.
newname=$tmp\($j\).txt
#move to folder /txt
mv $i ~/txt/$newname
You say:
Once the file has been renamed and it is held in $i...
But that is wrong - the file has not been renamed at this point.
You manipulated some text in a variable. That does not have any effect on the filesystem until you run a command, such as through using mv.
Also, in your else statement, it is not clear to me why you are running mv on a file that does not exist (fails the -f test).
I had some code here, but from reading your program again, I'm not sure exactly what you're trying to accomplish, exactly...
I am having trouble with a simple grading script I am writing. I have a directory called HW5 containing a folder for each student in the class. From my current directory, which contains the HW5 folder, I would like to copy all files starting with the word mondial, to each of the students' folders. My script runs but does not copy any of the files over. Any suggestions?
#!/bin/bash
for file in ./HW5; do
if [ -d $file ]; then
cp ./mondial.* ./$file;
fi
done
Thanks,
The first loop was executing only once, with file equal ./HW5. Add the star to actually select the files or directories inside it.
#!/bin/bash
for file in ./HW5/*; do
if [ -d "$file" ]; then
cp ./mondial.* ./"$file"
fi
done
As suggested by Mark Reed, this can be simplified:
for file in ./HW5/*/; do
cp ./mondial.* ./"$file"
done