I want to get the start and end days of every week between two dates. The dates's format is dd/mm/yyy hh24:mi:ss. I need the weeks in the format dd/mm/yyyy hh24:mi:ss because I have to calculate the days and hours between the start and end day of the week with the times
I wrote this statement
WITH
date_range AS (
SELECT
pdm.des_comercial serie,
pdm.id_material codserie,
ri.id_accion intervencion,
TO_CHAR(NVL(ri.fecha_salida_rev, SYSDATE), 'dd/mm/RRRR') fecha1,
to_char((CASE
WHEN ri.fecha_salida_rev > TO_DATE('18/06/2019', 'dd/mm/yyyy') THEN TO_DATE('18/06/2019', 'dd/mm/yyyy')
WHEN ri.fecha_salida_Rev IS NULL THEN TO_DATE('18/06/2019', 'dd/mm/yyyy')
ELSE ri.fecha_salida_Rev
END),'dd/mm/yyyy hh24:mi:ss') fechasalida,
to_char((CASE
WHEN ri.fecha_entrada_rev < TO_DATE('01/06/2019', 'dd/mm/yyyy') THEN TO_DATE('01/06/2019', 'dd/mm/yyyy')
ELSE ri.fecha_entrada_Rev
END),'dd/mm/yyyy hh24:mi:ss') fechaentrada
,
ri.cod_taller_rev,
ri.COD_MATRICULA,
ri.fecha_entrada_rev start_date,
ri.fecha_salida_rev end_date
FROM
r_intervencion ri,
planificador.pl_dh_material pdm
WHERE
ri.id_accion = ri.amortizada_por
AND ri.causa_entrada = 1
AND ri.tipo_accion = 1
AND pdm.id_material = ri.cod_serie
AND pdm.hasta = 99999999
AND ri.ID_ACCION = 'IM4'
AND ri.fecha_salida_rev BETWEEN TO_DATE('01/06/2019', 'dd/mm/yyyy') AND TO_DATE('18/06/2019', 'dd/mm/yyyy')
),
semanas AS (
SELECT LEVEL "Week"
,to_char(to_date(start_date,'dd/mm/yyyy hh24:mi:ss') + (7 * (LEVEL - 1)),'IW') startweek
,to_char(to_date(start_date ,'dd/mm/yyyy hh24:mi:ss')+ (7 * (LEVEL - 1)),'IW') + 6 endweek
,TO_CHAR(start_date + (7 * (LEVEL - 1)),'IW') "Iso Week",
serie,
codserie,
intervencion,
cod_taller_rev,
cod_matricula,
fechaentrada,
fechasalida,
start_date,
end_date
FROM date_range
CONNECT BY LEVEL <= (to_char(To_date(end_date,'dd/mm/yyyy hh24:mi:ss'),'IW') - to_char(To_date(start_date,'dd/mm/yyyy hh24:mi:ss'),'IW')) / 7 + 1
)
SELECT startweek,
endweek,
to_date(endweek,'dd/mm/yyyy hh24:mi:ss') - to_date(startweek,'dd/mm/yyyy hh24:mi:ss') dias,
serie,
codserie,
intervencion,
cod_taller_rev,
cod_matricula,
start_Date,
end_date,
fechaentrada,
fechasalida,
rd.descripcion
FROM semanas,r_depositos rd
WHERE cod_taller_rev = rd.cod_deposito
When I execute it, I get
Query execution failed
SQL Error [1840] [22008]: ORA-01840: ORA-01840: input value not long enough for date format
The error is in
,to_char(to_date(start_date,'dd/mm/yyyy hh24:mi:ss') + (7 * (LEVEL - 1)),'IW') startweek
,to_char(to_date(start_date ,'dd/mm/yyyy hh24:mi:ss')+ (7 * (LEVEL - 1)),'IW') + 6 endweek
How can I get the startweek and endweek with the format dd/mm/yyyy hh24:mi:ss
EDITED
start_date end_date
20/05/2019 20:00:00 05/06/2019 08:00:00
weeks
20/05/2019 20:00:00 26/05/2019 -> 6 days and xxx hours
27/05/2019 02/06/2019 -> 7 days
03/06/2019 05/06/2019 08:00:00 -> 3 days and xxx hours
I need to calculate the difference in days and hours for each week.
For example between 20/05/2019 20:00:00 and 26/05/2019
and last one between 03/06/2019 and 05/06/2019 08:00:00
My issue is with the calculation
to_date(endweek,'dd/mm/yyyy hh24:mi:ss') - to_date(startweek,'dd/mm/yyyy hh24:mi:ss') dias,
endweek and startweek have to have dd/mm/yyyy hh24:mi:ss
My issue is with the calculation
to_date(endweek,'dd/mm/yyyy hh24:mi:ss') - to_date(startweek,'dd/mm/yyyy hh24:mi:ss') dias,
endweek and startweek have to have dd/mm/yyyy hh24:mi:ss
Oracle dates are stored in an internal format which you generally don't need to worry about. Your application or client formats the date as a string, based on its own setting or your session NLS settings.
When you do something like:
to_date(endweek,'dd/mm/yyyy hh24:mi:ss')
you're really doing:
to_date(to_char(endweek),'dd/mm/yyyy hh24:mi:ss')
and as there is no explicit format mask specified for the implicit to_char() call it used your current session's NLS settings. Depending on the setting it might error; or might corrupt the value - e.g. mixing YY and YYYY masks can lose the century, converting 2019 to 0019. (Given the error you are getting, your NLS settings might be unusual?).
At best you're converting the date value to a string and back to exactly the same date value, which is pointless. You aren't changing the format of the datem because it doesn't have one. The intermediate string does, but you aren't using that, and you can't for calculations (at least without converting back to a date as you are, which again is pointless.)
Oracle has other functions to manipulate date values, including trunc(), so I think you might want something like this - showing the difference in three ways, though there are others and you can format the last one however you want:
with date_range (start_date, end_date) as (
-- dummy data from your example
select to_date('20/05/2019 20:00:00', 'DD/MM/YYYY HH24;MI:SS') as start_date,
to_date('05/06/2019 08:00:00', 'DD/MM/YYYY HH24;MI:SS') as end_date
from dual
),
semanas as (
select level as week,
start_date,
end_date,
greatest(trunc(start_date + (7 * (level - 1)), 'IW'), start_date) as start_week,
least(trunc(start_date + (7 * level), 'IW'), end_date) as end_week
from date_range
connect by level <= (trunc(end_date, 'IW') - trunc(start_date, 'IW')) / 7 + 1
)
select week,
to_char(start_week, 'IW') as iso_week,
to_char(start_week, 'DD/MM/YYYY HH24:MI:SS') as start_week,
to_char(end_week, 'DD/MM/YYYY HH24:MI:SS') as end_week,
end_week - start_week as diff_num,
numtodsinterval(end_week - start_week, 'DAY') as diff_interval,
to_char(date '1999-12-31' + (end_week - start_week), 'FMDD "days" HH24 "hours"') as diff_words
from semanas;
WEEK IS START_WEEK END_WEEK DIFF_NUM DIFF_INTERVAL DIFF_WORDS
---------- -- ------------------- ------------------- ---------- ------------------- ----------------
1 21 20/05/2019 20:00:00 27/05/2019 00:00:00 6.16666667 +06 04:00:00.000000 6 days 4 hours
2 22 27/05/2019 00:00:00 03/06/2019 00:00:00 7 +07 00:00:00.000000 7 days 0 hours
3 23 03/06/2019 00:00:00 05/06/2019 08:00:00 2.33333333 +02 08:00:00.000000 2 days 8 hours
As currently written the connect by only works properly if the date_range CTE generates a single value; if you actually get multiple rows back from your real query then you'll have to do a bit more work, or switch to recursive CTEs, or cross join/apply, depending on your Oracle version.
Your endweek calculation is
to_char(to_date(start_date ,'dd/mm/yyyy hh24:mi:ss')+ (7 * (LEVEL - 1)),'IW') + 6 endweek
This attempts to add the number 6 to a character string. I suspect that what you wanted was
to_char(to_date(start_date ,'dd/mm/yyyy hh24:mi:ss') + (7 * (LEVEL - 1) + 6),'IW') endweek
Here I've moved the + 6 so you're adding 6 to the date value, rather than to a character string.
I have the following WHEREclause in a query:
SELECT ...
FROM ...
WHERE IMPORT_DATE between
to_date('2018-03-16 00:00:00', 'yyyy-mm-dd hh24:mi:ss') and
to_date('2018-03-16 23:59:59', 'yyyy-mm-dd hh24:mi:ss')
And I would like to write two new queries:
One with this same clause but using "today" instead of "2018-03-16".
Another with the same clause but using "the day before yesterday" (today - 2) instead of "2018-03-16".
How can I do this in Oracle?
As Oracle has no real DATE data type and always includes a time, it's usually better to not use between for conditions like that, but to use >= together with < compared to midnight the next day.
To find the rows from "today" use:
SELECT ...
FROM ...
WHERE import_date >= trunc(sysdate)
AND import_date < trunc(sysdate) + 1;
or:
SELECT ...
FROM ...
WHERE import_date >= trunc(sysdate) - 2
AND import_date < (trunc(sysdate) - 2) + 1;
The parentheses aren't really required in the second expression, they are just there to document that it's the same expression as the first one.
select trunc(sysdate) from dual;
Returns today's date without any time
select trunc(sysdate) - interval '2' day from dual;
Returns the day 2 days before today without time.
You can also use month, hour, year etc instead of day.
Hi I want to run a query which extracts data from 7:00 am in the morning to 3:00 pm yesterday.
I run this query in afternoon.
Below query extracts data from time I run the query. I want the data from 7:00 am and backwards.
select *
from NOTES
where creation_date >= sysdate- interval '17:15' hour to minute
I would appreciate any help.
Try this in Oracle:
SELECT *
FROM NOTES
WHERE creation_date BETWEEN to_timestamp(to_char(sysdate) || ' 00:00:00', 'dd-Mon-yy hh24:mi:ss') - interval '9' hour
AND to_timestamp(to_char(sysdate) || ' 00:00:00', 'dd-Mon-yy hh24:mi:ss') + interval '7' hour;
Try this in MySQL:
SELECT *
FROM NOTES
WHERE creation_date >= (concat(current_date(), ' 00:00:00') - interval '09:00' hour)
AND creation_date <= (concat(current_date(), ' 00:00:00') + interval '07:00' hour);
Try this as optimal
For Oracle
SELECT *
FROM NOTES
WHERE creation_date BETWEEN trunc(sysdate) - INTERVAL '9' HOUR
AND trunc(curdate) + INTERVAL '7' HOUR;
For MySQL
SELECT *
FROM NOTES
WHERE creation_date BETWEEN curdate() - INTERVAL 9 HOUR
AND curdate() + INTERVAL 7 HOUR;
If you need detail info - just ask.
I'm attempting to speed up a timestamp comparison query by restricting the query to 30 minutes before and after the timestamp in question. This is the format I'm using:
Causedat
-----
11-NOV-15 10.20.58.000000000 AM
11-NOV-15 10.19.41.877000000 AM
10-NOV-15 11.01.40.000000000 AM
10-NOV-15 11.00.50.460000000 AM
05-NOV-15 01.53.30.966000000 PM
05-NOV-15 01.47.31.000000000 PM
What I'm trying to do is write a condition where i'll tell the system only to look for dates in the system that are +-00:30:00.000000000 (thirty minutes) from the Causedat date in the future or past from that time.
I've seen that for example, SYSDATE - SYSTIMESTAMP is a legitimate calculation. Is it possible to do something similar to this like this:
WHERE search.date >= (Causedat = Causedat - '000000000 00:30:00.000000000')
AND search.date <= (Causedat = Causedat + '000000000 00:30:00.000000000')
Please assume the date i'm searching and Causedat are in the same (timestamp) format for this question.
Thank you for any light you may be able to shine on the problem for me.
You can add an interval to a timestamp; you can read about datetime and interval arithmetic. There are conversion functions to go from a variable to an interval, but with known fixed values you can use an interval literal here. You can use the full string you have:
where search_date >= causedat - interval '000000000 00:30:00.000000000' day to second
and search_date <= causedat + interval '000000000 00:30:00.000000000' day to second;
Or just the non-zero part:
where search_date >= causedat - interval '30' minute
and search_date <= causedat + interval '30' minute;
Trivial demo of how these evaluate:
select systimestamp,
systimestamp - interval '000000000 00:30:00.000000000' day to second as minus_30,
systimestamp + interval '000000000 00:30:00.000000000' day to second as plus_30
from dual;
SYSTIMESTAMP MINUS_30 PLUS_30
----------------------------------- ----------------------------------- -----------------------------------
18-NOV-15 11.39.09.597473000 +00:00 18-NOV-15 11.09.09.597473000 +00:00 18-NOV-15 12.09.09.597473000 +00:00
select systimestamp,
systimestamp - interval '30' minute as minus_30,
systimestamp + interval '30' minute as plus_30
from dual;
SYSTIMESTAMP MINUS_30 PLUS_30
----------------------------------- ----------------------------------- -----------------------------------
18-NOV-15 11.39.09.653809000 +00:00 18-NOV-15 11.09.09.653809000 +00:00 18-NOV-15 12.09.09.653809000 +00:00
Direct arithmetic on date time column with required interval value.
WHERE search.date
BETWEEN Causedat - INTERVAL '30' MINUTE
AND Causedat + INTERVAL '30' MINUTE
I just went through the question. I have provided a simple example to illustrate how we can achieve this.
SELECT A.DT
FROM
( SELECT SYSTIMESTAMP - INTERVAL '60' MINUTE AS DT FROM DUAL
UNION
SELECT SYSTIMESTAMP - INTERVAL '30' MINUTE AS DT FROM DUAL
UNION
SELECT SYSTIMESTAMP AS DT FROM DUAL
UNION
SELECT SYSTIMESTAMP + INTERVAL '30' MINUTE AS DT FROM DUAL
UNION
SELECT SYSTIMESTAMP + INTERVAL '60' MINUTE AS DT FROM DUAL
)A
WHERE A.DT BETWEEN (SYSTIMESTAMP - INTERVAL '30' MINUTE) AND (SYSTIMESTAMP + INTERVAL '30' MINUTE);
Let me know if this helps.
I'm trying to calculate difference in minutes between two dates in Oracle with this testing query:
SELECT
(DATE2-DATE1)*24*60 DIFFINMINUTES
FROM
(
SELECT
TO_DATE('2014-06-06 10:30:00', 'YYYY-MM-DD HH24:MI:SS') DATE1,
TO_DATE('2014-06-06 11:25', 'YYYY-MM-DD HH24:MI') DATE2
FROM DUAL
);
The expected result should be 55 minutes but I'm getting 54,99999999.
ROUNDing this value gets the job done but I really wants to understand why this calculation was this behavior.
DATE2 - DATE1 Oracle calculates the difference in days. That's why some inaccuracy may occur.
Just an example with timestamps
select inter,
extract (day from inter) days,
extract (hour from inter) hours,
extract (minute from inter) minutes,
extract (second from inter) seconds
from
(select
cast(date2 as timestamp) - cast(date1 as timestamp) inter
FROM
(
SELECT
TO_DATE('2014-06-06 10:30:00', 'YYYY-MM-DD HH24:MI:SS') DATE1,
to_date('2014-06-06 11:25', 'YYYY-MM-DD HH24:MI') date2
from dual
));
Substraction of timestamps gives you exact INTERVAL